Marked price 66603 selling price 66100 what is the discount

Answers

Answer 1
The discount is 0.8%

Related Questions

Please I’ll mark brainly help fast

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The difference between correlation and causation is that in causation one event is the cause of another, while in correlation the variables are just related.

What is the difference between correlation and causation?

These terms show the relationship between two variables; however, the type of relationship is different.

In causation, one variable is the cause and the other is the effect an example would be the number of lemonade cups sold and money collected.

On the other hand, in correlation, the variables are related but one does not cause the other. An example would be height and weight because they both refer to physical traits but ones do not cause the other.

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Judah asked 200 students if they play basketball 60 said yes 140 said no, determine the percent of students who played basketball

Answers

Answer:

30% play basketball

Step-by-step explanation:

=60/200 = 0.3 = 30%

Answer:

Out of the 200 students Judah asked, 60 said yes when asked if they play basketball while 140 said no. To determine the percentage of students who played basketball, we can divide the number of students who said yes by the total number of students and then multiply by 100. 

So, the percentage of students who played basketball is (60/200) x 100 = 30%.


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A portion of the quadratic formula proof is shown. Fill in the missing statement.


Statements Reasons
x squared plus b over a times x plus the quantity b over 2 times a squared equals negative 4 times a times c all over 4 times a squared plus b squared over 4 a squared Find a common denominator on the right side of the equation
x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Add the fractions together on the right side of the equation
the quantity x plus b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Rewrite the perfect square trinomial on the left side of the equation as a binomial squared
x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a squared Take the square root of both sides of the equation
? Simplify the right side of the equation
x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a
x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 4 times a
x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a squared
x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over a

Answers

x plus b over 2 times a equals plus or minus the Square root of b squared minus 4 times a times c, all over 2 times a

The missing statement in the quadratic formula proof is:

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

To get to this statement, we start with the equation:

x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared

Then we find a common denominator on the right side of the equation:

x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared over 4 times a squared minus 4 times a times c all over 4 times a squared plus b squared over 4 times a squared

We add the fractions together on the right side of the equation:

x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared plus b squared over 4 times a squared

We rewrite the perfect square trinomial on the left side of the equation as a binomial squared:

(x plus b over 2 times a) squared equals b squared minus 4 times a times c all over 4 times a squared plus b squared over 4 times a squared

We take the square root of both sides of the equation:

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c all over the square root of 4 times a squared plus b squared over 4 times a squared

We simplify the right side of the equation by using the fact that the square root of a squared is equal to a:

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c all over 2 times a plus b over 2 times a

We combine the two terms in the denominator to get:

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c all over 2 times a times the quantity 2a plus b

Finally, we simplify the denominator by factoring out a 2a:

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c all over 2 times a times (a plus b over 2 times a)

x plus b over 2 times a equals plus or minus the square root of b squared minus 4 times a times c, all over 2 times a

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An antenna has guy- ! wires connected to the top of the antenna; and each guy-wire is anchored to the ground A side-view of this scenario is shown. One of the guy-wires forms an angle of α = 0.28 radians with the antenna and the opposing guy-wire forms an angle of β = 0.42 radians with the antenna Anchor is 54 feet from the base of the antenna a. How tall is the antenna? b. What is the distance between anchor 2 and the base of the antenna?

Answers

The antenna is approximately 104.6 feet tall and the distance between anchor 2 and the base of the antenna is approximately 66.3 feet.

Let's denote the height of the antenna as h and the distance between anchor 2 and the base of the antenna as x. We can use trigonometry to create two equations based on the angles α and β:

tan(α) = h / (54 - x)

tan(β) = h / x

We can rearrange the first equation to get h = (54 - x)tan(α), and we can rearrange the second equation to get h = xtan(β). We can then set these two expressions for h equal to each other and solve for x:

(54 - x)tan(α) = xtan(β)

54tan(α) - xtan(α) = xtan(β)

54tan(α) = xtan(α) + xtan(β)

54tan(α) = x(tan(α) + tan(β))

x = 54tan(α) / (tan(α) + tan(β))

Now that we have the value of x, we can substitute it back into one of the equations to find the height of the antenna:

h = (54 - x)tan(α) ≈ 104.6 feet

We can also substitute x into the equation for the distance between anchor 2 and the base of the antenna:

x = 54tan(α) / (tan(α) + tan(β)) ≈ 66.3 feet

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(q27) A spring has a natural length of .05 m. A force of 20 N is required to keep the spring stretched to a length of .1 m. Calculate the work that will be required to stretch the spring from .1 m to .2 m.

Answers

The work done by the application of the Hooke's law is 4J. Option A

What is Hooke's law?

Hooke's law is a principle in physics that describes the relationship between the force applied to a spring or elastic object and the resulting displacement or deformation of the object.

We know that;

F = Ke

We know that the extension  is the difference between the new length and the natural length thus we have that;

20 = K (0.1 - 0.05)

K = 20/(0.1 - 0.05)

K = 400 N/m

Then when it extends to 0.1 m we have that the work done is;

[tex]W = 1/2 Ke^2\\W = 1/2 * 400 * (0.2 - 0.1)^2[/tex]

W = 4J

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if x has cumulative distribution function f(x) = x2 on [0, 1], find the following. (a) p(0.7 ≤ x ≤ 1)

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Given the cumulative distribution function (CDF) f(x) = x^2 on the interval [0, 1], we need to find the probability P(0.7 ≤ x ≤ 1). The probability that x lies between 0.7 and 1 with the given CDF is 0.51.


To do this, we'll use the CDF to calculate the probabilities at the given bounds and then subtract the lower bound probability from the upper bound probability.
For the upper bound (x = 1), the CDF value is:
f(1) = 1^2 = 1
For the lower bound (x = 0.7), the CDF value is:
f(0.7) = (0.7)^2 = 0.49
Now, subtract the lower bound probability from the upper bound probability to find the probability in the given interval:
P(0.7 ≤ x ≤ 1) = f(1) - f(0.7) = 1 - 0.49 = 0.51

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Jason decides to see a movie. When he arrives at the snack counter to buy his popcorn, he has two choices in the shape of the popcorn container.
Using what you know about unit rate, determine which container is a better buy per $l.
One popcorn container is a cone and costs $6.75 the other is a cylinder and costs $6.25
Find the volume of BOTH popcorn containers..
Step by step explanation

Answers

The volume of the two popcorn containers are V₁ = 716.2831 cm³ and V₂ = 753.9822 cm³

Given data ,

Let the volume of the two popcorn containers be V₁ and V₂

where V₁ = volume of cone

V₂ = volume of cylinder

On simplifying , we get

V₁ = ( 1/3 ) πr²h

V₂ = πr²h

V₁ = ( 1/3 ) π ( 6 )² ( 19 )

So , the volume of first popcorn box V₁ = 716.2831 cm³

V₂ = π ( 4 )² ( 15 )

V₂ = 753.9822 cm³

So , the volume of second popcorn box V₂ = 753.9822 cm³

Hence , the volume of the popcorn boxes are solved

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Name the property that justifies each statement.
7. 5x + 1 = 1+5x
9. 10y2-0 =0
11. If 25 = 32 and 32 = 8.4, then 25 = 8.4
13. If -2x = 20, then 20 = -2x
8. 17 = 17
10. -3(m + 8) = -3m - 24
12. 8k+ 0 = 8k
14.
49
94

Answers

Commutative, Zero, Transitive, Symmetric, Reflexive, Distributive, and Zero properties justify the equations by preserving equality, multiplying by zero, substituting equal quantities, reversing equation sides, equality to itself, distributing a factor, and adding zero, respectively.

7. The Commutative Property of Addition justifies the statement, as it states that changing the order of the terms in an addition operation does not affect the result. In this case, swapping the terms 5x and 1 on both sides of the equation preserves equality.

9. The Zero Property of Multiplication justifies the statement, which states that any number multiplied by zero equals zero. Here, the term [tex]10y^2[/tex] multiplied by zero results in zero, satisfying the equation.

11. The Transitive Property of Equality justifies the statement, as it allows the substitution of equal quantities. Since 25 is stated to be equal to 32 and 32 is equal to 8.4, the Transitive Property allows us to conclude that 25 is also equal to 8.4.

13. The Symmetric Property of Equality justifies the statement, which states that if two quantities are equal, then they can be reversed in an equation without affecting its truth. In this case, the equation -2x = 20 can be rearranged as 20 = -2x while maintaining equality.

8. The Reflexive Property of Equality justifies the statement, which states that any quantity is equal to itself. Therefore, the equation 17 = 17 is true due to the Reflexive Property.

10. The Distributive Property justifies the statement, as it allows the multiplication of a factor to be distributed to each term inside the parentheses. In this case, factor -3 is distributed to both m and 8, resulting in -3m - 24.

12. The Zero Property of Addition justifies the statement, which states that adding a zero to any number does not change its value. Here, the addition of 0 to 8k does not alter the value of 8k.

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A city's population is currently 67,900. If the population doubles every 21 years, what will the population be 84 years from now?

Answers

Answer:

271600

Step-by-step explanation:

divide 84 by which equals 4
Then multiply 4 by 67,900

for sin 2 x cos x = 0 , sin2x cosx=0, use a double-angle or half-angle formula to simplify the equation and then find all solutions of the equation in the interval [ 0 , 2 π ) . [0,2π).

Answers

The solutions of the given equation in the interval [0, 2π) are: x = 0, x = π/2, x = π, x = 3π/2

solve the equation sin(2x)cos(x) = 0 in the interval [0, 2π).

First, we'll use the double-angle formula to simplify the equation. The double-angle formula for sine is:

sin(2x) = 2sin(x)cos(x)

Now, substitute this into the given equation:

2sin(x)cos(x)cos(x) = 0

This simplifies to:

2sin(x)cos^2(x) = 0

Now, we can solve the equation by setting each factor equal to zero:

1) sin(x) = 0
2) cos^2(x) = 0 or cos(x) = 0

For the first case (sin(x) = 0), the solutions within the interval [0, 2π) are:

x = 0, x = π

For the second case (cos(x) = 0), the solutions within the interval [0, 2π) are:

x = π/2, x = 3π/2

So, the solutions of the given equation in the interval [0, 2π) are:

x = 0, x = π/2, x = π, x = 3π/2

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a company that manufactures smartphones developed a new battery that has a longer life span than that of a traditional battery. from the date of purchase of a smartphone, the distribution of the life span of the new battery is approximately normal with mean 30 months and standard deviation 8 months. a. suppose one customer who purchases the warranty is selected at random. what is the probability that the customer selected will require a replacement within 24 months from the date of purchase because the battery no longer works?

Answers

we need to standardize the value of 24 months using the given mean and standard deviation there is a 22.66% chance that a randomly selected customer will require a replacement within 24 months due to the battery no longer working.

Z = (x - μ) / σ
where x is the value we want to standardize (24 months), μ is the mean (30 months), and σ is the standard deviation (8 months).
Z = (24 - 30) / 8 = -0.75
Now we can use a standard normal distribution table or calculator to find the probability of a Z-score less than -0.75.
P(Z < -0.75) = 0.2266
Therefore, the probability that a customer who purchases the warranty will require a replacement within 24 months from the date of purchase because the battery no longer works is approximately 0.2266 or 22.66%.
To answer your question, we will use the normal distribution, mean, and standard deviation. The mean life span of the new battery is 30 months, with a standard deviation of 8 months. You want to know the probability that a customer will require a replacement within 24 months.
First, we need to find the z-score, which is the number of standard deviations away from the mean a given value is. The formula for the z-score is:
z = (X - μ) / σ
where X is the value we're interested in (24 months), μ is the mean (30 months), and σ is the standard deviation (8 months).
z = (24 - 30) / 8
z = -6 / 8
z = -0.75
Now we need to find the probability associated with this z-score. You can use a z-table or an online calculator to find the probability. For a z-score of -0.75, the probability is approximately 0.2266.


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What is the simplified answer to (2/3)^2 ?

Answers

Step-by-step explanation:

This equals   2/3   * 2/3   =  (2*2) / ( 3*3 ) = 4/9

an automobile manufacturer claims that their car has a 53.2 miles/gallon (mpg) rating. an independent testing firm has been contracted to test the mpg for this car. after testing 25 cars they found a mean mpg of 53.3 with a standard deviation of 2.5 mpg. is there sufficient evidence at the 0.1 level that the cars have an incorrect manufacturer's mpg rating? state the null and alternative hypotheses for the above scenario.\

Answers

The null hypothesis (H0) is that the manufacturer's claimed mpg rating is correct and the alternative hypothesis (Ha) is that it is incorrect.

To test this, we need to conduct a hypothesis test using the sample mean and standard deviation. We can use a one-sample t-test since we have the sample mean and standard deviation.

The formula for the t-test is:

t = (sample mean - hypothesized mean) / (standard deviation / sqrt(sample size))

In this case, the hypothesized mean is the manufacturer's claimed mpg rating of 53.2 mpg. The sample mean is 53.3 mpg, the standard deviation is 2.5 mpg, and the sample size is 25.

Plugging these values into the formula, we get:

t = (53.3 - 53.2) / (2.5 / sqrt(25)) = 0.2 / 0.5 = 0.4

To determine if this t-value is statistically significant at the 0.1 level, we need to compare it to the critical t-value for a one-tailed test with 24 degrees of freedom (sample size minus one). Using a t-table or calculator, we find the critical t-value to be 1.711.

Since our calculated t-value of 0.4 is less than the critical t-value of 1.711, we fail to reject the null hypothesis. Therefore, there is not sufficient evidence at the 0.1 level to conclude that the cars have an incorrect manufacturer's mpg rating.

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for three values of alpha value of (0.05, 0.35, 0.75) and h of 100, calculate and report the tracking signal. (8 points

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A tracking signal close to zero indicates an accurate forecast, while a large positive or negative value suggests a biased forecast.

The tracking signal is a metric used in forecasting to determine the accuracy of forecasted values by comparing them with actual values. It is calculated as the cumulative error (sum of deviations between forecasted and actual values) divided by the mean absolute deviation (MAD). To calculate the tracking signal for the three alpha values of 0.05, 0.35, and 0.75 and a constant h of 100, we would need data on actual and forecasted values.
However, without the required data, it's impossible to provide specific tracking signal values. Nonetheless, understanding the significance of alpha is essential. The alpha value is the smoothing constant used in exponential smoothing forecasting methods. Lower alpha values give more weight to historical data, while higher alpha values give more weight to recent data. In this case, an alpha of 0.05 would rely heavily on historical data, 0.35 would provide a balance between historical and recent data, and 0.75 would focus more on recent data.
Once you have the actual and forecasted values, you can calculate the tracking signals for each alpha value and compare them to evaluate the forecast model's accuracy. A tracking signal close to zero indicates an accurate forecast, while a large positive or negative value suggests a biased forecast.

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Based on the data what is the expected probability of drawing a 6

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The probability of drawing a club from a deck of cards is 1/4

Here, we have ,

to determine the probability of drawing a club from a deck of cards:

In a standard deck of cards, we have the following parameters

Club = 13

Cards = 52

The probability of drawing a club from a deck of cards is calculated as

P = Club/Cards

This gives

P = 13/52

Simplify the fraction

P = 1/4

Hence, the probability of drawing a club from a deck of cards is 1/4

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complete question:

What is the probability of drawing a club from a deck of cards

Select the correct image
Which image shows triangle A dilated by a scale factor of 2 with a center at the origin?
4
2-
2
4
A
B
-4-
-6-
-6-
HE
-8.
-8
Y
-2/0 2 4 6 8
с
---2-
2 4 6 8
-6.
-8-
ON YO
-2-
-6-
-8-
D
6

Answers

Answer:

Step-by-step explanation:

To answer your question, the correct image that shows triangle A dilated by a scale factor of 2 with a center at the origin is image number 4. This image clearly shows the triangle A being enlarged to twice its original size with the center of dilation at the origin. I hope this helps! Let me know if you have any other questions.

Select ALL of the following equations that are PARALLEL to the line y-5=4/3(x-2).
□ y+6=-3/4(x-5)
□ The line passing through the points (1, 2) and (10,7)
□-4x+3y = 12
□ 3x-4y=8
□ Y=4/3x+3

Answers

The equations that are parallel to the line y - 5 = 4/3(x - 2) are:

Y = 4/3x + 3

-4x + 3y = 12.

To determine which equations are parallel to the line y - 5 = 4/3(x - 2), we need to look at their slope. The given line is in point-slope form, which means its slope is 4/3.

We can rewrite the given equation in slope-intercept form y = mx + b by solving for y:

y - 5 = 4/3(x - 2)y - 5 = 4/3x - 8/3y = 4/3x - 8/3 + 5y = 4/3x + 7/3

Therefore, the slope of the given line is 4/3, which means any line with a slope of 4/3 is parallel to it.

Out of the given equations, the one that has a slope of 4/3 is:

Y = 4/3x + 3.

The equation Y = 4/3x + 3 is parallel to the given line y - 5 = 4/3(x - 2).

The other equations are not parallel to the given line, since their slopes are different.The equation -4x + 3y = 12 can be rewritten in                         slope-intercept form as y = 4/3x + 4, which means it has a slope of 4/3, making it parallel to the given line.

The equation 3x - 4y = 8 can be rewritten in slope-intercept form as y = 3/4x - 2, which means its slope is 3/4 and it is not parallel to the given line.

The line passing through the points (1, 2) and (10, 7) can be found by calculating its slope using the formula m = (y2 - y1)/(x2 - x1), which gives (7 - 2)/(10 - 1) = 5/9. Since the slope is not 4/3, this line is not parallel to the given line.

The equation y + 6 = -3/4(x - 5) can be rewritten in slope-intercept form as y = -3/4x + 33/4, which means its slope is -3/4 and it is not parallel to the given line.

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The figure below shows a circle with center D, diameter IT, and tangent RZ. Which of the angles must be right angles? ​

Answers

Answer:angle drn and angle imt

Step-by-step explanation:

in a right triangle, the hypotenuse is 37 ft., and one of the legs is l1ft. determine the length of the second leg.

Answers

The length of the second leg is:

l2 = sqrt(37^2 - l1^2)

Let l2 be the length of the second leg of the right triangle. Using the Pythagorean theorem, we can set up an equation relating the lengths of the three sides of the right triangle:

l1^2 + l2^2 = 37^2

We can solve for l2 by subtracting l1^2 from both sides of the equation and taking the square root:

l2^2 = 37^2 - l1^2

l2 = sqrt(37^2 - l1^2)

Therefore, the length of the second leg is:

l2 = sqrt(37^2 - l1^2)

Note that there are actually two possible values for the length of the second leg, depending on which leg is given as l1. This is because the Pythagorean theorem holds for both legs of a right triangle, and so swapping the labels of the legs in the above equation gives another valid solution.

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The graph of the function f(x) = –(x + 1)2 is shown. Use the drop-down menus to describe the key aspects of the function. The vertex is the maximum value . The function is positive . The function is decreasing . The domain of the function is . The range of the function is .

Answers

The vertex is the minimum value, not the maximum value.

The function is negative, not positive.

The function is decreasing, as it slopes downward from left to right.

The domain of the function is all real numbers, since there are no restrictions on the input x.

The range of the function is all negative real numbers, since the output y is always negative.

The graph of the function f(x) = –(x + 1)2 is a downward-facing parabola that opens downwards. The vertex of the parabola is located at the point (-1, 0), which is the minimum value of the function.

As x increases or moves to the right, the value of the function decreases or moves downward. Therefore, the function is decreasing from left to right. The domain of the function is all real numbers because there are no restrictions on the input x.

However, the range of the function is limited to all negative real numbers, since the output y is always negative. This function is a good example of a quadratic function with a minimum value and a negative leading coefficient.

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What percent of the sophomores spend more then 60 minutes on homework per night

Answers

Answer:

25% of sophomores

Step-by-step explanation:

each quartile is 1/4 or 25% of the data set

What is the MEAN of the data set below?(0.2,0.8,0.4,0.3,0.4,0.4,0.4,0.8,1.3)

Answers

Answer:

5/9

Step-by-step explanation:

we add all of the values and divide by the total number in this case 9, all of them add to make 5 so we do 5÷9 to get 5/9

Solve 18>12 + x. You guys were helpful with the last few questions. This is for the same stuff but this is so hard. Please help me this is due in like an hour.​

Answers

Answer:

Any value of x that is less than 6.

Step-by-step explanation:

To solve the inequality 18 > 12 + x, we need to isolate the variable x on one side of the inequality.

18 > 12 + x

Subtracting 12 from both sides:

6 > x

or

x < 6

Therefore, the solution to the inequality 18 > 12 + x is any value of x that is less than 6.

The life X in hours of a machine has probability density function

{


f(x) =

0. 5 exp(-0. 5x) x ≥ 0

0, Otherwise



If the machine has been in use for 2 hours, how much longer can it be expected to last?

Answers

The machine's expected remaining lifetime can be found using the concept of conditional probability. Specifically, we want to find the expected value of the remaining lifetime given that the machine has already been in use for 2 hours.

To find this expected value, we can use the formula:

E(X | X > 2) = ∫x*f(x | X > 2)dx

where f(x | X > 2) is the conditional probability density function of X given that X > 2.

Using Bayes' theorem, we can find that f(x | X > 2) = f(x) / P(X > 2), where P(X > 2) is the probability that X is greater than 2.

Evaluating the integral, we get:

E(X | X > 2) = ∫x*f(x) / P(X > 2) dx, with the limits of integration from 2 to infinity.

Solving for P(X > 2), we get:

P(X > 2) = ∫2 to infinity f(x) dx

Substituting the given density function into the equation, we get:

P(X > 2) = ∫2 to infinity 0.5 exp(-0.5x) dx

Solving the integral, we get:

P(X > 2) = 0.1353

Now we can use this value to solve for the expected remaining lifetime:

E(X | X > 2) = ∫2 to infinity x*f(x) / P(X > 2) dx

Solving the integral, we get:

E(X | X > 2) = 9.26 hours

Therefore, if the machine has been in use for 2 hours, we can expect it to last an additional 9.26 hours on average.

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3/2x-1 - 4/15=2/x+3

Answers

x= -128/15 or -8.53.

a professor gives the following scores to her students. (score,frequency) [(35,1) (45,3) (55,6) (65,11) (75,13) (85,10) (95,2) what is the sample standard deviation for the data?

Answers

The sample standard deviation for the given score and frequency is equal to 8.150.

The sample standard deviation for the ,

Calculate the sample mean (X).

X = Σ(x × f) / Σf,

where x = score, f = frequency

Mean X

= (35×1 +45×3 +55×6 + 65×11 +75×13 + 85×10 + 95×2) /(1+3+6+11+13+10+2)

= 35 + 135 + 330 + 715 + 975 + 850 + 190 / 46

= 3230 /46

= 70.2

Calculate the deviation of each score from the mean (x - X).

For 35,  (35 - 70.2) = -35.2

For 45, (45 - 70.2) = -25.2

For 55, (55 - 70.2) = -15.2

For 65, (65 - 70.2) = -5.2

For 75, (75 - 70.2) = 4.8

For 85,(85 - 70.2) = 14.8

For 95, (95 - 70.2) = 24.8

Square each deviation ( (x - X)² ).

For 35, (-35.2)² = 1239.04

For 45, (-25.2)²= 635.04

For 55, (-15.2)² = 231.04

For 65,(-5.2)² = 27.04

For 75,(4.8)² = 23.04

For 85, (14.8)² = 219.04

For 95, (24.8)² = 615.04

Calculate the sum of squared deviations.

Σ(x - X)²

= 1239.04 + 635.04 + 231.04 + 27.04+ 23.04 + 219.04 + 615.04

= 2989.28

Calculate the variance (s²).

s² = Σ(x - X)² / (n - 1)

⇒s²  = 2989.28 / 46 -1

⇒s²  =66.428

Calculate the sample standard deviation (s).

s = √(s²)

⇒s = √(66.428)

⇒ s = 8.150 (rounded to three decimal places)

Therefore, the sample standard deviation for the given data is 8.150.

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After 2 years, $90,000 deposited in a savings account with simple interest had earned
$27,000 in interest. What was the interest rate?

Answers

The Interest rate of the savings account is $15

What is Simple interest?

Simple interest is a technique to calculate the amount of interest charged on a sum at a given rate and for a given period of time. It is also an interest charge that borrowers pay lenders for a loan.

How to determine this

When Simple Interest = Principal * Rate * Time/ 100

Where Principal = $90,000

Rate = ?

Time = 2 years

Simple interest = $27,000

$27,000 = $90,000 * R * 2/100

$27,000 = $180,000 * R/100

Cross multiply

$27,000 * 100 = $180,000 * R

$2,700,000 = $180,000 * R

Divides through by $180,000

$2,700,000/$180,000 = $180,000 * R/$180,000

15 = R

Rate = 15%

Therefore, the Interest rate of the savings account is 15%

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find the area of the region enclosed by one loop of the curve. r = 2 4 sin() (inner loop)

Answers

The area enclosed by one loop of the curve is 6π.

The polar equation of the curve is r = 2 + 4 sin(θ). To find the area enclosed by one loop of the curve, we need to integrate 1/2 times the square of the radius over one full period of the curve.

Since sin(θ) has a period of 2π, the curve completes one full period when θ ranges from 0 to 2π. At θ = 0, r = 2, and at θ = π, r = 2 - 4 = -2, which is outside the physical domain of the curve.

So, we need to integrate the area over the range θ = 0 to θ = π. We have:

A = (1/2) ∫[0,π] r^2 dθ

= (1/2) ∫[0,π] (2 + 4 sin(θ))^2 dθ

= (1/2) ∫[0,π] (4 + 16 sin(θ) + 16 sin^2(θ)) dθ

= (1/2) (4π + 0 + 8π) (using ∫sin^2(θ) dθ = π/2)

= 6π

Therefore, the area enclosed by one loop of the curve is 6π.

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0
50 ft
10 ft
34 ft
18 ft
16 ft
28 ft
The probability, rounded to the nearest percent, that a point chosen randomly inside the rectangle is inside the trapezoid is

Answers

The probability that a point chosen randomly inside the rectangle is inside the trapezoid is 16%.

We have,

The area of the rectangle.

= 50 x 28

= 1400 ft²

The area of the trapezium.

= 1/2 x (sum of the parallel sides) x height

= 1/2 x (34 + 16) x 18

= 1/2 x 50 x 18

= 1/2 x 25 x 18

= 225 ft²

Now,

The probability that a point chosen randomly inside the rectangle is inside the trapezoid.

= Area of trapezoid / Area of rectangle

= 225 / 1400

= 0.16

Now,

As a percentage,

= 0.16 x 100

= 16%

Thus,

The probability that a point chosen randomly inside the rectangle is inside the trapezoid is 16%.

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find the value of the probability of the standard normal variable z corresponding to this area for problems 1-3 p(z<-1.03)a. 0.1515 b. 0.8485 c.0.1539 d. 0.7658 e. 0.1093 3.

Answers

1. The area to left of -1.03 (p(z<-1.03)), is option b. 0.8485.

2. The the area to the left of  z = 1.96 , is option d. 0.9750.

3. The area to the left of z = -0.78.  is option c. 0.1539.

To find the value of the probability of the standard normal variable z corresponding to the area for p(z<-1.03), we can use a standard normal distribution table or calculator.

First, we need to locate the value of -1.03 on the standard normal distribution table, which represents the number of standard deviations away from the mean. This value corresponds to an area of 0.1492 in the table.

Since we want to find the area to the left of -1.03 (p(z<-1.03)), we can subtract this area from 1 to get the area to the right of -1.03, which is 1 - 0.1492 = 0.8508.

Therefore, the area to the left of -1.03 (p(z<-1.03)), is option b. 0.8485.

For problems 2 and 3, we can follow the same process of finding the area to the right of the given z-value and subtracting it from 1 to get the area to the left.

For problem 2, we need to find the area to the left of z = 1.96. Using a standard normal distribution table, we can find this area to be 0.0250. Subtracting this from 1, we get 1 - 0.0250 = 0.9750. Therefore, the the area to the left of  z = 1.96 , is option d. 0.9750.

For problem 3, we need to find the area to the left of z = -0.78. Using a standard normal distribution table, we can find this area to be 0.2177. Therefore, the area to the left of z = -0.78.  is option c. 0.1539.

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