MDM4U
11. Avery and Bradley work at a large electronics manufacturer that produces DVD players. The
defective rate on the assembly line has gone up to 12% and the manager wants to know the
probability that a skid of 50 DVD players will contain at least 3 defective units.
a) Help Avery use the binomial distribution P(x)=, C.pqrs to answer this question

Answer:

The first one is a linear function with the slope of 3 with no shift. the second is a vertical line on the 2 of the x axis. the third is a horizontal line on the -3 of the y axis.

Answer:

c.) 20%

Step-by-step explanation:

•1/3 chnace of picking Strawberry flavor

•2/3 chance of picking a milkshake or cone serving

(1/3)*(2/3)=2/9=0.222...(approx.)=0.20=20%

Edit for more clarification:

If you have a situation where multiple outcomes are favorable ("or" statements) then you add the odds together. The customer here wouldn't have minded a milkshake or a cone, so we add their odds together to get 2/3.

If you have a situation where a specific combination of outcomes is favorable ("and" statements) then we multiply the odds. The customer would be getting a flavor and a type of serving, so we multiply the odds of each combination together.

(Note that this is technically a simplified version of the general formulas/equations for probabilities so if you go look them up on the internet they might include some other ideas.)

Answer:C

Step-by-step explanation:

quiz says it was right

Answer:

The elevation when the boiling point of water is [tex]190[/tex] °[tex]F[/tex] is 12790.70 feet

Step-by-step explanation:

Let every 1,000 feet of elevation be [tex]x[/tex]. Hence, we can write

[tex]T = 212[/tex] [tex]- 1.72x[/tex]

Where [tex]T[/tex] is the boiling temperature of water at different elevations

Now, to the determine the elevation when the boiling point of water is [tex]190[/tex] °[tex]F[/tex].

We will determine [tex]x[/tex] by putting [tex]T = 190[/tex] °[tex]F[/tex].

Hence,

[tex]T = 212[/tex] [tex]- 1.72x[/tex]

[tex]190[/tex]  [tex]= 212[/tex]  [tex]- 1.72x[/tex]

[tex]190 - 212[/tex]    [tex]= - 1.72x[/tex]

[tex]- 22[/tex]  [tex]= - 1.72x[/tex]

[tex]22 = 1.72x\\x = \frac{22}{1.72} \\x = 12.79070[/tex]

Since [tex]x[/tex] represents every 1,000 feet of elevation, then the elevation when the boiling point of water is [tex]190[/tex] °[tex]F[/tex]

[tex]12.79070[/tex] × [tex]1000\\[/tex] [tex]= 12790.70[/tex] feet

Hence,  the elevation when the boiling point of water is [tex]190[/tex] °[tex]F[/tex] is 12790.70 feet

Answer:

53 and 54

Step-by-step explanation:

x + (x+1) = 107

2x+1 = 107

2x = 107

x = 53

x+1 = 54

Answer:

None of the above

Step-by-step explanation:

-5/2 is not equal to 5/2

5/2 - 39/8 = -19/8

if you calculate the two options you will see that none of them is equal to -19/8

Answer: KE= 900,000t^2

Step-by-step explanation:

Answer:

1,582.25 kilogramos

Step-by-step explanation:

Para determinar los kilogramos de maíz que lleva el camión, se debe multiplicar el peso de los dos tipos de bultos que lleva por la cantidad de cada uno y sumar estos valores para obtener la respuesta:

(20.5*32)+(48.75*19)=656+926.25=1,582.25

De acuerdo a esto, el camión lleva 1,582.25 kilogramos de maíz.

Answer:

x = 4 + √3 and  x = 4 − √3

Step-by-step explanation:

(a−b)^2=a^2−2ab+b2

a^2−b^2=(a−b)(a+b)

−2x^2+16x−26

=−2(1x^2−8x+13)

=−2(x^2−8x+13+3−3)

=−2(x^2−8x+16−3)

=−2(x^2−2(4)x+4^2−3)

=−2((x−4)^2−3)

=−2((x−4)^2−(√3)^2)

=−2((x−4)−√3)((x−4)+√3)

=−2((x−(4+√3)((x−(4−√3))

The zeros of the given algebraic expression are:

−2x^2+16x−26=0

−2((x−(4+√3)((x−(4−√3))=0

x = 4 + √3 and  x = 4 − √3

I strongly suggest using the quadratic formula as this problem is much easier to solve using it.

x = (−b ± [tex]\sqrt{b^{2}-4ac }[/tex] ) / 2

Answer:

I think its rational

Step-by-step explanation:

Answer: 0.35 is rational! :D Hopefully this will help others as well!

Step-by-step explanation:

Answer:

9 eazy

Step-by-step explanation:

Answer:

B.9

Step-by-step explanation:

3^4=81

3^2=9

81/9=9

The geometric terms that best describes each part of the tennis court are Playing Surface ⇒ Plane and Corner of Serving Box ⇒ Vertex

There are several geometric terms; some of them are:

Using the above definitions, the geometric terms that best describes each part of the tennis court are

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Answer:

c

Step-by-step explanation:

Answer:

  13.2

Step-by-step explanation:

√175 ≈ 13.2 . . . units

The area of a square is the square of the edge length. Hence, the edge length is the square root of the area.

[tex]\boxed{3:5}[/tex]

We need to first change the measurement of 2 feet to inches, and then find the most simplified version of the resulting ratio.

2 feet = 24 inches (1 foot = 12 inches)

Ratio: 24:40

Simplify ratio:

24/8 = 3

40/8 = 5

Ratio: 3:5

Therefore, the simplified ratio is 3:5 inches.

Answer:

a = - 1

Step-by-step explanation:

Given the points are equidistant from A then AP = AQ

Calculate the distance using the distance formula

d = [tex]\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }[/tex]

with (x₁, y₁ ) = A(0, a) and (x₂, y₂ ) = P(3, - 3)

AP = [tex]\sqrt{3-0)^2+(-3-a)^2}[/tex] = [tex]\sqrt{3^2+(-3-a)^2}[/tex] = [tex]\sqrt{9+(-3-a)^2}[/tex]

Repeat with (x₁, y₁ ) = A(0, a) and (x₂, y₂ ) = Q(- 2, 2)

AQ = [tex]\sqrt{(-2-0)^2+(2-a)^2}[/tex] = [tex]\sqrt{(-2)^2+(2-a)^2}[/tex] = [tex]\sqrt{4+(2-a)^2}[/tex]

Equating AP and AQ

[tex]\sqrt{9+(-3-a)^2}[/tex] = [tex]\sqrt{4+(2-a)^2}[/tex] ( square both sides )

9 + (- 3 - a)² = 4 + (2 - a )² ← expand parenthesis on both sides

9 + 9 + 6a + a² = 4 + 4 - 4a + a² ( subtract a² - 4a from both sides )

18 + 10a = 8 ( subtract 18 from both sides )

10a = - 10 ( divide both sides by 10 )

a = - 1

The value of a is -1 if A(0,a) is equidistant from P(3,-3) and Q(-2,2) the answer is a = -1.

It is defined as a representation of coordinates in a two-dimensional coordinate plane. It has a list of two elements in it, such as (x, y).

[tex]\rm Area = |\dfrac{(x_1y_2-y_1x_2)+(x_2y_3-y_2x_3)....+(x_ny_1-y_nx_1)}{2}|[/tex]

It is given that:

A(0,a) is equidistant from P(3,-3) and Q(-2,2).

It is required to find the value of a:

Using the distance formula:

The distance formula can be given as:

[tex]\rm d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

AP = AQ

[tex]\rm \sqrt{(3-0)^2+(-3-a)^2} = \sqrt{(-2-0)^2+(2-a)^2}[/tex]

After simplification:

9 + (3 + a)² = 4 + (2 - a)²

9 + 9 + 6a + a² = 4 + 4 - 4a + a²

18 + 10a = 8

10a = - 10

a = - 1

The arithmetic operation can be defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division.

Thus, the value of a is -1 if A(0,a) is equidistant from P(3,-3) and Q(-2,2) the answer is a = -1

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Answer:

$28.50

Step-by-step explanation:

21 chicken wings= $39.90

1 chicken wing= 39.90÷21= $1.90

15 chicken wings= 15×1.90= $28.50

Answer:

-5 < x < 10

Step-by-step explanation:

−6 < x − 1 < 9 just get rid of -1 by adding 1 to all three terms

-6 + 1 < x -1 + 1 < 9 + 1

-5 < x < 10

Answer:

| − 2 | − 7 2 x− 9 ⋅ 5 x − 4  − 6 ( y − 3 )

Step-by-step explanation:

Answer:

[tex]\huge\boxed{(3, 8)}[/tex]

Step-by-step explanation:

When we rotate a point 90° counterclockwise around the origin, it's the same as rotating it 270° clockwise around the origin.

When we rotate something 270° clockwise around the origin, the original coordinates (x, y) becomes (-y, x).

y is -3, and -(-3) is just 3, since two negatives make a positive.

x just remains x, but it's in a different position.

This makes the new coordinate [tex](3, 8)[/tex].

Hope this helped!

Answer:

hundred thousands

Step-by-step explanation:

You would move it to the left one place, so it would be the hundred thousands place.

Answer: The answer is hundred thousands place.

Step-by-step explanation: The question is wanting you to name the space the 8 is in. So 10's, 100's, 1000's and so on. But in this case an 8 in the hundred thousand's place has 10 times more value then an 8 in the ten thousand's place.

Answer: x= 2, y= -1/2

Step-by-step explanation:

The value of x is 2 and y is -1/2

equations are  3x-2y=7 --1

                         7x+2y=13 --2

lets  consider  3x-2y=7 as equation 1,

       consider  7x+2y=13 as equation 2

by putting both the equations :-

              3x-2y=7

               7x+2y=13

we get  10x=20

           x=20/10

           x=2

Now by putting the value of x in equation 1;

3(2)-2y=7

6-2y=7

-2y=1

y=-1/2

Simultaneous equations are two or more algebraic equations that share variables e.g. x and y. They are called simultaneous equations because the equations are solved at the same time. Each of these equations on its own could have infinite possible solutions.

algebraic equation, a statement of the equality of two expressions formulated by applying to a set of variables the algebraic operations, namely, addition, subtraction, multiplication, division, raising to a power, and extraction of a root.

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answer:

A.7/5 is the correct answer because numerator is more than denominator.

thank me plz

Answer:

the answer is A

Step-by-step explanation:

Answer:

Step-by-step explanation:

1). [tex]a^{3}\times a^5=a^8[/tex]

2). [tex](a^3)^3[/tex] = [tex]a^{9}[/tex]

3). [tex]\frac{a^{10}}{a^3}=a^{10-3}=a^7[/tex]

4). [tex]\frac{a^2}{a^7}=\frac{1}{a^{7-2}}=\frac{1}{a^5}[/tex]

5). [tex]\frac{a^5\times a^2}{a^7}=\frac{a^{5+2}}{a^7}=1[/tex]

6). [tex]\frac{16a^5b^3}{8a^2b}=(\frac{16\times 5}{8})(\frac{a^5}{a^2})(\frac{b^3}{b})[/tex]

              [tex]=\frac{80}{8}(a^{5-2})(b^{3-1})[/tex]

              = 10a³b²

7). [tex]\frac{2a^3b^3}{2b^2}=(\frac{2}{2})(a^3)(\frac{b^3}{b^2})[/tex]

             = a³b

8). [tex](\frac{a^{-8}}{b^{11}})^{-2}=(\frac{b^{11}}{a^{-8}})^2[/tex]

                 [tex]=(b^{11}a^8)^2[/tex]

                 = [tex]a^{16}b^{22}[/tex]

9). [tex]\frac{(2a^3)(a^4)^2}{8a^{11}}=(\frac{2}{8})(\frac{1}{a^{11-3}})(a^4)^2[/tex]

                   [tex]=\frac{1}{4}(\frac{a^8}{a^8})[/tex]

                   [tex]=\frac{1}{4}[/tex]

10). [tex]\frac{5a^7b^2}{15a^{10}b^{-3}}=(\frac{5}{15})(\frac{a^7}{a^{10}})(b^{2+3})[/tex]

                   [tex]=\frac{1}{3}(\frac{b^5}{a^3} )[/tex]

                   [tex]=\frac{b^5}{3a^2}[/tex]

11). 3a⁰ = 3(1) = 3

12). (a²b)⁴ = (a²)⁴(b)⁴

                = a⁸b⁴

Answer:

$278.40

Step-by-step explanation:

Note: "...an additional 10% off any shoe item, once the first discount has been applied." (emphasis added).

Note that the customer is buying 3 pairs of shoes for $120 each: 120 x 3 = $360

The first discount is the 20% discount  (on every single item), the second discount is the 10% discount coupon of of any item (which signifies one item only).

Solve for the first discount:

$360 x 0.20 = $72

$360 - 72 = $288.

Next, divide $288 by 3 (to get the individual prices of the shoes:

$288/3 = $96.

The customer then uses a birthday coupon for one of the shoes, which gives an additional 10% off.

$96 x 0.10 = 9.6

$96 - 9.6 = $86.4

Remember, the other two shoes still cost $96 each. Add the price together:

$96 + $96 + $86.4 = $278.40

$278.40 will be the total.

~

Answer:

278.40

Step-by-step explanation:

Answer:

GCF-12

Step-by-step explanation:

Find the prime factorization of 84

84 = 2 × 2 × 3 × 7

Find the prime factorization of 120

120 = 2 × 2 × 2 × 3 × 5

To find the GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2 × 2 × 3

GCF = 12

Answer: The GCF is 12

Step-by-step explanation:

84=2*2*3*7

120=2*2*2*3*5

So, the GCF is 2*2*3=12

Answer:

Step-by-step explanation:

[tex]8+9\div3\times6-5\\= 8+9\div \:3\times \left(6-5\right)\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(6-5\right)\::\quad 1\\=8+9\div \:3\times \:1\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:9\div \:3\times \:1\::\quad 3\\=8+3\\\\= 11[/tex]

[tex]5+3-8\div \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8\div \:4\::\quad 2\\=5+3-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:5+3-2-2\::\quad 4\\=4[/tex]

[tex]\left(5+3\right)-8\div \:4-2\\\\\mathrm{Follow\:the\:PEMDAS\:order\:of\:operations}\\\\\mathrm{Calculate\:within\:parentheses}\:\left(5+3\right)\::\quad 8\\=8-8\div \:4-2\\\\\mathrm{Multiply\:and\:divide\:\left(left\:to\:right\right)}\:8\div \:4\::\quad 2\\=8-2-2\\\\\mathrm{Add\:and\:subtract\:\left(left\:to\:right\right)}\:8-2-2\::\quad 4\\=4[/tex]

Answer:31

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

1) 85+(-96)=-11

2) 86+(-38)=48

3) 22+(-41)=-19

Step-by-step explanation:

1)

Here you are adding a negative to a positive. The if you were to take the absolute value of the negative number it would be greater than that of the positive.

Think about it like 96-85=11, but it was flipped so negative 11.

-11

2)

86+(-38) is the same as 86-38

48

3)

Here you are also adding a negative to a positive. The if you were to take the absolute value of the negative number it would be greater than that of the positive.

Think about it like 41-22=19, but it was flipped so negative 19.

-19

Hope this is helpful :-)

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{x = 300}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{110 + 0.70x = 50 + 0.90x}[/tex]

Move 0.90x to left hand side and change it's sign

⇒[tex] \sf{0.70x - 0.90x + 110 = 50}[/tex]

Move 110 to right hand side and change it's sign

⇒[tex] \sf{0.70x - 0.90x = 50 - 110}[/tex]

Collect like terms

⇒[tex] \sf{ - 0.2x = 50 - 110}[/tex]

Calculate

⇒[tex] \sf{ - 0.2x = - 60}[/tex]

Divide both sides of the equation by -0.2

⇒[tex] \sf{ \frac{ - 0.2x}{ - 0.2} = \frac{ - 60}{ - 0.2} }[/tex]

Calculate

⇒[tex] \sf{x = 300}[/tex]

Hope I helped!

Best regards!!