Maya is flying a kite, holding her hands a distance of 3.5 feet above the ground and letting all the kite’s string play out. She measures the angle of elevation from her hand to the kite to be 34^{\circ}

. If the string from the kite to her hand is 125 feet long, how many feet is the kite above the ground? Round your answer to the nearest tenth of a foot if necessary.

Answers

Answer 1

Answer:

The kite is 73.4 feet above the ground.

Step-by-step explanation:

125 sin 34=

Cross multiply.

x=69.899112...

x=69.899112...

{Add 3.5, the distance from the ground to her hand:}

Add 3.5, the distance from the ground to her hand:

69.899112...+3.5=

73.399112...

Answer 2

The kite is 73.4 feet above the ground.

A right angled triangle is a triangle (has three sides and three angles) in which one of the angles measure 90°.

Trigonometric ratios is used to show the relationship between the sides of the right angled triangle and its angles.

Let h represent the perpendicular distance from the top of the kite to her hand. The angle of elevation = 34°. Hence:

sin(34) = h/125

h = 69.9 feet

The distance from the kite to the ground = 69.9 + 3.5 = 73.4 feet

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Answer:

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Step-by-step explanation:

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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Answer:

28, 44, 22

Step-by-step explanation:

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I need filler, hope this helps

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

Answer:

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Answers

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Answers

Answer:

[tex]{ \tt{f(x) = 400 - 15x}} \\ { \boxed{ \tt{when \: f(x )\: is \: 50}}} \\ 400 - 15x = 50 \\ 15x = 400 - 50 \\ 15x = 350 \\ x = 23.3 \approx23 \: buckets \\ \\ { \underline{ \blue{ \tt{becker \: jnr}}}}[/tex]

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