Merry Soy, married, earns a weekly salary of $830 and claims one withholding allowance. By the percentage method, how much income tax will be withheld? (Use tables in the text or the Handbook.)

Answers

Answer 1

Answer:

Hello!

_____________________

The total amount of income tax to withhold is: 35.70 + 34.67 = 70.37$

Step-by-step explanation: Subtract this amount from the salary: 830 - 77.90 = 752.1 $. This is the amount subject to withholding.

The amount subject to withholding is between 521 and 1613$, which means that the income tax to withhold is: 35.70$ + 15% of excess over $521

Therefore, calculate the excess: 752.1 - 521 = 231.1$

Now, calculate the percentage: 231.1 × 15 ÷ 100 = 34.67$

Hope this helped you!


Related Questions

A tank contains 4,000 L of brine with 18 kg of dissolved salt. Pure water enters the tank at a rate of 40 L/min. The solution is kept thoroughly mixed and drains from the tank at the same rate.
a. How much salt is in the tank after t minutes?
b. How much salt is in the tank after 30 minutes? (Round your answer to one decimal place.

Answers

Answer:

(a)[tex]A(t)=18e^{ -\frac{t}{100}}[/tex]

(b)13.3 kg

Step-by-step explanation:

The volume of brine in the tank = 4000L

Initial Amount of salt, A(0)=18 kg

The rate of change in the amount of salt in the tank at any time t is represented by the equation:

[tex]\dfrac{dA}{dt}=$Rate In$-$Rate Out[/tex]

Rate In = (concentration of salt in inflow)(input rate of brine)

Since pure water enters the tank, concentration of salt in inflow =0

Rate In = 0

Rate Out=(concentration of salt in outflow)(output rate of brine)

[tex]=\frac{A(t)}{4000}\times 40\\ =\frac{A(t)}{100}[/tex]

Therefore:

[tex]\dfrac{dA}{dt}=-\dfrac{A(t)}{100}\\\dfrac{dA}{dt}+\dfrac{A(t)}{100}=0[/tex]

This is a linear D.E. which we can then solve for A(t).

Integrating Factor: [tex]e^{\int \frac{1}{100}d}t =e^{ \frac{t}{100}[/tex]

Multiplying all through by the I.F.

[tex]\dfrac{dA}{dt}e^{ \frac{t}{100}}+\dfrac{A(t)}{100}e^{ \frac{t}{100}}=0e^{ \frac{t}{100}}\\(Ae^{ \frac{t}{100}})'=0[/tex]

Taking integral of both sides

[tex]Ae^{ \frac{t}{100}}=C\\A(t)=Ce^{ -\frac{t}{100}}[/tex]

Recall our initial condition

A(0)=18 kg

[tex]18=Ce^{ -\frac{0}{100}}\\C=18[/tex]

Therefore, the amount of salt in the tank after t minutes is:

[tex]A(t)=18e^{ -\frac{t}{100}}[/tex]

(b)When t=30 mins

[tex]A(30)=18e^{ -\frac{30}{100}}\\=18e^{ -0.3}\\=13.3 $kg(correct to 1 decimal place)[/tex]

The amount of salt in the tank after 30 minutes is 13.3kg

In this exercise we have to use the integral to calculate the salt concentration:

(a)[tex]A(t)=18e^{-\frac{t}{100} }[/tex]

(b)[tex]13.3 kg[/tex]

Knowing that the volume of brine in the tank = 4000L, the initial Amount of salt, A(0)=18 kg. The rate of change in the amount of salt in the tank at any time t is represented by the equation:

[tex]\frac{dA}{dt} = Rate \ in - Rate \ out[/tex]

Rate In = (concentration of salt in inflow)(input rate of brine). Since pure water enters the tank, concentration of salt in inflow =0.

Rate In = 0

Rate Out=(concentration of salt in outflow)(output rate of brine)

[tex]\frac{A(t)}{4000}*(40)[/tex]

[tex]= \frac{A(t)}{100}[/tex]

Therefore:

[tex]\frac{dA}{dt} = \frac{A(t)}{100}\\\frac{dA}{dt} + \frac{A(t)}{100} = 0[/tex]

This is a linear D.E. which we can then solve for A(t). Integrating Factor:  [tex]e^{\int\limits {\frac{t}{100} } \, dt\\e^{t/100}[/tex] . Multiplying all through by the Integrating Factor:  

[tex]\frac{dA}{dt} = e^{t/100}+\frac{A(t)}{100}e^{t/100}\\(Ae^{1/100})'=0[/tex]

Taking integral of both sides:

[tex]Ae^{t/100}=C\\A(t)=Ce^{-t/100}[/tex]

Recall our initial condition:

[tex]A(0)=18 kg\\18=Ce^{0}\\C=18[/tex]

Therefore, the amount of salt in the tank after t minutes is:

[tex]A(t)=18e^{-t/100}[/tex]

(b)When t=30 mins

[tex]A(30)=18e^{-30/100}\\=18e^{-0.3}\\=13.3[/tex]

The amount of salt in the tank after 30 minutes is 13.3kg.

See more about concentration at brainly.com/question/12970323

Find the value of c such that the three points (5,5), (-3,1), and (6,c) lie on the same line. Note: Three points are on the same line if the slope of the line through any two points is always the same.

Answers

Answer:

c = 5.5

Step-by-step explanation:

We can find the slope of the line using the given points (5,5) and (-3,1) using rise over run:

-4/-8 = 1/2

Now, we can plug in the slope and a point into the equation y = mx + b to find b:

5 = 1/2(5) + b

5 = 2.5 + b

2.5 = b

Then, we can plug in 6 in the point (6,c) to find c:

y = (1/2)(6) + 2.5

y = 3 + 2.5

y = 5.5

c = 5.5

Answer:

c = 5.5

Step-by-step explanation:

Find the slope with two points

m = (y2-y1)/(x2-x1)

m = (1-5)/(-3-5)

   = -4/-8

   = 1/2

If all the points are on the same line, then they have the same slope

m = (y2-y1)/(x2-x1)

Using the first and third points

1/2 = (c-5)/(6-5)

1/2 =  (c-5)/1

1/2 = c-5

Add 5 to each side

5+1/2 = c

5.5 =c

Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. What is the estimated probability that Rita will need to pick at least five beads before she picks a gray bead from her collection? Use the table of randomly generated outcomes to answer the question. Each letter represents the first letter of the bead color.

Answers

Step-by-step explanation:

Given that Rita is making a beaded bracelet. She has a collection of 160 blue beads, 80 gray beads, and 240 pink beads. We are to calculate the probability that Rita will need to pick atleast 5 beads before she picks a grey bead from her collection.

Prob for drawing atleast 5 beads before she picks a grey bead from her collection

= 1-Prob for drawing atleast one grey beed in the first 5 draws.

(Because these two are complementary events)

no of grey beeds drawn in first 5 trials is

Bi=(5,1/6)

Prob for drawing atleast one grey beed in the first 5 draws.

=1-Prob of no grey

Hence required prob=P(X=0 in first 5 draws)

= 0.4018

6th beeds onwards can be grey also.

Nearest answer is c)0.45

Answer:

o.45

Step-by-step explanation:

i just did the test

Find an equation of the tangent line to the curve at the given point.x2+2xy−y2+x=101, (7,9) (hyperbola)

Answers

Answer:

The equation of the tangent line of the given curve

  [tex]\frac{dy}{dx} = \frac{- (2x +2y +1)}{( 2 x - 2 y)}[/tex]

The tangent of the given curve at the point

 [tex](\frac{dy}{dx})_{(7,9)} = \frac{33}{4}[/tex]

Step-by-step explanation:

Explanation :-

Step(i):-

Given equation of the parabola

            x²+2xy−y²+x=101  ...(i)

apply derivative Formulas

   a)   [tex]\frac{dx^{n} }{dx} = n x ^{n-1}[/tex]

   b)  [tex]\frac{d U V }{dx} = U \frac{dV}{dx} + V \frac{dU}{dx}[/tex]

Step(ii):-

Differentiating equation (i) with respective to 'x' , we get

 [tex]2 x + 2 ( x \frac{dy}{dx} + y) - 2 y \frac{dy}{dx} +1 = 0[/tex]

 [tex]2 x + 2 x \frac{dy}{dx} +2 y - 2 y \frac{dy}{dx} +1 = 0[/tex]

on simplification , we get

[tex]( 2 x - 2 y) \frac{dy}{dx} = - (2x +2y +1)[/tex]

        [tex]\frac{dy}{dx} = \frac{- (2x +2y +1)}{( 2 x - 2 y)}[/tex]

The tangent of the given curve at the point ( 7,9)

    [tex](\frac{dy}{dx})_{(7,9)} = \frac{- ((2(7) +2(9) +1))}{( 2 (7) - 2 (9)}[/tex]

    [tex](\frac{dy}{dx})_{(7,9)} = \frac{- (33)}{( -4} = \frac{33}{4}[/tex]

Final answer :-

The equation of the tangent line of the given curve

  [tex]\frac{dy}{dx} = \frac{- (2x +2y +1)}{( 2 x - 2 y)}[/tex]

The tangent of the given curve at the point

 [tex](\frac{dy}{dx})_{(7,9)} = \frac{33}{4}[/tex]

Phil Nelson deposited $35,000 at Wachovia Bank at 3.5% interest
compounded quarterly. How much money will be in this account at
the end of the year?​

Answers

Answer:

$36,241.20

Step-by-step explanation:

Compounded Interest Rate Formula: A = P(1 + r/n)^nt

Since we are given P, r, n, and t, simply plug it into the formula:

A = 35000(1 + 0.035/4)⁴⁽¹⁾

A = 35000(1 + 0.00875)⁴

A = 35000(1.00875)⁴

A = 35000(1.03546)

A = 36241.2

20. The profit of a company increased steadily over a ten-year span. The following ordered pairs show the number of units sold in hundreds and the profit in thousands of units over the ten-year span, (number of units sold, profit) for specific recorded years: (46,250), (48, 305), (50,350), (52, 390), (54, 410) a) Use linear regression to determine a function y, where profit in thousands of dollars depends on the number of units sold in hundreds. b) Predict when the profit will exceed one million dollars.

Answers

Answer:

20

Step-by-step explanation:

The linear function represents the number of units sold y in terms of profit x is y = 27.5x - 1015.

What is a linear function?

A straight line on the coordinate plane is represented by a linear function.

A linear function always has the same and constant slope.

The formula for a linear function is f(x) = ax + b, where a and b are real values.

As per the given pair of (number of units sold y, profit x)

Linear equation slope and y-intercept

A linear equation or function is given as ;

y = mx + c

Here, c is the y-intercept and m is the slope.

The slope associated with two points (x₁, y₁) and (x₂, y₂) is given by

Slope m  = (y₂ - y₁)/(x₂ - x₁)

Therefore slope of (46,250), (48, 305)

m = (305 - 250)/(48 - 46) = 27.5

Put, m = 27.5 and (46,250)

250 = 27.5(46) + c

c = -1015

y = 27.5x - 1015

Hence "The linear function represents the number of units sold y in terms of profit x is y = 27.5x - 1015".

For more about the linear function,

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Which point is located at (Negative 3.5, Negative 4.5)? On a coordinate plane, point A is 3.5 units to the left and 4.5 units down. Point K is 3.5 units to the right and 4.5 units up. Point R is 3.5 units to the left and 4.5 units up. Point Y is 4.5 units to the left and 3.5 units down. point A point K point R point Y

Answers

Answer:

Point A

Step-by-step explanation:

We know that on a coordinate plane, negative numbers can be found by moving down or moving to the left. This point must be found by moving down and left. To establish whether it is point A or point Y, we can remember that x coordinates move left and right and y coordinates move up and down. So, we would need to move 3.5 units left for x and then 4.5 units down for y. This leads us to point A.

hope this helps!

Answer:

it is point A

Step-by-step explanation:

[PLEASE HELP] Each of these statements describe a transformation of a graph of y = x, The which of the statements correctly describe the graph of y =x + 7???

Answers

Answer:

B

Step-by-step explanation:

Adding the 7 to the input (x) will increase the output (y) by 7. Therefore, the graph is translated 7 units up.

Answer:

The answer is B

Step-by-step explanation:

well the equation of a line is : y = mx + b

in this question the equation is y = x

so the line y = x +7  will be 7 units up than y = x

Express the confidence interval (0.036, 0.086) in the form of p-e< p

Answers

Answer:

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

Step-by-step explanation:

Given;

Confidence interval CI = (a,b) = (0.036, 0.086)

Lower bound a = 0.036

Upper bound b = 0.086

To express in the form;

p-e< p < p+e

Where;

p = mean Proportion

and

e = margin of error

The mean p =( lower bound + higher bound)/2

p = (a+b)/2

Substituting the values;

p = (0.036+0.086)/2

Mean Proportion p = 0.061

The margin of error e = (b-a)/2

Substituting the given values;

e = (0.086-0.036)/2

e = 0.025

Re-writing in the stated form, with p = 0.061 and e = 0.025

p-e< p < p+e

(0.061 - 0.025) < 0.061 < (0.061 + 0.025)

0.036 < 0.061 < 0.086

Which of the following is a negation for "There exists a real number x such that for all real numbers y, xy > y."1) There exists a real number x such that for all real numbers y, xy ≤ y.2) There exists a real number y such that for all real numbers x, xy ≤ y.3) There exists real numbers x and y such that xy ≤ y.4) For all real numbers x there exists a real number y such that xy ≤ y.5) For all real numbers y there exists a real number x such that xy ≤ y.

Answers

Answer:

1) There exists a real number x such that for all real numbers y, xy ≤ y.

Step-by-step explanation:

Given the statement:

"There exists a real number x such that for all real numbers y, xy > y"

The negation of the statement is:

"There exists a real number x such that for all real numbers y, xy ≤ y"

The correct option is 1

make d the subject of the formula; n=k/d^2

Answers

Answer:

[tex]n = \frac{k}{ {d}^{2} } [/tex]

[tex] {d}^{2} = \frac{k}{n} [/tex]

[tex]d = \sqrt{ \frac{k}{n} } [/tex]

Here is the required firmula....

Answer:

d = √(k/n)

Step-by-step explanation:

n = k/d²

n/1 = k/d²

Cross multiply.

k = nd²

Divide both sides by n.

k/n = nd²/n

k/n = d²

Take the square root on both sides.

√(k/n) = √(d²)

√(k/n) = d

1. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The expected frequency of satisfied customers from the Berwick sample is________.
a. 60
b. 75
c. 80
d. 90
2. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The expected frequency of satisfied customers from the Milton sample is________.
a. 60
b. 75
c. 80
d. 90
3. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The expected frequency of satisfied customers from the Leesburg sample is________.
a. 60
b. 75
c. 80
d. 90
4. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The chi-square test statistic for these samples is_______.
a. 1.49
b. 2.44
c. 4.15
d. 5.33
5. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The degrees of freedom for the chi-square critical value is_______.
a. 1
b. 2
c. 3
d. 4
6. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
The chi-square critical value using alpha = 0.05 is_______.
a. 2.706
b. 3.841
c. 5.991
d. 7.815
7. Lisa is a regional manager for a restaurant chain that has locations in the towns of Berwick, Milton, and Leesburg. She would like to investigate if a difference exists in the proportion of customers who rate their experience as satisfactory or better between the three locations. The following data represent the number of customers who indicated they were satisfied from random samples taken at each location.
Berwick Milton Leesburg
Number Satisfied 80 85 60
Sample Size 100 120 80
Using alpha = 0.05, the conclusion for this chi-square test would be that because the test statistic is
A. More than the critical value, we can reject the null hypothesis and conclude that there is a difference in proportion of satisfied customers between these three locations.
B. Less than the critical value, we can reject the null hypothesis and conclude that there is a difference in proportion of satisfied customers between these three locations.
C. More than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.
D. Less than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.

Answers

Answer:

1) Option B is correct.

Expected frequency of satisfied customers from the Berwick sample = 75

2) Option D is correct.

Expected frequency of satisfied customers from the Milton sample = 90

3) Option A is correct.

Expected frequency of satisfied customers from the Leesburg sample = 60

4) Option B is correct.

The chi-square test statistic for these samples = 2.44

5) Option B is correct.

The degrees of freedom for the chi-square critical value = 2

6) Option C is correct.

The chi-square critical value using alpha = 0.05 is 5.991

7) Option D is correct.

The conclusion for this chi-square test would be that because the test statistic is less than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.

Step-by-step explanation:

Berwick Milton Leesburg

Number Satisfied 80 85 60

Unsatisfied 20 35 20

Sample Size 100 120 80

Since this is a chi test that aims to check if there are differences in the proportion of expected number of customers for each location, we state the null and alternative hypothesis first.

The null hypothesis usually counters the claim we hope to test and would be that there is no difference between the proportion of expected frequency of satisfied customers at the three locations.

The alternative hypothesis confirms the claim we want to test and is that there is a significant difference between the proportion of expected frequency of satisfied customers at the three locations.

So, the total proportion of satisfied customers is used to calculate the expected number of satisfied customers for each of the three locations.

80+85+60= 225

Total number of customers = 100 + 120 + 80 = 300

Proportion of satisfied customers = (225/300) = 0.75

1) Expected frequency of satisfied customers from the Berwick sample = np = 100 × 0.75 = 75

2) Expected frequency of satisfied customers from the Milton sample = np = 120 × 0.75 = 90

3) Expected frequency of satisfied customers from the Leesburg sample = np = 80 × 0.75 = 60

4) Berwick Milton Leesburg

Number Satisfied 80 85 60

Unsatisfied 20 35 20

Sample Size 100 120 80

Proportion for unsatisfied ccustomers = 0.25

So, expected number of unsatisfied customers for the three branches are 25, 30 and 20 respectively.

Chi square test statistic is a sum of the square of deviations from the each expected value divided by the expected value.

χ² = [(X₁ - ε₁)²/ε₁] + [(X₂ - ε₂)²/ε₂] + [(X₃ - ε₃)²/ε₃] + [(X₄ - ε₄)²/ε₄] + [(X₅ - ε₅)²/ε₅] + [(X₆ - ε₆)²/ε₆]

X₁ = 80, ε₁ = 75

X₂ = 85, ε₂ = 90

X₃ = 60, ε₃ = 60

X₄ = 20, ε₄ = 25

X₅ = 35, ε₅ = 30

X₆ = 20, ε₆ = 20

χ² = [(80 - 75)²/75] + [(85 - 90)²/90] + [(60 - 60)²/60] + [(20 - 25)²/25] + [(35 - 30)²/30] + [(20 - 20)²/20]

χ² = 0.3333 + 0.2778 + 0 + 1 + 0.8333 + 0 = 2.4444 = 2.44

5) The degree of freedom for a chi-square test is

(number of rows - 1) × (number of columns - 1)

= (2 - 1) × (3 - 1) = 1 × 2 = 2

6) Using the Chi-square critical value calculator for a degree of freedom of 2 and a significance level of 0.05, the chi-square critical value is 5.991.

7) Interpretation of results.

If the Chi-square test statistic is less than the critical value, we fail to reject the null hypothesis.

If the Chi-square test statistic is unusually large and is greater than the critical value, we reject the null hypothesis.

For this question,

Chi-square test statistic = 2.44

Critical value = 5.991

2.44 < 5.991

test statistic < critical value

The test statistic is Less than the critical value, we fail to reject the null hypothesis and conclude that there is no difference in proportion of satisfied customers between these three locations.

Hope this Helps!!!

Can somebody help me with this question

Answers

Answer:

93 ft

Step-by-step explanation:

the area of a triangle is :

A = (b*h)/2 where b is the base and h the height(here t)

4092 = (88*t)/2

2*4092 = 88*t

t= (4092*2)/88 = 93 ft

According to a government commision, 70% of all the nation’s households have vcrs. In a random sample of 15 households, what is the probability that exactly 10 have vcrs

Answers

Answer:  P(10,15,0.7)=3003*0.7^10*0.3^5=approx  0.2061

Step-by-step explanation:

The required probability P(10,15,0.7)= C15 10 *p^10*q^(15-10) where

C15 10=  15 !/10!/5!= 11*12*13*14*15/(2*3*4*5)=11*12*13*14/(2*4)=11*3*13*7=

=77*39=3003

p=0.7    q=1-p =1-0.7= 0.3 (probability of not having vcrs)

So P(10,15,0.7)=3003*0.7^10*0.3^5=approx  0.2061

Nine balls, each marked with a number from 1 to 9, are placed in a bag and one

Ball is taken out at random. What is the probability that the number on the ball is:

(a) odd, (b) a multiple of 3, (c) 5, (d) not a 7​

Answers

Answer:

a =5/9 b=1/3 c=1/9 d=8/9

Step-by-step explanation:

there are total 9 numbers

in a

there are 5 odd numbers

in b

there are 3 multiplier of 3

in c

there is only one 5

in d

there are 8 numbers except 7

a) 5/9 b) 1/3 c) 1/9 d) 8/9

Step-by-step explanation:

a) odd numbers between 1 to 9 are 1,3,5,7,9. so there are 5 odd numbers.

total balls are 9

=> probability is 5/9

b) multiples of 3 = 3, 6,9 there are 3 numbers.

=> probability is = 3/9 = 1/3

c) 5. only one 5 is there between 1 to 9 numbers.

=> probability is 1/9

d) not a 7.

removing 7. there will 8 numbers.

=> probability is 8/9

If f(x)=2x−1, show that f(f(x))=4x−3. Find f(f(f(x))).

Answers

Answer: f(f(f(x)))=8x-7

Step-by-step explanation:

Since we were given f(x) and f(f(x)), We plug that into f(x) again to get f(f(f(x))).

2(4x-3)-1                          [distribute]

8x-6-1                              [combine like terms]

8x-7

forex is the name of the U.S. stock exchange.

-true
-false

Answers

Answer:

false

Step-by-step explanation:

hello

this is false

FOREX means Foreign Exchange

it refers to the foreign exchange market

hope this helps

Answer:

true, forex trading is a profitable than staking cryptocurrency. forex trading is the best thing I will refer someone I love because learning never stops and no on is above blowing accounts when beginning Forex

Which is a possible paycheck deduction? Select all that apply.
commission
federal income tax
health insurance premium
overtime hours
state income tax

Answers

Answer:

Federal income taxes, health insurance premium, state income tax

Step-by-step explanation:

Commission may be a bonus from a sale you made and overtime hours are extra hours over 40.00 that you worked during the week

2  things are certain in life death and taxes

Want Brainliest? Get this correct Which of the following is the product of the rational expressions shown below?

Answers

Answer: Choice D   [tex]\frac{2x^2}{x^2-x-20}[/tex]

We multiply the numerators together to get x*2x = 2x^2 as the numerator for the answer.

The denominators pair up and multiply to get (x-5)(x+4) = x^2+4x-5x-20 = x^2-x-20. You can use the distributive property, FOIL, or the box method to expand out (x-5)(x+4)

So that's how we end up with (2x^2) all over (x^2-x-20) as the answer.

Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
Rewrite the following equation in the form y = a(x - h)2 + k. Then, determine the x-coordinate of the minimum.

y = 2x2 - 32x + 56

The rewritten equation is y =
(x -
)2 +
.

The x-coordinate of the minimum is
.

Answers

Answer:

Therefore the x - coordinate of the minimum is x = -8

Step-by-step explanation:

[tex]y = 2x^2 + 32x + 56 = 2(x^2 + 16x ) + 56 = 2(x^2 + 16x +64 - 64) + 56 \\= 2(x^2 + 16x +64) - 128 + 56 = 2(x+8)^2 - 72[/tex]

Therefore the x - coordinate of the minimum is x = -8

Now that we have our linear regression model, let’s try to make a prediction for the sales given a new set of advertising budgets as follows: new.dat <- data.frame(TV=200, Radio=10, Newspaper=20) You are required to report the predicted sales as well as the lower and upper bound for the 95% prediction interval. What will you report?

Answers

Answer:

The predicted sales for the new set of advertising budgets is 14.

Step-by-step explanation:

The linear regression model is:

[tex]\text{Sales}=2.9389+0.0458\cdot(\text{TV})+0.1885\cdot(\text{Radio})-0.0010\cdot(\text{Newspaper})[/tex]

Compute the value of sales for:

TV = 200,

Radio = 10,

Newspaper = 20

[tex]\text{Sales}=2.9389+0.0458\cdot(\text{TV})+0.1885\cdot(\text{Radio})-0.0010\cdot(\text{Newspaper})[/tex]

        [tex]=2.9389+0.0458\cdot(200)+0.1885\cdot(10)-0.0010\cdot(20)\\=2.9389+9.16+1.885-0.0002\\=13.9837\\\approx 14[/tex]

Thus, the predicted sales for the new set of advertising budgets is 14.

A sample of bacteria is decaying according to a half-life model. If the sample begins with 800 bacteria, and after 13 minutes there are 320 bacteria, after how many minutes will there be 15 bacteria remaining? Round your answer to the nearest whole number.

Answers

Answer:

56.42 minutes

Step-by-step explanation:

The initial sample= y0 = 800

After 13 minutes , amount = 320

Y= y0e-kt

320 = 800e-k(13)

320/800 = e-k13

0.4 = e-k13

In0.4 = -k13

-0.91629= -k13

0.07048= k

Y = 800e-0.07048t

Minutes when the bacterial present will be 15

15 = 800e-0.07048t

15/800= e-0.07048t

0.01875 = e-0.07048t

In 0.01875 = -0.07048t

-3.97656 = -0.07048t

-3.97656/-0.07048= t

56.42 = t

56.42 minutes

Number of non sqaure number are there between 36² and 37²

Answers

Answer:

A 1,296

B 1,369

36 answer


A number increased by negative eight is equal to fourteen. Which equation could be used to find the number?

Answers

Answer:

-8 + x = 14

Number = 22

Step-by-step explanation:

Let x be the number.

First, we know that we'll be using addition to find the number because the problem says "increased" which means add or addition.

Next, We also know that the starting number is -8 and the answer to the equation is 14.

That's why the equation is -8 (starting number) + x = 14 (ending number)

Therefore the answer would be: -8 + x = 14

Which side lengths form a right triangle?

Answers

Answer:

B) 1, 8, √65

Step-by-step explanation:

For 3 side lengths to form a triangle the sum of two random sides must be bigger than the third side and their differences must be smaller than the third side.

1+8 > √65 because √65 is approximately 8.1

8-1 < √65

Answer:

B. 1,8,(65)½

Step-by-step explanation:

For the side lengths to form a right triangle they have to obey the Phythagorean Theorem which when paraphrased says " the square of the longer side is equal to the sum of the squares of the other sides"

A . 2² + 15² = 4 + 225 = 229

17² = 289

Not a Phythagorean triple

B. 1² + 8² = 1 + 64 = 65

(65½)² = 65

A Phythagorean triple

C. 2² + (80½)² = 4 + 80 = 84

9² = 81

Not a Phythagorean triple.

Assume that the profit generated by a product is given by where x is the number of units sold. If the profit keeps changing at a rate of per month, then how fast are the sales changing when the number of units sold is 1900

Answers

Answer:

21794.495 units/month

Step-by-step explanation:

Some data are missing which i can assume as per requirement of the Question.

Let us consider that profit generated by a product is given by

p(x) =4√x

Also, consider that the profit keeps changing at a rate of $1000 per month.

Now, Using the chain rule we can write

dp/dx=(dp/dt)÷(dx/dt).

So, we  can calculate

dp/dx=2x^(-1/2)=2/√x.

As per  question we have to find out  dx/dt

Since, dx/dt= (dp/dt)/(dp/dx),

so plugging  x=1900  we get 1000√1900/2=21794.495 units/month increase in sales.

A rectangle is placed around a semicircle as shown below. The length of the rectangle is 12 cm. Find the area of the shaded region.
Use the value 3.14 for at, and do not round your answer. Be sure to include the correct unit in your answer.

Answers

Answer:

15.48 ft^2

Step-by-step explanation:

According to the image we have the following information:

the length of the rectangle = diameter of the semicircle, therefore it is 12 feet

, the radius of the semicircle (half the diameter) = width of the rectangle = 12/2 ft = 6 ft

We also know that the area of the shaded region would be equal to the area of the rectangle minus the area of the semicircle.

Therefore, we replace:

Area of the rectangle = width * length

Ar = 6 ft * 12 ft = 72 ft ^ 2

Area of the semicircle = [1/2] * π * (r ^ 2)

As = [1/2] * 3.14 * (6 feet) ^ 2 = 56.52 ft ^ 2

We replace in the area of the shaded region

shaded region area = 72 ft ^ 2 - 56.52 ft ^ 2 =

Shaded region area = 15.48 ft ^ 2

The price of a vase was increased by 10% to £22.What was the price before the increase

Answers

Answer: £20.

Step-by-step explanation:

Let the old price = £x

Percent increase. = 10%

Increment. = 10% of £x

= 10x/100

Now new price = £22

To determine the old price we have

x + 10x/100. = 22

We now multiply everything by 100 to make it a linear expression

100x + 10x = 2200

110x = 2200, therefore

x. = 2200/110

= £20

Therefore, the price before the increase. = £20.

Please help me with this question!!

Answers

Answer:

rationalirrationalirrationalirrational√7, it is irrational

Step-by-step explanation:

A rational number is one that can be expressed as the ratio of two integers. All fractions that have integer numerators and (non-zero) denominators are rational numbers. Any finite decimal number, or any repeating decimal number, is a rational number. These can always be expressed as the ratio of two integers. For example, 0.4040... = 40/99, and 0.286 = 286/1000.

To make an irrational sum, at least one of the contributors must be irrational. You want an irrational 2-number sum that has 7/8 as one of the contributors. Since 7/8 is rational, the other contributor must be irrational.

__

Step 1. The number 7/8 is rational.

Step 2. The desired sum is irrational.

Step 3. The rule rational + irrational = irrational applies.

Step 4. An irrational number must be chosen.

Step 5. √7 will produce an irrational sum, because it is irrational.

A rookie quarterback is negotiating his first NFL contract.His opportunity cost is 10%. He has been offered three possible 4-year contracts. Payments are guaranteed, and they would be made at the end of each year. Terms of each contract are as follows:________.
1 2 3 4
Contract 1 $3,000,000 $3,000,000 $3,000,000 $3,000,000
Contract 2 $2,000,000 $3,000,000 $4,000,000 $5,000,000
Contract 3 $7,000,000 $1,000,000 $1,000,000 $1,000,000
As his advisor, which contract would you recommend that he accept?

Answers

Answer:

He should accept contract 2 because it has a higher present value.

Step-by-step explanation:

we need to find the present value of each contract:

Contract 1 = $3,000,000/1.1 + $3,000,000/1.1² + $3,000,000/1.1³ + $3,000,000/1.1⁴  = $2,727,273 + $2,479,339 + $2,253,944 + $2,049,040 = $9,509,596

Contract 2 $2,000,000/1.1 + $3,000,000/1.1² $4,000,000/1.1³ + $5,000,000 /1.1⁴  = $1,818,182 + $2,479,339 + $3,005,259 + $3,415,067 = $10,717,847

Contract 3 $7,000,000/1.1 + $1,000,000/1.1² + $1,000,000/1.1³ + $1,000,000/1.1⁴  = $6,363,636 + $826,446 + $751,315 + $683,013 = $8,624,410

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