Answer: 1,080 in. cubed
Step-by-step explanation:
Answer:
d
Step-by-step explanation:
Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?
Answer:
[tex]x^2-2x+1[/tex]
Step-by-step explanation:
=> (x-1)(x-1)
Using FOIL
=> [tex]x^2-x-x+1[/tex]
=> [tex]x^2-2x+1[/tex]
Answer:
[tex]\boxed{x^2-2x+1}[/tex]
Step-by-step explanation:
[tex](x-1)(x-1)[/tex]
Apply FOIL Method.
[tex]x(x-1)-1(x-1)[/tex]
[tex]x^2-x-x+1[/tex]
Combine like terms.
[tex]x^2-2x+1[/tex]
Skylar has 4 times as many books as Karen. If Skylar has 164 books, how many books does Karen have?
Answer:
41
Step-by-step explanation:
If Skylar has 4 times as many books as Karen, that means that you have to do a division problem to figure out how books Karen has. Because Skylar has 4 times as many books, and she has 164 books, the division problem is 164÷4=41 books.
The number of books Karen has will be 41.
What exactly is simplification?Simplifying means making something easier to do or comprehend, as well as making something less difficult.
Let,
Skylar has x number of books
Karen has y number of books = 164
Given condition;
y=4x
164=4x
x=41 books
Hence Karen has 41 books.
To learn more about the simplification, refer to:
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I NEED HELP PLEASE, THANKS! :)
Answer:
Symmetric with respect to the polar axis in agreement with the second answer listed.
Step-by-step explanation:
This is the shape of a cardioid [tex]14\,(1+cos(\theta))[/tex] it contains the function cosine of the angle so it must be symmetric with respect to the polar axis, since the cosine function is also symmetric for positive and negative values of the angle.
There are no solutions to the system of inequalities shown below.
y< 3x+ 5
y> 3x-1
True or false
Someone help please
Answer:
False, there are actually infinite solutions as these are parallel lines.
Step-by-step explanation:
Find the value of x.
Answer:
[tex]\huge\boxed{x=\sqrt{66}}[/tex]
Step-by-step explanation:
ΔADC and ΔABD are similar (AAA)
Therefore the cooresponging sides are in proportion:
[tex]\dfrac{AD}{AC}=\dfrac{AB}{AD}[/tex]
Substitute
[tex]AD=x;\ AC=6+5=11;\ AB=6[/tex]
[tex]\dfrac{x}{11}=\dfrac{6}{x}[/tex] cross multiply
[tex](x)(x)=(11)(6)\\\\x^2=66\to x=\sqrt{66}[/tex]
Two parallel lines are crossed by a transversal.What is the value of d?
Step-by-step explanation:
if there is any confusion then again ask me always with you
Answer:
d = 125
Step-by-step explanation:
E2020
pls mark Brainliest
Finally, you meet a group of six natives, U, V, W, X, Y, and Z, who speak to you as follows. U says: None of us is a knight. V says: At least three of us are knights. W says: At most three of us are knights. X says: Exactly five of us are knights. Y says: Exactly two of us are knights. Z says: Exactly one of us is a knight. Which are knights
Answer:
w and y are knights
Step-by-step explanation:
Of the six natives, W and Y are the knights.
What is the reasoning?In mathematics, reasoning entails making logical deductions from data or presumptions. Making sense of something can be defined as gaining comprehension of a situation, setting, or idea by relating it to what is already known or has already happened.
Given that you meet a group of six natives, U, V, W, X, Y, and Z, who speak to you as follows. U says: None of us is a knight. V says: At least three of us are knights. W says: At most three of us are knights. X says: Exactly five of us are knights. Y says: Exactly two of us are knights. Z says: Exactly one of us is a knight.
From the given data it is concluded that W and Y are the knights because their statement is W says: At most three of us are knights and Y says: Exactly two of us are knights.
To know more about reasoning follow
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The height of a projectile launched upward at a speed of 32 feet/ second from a height of 128 feet is given by the function h(t)=-16t^2+32t+128. How long will it take the projectile to hit the ground?
Answer:
8.51 seconds
Step-by-step explanation:
Time to reach maximum height
=( Usin90)/2g
= 32/2*9.81
= 32/19.62
= 1.63 s
Max height = U²Sin²tita/g
= 32²/9.81
= 1024/9.81
= 104.38ft
Total height=104.38 + 128= 232.38
Time to fall back to the ground using the formula
h = ut+(1/2)gt²
U= 0
H= 232.38
g = 9.81
(232.38 *2 )/9.81= t²
47.376= t²
t = 6.88 s
Total time taken to hit ground
= 6.88 + 1.63
= 8.51 seconds
Suppose you are starting your own company selling chocolate covered strawberries. You decide to sell the milk chocolate covered strawberries for a profit of $2.25 $ 2.25 /box and the white chocolate covered strawberries at $2.50 $ 2.50 /box. Market tests and available resources, however, have given you the following constraints. The combined production level should not exceed 800 800 boxes per month. The demand for the white chocolate is no more than half the demand for milk chocolate strawberries. The production level for white chocolate should be less than or equal to 200 200 boxes.
Answer:
$1850 per month
Step-by-step explanation
There are two types of chocolates that can be produced milk chocolate and strawberry covered chocolate. To find the profit we make following equation,
P = $2.25 SC + $2.50 WC
where SC is strawberry chocolate and WC is White milk chocolate.
The maximum production level can be 800 boxes per month and white chocolates can not exceed the 200 boxes per month so we assume making 600 boxes of Strawberry covered chocolates and 200 boxes of white chocolates.
Profit = 2.25 * 600 + 2.50 * 200
Profit = $1850
This is the maximum profit that can be earned after making combination of two types of chocolates.
How many gallons of fuel costing $1.15 a gallon must be mixed with a fuel costing $0.85 per gallon to get 40
gallons of a fuel that costs $1 per gallon? Formulate an equation and then solve it in order to determine how
many gallons of fuel costing $1.15.
Answer:
multiply 0.85x40
Step-by-step explanation:
In a book the characters are trying to determine whether the Poisson probabilistic model can be used to describe the locations that rockets landed in a city. They divided the city into 0.25-kmsquared regions. They then counted the number of rockets that landed in each region, with the results shown in the table below. Complete parts (a) through (e). Number of rocket hits 0 1 2 3 4 5 6 7 Observed number of regions 228 214 94 32 7 0 0 1 (a) Estimate the mean number of rocket hits in a region by computing mu equals Summation from nothing to nothing xP left parenthesis x right parenthesis.
Answer:
The estimated mean number of rockets hits in the region is 533.
Step-by-step explanation:
We are given the following information,
Number of rocket hits | Observed number of regions
0 | 228
1 | 214
2 | 94
3 | 32
4 | 7
5 | 0
6 | 0
7 | 1
We are asked to estimate the mean number of rocket hits in the region.
The mean or expected value is given by
[tex]\mu = \sum (x \cdot P(x)) \\\\\mu = (0 \cdot 228) + (1 \cdot 214) + (2 \cdot 94) + (3 \cdot 32) + (4 \cdot 7) + (5 \cdot 0) + (6 \cdot 0) + (7 \cdot 1) \\\\\mu = 0 + 214 +188+ 96 +28 +0+ 0 + 7 \\\\\mu = 533[/tex]
Therefore, the mean number of rockets hits in the region is 533.
Which of the following lists of ordered pairs is a function?
Α. (Ο, 2), (2, 3), (ο, - 2), (4, 1)
Β. (1, 2), (1,2), 2), (3, 4)
C. 1, 5). 2, 1, 4, 9), το, 5)
D. (2, 4), (0, 2), (2, -4), (5, 3)
Answer:
the answer will be D
Step-by-step explanation:
Please answer this correctly
Answer:
1/4
Step-by-step explanation:
The probability of landing on an odd number is 2/4.
The probability of landing on a number greater than 5 is 2/4.
2/4 × 2/4
4/16 = 1/4
A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 75 pounds. The truck is transporting 55 large boxes and 50 small boxes. If the truck is carrying a total of 4025 pounds in boxes, how much does each type of box weigh?
Answer:
There are 50 large boxes.
Step-by-step explanation:
First, "boxes of two sizes" means we can assign variables:
Let x = number of large boxes
y = number of small boxes
"There are 115 boxes in all" means x + y = 115 [eq1]
Now, the pounds for each kind of box is:
(pounds per box)*(number of boxes)
So,
pounds for large boxes + pounds for small boxes = 4125 pounds
"the truck is carrying a total of 4125 pounds in boxes"
(50)*(x) + (25)*(y) = 4125 [eq2]
It is important to find two equations so we can solve for two variables.
Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x:
x = 115 - y [from eq1]
50(115-y) + 25y = 4125 [from eq2]
5750 - 50y + 25y = 4125 [distribute]
5750 - 25y = 4125
-25y = -1625
y = 65 [divide both sides by (-25)]
There are 65 small boxes.
Put that value into either equation (now, which is easier?) to solve for x:
x = 115 - y
x = 115 - 65
x = 50
9(d − 93) = –36 d = _______
Steps to solve:
9(d - 93) = -36d
~Distribute
9d - 837 = -36d
~Subtract 9d to both sides
-837 = -45d
~Divide -45 to both sides
18.6 = d
Best of Luck!
On Wednesday and Thursday
a total of 32 records were sold.
The number of records sold on
Thursday was 3 times the number
of records sold on Wednesday.
c) How many records were (2)
sold on Wednesday?
d) How many records were (1)
sold on Thursday?
Total marks: 5
Answer:
8 records were sold on Wednesday, and 24 records were sold on Thursday
Step-by-step explanation:
Let's call the number of records sold on Wednesday w, and the number sold on Thursday t.
t+w=32
t=3w
Substituting:
(3w)+w=32
4w=32
w=8
t=3w=3(8)=24
Hope this helps!
The board of directors of a company decides to promote 3 of its 10 senior staff members to the position of first vice president, second vice president, and third vice president. In how many ways can this promotion be made?
Answer:
720 ways
The number of ways in which the promotion can be made is 720 ways
Step-by-step explanation:
Given that;
The board of directors of a company decides to promote 3 of its 10 senior staff members to the position of first vice president, second vice president, and third vice president.
This is a permutation problem because the order of selection is relevant. They will be promoted to various positions.
N = nPr = n!/(n-r)!
n = 10, r = 3
Substituting the values;
N = 10P3
N = 10!/(10-3)! = 10!/7!
N = 720 ways
The number of ways in which the promotion can be made is 720 ways
The base of pyramid A is a rectangle with a length of 10 meters and a width of 20 meters. The base of pyramid B is a square with 10-meter sides.
The heights of the pyramids are the same.
The volume of pyramid Als
y the volume of pyramid B. If the helght of pyramid B increases to twice that of pyramid A, the
new volume of pyramid B is
the volume of pyramid A.
Answer:
a. The volume of Pyramid A is double that of Pyramid B.
b. The new volume of B is equal to the volume of A.
Step-by-step explanation:
The base of pyramid A is a rectangle with length 10 meters and width 20 meters.
The base of pyramid B is a square of side length 10 meter.
Both pyramids have the same height, h.
The volume of a pyramid is given as:
V = lwh / 3
where l = length
w = width
h = height
The volume of Pyramid A is:
V = (10 * 20 * h) / 3 = 66.7h cubic metres
The volume of Pyramid B is:
V = (10 * 10 * h) / 3 = 33.3h cubic metres
By comparing their values, the volume of Pyramid A is double that of Pyramid B.
If the height of B increases to 2h, its new volume is:
V = (10 * 10 * 2h) / 3 = 66.7h cubic metres
The new volume of B is equal to the volume of A.
A tank contains 40 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min; it mixes with the solution there, and then the mixture is pumped out at a rate of 5 gal/min. Determine A(t), the amount of salt in the tank at time t, if the concentration of salt in the inflow is variable and given by cin(t)
Answer:
[tex]A(t)=500C_{in}(t)+[40-500C_{in}(t)]\cdot e^{-\frac{t}{100}}[/tex]
Step-by-step explanation:
Volume of water in the Tank =500 gallons
Let A(t) be the amount of salt in the tank at time t.
Initially, the tank contains 40 lbs of salt, therefore:
A(0)=40 lbs
Rate of change of the amount of Salt in the Tank
[tex]\dfrac{dA}{dt}=R_{in}-R_{out}[/tex]
Rate In=(concentration of salt in inflow)(input rate of brine)
[tex]=(C_{in}(t))( 5\frac{gal}{min})\\=5C_{in}(t)\frac{lbs}{min}[/tex]
Rate Out=(concentration of salt in outflow)(output rate of brine)
[tex]=(\frac{A(t)}{500})( 5\frac{gal}{min})=\frac{A}{100}[/tex]
Therefore:
[tex]\dfrac{dA}{dt}=5C_{in}(t)-\dfrac{A}{100}[/tex]
We then solve the resulting differential equation by separation of variables.
[tex]\dfrac{dA}{dt}+\dfrac{A}{100}=5C_{in}(t)\\$The integrating factor: e^{\int \frac{1}{100}}dt =e^{\frac{t}{100}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{100}}+\dfrac{A}{100}e^{\frac{t}{100}}=5C_{in}(t)e^{\frac{t}{100}}\\(Ae^{\frac{t}{100}})'=5C_{in}(t)e^{\frac{t}{100}}[/tex]
Taking the integral of both sides
[tex]\int(Ae^{\frac{t}{100}})'=\int [5C_{in}(t)e^{\frac{t}{100}}]dt\\Ae^{\frac{t}{100}}=5*100C_{in}(t)e^{\frac{t}{100}}+C, $(C a constant of integration)\\Ae^{\frac{t}{100}}=500C_{in}(t)e^{\frac{t}{100}}+C\\$Divide all through by e^{\frac{t}{100}}\\A(t)=500C_{in}(t)+Ce^{-\frac{t}{100}}[/tex]
Recall that when t=0, A(t)=40 lbs (our initial condition)
[tex]A(t)=500C_{in}(t)+Ce^{-\frac{t}{100}}\\40=500C_{in}(t)+Ce^{-\frac{0}{100}}\\C=40-500C_{in}(t)\\$Therefore, the amount of salt in the tank at any time t is:\\\\A(t)=500C_{in}(t)+[40-500C_{in}(t)]\cdot e^{-\frac{t}{100}}[/tex]
What ray is a common side of
Current research indicates that the distribution of the life expectancies of a certain protozoan is normal with a mean of 49 days and a standard deviation of 10.2 days. Find the probability that a simple random sample of 64 protozoa will have a mean life expectancy of 54 or more days.
Answer:
The probability that a simple random sample of 64 protozoa will have a mean life expectancy of 54 or more days is P(M>54)=0.00004.
Step-by-step explanation:
In this case, we have a population lifetime normally distributed with mean 49 and standard deviation 10.2.
We take a sample of size n=64.
Then, we can calculate the z-score for a sample mean M=54, in order to calculate P(M>54):
[tex]z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{54-49}{10.2/\sqrt{64}}=\dfrac{5}{1.275}=3.922\\\\\\P(M>54)=P(z>3.922)=0.00004[/tex]
The probability that a simple random sample of 64 protozoa will have a mean life expectancy of 54 or more days is P(M>54)=0.00004.
Functions f(x) and g(x) are shown below: f(x) = x2 g(x) = x2 + 8x + 16 In which direction and by how many units should f(x) be shifted to obtain g(x)? (1 point) Left by 4 units Right by 4 units Left by 8 units Right by 8 units
Answer: left 4 units
Step-by-step explanation: use the formula -b/2a to find the new x value. Or use a graphing calculator and compare the position of g(x) to f(x)
Answer:
Answer: left 4 units
Step-by-step explanation:
What is the quotient in polynomial form?
Answer:
The quotient in polynomial form= 2x + 6
Step-by-step explanation:
In order to calculate the quotient in polynomial form of the following synthetic division we would have to make the following:
According to the given data we have the following:
-1|2 8 6
Therefore, quotient in polynomial form would be calculated as follows:
-1 | 2 8 6
-2 -6
2 6 0
Therefore, quotient in polynomial form= 2x + 6
The quotient in polynomial form= 2x + 6
In a random sample of 400 registered voters, 120 indicated they plan to vote for Candidate A. Determine a 95% confide
Answer:
Step-by-step explanation:
Using the formula
p +/- (z* √[p(1-p) /n]
Where p is sample proportion = 120/400= 0.3 z*= 1.96 (z score for 95% confidence) and n is 400.
0.3 + (1.96 √[0.3(1-0.3) / 400])
0.3 + (1.96 √[(0.3*0.7)/400
0.3 + (1.96√ (0.21/400))
0.3 + (1.96 √0.000525)
0.3 + (1.96* 0.023)
0.3 + (0.045)
= 0.345 ~ 35%
For the lower interview
0.3 - (0.045)
= 0.255 ~ 26%
Thus, a 95% confidence interval for this study is between 26% and 35%
Determine whether the lines L1:x=25+7t,y=17+6t,z=t and L2:x=−12+8ty=−17+8tz=−11+4t intersect, are skew, or are parallel. If they intersect, determine
Answer: The lines are skew.
Step-by-step explanation: Two lines can only be parallel OR skew Or intersect each other. To determine that:
1) If the lines are parallel, divide the coefficient that precedes the variable of each equation and compare:
[tex]\frac{7}{8} \neq \frac{6}{8} \neq \frac{1}{4}[/tex]
Since they are not equal, L1 and L2 are not parallel.
2) If the lines intersect, when you equal the equations the variable is a valid statement:
25 + 7t = - 12 + 8t (1)
17 + 6t = - 17 + 8t (2)
t = - 11 + 4t (3)
Using (3) to solve the system:
t - 4t = - 11
3t = 11
t = [tex]\frac{11}{3}[/tex]
Substituing t in (1):
25 + 7(11/3) = -12 + 8(11/3)
25 + 77/3 = - 12 + 88/3
[tex]\frac{152}{3} = \frac{52}{3}[/tex]
Which is not true, so, the lines does NOT intersect.
As they are none of the other options, it can be concluded that the lines L1 and L2 are skew.
O número inteiro positivo, cujo produto de seu antecessor com seu sucessor é igual a 8, é
A) 5
B) 4
C) -3
D) 3
El 2
Answer:
Olá!
`~~~~~~~~~~~~~~~~~~
3 (número inteiro positivo)
2 (antessor)
4 (sucessor)
Para provar isso, simplesmente multiplicamos entre 4 e 2:
4 x 2 = 8
Espero que isso tenha ajudado! Também seria bom se você me desse Brainliest!
What is the domain of the equation y=1/X+5?
Answer:
Domain is
{
x
∈
R
;
x
≠
−
5
}
Range is
{
y
∈
R
;
y
≠
0
}
Step-by-step explanation:
Explanation:
Domain: Denominator should not be
0
∴
x
+
5
≠
0
or
x
≠
−
5
Domain is any real value except
x
=
−
5
or
{
x
∈
R
;
x
≠
−
5
}
Range is any real value except
y
=
0
or
{
y
∈
R
;
y
≠
0
}
graph{1/(x+5) [-10, 10, -5, 5]}
Finding missing angles
Answer:
x=15
Step-by-step explanation:
165+x=180
180-165=15
Hope this helps!!
I NEED HELP PLEASE, THANKS! :) A commercial passenger jet is flying with an airspeed of 185 miles per hour on a heading of 036°. If a 47-mile-per-hour wind is blowing from a true heading of 120°, determine the velocity and direction of the jet relative to the ground. 186.1 mph, 021° 188.5 mph, 021° 195.6 mph, 069° 186.1 mph, 069°
We are given that the passenger's jet is flying at a speed of 185 miles per hour, with a direction of 36 degrees, and the wind speed being 47 mph with a direction of 120 degrees. From this, you could create a diagram is shown in the attachment.
[ 185 cos 36, 185 sin 36 ]
+ [ 47 cos 120, 47 sin 120 ]
_______________________
[ 185 cos 36 + 47 cos 120, 185 sin 36 + 47 sin 120 ]
√( 4263 + 33988 )^2
= ( About ) √38251 = 195.57 mph
Solution = 195.6 mph, 069°
Last winter Armand had StartFraction 5 Over 6 EndFraction of a row of stacked logs. At the end of the winter he had StartFraction 8 Over 15 EndFraction of the same row left. How much wood did he burn over the winter?
Answer:
3/10
Step-by-step explanation:
We have that the Armans last winter had 5/6 of a row of stacked logs and at the end of the winter he had 8/15 of the same row left, therefore:
Ambitious
First we have to do is that the denominator is the same.
in the case of 5/6 it would be 25/30
and for 8/15 it would be 16/30
Now if we can do the subtraction and it would be:
25/30 - 16/30 = 9/30 or what equals 3/10
3/10 was the amount of wood he burned in the winter
Answer:
D) 3/10 row
Step-by-step explanation: