Maleia is tracking her running training program. The table gives her 5K run time at the end of each month.


Month Time (minutes)
1 47
2 43
3 39
4 36
5 35
6 33


What is the equation for the line of best fit where x represents the month and y represents the time?
y = −2.78x + 33.6
y = −2.78x + 48.5
y = 2.78x + 33.6
y = 2.78x + 48.5

Answer:

Step-by-step explanation:

In the year 2002 the exports of Chinese's automobile parts will $5.3 billion.

The exponential function for the given export of Chinese's automobile parts is-

5.3 = 1.8208 e^0.3387x

5.3/1.8208 = e^0.3387x

Taking ln both sides-

ln(5.3/1.8208) = ln e^0.3387x

ln(5.3/1.8208) = 0.3387x

Further simplifying

x = ln(5.3/1.8208)/0.3387

x =  3.15

x ≈ 3 year ad some months

Add 3 years to 1998 to get the required year.

Year = 1998 + 3

Year = 2001 and months

Year = 2002

Thus, in the year 2002 the exports of Chinese's automobile parts will $5.3 billion.

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The correct question is-

The value of China's exports of automobiles and parts (in billions of dollars) is approximately f(x) = 1.8208e^.3387x, where x = 0 corresponds to 1998.

In what year did/will the exports reach $5.3 billion?

240 people can seat in a row without restriction in an arrangement.

A permutation of a set is, loosely speaking, an arrangement of its members into a sequence or linear order, or if the set is already ordered, a rearrangement of its elements. The word "permutation" also refers to the act or process of changing the linear order of an ordered set.

Permutations differ from combinations, which are selections of some members of a set regardless of order. For example, written as tuples, there are six permutations of the set {1, 2, 3}, namely (1, 2, 3), (1, 3, 2), (2, 1, 3), (2, 3, 1), (3, 1, 2), and (3, 2, 1). These are all the possible orderings of this three-element set. Anagrams of words whose letters are different are also permutations: the letters are already ordered in the original word, and the anagram is a reordering of the letters. The study of permutations of finite sets is an important topic in the fields of combinatorics and group theory.

According to the question:

Consider A and B being the people sitting next to each other, as one entity AB or BA.

There are now 5 entities (one of two persons A and B and five of one single person) that have to be placed in a row.

With AB, there are thus 5! possibilities. With BA, there are also 6! possibilities.

Considering both, there are thus 2× 5! = 240 ways to seat 6 people in a row of six seats if two people insist on sitting next to each other.

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There is sufficient data to back up the assertion that salespeople with college degrees generate much higher average sales than salespeople without.

Given,

This is a test of the hypothesis that the means of the two populations differ.

The assertion is that salespeople with college degrees generate much higher average sales than salespeople without.

The alternative and null hypothesis are then:

H₀ ; μ₁ - μ₂ = 0

Hₐ ;  μ₁ - μ₂ > 0

The level of significance is 0.05.

The mean and standard deviation for sample 1 (college degree), with n1=14, are 3542 and 468, respectively.

The mean and standard deviation of sample 2 (non-college degree), with n2=17, are 3301 and 642, respectively.

Now,

Md = M₁ - M₂ = 3542 - 3301 = 241

Md=241 is the difference between the sample means.

The following formula is used to calculate the estimated standard error of the difference between means:

S Md = √(σ₁²/n₁ + σ₂²/n₂) = √(468²/14 + 642²/17) = √(15644.6 + 24244.94) = 199.72

Then, we can calculate the t-statistic as:

t = (Md - (μ₁ - μ₂) / S Md = 241 - 0 / 199.72 = 241/199.72  = 1.21

The degrees of freedom for this test are:

Df = n₁ + n₂ - 2 = 14 + 17 - 2 = 29

Right-tailed tests have 29 degrees of freedom and t=1.21, so the following formula is used to determine the P-value for this test:

P Value = P(t > 1.21) = 0.118025

The effect is significant since the P-value (0.118025) is less than the 0.05 standard of significance.

The null hypothesis is rejected.

Therefore,

The idea that salespeople with college degrees generate much higher average sales than those without is supported by sufficient data.

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Answer:

−3 < −1

−3 ≤ −1

Step-by-step explanation:

Symbol explanation

A negative number is any number that is less than zero.

On the number line the negative numbers are to the left of the zero.

-3 is less than -1 because -3 lies to the left of -1 on the number line.

Therefore, the only given inequalities that are true statements are:

Answer:

Step-by-step explanation:

The number of ways we can paint is g(nk)=1/n ∑d | n ϕ(d) ((k−1)^n/d +(−1)^n/d (k−1))

Given,

Whether your circle has named sectors (i.e., is fixed) or lacks labels will determine this (i.e. is free).

In the first scenario, inclusion-exclusion can be used to create sets Ai,j of colorings with adjacent sectors I and j having the same color. Next, generally

|Ai1,j1∩⋯∩Air,jr|={(k^n − r r<n) ( k r=n)

And inclusion-exclusion yields f(n, k), the number of sectors that are colored with k colors that are not related to any of Ai, j (i.e., do not have similar adjacent colors):

f(n, k) = ∑r = 0 n−1 (−1)^r (n, r) k^n - r + (−1)^n (n, n)k

And the result of adding and subtracting (1) is:

⟹f(n, k) = ∑r = 0 n−1 (−1)^r (n, r) k^n−r + (−1)^n (n, n)k = (k−1)^n + (−1)^n (k−1)

That is your response to the fixed circle.

Burnside's Lemma, which generates the cycle index of a combinatorial necklace, must be applied if you want the solution for a free circle (assuming the symmetries involved are merely rotations):

Z(Cn) = 1n∑d∣nϕ(d)an/dd

Then, n/d cycles with dN sectors in each cycle, an/dd permutations representing rotations of sectors, and (d) is the Euler Totient Function[4] are used.

Since each cycle must contain a single color from the n available options, we must swap out an/dd with f(n/d, k), resulting in a total of g(n, k) free colorings for n>1*:

g(n, k)=1/n ∑d∣n ϕ(d) ((k−1)^n/d +(−1)^n/d (k−1))

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Answer:

Ava is running faster than Maura.

Step-by-step explanation:

We are finding the speed in miles/minute.

6/75=0.08miles/minute

5/45=0.(1)miles/minute

0.(1)is greater than 0/08

Ava is running faster than Maura.

Answer:

c) Multiplicative Identity

Step-by-step explanation:

Given equation,

→ c × 1 = c

Then the given equation shows,

→ Multiplicative Identity

(number × 1 = number)

Hence, the option (c) is correct.

From the origin (6,18,36) to the tip, the exact length of the curve is 42.

A mathematical statement that has a "equal to" symbol between two expressions with equal values is called an equation. as in 3x + 5 Equals 15, for instance.

Equations come in a variety of forms, including linear, quadratic, cubic, and others.

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

We have LHS = RHS (left hand side = right hand side) in every mathematical equation. To determine the value of an unknown variable that represents an unknown quantity, equations can be solved. The statement is not an equation if there is no "equal to" sign in it.

According to our question-

let x = t

x^2= 2y

y = t^2

44/3

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The equation is P = 1700x + 22,000 and the population in 2009 is 32,200.

Here we have to find the equation to get to know the population after x years.

Data provided:

Population in 2003 = 22,000

Year = x year

Population increases every year = 1700

Let P be the population after x year.

So the equation is:

P = 1700x + 22,000

Now we have to find the population in 2009.

So 2009 - 2003 = 6

Put x = 6

P = 1700 × 6 + 22,000

  = 10200 + 22,000

  = 32,200

Therefore the equation is P = 1700x + 22,00 and in 2009 population is 32,200.

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Answer:

1 1/3 or 4/3

Step-by-step explanation:

1/6 + 1/6 = 2/6

simplified, it would be 1/3 then you add the one, and you get 1 1/3 or (written as a mixed number,) 4/3

Answer:

2

Step-by-step explanation:

Since the denominator is the same, we can add the numerators.

11/6  +  1/6  =  12/6

We can simplify this to 2.

So, the answer is 2.

One sample mean t test is used to to check whether the true average is 59k.

Average:

In statistics, average means a mean value which is equal to the ratio of the sum of the number of a given set of values to the total number of values present in the set.

Given,

Here we need to find in what test can you use to check whether the true average is 59k.

While we looking into the given question we have identified the following details,

Number of students = 49

True average = 59k

Sample average = 44k

In this given situation, the perfectly suitable test is one sample t test,

Why we used this because of a statistical hypothesis test used to determine whether an unknown population mean is different from a specific value.

Suppose our student center published data that the average starting salary for college graduates is 59k. You randomly sampled 49 college graduates and calculated the sample average salary is 44k.

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Answer:33%

Step-by-step explanation: take 1 divided by 3 which equals 0.33 multiply that by 100 to get a percentage of 33 percent

you don't need to give me anything

Answer:

33%

Step-by-step explanation:

I want your chocolate.

The probability that they will have exactly one affected child is 9/64.

What is probability?

Simply put, probability measures how probable something is to occur. We can discuss the probabilities of various outcomes, or how likely they are, whenever we are unsure of how an event will turn out. Statistics is the study of events subject to probability.

The likelihood that a population parameter will be less than a given value when the null hypothesis is true is expressed as the p-value, also known as a probability value or a measure of significance, for a particular statistical model.

Probability of affecting for 1 child = 3/4  = q

Probability of not affecting on 1 child =p=1/4

Formula:

P( exactly one affected child )

= [tex]^{3}C_{1}[/tex] * * (1/4)² * (3/4) = 9/64

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Dividing the class by using Coin flip , The instructor has created minimal group

Researchers employ a technique called the minimal group paradigm to instigate new social groups in the lab. The objective is to classify people into groups using minimal, meaningless, or arbitrary criteria.

A minimal group is a a group lacking interdependence, group cohesion, structure, and other characteristics typically found in social groups.

An example is a group of people disembarking from a bus.

According to the question ,

The instructor is dividing the class by means of coin

Here, the flipping of coin is an arbitrary criteria . Also , the group formed will be anonymous

Hence , the formed group will be minimal group

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In general, there are n>3 lines in the plane. Show that at least n - 2 triangles are formed by these lines.

Let's consider the following diagram, where each line is labelled with a letter:

A-B-C-D-E

Since each line intersects with at least one other line, there are at least n-2 triangles that can be formed. For example, triangle ABC, triangle ABD, triangle ABE, triangle BCD, triangle BDE, and triangle CDE are all triangles that can be formed from our five lines.

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The equation of the line in slope intercept form is y = 4/5 x.

For the stated question-

The given points are-

(x1, y1) = (5,4)

(x2, y2) = (10,8)

Slope m = (y2 -y1)/ (x2 - x1)

m = (8 - 4)/(10 - 5)

m = 4/5

Equation of the line;

y - y1 = m(x - x1)

y - 4 = 4/5 (x - 5)

y = 4/5 x - 4 + 4

y = 4/5 x

Thus, the equation of the line in slope intercept form is y = 4/5 x.

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Answer:

r = 0

Step-by-step explanation:

the first thing you can do to solve this equation is to remove the parenthesis

2r + 4 = r + 4

now subtract 4 from both sides

2r = r

subtract 4 from both sides

r = 0

that is your answer

The measures of central tendency from the given stem-and-leaf plot are given as follows:

The stem-and-leaf plot shows the measures of the data-set, in which:

For example:

4|7 = 47.

Hence all the measures of the data-set are given as follows:

47, 51, 56, 57, 62, 63, 63, 66, 66, 68, 68, 70, 71, 73, 73, 73, 73, 76, 76, 77, 77, 79, 80, 81, 82, 83, 86, 88, 88, 90, 91, 93, 93, 97.

The mean is given by the sum of all scores divided by the number of scores, hence it is given as follows:

Mean = 74.62.

The median is the middle value of the data-set. The data-set has 34 elements, which is an even cardinality, hence the median is given by the mean of the 17th and of the 18th element, as follows:

Median = (73 + 76)/2 = 74.5.

The mode is the value that appears the most times in the data-set, which is of 73, as it is the only score to appear four times in the data-set.

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The Coefficient of determination is the proportion of variability of the dependent and independent variable this statement is true.

The primary result of the regression analysis is the coefficient of determination because it indicates the percentage of variations in the dependent variable that can be accounted for by the independent variable.

The effectiveness of a statistical model in forecasting a result is indicated by the coefficient of determination [tex]R^2[/tex]. The dependent variable in the model is a representation of the result. [tex]R^2[/tex] can have a minimum value of 0 and a maximum value of 1.

Researchers frequently rely on coefficient, also referred to as R-squared (or [tex]R^2[/tex]), when performing trend analysis to determine how strong the linear relationship is between two variables.

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If Diandre completed 15 drills in 2 hours, the unit rate will be 7.5 drills per hour.

It is defined as the change in values of a dependent variable with respect to the independent variables.

It is given that, Diandre completed 15 drills in 2 hours. The rate is 15/2

A unit rate is a cost for just one of something. This is expressed as a ratio with a denominator of 1. For instance, it is useful in large applications like finding the average speed.

Thus, if Diandre completed 15 drills in 2 hours, the unit rate will be 7.5 drills per hour.

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The equation that doesn't belong is (c) 12(p + 8) = 3(20 - 2p)

From the question, we have the following parameters that can be used in our computation:

Options A to D

Looking through the options, we can see that:

However, three of the equations have their variables on one side

While the last has its variable on both sides

Hence, the one that does not belong is (c) 12(p + 8) = 3(20 - 2p)

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The example that represents a proportional relationship is A. y = -x

Proportional relationships are relationships between two variables where their ratios are equivalent. Another way to think about them is that, in a proportional relationship, one variable is always a constant value times the other.

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form of y = kx.

In the proportional relationship, the constant of proportionality k is equal to the slope m and the line passes through the origin

It should be noted that y = -x is a linear equation that passes through the origin.

In conclusion, the correct option is A.

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Sample error is ±2.9872 from the sample mean of 22 inch and standard deviation of 8 inch and sample size of 30 inch.

An analyst makes a statistical error known as a sampling error when they choose a sample that does not accurately represent the complete population of data. As a result, the sample's findings do not accurately reflect the findings from the total population.

Here,

mean=22 inch

standard deviation=8 inch

sample size=30 inch

degree of freedom=29 inch

The sampling error is calculated by dividing the standard deviation of the population by the square root of the size of the sample, and then multiplying the resultant with the Z-score value, which is based on the confidence interval.

By using this,

sampling error=±2.9872 inch

With a sample mean of 22 inches, a standard deviation of 8 inches, and a sample size of 30 inches, the sample error is 2.9872 inches.

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Answer:

The total length of the tree in the total of 19 years (including the first year) would be 210 inches.

Answer: 210in

Step-by-step explanation:

The pass numbers are independent of the school of study.

Given that a high  school offers math placement exams for incoming freshmen to place students into the appropriate math class during their freshman year

Set up hypotheses as

H₀ : Pass independent of school

Hₐ : Pass independent on school

Two tailed chi square test for independence)

Contingency table is shows as below

School A B C Total

Pass 42 29 45 116

Expected 38.6667 38.6667 38.6667 116.0000667

Obs-exp)^2/observed 0.2874 2.4167 1.0373 3.74138208

df 2    

p value = 0.154

Since p > alpha(0.1) we accept null hypothesis

The pass numbers are independent of the school of study.

Hence we get the required answer.

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