The maximum value of 3x + y is 5/3, which is achieved when x = 1/3 and y = 4/3.
We can solve this optimization problem using the simplex method. First, we convert the problem to standard form:
Maximize: 3x + y + 0u + 0v + 0s1 + 0s2
Subject to:
-x + y + u + s1 = 1
2x + y + v + s2 = 4
x, y, u, v, s1, s2 ≥ 0
We then construct the initial simplex tableau:
| 1 -1 1 0 1 0 | 1
| 2 1 0 1 0 4 | 4
| 3 1 0 0 0 0 | 0
The pivot element is the entry in the first row and first column, which is 1. We use row operations to make all other entries in the first column zero. We subtract row 1 from row 2, and subtract 3 times row 1 from row 3:
| 1 -1 1 0 1 0 | 1
| 0 3 -1 1 -1 4 | 3
| 0 4 -3 0 -3 0 | -3
The new pivot element is the entry in the second row and second column, which is 3. We use row operations to make all other entries in the second column zero. We divide row 2 by 3, and subtract 4 times row 2 from row 3:
| 1 0 1/3 -1/3 2/3 4/3 | 5/3
| 0 1 -1/3 1/3 -1/3 4/3 | 1
| 0 0 -1/3 -4/3 -5/3 -16/3 | -5
All entries in the objective row are positive or zero, so we have found the optimal solution. The maximum value of 3x + y is 5/3, which is achieved when x = 1/3 and y = 4/3.
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Let A be a 8 times 9 matrix. What must a and b be if we define the linear transformation by T: R^a rightarrow R^b as T(x) = Ax ? a = ___________ b = __________
The required answer is a vector in R^5, then we would set b = 5.
To determine the values of a and b in the linear transformation defined by T(x) = Ax, we need to consider the dimensions of the matrix A and the vector x.
We know that A is an 8x9 matrix, which means it has 8 rows and 9 columns. We also know that x is a vector in R^a, which means it has a certain number of components or entries.
The matrix A has 8 rows and 9 columns, which means it maps 9-dimensional vector to 8-dimensional vectors .
To ensure that the matrix multiplication Ax is defined and results in a vector in R^b, we need the number of columns in A to be equal to the number of components in x. In other words, we need 9 = a and b will depend on the number of rows in A and the desired output dimension of T(x).
Therefore, a = 9 and b can be any number between 1 and 8, inclusive, depending on the desired output dimension of T(x). For example,
if we want T(x) to output a vector in R^5, then we would set b = 5.
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Twi triangles are similar. The length of side of one of the triangles is 6 times that of the corresponding sides of the other. Find the ratios of the perimeters and area of the triangles
Answer:
ratio of Perimeters:1:6
Ratio of areas:1:36
Step-by-step explanation:
definition of similarity
Will give brainlest and 25 points
Answer:
The angles are complementary. It is a 90° angle or a right angle.
x = 50°
Hope this helps!
Step-by-step explanation:
50° + 40° = 90°
Explicit formulas for compositions of functions. The domain and target set of functions f, g, and h are Z. The functions are defined as: . . f(x) = 2x + 3 g(x) = 5x + 7 h(x) = x2 + 1 = . Give an explicit formula for each function given below. (a) fog (b) gof (C) foh (d) hof
Explicit formulas are mathematical expressions that represent a function or relationship between variables in a direct and clear way, without the need for further calculations or interpretation.
To find the explicit formulas for the compositions of the given functions, we need to substitute the function inside the other function and simplify:
(a) fog(x) = f(g(x)) = f(5x + 7) = 2(5x + 7) + 3 = 10x + 17
So the explicit formula for fog(x) is 10x + 17.
(b) gof(x) = g(f(x)) = g(2x + 3) = 5(2x + 3) + 7 = 10x + 22
So the explicit formula for gof(x) is 10x + 22.
(c) foh(x) = f(h(x)) = f(x^2 + 1) = 2(x^2 + 1) + 3 = 2x^2 + 5
So the explicit formula for foh(x) is 2x^2 + 5.
(d) hof(x) = h(f(x)) = h(2x + 3) = (2x + 3)^2 + 1 = 4x^2 + 12x + 10
So the explicit formula for hof(x) is 4x^2 + 12x + 10.
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from sin(3) = 1 2 , solve for 3 on the interval [0, 2). (enter your answers as a comma-separated list.)
The solution for 3 on the interval [0, 2) is 3 = π/6, 13π/6 or 30°, 390°.
To solve for 3 from sin(3) = 1/2 on the interval [0, 2), we need to use the inverse sine function (arcsin) and solve for the angle whose sine is equal to 1/2.
arcsin(1/2) = 30° or π/6 radians
Since the interval is [0, 2), we need to add 2π to the angle if it is less than 0 or greater than or equal to 2π.
So, the solution for 3 on the given interval is:
3 = π/6 or 30°, or
3 = π/6 + 2π = 13π/6 or 390°
Therefore, the solution for 3 on the interval [0, 2) is 3 = π/6, 13π/6 or 30°, 390°.
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An open-top box with a square bottom and rectangular sides is to have a volume of 256 cubic inches. Find the dimensions that require the minimum amount of material.
The dimensions that require the minimum amount of material for the open-top box are:
Length = 8 inches, Width = 8 inches, Height = 4 inches.
What are the dimensions for minimizing material usage?To find the dimensions that minimize the amount of material needed, we can approach the problem by using calculus and optimization techniques. Let's denote the length of the square bottom as "x" inches and the height of the box as "h" inches. Since the volume of the box is given as 256 cubic inches, we have the equation:
Volume = Length × Width × Height = x² × h = 256.
To minimize the material used, we need to minimize the surface area of the box. The surface area consists of the bottom area (x²) and the combined areas of the four sides (4xh). Therefore, the total surface area (A) is given by the equation:
A = x² + 4xh.
We can solve for h in terms of x using the volume equation:
h = 256 / (x²).
Substituting this expression for h in terms of x into the surface area equation, we get:
A = x² + 4x(256 / (x²)).
Simplifying further, we obtain:
A = x² + 1024 / x.
To minimize A, we take the derivative of A with respect to x, set it equal to zero, and solve for x:
dA/dx = 2x - 1024 / x² = 0.
Solving this equation yields x = 8 inches. Plugging this value back into the equation for h, we find h = 4 inches.
Therefore, the dimensions that require the minimum amount of material are: Length = 8 inches, Width = 8 inches, and Height = 4 inches.
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Calculate the Taylor polynomials T2 and T3 centered at a = 0 for the function f(x) = 13 tan(x). (Use symbolic notation and fractions where needed.) T2(x) = T3(x) =
The Taylor polynomial T2 centered at a = 0 for f(x) = 13 tan(x) is T2(x) = 13x, and the Taylor polynomial T3 centered at a = 0 is T3(x) = 13x + (26/3)x³.
To calculate the Taylor polynomials T2 and T3 centered at a = 0 for the function f(x) = 13 tan(x), we need to find the first few derivatives of f(x) and then evaluate them at a = 0.
1. Find the first few derivatives:
f'(x) = 13 sec²(x)
f''(x) = 26 sec²(x)tan(x)
f'''(x) = 26 sec²(x)(tan^2(x) + 2)
2. Evaluate derivatives at a = 0:
f(0) = 13 tan(0) = 0
f'(0) = 13 sec²(0) = 13
f''(0) = 26 sec²(0)tan(0) = 0
f'''(0) = 26 sec²(0)(tan²(0) + 2) = 52
3. Form the Taylor polynomials:
T2(x) = f(0) + f'(0)x + (1/2)f''(0)x² = 0 + 13x + 0 = 13x
T3(x) = T2(x) + (1/6)f'''(0)x³ = 13x + (1/6)(52)x³ = 13x + (26/3)x³
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Juan and Rajani are both driving along the same highway in two different cars to a stadium in a distant city. At noon, Juan is 260 miles away from the stadium and Rajani is 380 miles away from the stadium. Juan is driving along the highway at a speed of 30 miles per hour and Rajani is driving at speed of 50 miles per hour. Let � J represent Juan's distance, in miles, away from the stadium � t hours after noon. Let � R represent Rajani's distance, in miles, away from the stadium � t hours after noon. Graph each function and determine the interval of hours, � , t, for which Juan is closer to the stadium than Rajani.
The interval of hours for which Juan is closer to the stadium than Rajani is t < 6, which means within the first 6 hours after noon.
To graph the functions representing Juan's and Rajani's distances from the stadium, we can use the equations:
J(t) = 260 - 30t (Juan's distance from the stadium)
R(t) = 380 - 50t (Rajani's distance from the stadium)
The functions represent the distance remaining (in miles) as a function of time (in hours) afternoon.
To determine the interval of hours for which Juan is closer to the stadium than Rajani, we need to find the values of t where J(t) < R(t).
Let's solve the inequality:
260 - 30t < 380 - 50t
-30t + 50t < 380 - 260
20t < 120
t < 6
Thus, the inequality shows that for t < 6, Juan is closer to the stadium than Rajani.
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Tamera graphs the following points on a coordinate plane. P(3,-4) Q(-7,2) R(5,3) S(6,-1)
The graph would show the points P, Q, R, and S at their respective locations based on their coordinates (x, y).
Tamera graphs the following points on a coordinate plane:
P(3, -4)
Q(-7, 2)
R(5, 3)
S(6, -1)
These points represent the coordinates of four distinct locations on the plane. Each point is represented by an ordered pair (x, y), where the first value represents the x-coordinate and the second value represents the y-coordinate.
For example, the point P(3, -4) means that the x-coordinate is 3 and the y-coordinate is -4. Similarly, the point Q(-7, 2) has an x-coordinate of -7 and a y-coordinate of 2.
By plotting these points on a coordinate plane, Tamera would mark the location of each point using the respective x and y values. This helps visualize the positions of the points relative to each other and the axes of the plane.
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he average width x is 31.19 cm. the deviations are: what is the average deviation?31.5 0.086 cm 0.25 O1
The average deviation from the mean width of 31.19 cm is 0.1725 cm. This means that, on average, the data points are about 0.1725 cm away from the mean width.
The average deviation of a data set is a measure of how spread out the data is from its mean.
It is calculated by finding the absolute value of the difference between each data point and the mean, then taking the average of these differences.
In this problem, we are given a set of deviations from the mean width of 31.19 cm.
The deviations are:
31.5, 0.086 cm, 0.25, -0.01
The average deviation, we need to calculate the absolute value of each deviation, then their average.
We can use the formula:
average deviation = (|d1| + |d2| + ... + |dn|) / n
d1, d2, ..., dn are the deviations and n is the number of deviations.
Using this formula and the given deviations, we get:
average deviation = (|31.5 - 31.19| + |0.086| + |0.25| + |-0.01|) / 4
= (0.31 + 0.086 + 0.25 + 0.01) / 4
= 0.1725 cm
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The average deviation from the mean width of 31.19 cm is 20.42 cm. This tells us that the data points are spread out from the mean by an average of 20.42 cm, which is a relatively large deviation for a dataset with a mean of 31.19 cm.
In statistics, deviation refers to the amount by which a data point differs from the mean of a dataset. The average deviation is a measure of the average distance between each data point and the mean of the dataset. To calculate the average deviation, we first need to calculate the deviation of each data point from the mean.
In this case, we have the mean width x as 31.19 cm and the deviations of the data points as 0.5 cm and -0.086 cm. To calculate the deviation, we subtract the mean from each data point:
Deviation of 31.5 cm = 31.5 - 31.19 = 0.31 cm
Deviation of 0.5 cm = 0.5 - 31.19 = -30.69 cm
Deviation of -0.086 cm = -0.086 - 31.19 = -31.276 cm
Next, we take the absolute value of each deviation to eliminate the negative signs, as we are interested in the distance from the mean, not the direction. The absolute deviations are:
Absolute deviation of 31.5 cm = 0.31 cm
Absolute deviation of 0.5 cm = 30.69 cm
Absolute deviation of -0.086 cm = 31.276 cm
The average deviation is calculated by summing the absolute deviations and dividing by the number of data points:
Average deviation = (0.31 + 30.69 + 31.276) / 3 = 20.42 cm
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Show that the curve with parametric equations x = t^2, y = 1 - 3t, z = 1 + t^3 passes through the points (1, 4, 0) and (9, -8, 28) but not through the point (4, 7, -6)
Answer: To show that the curve passes through a point, we need to find a value of t that makes the parametric equations satisfy the coordinates of the point.
Let's first check if the curve passes through the point (1, 4, 0):
x = t^2, so when x = 1, we have t = ±1.
y = 1 - 3t, so when t = 1, we have y = -2.
z = 1 + t^3, so when t = 1, we have z = 2.
Therefore, the curve passes through the point (1, 4, 0).
Next, let's check if the curve passes through the point (9, -8, 28):
x = t^2, so when x = 9, we have t = ±3.
y = 1 - 3t, so when t = -3, we have y = 10.
z = 1 + t^3, so when t = 3, we have z = 28.
Therefore, the curve passes through the point (9, -8, 28).
Finally, let's check if the curve passes through the point (4, 7, -6):
x = t^2, so when x = 4, we have t = ±2.
y = 1 - 3t, so when t = 2, we have y = -5.
z = 1 + t^3, so when t = 2, we have z = 9.
Therefore, the curve does not pass through the point (4, 7, -6).
Hence, we have shown that the curve passes through the points (1, 4, 0) and (9, -8, 28) but not through the point (4, 7, -6).
(1 point) for the function f(x)=x3−27x, its local maximum is
The function f(x)=x3−27x has a local maximum at x=3.
To determine this, we can take the derivative of the function and set it equal to zero to find the critical points. The derivative of f(x) is f'(x)=3x2-27. Setting this equal to zero, we get 3x2-27=0, which simplifies to x2=9.
Taking the square root of both sides, we get x=±3. We can then use the second derivative test to determine that x=3 is a local maximum.
The second derivative of f(x) is f''(x)=6x, which is positive at x=3, indicating a concave up shape and a local maximum. Therefore, the local maximum of f(x) is at x=3.
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In ΔGHI, the measure of ∠I=90°, the measure of ∠G=82°, and GH = 3. 4 feet. Find the length of HI to the nearest tenth of a foot
In triangle ΔGHI, with ∠I measuring 90° and ∠G measuring 82°, and GH measuring 3.4 feet, the length of HI is 24.2 feet.
To find the length of HI, we can use the trigonometric function tangent (tan). In a right triangle, the tangent of an angle is equal to the ratio of the length of the side opposite the angle to the length of the side adjacent to it. In this case, the side opposite ∠G is HI, and the side adjacent to ∠G is GH. Therefore, we can set up the equation: tan(82°) = HI / GH.
Rearranging the equation to solve for HI, we have: HI = GH * tan(82°). Plugging in the given values, we get: HI = 3.4 * tan(82°). Using a calculator, we find that tan(82°) is approximately 7.115. Multiplying 3.4 by 7.115, we find that HI is approximately 24.161 feet. Rounded to the nearest tenth of a foot, the length of HI is 24.2 feet.
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Kground
Clear frame
2 Kyle spends a total of $44 for four sweatshirts. Each sweatshirt costs the same
amount of money.
Which bar model could be used to show this situation?
The answer is , to represent this situation in a bar model, we can use a Clear frame model.
To show the situation where Kyle spends a total of $44 for four sweatshirts, with each sweatshirt costing the same amount of money, the bar model that can be used is a Clear frame model.
Here's an explanation of the solution:
Given, that Kyle spends a total of $44 for four sweatshirts and each sweatshirt costs the same amount of money.
To find how much each sweatshirt costs, divide the total amount spent by the number of sweatshirts.
So, the amount that each sweatshirt costs is:
[tex]\frac{44}{4}[/tex] = $11
Thus, each sweatshirt costs $11.
To represent this situation in a bar model, we can use a Clear frame model.
A Clear frame model is a bar model in which the total is shown in a separate section or box, and the bars are used to represent the parts of the whole.
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consider the following system. dx dt = x y − z dy dt = 5y dz dt = y − z find the eigenvalues of the coefficient matrix a(t). (enter your answers as a comma-separated list.)
The eigenvalues of the coefficient matrix a(t) are 5,1,-1.
To find the eigenvalues of the coefficient matrix, we need to first form the coefficient matrix A by taking the partial derivatives of the given system of differential equations with respect to x, y, and z. This gives us:
A = [y, x, -1; 0, 5, 0; 0, 1, -1]
Next, we need to find the characteristic equation of A, which is given by:
det(A - λI) = 0
where I is the identity matrix and λ is the eigenvalue we are trying to find.
We can expand this determinant to get:
(λ - 5)(λ - 1)(λ + 1) = 0
Therefore, the eigenvalues of the coefficient matrix are λ = 5, λ = 1, and λ = -1.
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how do you distinguish between sr and lr cost functions? example?
The terms "sr" and "lr" cost functions typically refer to "short-run" and "long-run" cost functions in economics. The distinction between the two depends on the time horizon over which the costs are being considered.
In the short run, some inputs are fixed and cannot be changed, while others are variable and can be adjusted. For example, in the short run, a factory may have fixed costs such as rent, property taxes, and insurance, while variable costs may include labor, raw materials, and utilities. The short-run cost function reflects how the total cost of production changes as the variable inputs are increased or decreased while the fixed inputs remain constant.
In the long run, all inputs are variable and can be adjusted. For example, in the long run, a factory may be able to build a larger building, buy more machines, or relocate to a cheaper area. The long-run cost function reflects how the total cost of production changes as all inputs are increased or decreased.
An example of a short-run cost function could be the cost of producing bread in a bakery, where the cost of flour, yeast, and electricity are variable costs, but the cost of rent for the bakery building is a fixed cost.
An example of a long-run cost function could be the cost of running a transportation company, where the cost of vehicles, fuel, and labor are all variable costs, but the cost of building a new headquarters or expanding the business into a new market are fixed costs.
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Find the area of a regular hexagon inscribed in a circle of radius 12 inches
To find the area of a regular hexagon inscribed in a circle, we can use the formula:
Area of Hexagon = (3√3/2) * s^2
Where s is the length of each side of the hexagon.
In this case, the hexagon is inscribed in a circle of radius 12 inches. The length of each side of the hexagon is equal to the radius of the circle.
Therefore, the length of each side (s) is 12 inches.
Plugging the value of s into the formula, we get:
Area of Hexagon = (3√3/2) * (12^2)
Area of Hexagon = (3√3/2) * 144
Area of Hexagon = (3√3/2) * 144
Area of Hexagon ≈ 374.52 square inches
The area of the regular hexagon inscribed in the circle with a radius of 12 inches is approximately 374.52 square inches.
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Dave is going to make 6 pizzas. He plans to use 25pound of tomatoes for each pizza. The number of pounds of tomatoes Dave needs falls between which two whole numbers? Show your work:
If Dave plans to use 25 pounds of tomatoes for each pizza and he is making a total of 6 pizzas, then the total amount of tomatoes he needs can be calculated by multiplying the amount per pizza by the number of pizzas:
25 pounds/pizza * 6 pizzas = 150 pounds
Therefore, Dave needs a total of 150 pounds of tomatoes.
The whole numbers falling between which this amount of tomatoes falls can be determined by considering the next smaller and next larger whole numbers.
The next smaller whole number is 149 pounds, and the next larger whole number is 151 pounds.
So, the number of pounds of tomatoes Dave needs falls between 149 and 151 pounds.
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Graph the points on the coordinate plane.
M(−212, −3), N(−1.5, 3.5), P(−312, 34), Q(0.5, −3.5), R(234, −112)
Use the Point Tool to plot the points.
Keyboard Instructions
Initial graph state
The horizontal axis goes from -4.5 to 4.5 with ticks spaced every 1 unit(s).
The vertical axis goes from -4.5 to 4.5 with ticks spaced every 1 unit(s).
Skip to navigation
The graph along the coordinate plane is attached below
What is graph of the points on the coordinate plane?To find the graph of the points along the coordinate plane, we simply need to use a graphing calculator to plot the points M - N, N - P, P - Q, Q - R and R - M.
These individual points in this coordinates cannot form a quadrilateral on the plane.
The total perimeter or distance of the plane cannot be calculated by simply adding up all the points along the line.
However, these lines seem not to intersect at any point as they travel across the plane in different directions.
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Express the following ratios as fractions in their lowest term 4 birr to 16 cents
To express the ratio of 4 birr to 16 cents as a fraction in its lowest terms, we need to convert the currencies to a common unit.
1 birr is equal to 100 cents, so 4 birr is equal to 4 * 100 = 400 cents.
Now we have the ratio of 400 cents to 16 cents, which can be simplified by dividing both the numerator and denominator by their greatest common divisor (GCD), which in this case is 8.
400 cents ÷ 8 = 50 cents
16 cents ÷ 8 = 2 cents
Therefore, the ratio 4 birr to 16 cents expressed as a fraction in its lowest terms is:
50 cents : 2 cents
Simplifying further:
50 cents ÷ 2 = 25
2 cents ÷ 2 = 1
The fraction in its lowest terms is:
25 : 1
So, the ratio 4 birr to 16 cents is equivalent to the fraction 25/1.
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A study of the amount of time it takes a specialist to repair a mobile MRI shows that the mean is 8. 4 hours and the standard deviation is 1. 8 hours. If a broken mobile MRI is randomly selected, find the probability that its mean repair time is less than 8. 9 hours
The probability that the mean repair time is less than 8.9 hours is 0.6103 (or 61.03%).
Given information: Mean repair time is 8.4 hours and Standard deviation is 1.8 hours
To find: Probability that the mean repair time is less than 8.9 hoursZ score can be calculated using the formula;
Z = (X - μ) / σWhere,
Z = z score
X = Value for which we need to find the probability (8.9 hours)
μ = Mean (8.4 hours)
σ = Standard deviation (1.8 hours)
Substituting the values in the above formula;
Z = (8.9 - 8.4) / 1.8Z = 0.28
Probability for z-score of 0.28 can be found from z table.
The value from the table is 0.6103
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.I have a linear algebra quetion related to eignevalues and eigenvectors
If v1=[ -5 -4]
and v2= [ -4 -3]
are eigenvectors of a matrix A corresponding to the eigenvalues λ1=3 and λ2=−1, respectively,
then
1. A(v1+v2)= ( The answer is a vector0
2. A(−2v1)= (The is a vector)
1. the answer is the vector [-11 -9] and 2. The answer is the vector [-30 -24].
First, let's recall the definition of eigenvectors and eigenvalues. An eigenvector of a matrix A is a non-zero vector v such that when A is multiplied by v, the result is a scalar multiple of v. That scalar multiple is called the eigenvalue corresponding to that eigenvector. In other words, if v is an eigenvector of A with eigenvalue λ, then Av = λv.
Now, let's use this definition to answer your questions.
1. A(v1+v2) = Av1 + Av2 = λ1v1 + λ2v2. Substituting in the given values of λ1, λ2, v1, and v2, we get:
A(v1+v2) = 3[-5 -4] + (-1)[-4 -3]
= [-15 -12] + [4 3]
= [-11 -9]
So the answer is the vector [-11 -9].
2. A(-2v1) = -2Av1 = -2λ1v1. Substituting in the given value of λ1 and v1, we get:
A(-2v1) = -2(3)[-5 -4]
= [-30 -24]
So the answer is the vector [-30 -24].
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1.the answer is the vector [-11 -9] and 2.The answer is the vector [-30 -24].
Since [tex]v_{1}[/tex] and [tex]v_{2}[/tex] are eigenvectors of matrix A, we know that:
A [tex]v_{1}[/tex] = λ1 [tex]v_{1}[/tex]
A [tex]v_{2}[/tex] = λ2 [tex]v_{2}[/tex]
Let's use this information to solve the given problems:
1. A( [tex]v_{1}[/tex] + [tex]v_{2}[/tex] ) = A [tex]v_{1}[/tex] + A [tex]v_{2}[/tex] = λ1 [tex]v_{1}[/tex] + λ2 [tex]v_{2}[/tex]
Substituting the values of λ1, [tex]v_{1}[/tex] , λ2, [tex]v_{2}[/tex] and that were given:
A( [tex]v_{1}[/tex] + [tex]v_{2}[/tex] ) = 3[-5 -4] + (-1)[-4 -3]
= [-15 -12] + [4 3] = [-11 -9]
So the answer is the vector [-11 -9].
2. A(-2[tex]v_{1}[/tex] ) = -2 A [tex]v_{1}[/tex]
Using the given equation for A [tex]v_{1}[/tex] , we get:
A(-2[tex]v_{1}[/tex] ) = -2 λ1 [tex]v_{1}[/tex]
Substituting the values of λ1 and [tex]v_{1}[/tex] that were given:
A(-2[tex]v_{1}[/tex]) = -2(3)[-5 -4] = [30 24]
So the answer is the vector [30 24].
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Express the limit as a definite integral. [Hint: Consider
f(x) = x8.]
lim n→[infinity]
n 3i8
n9
sum.gif
i = 1
The given limit can be expressed as the definite integral:
∫[0 to 1] 3x^8 dx
To express the limit as a definite integral, we can use the definition of a Riemann sum. Let's consider the function f(x) = x^8.
The given limit can be rewritten as:
lim(n→∞) Σ[i=1 to n] (3i^8 / n^9)
Now, let's express this limit as a definite integral. We can approximate the sum using equal subintervals of width Δx = 1/n. The value of i can be replaced with x = iΔx = i/n. The summation then becomes:
lim(n→∞) Σ[i=1 to n] (3(i/n)^8 / n^9)
This can be further simplified as:
lim(n→∞) (1/n) Σ[i=1 to n] (3(i/n)^8 / n)
Taking the limit as n approaches infinity, the sum can be written as:
lim(n→∞) (1/n) ∑[i=1 to n] (3(i/n)^8 / n) ≈ ∫[0 to 1] 3x^8 dx
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An order of complexity that is worse than polynomial is called quadratic.A. TrueB. False
An order of complexity that is worse than polynomial is called quadratic is B. False.
An order of complexity that is worse than polynomial is not called quadratic.
A polynomial function is a function that can be expressed as the sum of finite terms, where each term is a constant multiplied by a variable raised to a non-negative integer power.
A quadratic function is a type of polynomial function of degree 2, meaning the highest power of the variable is 2. The order of complexity of an algorithm is a measure of the amount of time or space required by the algorithm to solve a problem, expressed in terms of the input size of the problem.
An algorithm with a polynomial time complexity has an execution time that grows at most as a polynomial function of the input size.
An algorithm with an exponential time complexity has an execution time that grows exponentially with the input size, and an algorithm with a factorial time complexity has an execution time that grows as a factorial of the input size.
Therefore, an order of complexity that is worse than polynomial is usually referred to as exponential or factorial complexity, not quadratic. Understanding the order of complexity of an algorithm helps us understand how well an algorithm will scale as the input size grows.
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there are 24 people in a fitness studio. 3/8 of the people are lifting weights, 1/3 are cross training, and the remaining people are running. what fraction of people are running
Answer:
7/24
Step-by-step explanation:
Total people in the studio = 24
3/8 are lifting weights
==> Number of people lifting weights = 3/8 x 24 = 9
1/3 are cross training
==> Number of people cross training = 1/3 x 24 = 8
Therefore the remaining people who are running = 24 - (9 +8)
= 24 - 17
= 7
As a fraction of the total people, this would be
7/24
A bag of pennies weighs 711.55 grams. Each penny weighs 3.5 grams. About how many pennies are in the bag? *
Therefore, there are about 203 pennies in the bag. This is a 90-word long answer. If you need to provide a 250-word answer, you can expand the explanation by discussing the weight and denomination of pennies, their history, and their use.
To find out the number of pennies in a bag that weighs 711.55 grams, we need to divide the total weight by the weight of each penny. We know that each penny weighs 3.5 grams,
therefore: Number of pennies = Total weight of bag / Weight of one penny= 711.55 / 3.5 = 203.015 ≈ 203 (rounded to the nearest whole number)
Therefore, there are about 203 pennies in the bag. To summarize the answer in a long answer format, we can write: We can find the number of pennies in the bag by dividing the total weight of the bag by the weight of each penny. Given that each penny weighs 3.5 grams, we can find out the number of pennies by dividing 711.55 grams by 3.5 grams.
Therefore, Number of pennies = Total weight of bag / Weight of one penny= 711.55 / 3.5 = 203.015 ≈ 203 (rounded to the nearest whole number)
Therefore, there are about 203 pennies in the bag. This is a 90-word long answer. If you need to provide a 250-word answer, you can expand the explanation by discussing the weight and denomination of pennies, their history, and their use.
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Find the values of x, y and z that correspond to the critical point of the function f(x,y) 4x2 + 7x + 6y + 2y?: Enter your answer as a number (like 5, -3, 2.2) or as a calculation (like 5/3, 2^3, 5+4). c= za
The values of x, y and z that correspond to the critical point of the function f(x,y) 4x2 + 7x + 6y + 2y are (-7/8, -3/2).
To find the values of x, y, and z that correspond to the critical point of the function f(x, y) = 4x^2 + 7x + 6y + 2y^2, we need to find the partial derivatives with respect to x and y, and then solve for when these partial derivatives are equal to 0.
Step 1: Find the partial derivatives
∂f/∂x = 8x + 7
∂f/∂y = 6 + 4y
Step 2: Set the partial derivatives equal to 0 and solve for x and y
8x + 7 = 0 => x = -7/8
6 + 4y = 0 => y = -3/2
Now, we need to find the value of z using the given equation c = za. Since we do not have any information about c, we cannot determine the value of z. However, we now know the critical point coordinates for the function are (-7/8, -3/2).
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3. In questions 1 and 2 we looked at the limit of a function as the input approached a pre-chosen value. Now let's look at limits being used to calculate an instantaneous rate of change. We want to find out the rate at which P(x)=-2x² + 3x +5 is changing when x = 2. Recall the Difference Quotient. Do-f(x+h)-f(x) is the slope of the line that goes through the points (x, f(x)) and (x +h, f(x+h)). This can be thought of as the _rate of change of f(x) over the interval
The Difference Quotient can be thought of as the average rate of change of the function f(x) over the interval [x, x+h]. To find the instantaneous rate of change of f(x) at a specific point, we need to take the limit of the Difference Quotient as h approaches zero. This limit will give us the slope of the tangent line to the graph of f(x) at the point x, which is the instantaneous rate of change of the function at that point.
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My Notes Ask Your Teacher (a) Find parametric equations for the line through (1, 3, 4) that is perpendicular to the plane x-y + 2z 4, (Use the parameter t.) )13-12-4 (b) In what points does this line intersect the coordinate planes? xy-plane (x, y, z)-((-1,5,0)|x ) yz-plane (x, y, z)- xz-plane x, 9+ Need Help? Read it Talk to a Tutor Submit Answer Save Progress Practice Another Version
Parametric equations for the line through (1, 3, 4) that is perpendicular to the plane x-y+2z=4 are:
x = 1 + 2t
y = 3 - t
z = t
We know that the direction vector of the line should be perpendicular to the normal vector of the plane. The normal vector of the plane x-y+2z=4 is <1, -1, 2>. Thus, the direction vector of our line should be parallel to the vector <1, -1, 2>.
Let the line pass through the point (1, 3, 4) and have the direction vector <1, -1, 2>. We can write the parametric equations of the line as:
x = 1 + at
y = 3 - bt
z = 4 + c*t
where (a, b, c) is the direction vector of the line. Since the line is perpendicular to the plane, we can set up the following equation:
1a - 1b + 2*c = 0
which gives us a = 2, b = -1, and c = 1.
Substituting these values in the parametric equations, we get:
x = 1 + 2t
y = 3 - t
z = t
To find the intersection of the line with the xy-plane, we set z=0 in the parametric equations, which gives us x=1+2t and y=3-t. Solving for t, we get (1/2, 5/2, 0). Therefore, the line intersects the xy-plane at the point (1/2, 5/2, 0).
Similarly, we can find the intersection points with the yz-plane and xz-plane by setting x=0 and y=0 in the parametric equations, respectively. We get the intersection points as (-1, 5, 0) and (9, 0, 3), respectively.
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let x(t) = 11 cos(7πt − π/3). in each of the following parts, the discrete-time signal x[n] is obtained by sampling x(t) at a rate fs samples/s, and the resultant x[n] can be written ax[n] = A cos(ω1n + φ) For each part below, determine the values of A, φ, and ω1 such that 0 ≤ ω1 ≤ π. In addition, state whether or not the signal has been over-sampled or under-sampled. Sampling frequency is fs = 9 samples/s. Sampling frequency is fs, = 6 samples/s. Sampling frequency is fs = 3 samples/s.
1. the values of A, φ, and ω1 are A = 11, φ = -π/3, and ω1 = 7π/81.
2. The values of A, φ, and ω1 are A = 11, φ = -π/3, and ω1 = 2π/3.
Part 1: Sampling frequency is fs = 9 samples/s.
The sampling period is T = 1/fs = 1/9 seconds.
The discrete-time signal x[n] is obtained by sampling x(t) at a rate of 9 samples/s, so we have:
x[n] = x(nT) = 11 cos(7πnT - π/3)
= 11 cos(7πn/9 - π/3)
The angular frequency is ω = 7π/9, which satisfies 0 ≤ ω ≤ π.
The amplitude A can be found by taking the absolute value of the maximum value of the cosine function, which is 11. So A = 11.
The phase φ can be found by setting n = 0 and solving for φ in the equation x[0] = A cos(φ). We have:
x[0] = 11 cos(π/3) = 11/2
A cos(φ) = 11/2
φ = ±π/3
We choose the negative sign to satisfy the condition 0 ≤ ω1 ≤ π. So φ = -π/3.
The angular frequency ω1 is given by ω1 = ωT = 7π/9 * (1/9) = 7π/81.
Since the angular frequency satisfies 0 ≤ ω1 ≤ π, the signal is not over-sampled or under-sampled.
Therefore, the values of A, φ, and ω1 are A = 11, φ = -π/3, and ω1 = 7π/81.
Part 2: Sampling frequency is fs, = 6 samples/s.
The sampling period is T = 1/fs, = 1/6 seconds.
The discrete-time signal x[n] is obtained by sampling x(t) at a rate of 6 samples/s, so we have:
x[n] = x(nT) = 11 cos(7πnT - π/3)
= 11 cos(7πn/6 - π/3)
The angular frequency is ω = 7π/6, which does not satisfy 0 ≤ ω ≤ π. Therefore, the signal is over-sampled.
To find the values of A, φ, and ω1, we need to first down-sample the signal by keeping every other sample. This gives us:
x[0] = 11 cos(-π/3) = 11/2
x[1] = 11 cos(19π/6 - π/3) = -11/2
x[2] = 11 cos(25π/6 - π/3) = -11/2
We can see that x[n] is a periodic signal with period N = 3.
The amplitude A can be found by taking the absolute value of the maximum value of the cosine function, which is 11. So A = 11.
The phase φ can be found by setting n = 0 and solving for φ in the equation x[0] = A cos(φ). We have:
x[0] = 11/2
A cos(φ) = 11/2
φ = ±π/3
We choose the negative sign to satisfy the condition 0 ≤ ω1 ≤ π. So φ = -π/3.
The angular frequency ω1 is given by ω1 = 2π/N = 2π/3.
Therefore, the values of A, φ, and ω1 are A = 11, φ = -π/3, and ω1 = 2π/3.
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