Match the information on the left with the appropriate equation on the right.

Answer:

(x+2.3)^2 + (y) ^2 = (6/7)^2

Step-by-step explanation:

The equation of a circle can be written as

(x-h)^2 + (y-k) ^2 = r^2  where ( h,k) is the center and r is the radius

(x- -2.3)^2 + (y-0) ^2 = (6/7)^2

(x+2.3)^2 + (y) ^2 = (6/7)^2

Answer:

b. (10,10,0)

Step-by-step explanation:

r+v can be evaluated if the vectors/matrices have the same dimensions.

These do. They are both 1 by 3 vectors.

Just add first to first in each.

Just add second to second in each.

Just add third to third in each.

Example:

(5,-5,6)+(1,2,3)

=(5+1,-5+2,6+3)

=(6,-3,9)

Done!

In general, (a,b,c)+(r,s,t)=(a+r,b+s,c+t).

r+v

=(7,3,9)+(3,7,-9)

=(7+3,3+7,9+-9)

=(10,10,0)

Done!

Answer:

Perpendicular Slope: 8/5

Parallel Slope: -5/8

Step-by-step explanation:

First, let's rewrite the line into slope intercept form.

-5x - 8y = 3

-8y = 5x + 3

y = -5x/8 + -3/8

Okay, so now we know the slope, -5/8, and the y-intercept, -3/8.

For a line to be perpendicular, the slope needs to be opposite of the given line's slope.  This will cause the two lines to cross at a 90-degree angle, and therefore be perpendicular.

So a perpendicular line could be as follows:

y = 8x/5 + -3/8

So the perpendicular slope would be 8/5.

For a line to be parallel, the slope needs to be the same so that the two lines will never cross.

So a parallel line could be as follows:

y = -5x/8 + 1

So the parallel slope would be -5/8.

Cheers.

Answer:

Perpendicular Slope: [tex]\boxed{\frac{8}{5}}[/tex]

Parallel Slope: [tex]\boxed{-\frac{5}{8}}[/tex]

Step-by-step explanation:

Part 1: Rewrite into slope-intercept form

Firstly, the equations are written in standard form and not slope-intercept form, so to change that, follow the steps below.

Note: Remember the slope-intercept form equation - [tex]\boxed{y=mx+b}[/tex]

[tex]-5x-8y=3\\\\5x + (-5x-8y)=3+5x\\\\-8y=5x+3\\\\\frac{-8y}{-8} =\frac{5x+3}{-8} \\[/tex]

[tex]y=-\frac{5}{8}x-\frac{3}{8}[/tex]

Add [tex]5x[/tex] to both sides of the equation to isolate the y-variable. Then, divide by the coefficient of y to isolate it entirely. The equation is now in slope-intercept form.

Part 2: Determine the perpendicular slope

Perpendicular slopes are reciprocals of the given slopes. To turn the original slope into its reciprocal counterpart, follow these steps:

To follow this for the slope of the given equation:

Part 3: Determine the parallel slope

Parallel slopes are equal - otherwise, the lines would eventually intersect. Therefore, the given slope is also the parallel slope.

The parallel slope is [tex]\boxed{-\frac{5}{8}}[/tex].

Answer:

x=5

Step-by-step explanation:

h (x) = 3

We want the x values where y =3

The values are x = -7 and x=5

Answer:

[tex] x = 2 [/tex]

Step-by-step explanation:

Given a right-angled triangle as shown above,

Included angle = 60°

Opposite side length = 3

Adjacent side length = x

To find x, we would use the following trigonometric ratio as shown below:

[tex] tan(60) = \frac{3}{x} [/tex]

multiply both sides by x

[tex] x*tan(60) = \frac{3}{x}*x [/tex]

[tex] x*tan(60) = 3 [/tex]

Divide both sides by tan(60)

[tex] \frac{x*tan(60)}{tan(60} = \frac{3}{tan(60} [/tex]

[tex] x = \frac{3}{tan(60} [/tex]

[tex] x = 1.73 [/tex]

[tex] x = 2 [/tex] (approximated to whole number)

That's a pretty tall order for Brainly homework.  Let's start with the depressed cubic, which is simpler.

Solve

[tex]y^3 + 3py = 2q[/tex]

We'll put coefficients on the coefficients to avoid fractions down the road.

The key idea is called a split, which let's us turn the cubic equation in to a quadratic.  We split unknown y into two pieces:

[tex]y = s + t[/tex]

Substituting,

[tex](s+t)^3 + 3p(s+t) = 2q[/tex]

Expanding it out,

[tex]s^3+3 s^2 t + 3 s t^2 + t^3 + 3p(s+t) = 2q[/tex]

[tex]s^3+t^3 + 3 s t(s+t) + 3p(s+t) = 2q[/tex]

[tex]s^3+t^3 + 3( s t + p)(s+t) = 2q[/tex]

There a few moves we could make from here. The easiest is probably to try to solve the simultaneous equations:

[tex]s^3+t^3=2q, \qquad st+p=0[/tex]

which would give us a solution to the cubic.

[tex]p=-st[/tex]

[tex]t = -\dfrac p s[/tex]

Substituting,

[tex]s^3 - \dfrac{p^3}{s^3} = 2q[/tex]

[tex](s^3)^2 - 2 q s^3 - p^3 = 0[/tex]

By the quadratic formula (note the shortcut from the even linear term):

[tex]s^3 = q \pm \sqrt{p^3 + q^2}[/tex]

By the symmetry of the problem (we can interchange s and t without changing anything) when s is one solution t is the other:

[tex]s^3 = q + \sqrt{p^3+q^2}[/tex]

[tex]t^3 = q - \sqrt{p^3+q^2}[/tex]

We've arrived at the solution for the depressed cubic:

[tex]y = s+t = \sqrt[3]{q + \sqrt{p^3+q^2}} + \sqrt[3]{ q - \sqrt{p^3+q^2} }[/tex]

This is all three roots of the equation, given by the three cube roots (at least two complex), say for the left radical.  The two cubes aren't really independent, we need their product to be [tex]-p=st[/tex].

That's the three roots of the depressed cubic; let's solve the general cubic by reducing it to the depressed cubic.

[tex]x^3 + ax^2 + bx + c=0[/tex]

We want to eliminate the squared term.  If substitute x = y + k we'll get a 3ky² from the cubic term and ay² from the squared term; we want these to cancel so 3k=-a.

Substitute x = y - a/3

[tex](y - a/3)^3 + a(y - a/3)^2 + b(y - a/3) + c = 0[/tex]

[tex]y^3 - ay^2 + a^2/3 y - a^3/27 + ay^2-2a^2y/3 + a^3/9 + by - ab/3 + c =0[/tex]

[tex]y^3 + (b - a^2/3) y = -(2a^3+9ab) /27 [/tex]

Comparing that to

[tex]y^3 + 3py = 2q[/tex]

we have [tex] p = (3b - a^2) /9, q =-(a^3+9ab)/54 [/tex]

which we can substitute in to the depressed cubic solution and subtract a/3  to get the three roots.  I won't write that out; it's a little ugly.

Answer: hundredths place

Step-by-step explanation:

In any coordinate pair, the first number is the x-value and the second number is the y-value.

To find the slope, simply take the difference of the y values and divide by the difference in the x values: (14-9)/(1-4) is equal to -5/3.

The slope of the line that passes through (1, 14) and (4,9) is -5/3.

It is find the slope of the line.

The slope of any line, ray, or line segment is the ratio of the vertical to the horizontal distance between any two points on it (“slope equals rise over run”).

The slope is always calculated from the rise divided by the run. Typically, the equation is presented as:

m = Rise/Run

If you have two points, the points should be [tex]P_{1} (x_{1} ,y_{1} )[/tex] and [tex]P_{2} (x_{2} ,y_{2} )[/tex]  So, the equation would be:

[tex]m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

In any coordinate pair, the first number is the x-value and the second number is the y-value.

The difference of the y values and divide by the difference in the x values:

m=(14-9)/(1-4) is equal to -5/3.

The slope of the line that passes through (1, 14) and (4,9) is  -5/3.

Learn more about slope here:

https://brainly.com/question/17114095

#SPJ5

Answer:

X=18

Step-by-step explanation:

Answer:

x = 18or x = - 20

Step-by-step explanation:

Given

x² + 2x = 360 ( subtract 360 from both sides )

x² + 2x - 360 = 0 ← quadratic in standard form

Consider the factors of the constant term (- 360) which sum to give the coefficient of the x- term (+ 2)

The factors are + 20 and - 18, since

20 × - 18 = - 360 and 20 - 18 = 2 , thus

(x + 20)(x - 18) = 0

Equate each factor to zero and solve for x

x + 20 = 0 ⇒ x = - 20

x - 18 = 0 ⇒ x = 18

Thus the number could be 18 or - 20

Answer:

y = 3/8x

or

3/8 cups of sugar for every 1/2 batch of muffins

Step-by-step explanation:

Since we are only making 1/2 of the full batch of muffins, we only need to use 1/2 the cups of sugar:

[tex]\frac{3}{4} (\frac{1}{2} )= \frac{3}{8}[/tex] cups of sugar.

Answer:

[tex]\frac{x}{2} = \frac{3y}{8}[/tex]

Step-by-step explanation:

Let the batch be x and the amount of sugar be y

Condition:

x = [tex]\frac{3}{4} y[/tex]

Multiplying both sides by 1/2

[tex]\frac{1}{2} x = \frac{3}{4}y * \frac{1}{2}[/tex]

[tex]\frac{x}{2} = \frac{3y*1}{4*2}[/tex]

[tex]\frac{x}{2} = \frac{3y}{8}[/tex]

So, For 1/2 batch of muffins, Farid need 3/8 cups of sugar.

Answer:

68

Step-by-step explanation:

Answer:

The answer is

Step-by-step explanation:

To solve this problem we use ratio and proportion

For 3 minutes his heart rate was 204 beats

So 1 minute will be

[tex] \frac{204 \: beats}{3} \times 1[/tex]

Hope this helps you

Answer:

Correlation Coefficient

Step-by-step explanation:

Answer:

x= 50

Step-by-step explanation:

First, simplify the equation

Expand the terms on the left hand side to make it easier to rearrange

   -0.2(x-20) =44-x

   -0.2x+4 =44-x

Rearrange the equation by moving the numbers to one side and the variables to the other

   -0.2x +x= 44-4

    0.8x = 40

Isolate for x

    x= 40/0.8

    x= 50

Answer:

It will take them 2 2/5 days working together

Step-by-step explanation:

To find the time worked

1/a + 1/b = 1/t

Where a and b are the times worked individually and t is the time worked together

1/4 + 1/6 = 1/t

Multiply each side by 12t to clear the fractions

12t( 1/4 + 1/6 = 1/t)

3t + 2t =12

Combine like terms

5t = 12

Divide by 5

t = 12/5

t = 2 2/5

It will take them 2 2/5 days working together

Answer:

236

Step-by-step explanation:

The interquartile range is the right edge of the box minus the left edge of the box

The right edge of the box is 301

The left edge of the box is 65

301 -65 =236

The interquartile range is 236

Answer:

65

Step-by-step explanation:

To find interquartile range, you substract upper quartile( 130 in this problem) and the lower quartile(65 in this problem)

Finally, you get the answer 65.

Hope this helps!

Answer:

43\ 12 , 35/ 6

Step-by-step explanation:

43\ 12 , 35/ 6

Answer:  B: (3, -7)

Step-by-step explanation:

4x + 4y = -9

         y = 2x - 13

Use Substitution:

4x + 4(2x - 13) = -9

4x + 8x - 52 = -9

       12x - 52 = -9

               12x = 43

                   [tex]x=\dfrac{43}{12}[/tex]

None of the options provided are valid so either there is a typo on your worksheet or you typed in one of the equations wrong.

Plan B: Input the choices into the equation to see which one makes a true statement.

               4x + 4y = -9

A) (x, y) = (-3, -7)

               4(-3) + 4(-7) = -9

                -12   +   -28 = -9

                             -40 ≠ -9

B) (x, y) = (3, -7)

               4(3) + 4(-7) = -9

                12   +   -28 = -9

                             -16 ≠ -9

C) (x, y) = (3, 7)

               4(3) + 4(7) = -9

                12   +   28 = -9

                            40 ≠ -9

D) (x, y) = (-3, 7)

               4(-3) + 4(7) = -9

                -12   +   28 = -9

                              16 ≠ -9

Obviously there is something wrong with the first equation because none of the options provide a true statement.

               y = 2x - 13

A) (x, y) = (-3, -7)

               -7 = 2(-3) - 13

               -7  = -6    -13

                -7 ≠ -19

B) (x, y) = (3, -7)

               -7 = 2(3) - 13

               -7  = 6    -13

                -7 = -7                   this works!!!

C) (x, y) = (3, 7)

               7 = 2(3) - 13

               7  = 6    -13

                7 ≠ -7

D) (x, y) = (-3, 7)

               7 = 2(-3) - 13

               7  = -6    -13

                7 ≠ -19

Option B is the only one that provides a true statement so this must be the answer.

Answer:

Q(1,1), N(3,2) A(2,5)

Step-by-step explanation:

Answer:

[2.5 ,4]

Step-by-step explanation:

The graph in this interval has a vertex while opening up wich means it's a minimum

Answer:

A) $0.11

Step-by-step explanation:

Since a dozen (12) eggs cost $1.35. You will divide $1.35 by 12. And it will equal 0.1125. Round it up it equals to 0.11.

Answer:

C.

6a + 18x + 18p

Step-by-step explanation:

3(2a + 6 (x + p)) firs multiply (x + p) with 6

3 (2a + 6x + 6z) now multiply inside the parenthesis with 3 and the answer would be 6a + 18x + 18p

Answer:

The transformations needed to obtain the new function are horizontal scaling, vertical scaling and vertical translation. The resultant function is [tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex].

The domain of the function is all real numbers and its range is between -4 and 5.

The graph is enclosed below as attachment.

Step-by-step explanation:

Let be [tex]z (x) = \cos x[/tex] the base formula, where [tex]x[/tex] is measured in sexagesimal degrees. This expression must be transformed by using the following data:

[tex]T = 180^{\circ}[/tex] (Period)

[tex]z_{min} = -4[/tex] (Minimum)

[tex]z_{max} = 5[/tex] (Maximum)

The cosine function is a periodic bounded function that lies between -1 and 1, that is, twice the unit amplitude, and periodicity of [tex]2\pi[/tex] radians. In addition, the following considerations must be taken into account for transformations:

1) [tex]x[/tex] must be replaced by [tex]\frac{2\pi\cdot x}{180^{\circ}}[/tex]. (Horizontal scaling)

2) The cosine function must be multiplied by a new amplitude (Vertical scaling), which is:

[tex]\Delta z = \frac{z_{max}-z_{min}}{2}[/tex]

[tex]\Delta z = \frac{5+4}{2}[/tex]

[tex]\Delta z = \frac{9}{2}[/tex]

3) Midpoint value must be changed from zero to the midpoint between new minimum and maximum. (Vertical translation)

[tex]z_{m} = \frac{z_{min}+z_{max}}{2}[/tex]

[tex]z_{m} = \frac{1}{2}[/tex]

The new function is:

[tex]z'(x) = z_{m} + \Delta z\cdot \cos \left(\frac{2\pi\cdot x}{T} \right)[/tex]

Given that [tex]z_{m} = \frac{1}{2}[/tex], [tex]\Delta z = \frac{9}{2}[/tex] and [tex]T = 180^{\circ}[/tex], the outcome is:

[tex]z'(x) = \frac{1}{2} + \frac{9}{2} \cdot \cos \left(\frac{\pi\cdot x}{90^{\circ}} \right)[/tex]

The domain of the function is all real numbers and its range is between -4 and 5. The graph is enclosed below as attachment.

Answer:

5050

Step-by-step explanation:

Place value of a digit is the value of digit based on its position the given number.

to determine the place value of a digit

we multiply the digit by number of 10's which is equal to number of digits in its right.

example

for a number 1234687

the place value of 3 is

we take 3 and

multiply it by number of 10' in its right

number of 10's in the right is 4

thus place value of 3 = 3*10*10*10*10 = 30000

________________________________________________

15954

place value of 5 at thousandth position = 5*10*10*10 = 5000

place value of 5 at tens position = 5*10 = 50

Thus, sum of place value of 5 in 15954 = 5000+50 = 5050

Answer:

x^2 +3

Step-by-step explanation:

f(x) = 2x^2 + 2

g(x) = x2 – 1,

find (f – g)(X).

f(x) - g(x) = 2x^2 + 2 -( x^2 – 1)

Distribute the minus sign

             = 2x^2 +2 -x^2 +1

             = x^2 +3

Answer:

The center is (1,4)

Step-by-step explanation:

The coordinates of the center of an ellipse are the coordinates that are in the middle of the two focus.

Then if we have a focus on [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex], we can say that the coordinates for x and y can be calculated as:

[tex]x=\frac{x_1+x_2}{2}\\ y=\frac{y_1+y_2}{2}[/tex]

So, replacing [tex](x_1,y_1)[/tex] by (-4,4) and [tex](x_2,y_2)[/tex] by (6,4), we get that the center is:

[tex]x=\frac{-4+6}{2}=1\\ y=\frac{4+4}{2}=4[/tex]

Answer:

yeyyyaya

Step-by-step explanation:

Answer:

Hey there!

The circumference of a circle is [tex]\pi(d)[/tex], where d is the diameter, and [tex]\\\pi[/tex] is a constant roughly equal to 3.14.

The diameter is 16, so plugging this into the equation, we get 3.14(16)=50.24.

The circumference of the circle is 50.24 yards.

Hope this helps :)

Answer:

A

Step-by-step explanation:

Answer:

$54,000

Step-by-step explanation:

Assuming that her salary does not change. Note that annual means "a year", which would mean 12 months.

First, find how much Linda makes per month. Divide the total earned in 3 months with 3 months:

13,500/3 = 4,500

Next, multiply 4,500 (the amount made per month) with 12 to get your annual salary:

4,500 x 12 = 54,000

Linda makes $54,000 annually.

Answer:

Option (3)

Step-by-step explanation:

[tex](x-i\sqrt{3})[/tex] is a factor of a polynomial given in the options, that means a polynomial having factor as [tex](x-i\sqrt{3})[/tex] will be 0 for the value of x = [tex]i\sqrt{3}[/tex].

Option (1),

3x⁴ + 26x² - 9

= [tex]3(i\sqrt{3})^{4}+26(i\sqrt{3})^2-9[/tex] [For x = [tex]i\sqrt{3}[/tex]]

= 3(9i⁴) + 26(3i²) - 9

= 27 - 78 - 9 [Since i² = -1]

= -60

Option (2),

4x⁴- 11x² + 3

= [tex]4(i\sqrt{3})^4-11(i\sqrt{3})^2+3[/tex]

= 4(9i⁴) - 33i² + 3

= 36 + 33 + 3

= 72

Option (3),

4x⁴ + 11x² - 3

= [tex]4(i\sqrt{3})^4+11(i\sqrt{3})^2-3[/tex]

=  4(9i⁴) + 33i² - 3

= 36 - 33 - 3

= 0

Option (4),

[tex]3x^{4}-26x^{2}-9[/tex]

= [tex]3(i\sqrt{3})^4-26(i\sqrt{3})^{2}-9[/tex]

= 3(9i⁴) - 26(3i²) - 9

= 27 + 78 - 9

= 96

Therefore, [tex](x-i\sqrt{3})[/tex] is a factor of option (3).

Answer:

The answer is 4 + √15 .

Step-by-step explanation:

You have to get rid of surds in the denorminator by multiplying it with the opposite sign :

[tex] \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } [/tex]

[tex] = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } [/tex]

[tex] = \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } [/tex]

[tex] = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} } [/tex]

[tex] = \frac{5 + 2 \sqrt{15} + 3 }{5 - 3} [/tex]

[tex] = \frac{8 + 2 \sqrt{15} }{2} [/tex]

[tex] = 4 + \sqrt{15} [/tex]