Lucia and Ronnie love running. Lucia runs 5 and 2/3 miles a day, if Ronnie runs 2/4 of what Lucia runs, how far does Ronnie run a day? *

Answer:

0.25

Step-by-step explanation:

use desmos for this, it's very helpful :)

Answer:

the height is 11 units the base is 12 units and the area is (i think) 84

Answer:

200.06

Step-by-step explanation:

Area= πr2

Divide 16/2 to get radius

A= 3.14 x 8 x 8

A= 3.14 x 64

A= 200.06

Answer:

80000

Step-by-step explanation:

Answer:

12        4          (12, 4)

18        6          (18, 6)

Step-by-step explanation:

On coordinate plane, the "add 6" column values are x-axis values and "add 2" column values are y-axis values.

Answer:

4 and 3/4 inches less for April

and 1 and  1/2 inches  less for March

Step-by-step explanation:

Answer:

B and F are non-statistical questions

Step-by-step explanation:

B is asking how many years until you are 16; this is not statistical because it just a fact. F is pretty much the same because it's just asking a subjective fact-like question.

Statistical questions ask for a collection of varying data. If there is only one data point, it is non-statistical.

Answer:

-.4685

Step-by-step explanation:

[tex]x^y=z\\y=log_zy\\10^{x+2}=34\\x+2=log_{10}34\\x+2=log34\\x+2=1.531478917\\x=-.468521083[/tex]

Answer:

[tex]Mean = \$15[/tex]

[tex]Standard\ Deviation = \$53.85[/tex]

Step-by-step explanation:

Given

See attachment for probability distribution

Required

Determine the mean and the standard deviation

The mean of the distribution is:

[tex]Mean = E(x)[/tex]

and

[tex]E(x) = \sum x * P(x)[/tex]

So, we have:

[tex]Mean = \$500 * 0.01 + \$100 * 0.05 + \$25 * 0.20 + \$0 * 0.74[/tex]

[tex]Mean = \$5 + \$5 + \$5 + \$0[/tex]

[tex]Mean = \$15[/tex]

So:

[tex]E(x) = 15.00[/tex]

The standard deviation of the distribution is:

[tex]S = \sqrt{Var(x)}[/tex]

Where:

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

[tex]E(x^2) = \sum x^2 * P(x)[/tex]

So, we have:

[tex]E(x^2) = 500^2 * 0.01 + 100^2 * 0.05 + 25^2 * 0.20 +0^2 * 0.74[/tex]

[tex]E(x^2) = 2500 + 500 + 125 +0[/tex]

[tex]E(x^2) = 3125[/tex]

So:

[tex]Var(x) = E(x^2) - (E(x))^2[/tex]

Where

[tex]E(x^2) = 3125[/tex]

[tex]E(x) = 15.00[/tex]

[tex]Var(x) = 3125 - 15^2[/tex]

[tex]Var(x) = 3125 - 225[/tex]

[tex]Var(x) = 2900[/tex]

Recall that:

[tex]S =\sqrt{Var(x)[/tex]

[tex]S =\sqrt{2900[/tex]

[tex]S =53.85[/tex]

The time that the  height of 80 feet occur on the interval 0 is 4.662 seconds.

Given:

50 cos (π/15(x-10))+52

Height=80 feet

Time= x second

Hence:

height (h)= 50 cos [pie(x - 10 )/15 ] + 52

80 = 50 cos [pie( x - 10 )/15 ]+ 52

Collect like terms

80 - 52 = 50 cos [ pie( x - 10 )/15 ]

28 = 50 cos [ pie( x - 10 )/15 ]

cos [pie( x - 10 )/15 ] = 28/50

cos [ pie( x - 10 )/15 ] =56

cos [pie( x - 10 )/15 ]= cos ( 56 )

cos [ pie( x - 10 )/15 )]= cos ( 0.3111 pie )

Hence:

pie( x - 10 )/15 = 0.3111

( x - 10 )/15 = 0.3111

x - 10 = 15 × 0.3111

x - 10 = 4.662

x = 10 + 4.662

x = 14.662 seconds

Therefore the correct option is C.

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Answer:

cake 90

Step-by-step explanation:

8×5×2=90

length ×width ×height

Answer: -3

Step-by-step explanation:

Given

Equations of the lines are

[tex]y=-x-4\\3y=cx-18[/tex]

For the system of linear equation [tex]a_1x+b_1y=c_1,a_2x+b_2y=c_2[/tex] has no solution if

[tex]\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\neq \dfrac{c_1}{c_2}[/tex]

Rewrite the equations

[tex]x+y=-4,\ cx-3y=18[/tex]

Insert the values for the no solution condition

[tex]\Rightarrow \dfrac{1}{c}=\dfrac{1}{-3}\\\\\Rightarrow c=-3[/tex]

Therefore, for c=-3, the system of linear equation ha no solution.

Answer:Move the decimal so there is one non-zero digit to the left of the decimal point. The number of decimal places you move will be the exponent on the

10

. If the decimal is being moved to the right, the exponent will be negative. If the decimal is being moved to the left, the exponent will be positive.

3.5×10^−12

Step-by-step explanation:

in simple terms 3.5×10^−12 or 3.5 times 10 to the power of -12

Answer:

Slope of line passing through two points

                           [tex](x_{1}, x_{2} ) \ and \ (y_{1}, y_{2} ) \ is\ \frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex]

Slope of the line passing through (6, 7) and (9, 3)

                               [tex]\frac{3-7}{9-6} = \frac{-4}{3}[/tex]

Answer:

[tex]an=2n+4[/tex]

Step-by-step explanation:

Answer: 15

Step-by-step explanation:

Factors:

75: 1, 3, 5, 15, 25,

15: 1, 3, 5, 15

Write out all the factors of each number and circle the highest factor that both numbers have

Answer:

85 hours

Step-by-step explanation:

Number of hours per day = 13 hours

Number of days = 6

Number of hours worked for 6 days = 6 days × 13 hours

= 78 hours

then he worked 7 hours

Total Number of hours worked = Number of hours worked for 6 days + 7 hours

= 78 hours + 7 hours

= 85 hours

Total Number of hours worked = 85 hours

Answer:a I think

Step-by-step explanation:

Answer:

1. 4-2=2

2.2 10/21

Step-by-step explanation:

Answer:

B.) 90

Step-by-step explanation:

Number line graph with closed circle on 90 and shading to the right. It shows that 90 should be greater or more. So its B.

I hope this helped! I also took the test and got it correct! :)

Answer:

If its set up like

1 2

3 4

5 6

the answer is 1,2,4,6

Step-by-step explanation:

i hope my math on desmos was right xD

The equations of ellipses[tex]2x^{2} +8y^{2} -12x+16y-174=0[/tex], [tex]4x^{2} +y^{2} +16x+4y+4=0[/tex],[tex]3x^{2}+12y^{2} +18x-24y-69=0[/tex] and [tex]x^{2} +9y^{2} -2x+18y-71=0[/tex] having the major axis lengths are twice their minor axis length.

Equations of ellipse

[tex]\frac{(x-h)^{2} }{a^{2} } +\frac{(y-k)^{2} }{b^{2} } =1[/tex]         (for horizontal major axis ,a>b)

[tex]\frac{(x-h)^{2} }{b^{2} } +\frac{(y-k)^{2} }{b^{2} }=1[/tex]           ( for vertical major axis, b>a))

Where, (h, k) is the center of ellipse.

The major axis of an ellipse is its longest diameter(a line that runs through the center and both foci, with ends at the two most widely separated points  on perimeter).

length of major axis = 2a       (where a is the length of semi major axis)

The minor axis of an ellipse is the line that contains the shorter of the two line segments about which the ellipse is symmetrical.

length of minor axis = 2b               (where b is the length of semi minor axis)

According to the given question

we have, the equations  of ellipses

A) [tex](4x^{2} +32x)+(25y^{2} -250y)+589=0[/tex]

[tex]4(x^{2} +8x)+25(y^{2} -10y)+589=0[/tex]

[tex]4(x^{2} +8x+b^{2} )-4b^{2} +25(y^{2} -10y+b^{2} )-25b^{2} +589=0[/tex]

[tex]4(x^{2} +8x+4^{2})-4(4^{2})+25(y^{2} -10y+b^{2} )-25(5^{2} ) +589=0[/tex]

[tex]4(x+4)^{2}+25((y-5)^{2} )-100=0[/tex]

[tex]4(x+4)^{2} +25(y-5)^{2} =100[/tex]

dividing both the sides by 100

[tex]4\frac{(x+4)^{2} }{100} +25\frac{(y-5)^{2} }{100} =1[/tex]

[tex]\frac{(x+4)^{2} }{25} +\frac{(y-5)^{2} }{4} =1[/tex]

[tex]\frac{(x+4)^{2} }{5^{2} } +\frac{((y-5)^{2} }{2^{2} }=1[/tex]

here, h=-4 and k=5

major axis =2a=2×5=10

minor axis=2b=2×2=4

⇒ the length of major axis is not twice the length of minor axis.

Similarly, we will do for the other equations

B).

[tex]2x^{2} +8y^{2} -12x+16y-174=0\\\frac{(x-3)^{2} }{10^{2} } +\frac{(y+1)^{2} }{5^{2} } =1[/tex]

here, h=3 and k=-1

major axis:2a=2×10=20

minor axis:2b=2×5=10

⇒ length of major axis is twice the length of minor axis.

C).

[tex]4x^{2} +y^{2} +16x+4y+4=0[/tex]

[tex]\frac{(x+2)^{2} }{2^{2} } +\frac{(y+2)^{2} }{4^{2} } =1[/tex]

here, h=-2 and k= -2

major axis: 2b=2×4=8

minor axis: 2a= 2×2=4

⇒ the length of the major axis is twice of the length of minor axis.

D).

[tex]x^{2} +4y^{2} +6x-8y-23=0[/tex]

[tex]\frac{(x+3)^{2} }{6^{2} } +\frac{(y-1)^{2} }{3^{2} } =1[/tex]

here, h=-3 and k=1

major axis: 2a=2×6=12

minor axis: 2b= 2×3=6

⇒ the length of major axis is twice of the length of minor axis.

E).

[tex]16x^{2} +y^{2} -64x+8y+16=0[/tex]

⇒[tex]\frac{(x-2)^{2} }{2^{2} } +\frac{(y+4)^{2} }{2^{2}} =1[/tex]

here, h=2 and k=-4

major axis: 2a=  4

minor axis :2b=4

⇒ the length of major axis is not the twice of minor axis.

F)

[tex]x^{2} +9y^{2} -2x+18y-71=0[/tex]

⇒[tex]\frac{(x-1)^{2} }{9^{2} } + \frac{(y+1)^{2} }{3^{2} } =1[/tex]

here, h=1,  and k=-1

major axis: 2a= 18

minor axis: 2b = 9

⇒ the length of major axis is twice to the length of minor axis.

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The answer is (8, 7)

Answer:

128

Step-by-step explanation:

In math, volume can be defined as the 3-dimensional space enclosed by a boundary or occupied by an object.

Answer:

256π cm³

Step-by-step explanation:

πr²·h=Volume

π·(4)²·16=π·16·16=256π cm³

The minimum amount of extra cardboard needed to construct a new box is : 84in².

First step

Surface area=2(16) (5) in²+ 2(20in) (5in)  + 2(16in) (20in)

Surface area=1000in²

Second step

Surface area if the length increase by 2 inches

Surface area=2(16) (5) + 2(20+2) (5in)  + 2(16in) (20+2)

Surface area=1084in²

Third step

Surface area=1084in²-1000in²

Surface area=84in²

Therefore the minimum amount of extra cardboard needed to construct a new box is : 84in².

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Answer:

y intercept is (0,4)

Step-by-step explanation:

Answer:

It is C.

III is saying that the two functions are inverse functions. If two functions, f(x) and g(x) are inverse, then f(g(x)) = x and g(f(x)) = x. Therefore, we see that if III is true, then I and II should also be true. Now, all we have to prove is that f(x) and g(x) are inverse functions. As we said before, if two functions are inverse, then f(g(x)) = x and g(f(x)) = x.

f(g(x)) = 3([tex]\sqrt[3]{\frac{x-2}{3} }[/tex])^3 + 2

f(g(x)) = 3[(x-2)/3]+2

f(g(x)) = x-2 + 2

f(g(x)) = x

Therefore, we have proved that f(g(x)) = x, and so f(x) and g(x) are inverse functions, and so all of I, II, and III are true. Thus, the answer is C.

fyi, we didn't have to do g(f(x)) because if f(g(x)) = x, then so will g(f(x)).

Answer:

take another pic I can't see because of the glare