Answer: I think it is D
Explanation:
What is generally true of atoms with relatively large atomic radii?
Answer:
Large atoms hold their electrons very tightly. ... Large atoms tend to be found on the right side of their period on the periodic table.
Explanation:
Answer:
Explanation:
Large atoms tend to have a low ionization energy and a low electron affinity.
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Question 1
1 pts
Where did most of the heat of the Earth come from at its formation?
O Seismic waves
O Radioactive decay
O Planetesimals crashing into each other
Peridotite xenoliths
Question 2
1 pts
Answer:
radioactive decay
Explanation:
a study reveals that only about half of our planets internal heat stems from natural radioactivity the rest is primordial heat left over from when earth first coalesced from a hot ball of gas dust and other material
What is the atomic number of this atom?
6
8
9
16
The atomic number of this atom : 8
Further explanationGiven
Atomic model (attached)
Required
The atomic number
Solution
To determine the atomic number of an element, we can look at the number of electrons or the number of protons, because
atomic number = number of protons = number of electrons in neutral atoms
While the mass number is the number of neutrons + the number of protons located in the atomic nucleus
The charge of each of these atomic sub particles:
electron: charge -1proton: charge +1neutron: not charged / 0If we look at this atomic model, there are 8 electrons in the shell, consisting of 2 electrons in the first shell and 6 electrons in the second shell (which can also be called valence electrons)
Whereas in the atomic nucleus there are 8 protons and 10 neutrons
Answer:8
Explanation:
what is the dilution factor if you add a 0.1ml aliquot of a specimen to 9.9 dilutent
The dilution factor : 100
Further explanationThe dilution factor(DF) : ratio of concentration of stock solution and diluted solution or ratio of the volume of final solution to the initial volume from stock solution
From equation of dilution :
M₁V₁=M₂V₂
[tex]\tt DF=\dfrac{M_1}{M_2}=\dfrac{V_2}{V_1}[/tex]
Volume of aliquot = 0.1 ml
Volume of diluent = 9.9 ml
So final volume :
[tex]\tt V_f(final~volume)=volume~aliquot+volume~diluent\\\\V_f=0.1+9.9=10~ml[/tex]
The dilution factor (DF) :
[tex]\tt D_f=\dfrac{V_f}{V_i}\\\\D_f=\dfrac{10}{0.1}=100[/tex]
Based on the chemical equation, use the drop-down menu to choose the coefficients that will balance the chemical equation:
(
)O2 → (
)O3
Answer:
3
2
Explanation:
3O2 => 2O3
the equation is balancing
if you aint stephanie dont anwer
Answer:
wsp
Explanation:
Plz help
Plz and thank u
Write out the electron configurations of the ions below and determine which one is listed with an incorrect charge. (the numbers and charges written after the elemental symbol should be understood as superscripts)
A. I-
B.O2+
C. Al3+
D. Mg2+
E. none of the above
Answer:
I think B. O2+
Explanation:
Answer:
B
it must be O2- not O2+, because it's an anion not a cation.
how dose dissolving sugar in water show that matter is made up of particles
Answer:
When sugar dissolves, the sugar particles separate from each other and mix with the water particles. When the sugar particles separate, the smaller water particles fit into the spaces between the larger sugar particles. The water and sugar particles are attracted to each other, so they move closer together when they mix.
Explanation:
: )
Will give brainliest
Answer:
c. both gases have the same number of molecules
brainliest?
I am a nonmetal.I am in the Oxygen family and in row 3.I have 6 valence electrons.I am yellow and have a stinky smell.Who am i
Answer:
sulfur
Explanation:
In oxygen family sulfur has yellow color and also having stinky smell. Thus given statements are about sulfur.
It is present in oxygen family.
It has six valance electrons.
Its atomic number is 16.
Its atomic weight is 32 amu.
The electronic configuration of sulfur is given below,
S₁₆ = 1s² 2s² 2p⁶ 3s² 3p⁴
We can see the valance shell is third shell and it have six electrons thus sulfur have six valance electrons. (3s² 3p⁴ )
Sulfur is used in vulcanisation process.
It is used in bleach and also as a preservative for many food.
it is used to making gun powder.
True or False: All metals have high melting points.
Answer:
True. All metals have a melting point when it reaches a certain degree of temperature
Explanation:
1. Which statement is true about the relationship between chromosomes, genes and
traits?
A. Genes are found within traits, and their codes are used to make chromosomes.
B. Chromosomes are found within genes, and their codes are used to make traits.
C. Genes are found within chromosomes, and their codes are used to make traits.
D. One gene is found on every chromosome and they are used to make traits.
Answer:
the answer is C.Explanation:
Which defines the average inetic energy of a system's particles?
O density
O pressure
O temperature
O volume
HELP FAST! PLEASE
This is due in 4 hrs!!!!! Ahhhh
The amplitude is greater for both
The frequency is for wave two
Explanation:
Please Help!
Your car has 1.95 gallons of gasoline (octane, d = 0.6916 g/mL), which reacts with oxygen
according to the balanced reaction below. Your car uses the energy produced by this reaction
at a rate of 115 kJ per second while traveling at a speed of 65 miles per hour. Calculate the
distance (in miles) the car can travel using this amount of octane.
2 C8H18(g) + 25 O2(g) -----> 16 CO2(g) + 18 H2O(g) ΔHrxn = -10,900 kJ
Answer:
38.3 miles
Explanation:
First, we convert 1.95 gallons to mililiters:
1.95 gallons * [tex]\frac{3.785 L}{1gallon}*\frac{1000mL}{1 L}[/tex]= 7380.75 mLThen we calculate how many grams of octane are available for the reaction, using its density:
0.6916 g/mL * 7380.75 mL = 5104.53 g C₈H₁₈Now we convert octane grams into octane moles, using its molar mass:
5104.53 g C₈H₁₈ ÷ 114 g/mol = 44.78 mol C₈H₁₈Then we calculate how many kJ are produced from the combustion of 44.78 mol C₈H₁₈, if 2 moles produce 10900 kJ:
44.78 mol * 10900 kJ / 2 mol = 244032 kJWe calculate how many seconds is the car available to keep going, if it spends 115 kJ per second:
244032 kJ * 1 s / 115 kJ = 2122.02 sWe convert seconds to hours:
2122.02 / 3600 = 0.59 hoursFinally we calculate the distance:
65 mi/hour * 0.59 hour = 38.3 miYou want to measure the volume of a gold bracelet. For this purpose, a specimen with 20 mL of water is available; when inserting the bracelet, the water level rises to 25 mL. If the density of gold is 19300 Kg/m3. What will be the mass of the bracelet?
Answer:
volume of bracelet is 5cm3
mass is 0.0965Kg
Explanation:
1ml = 1cm3
1m3 = 1000000cm3
0.000005m3
Mass = volume*density
19300 Kg/m3 * 0.000005m3 = 0.0965Kg
Please help, it’s much appreciated
If the hydrogen ion concentration,
[H+], in a solution is 2.65 x 10-2 M,
what is [OH-]?
Answer: acidic
Explanation:
Answer:
3.77 x 10^-13 M
Explanation:
what does the phrase sea of electrons describe?? please help
Answer: Metallic Bonding.In metallic bonds, the valence electrons from the s and p orbitals of the interacting metal atoms delocalize. That is to say, instead of orbiting their respective metal atoms, they form a “sea” of electrons that surrounds the positively charged atomic nuclei of the interacting metal ions.
Explanation:
it was believed that earth was a stationary object at the center of the universe all other objects in space without to go around earth which of these is a criticism of this idea
Answer: is that a question or
Explanation:
Answer:
its c
Explanation:
How many grams are in 2.3 x 1024 formula units of KNO3?
390 g KNO₃
General Formulas and Concepts:ChemistryAtomic Structure
Reading a Periodic TableUsing Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.MathPre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right Explanation:Step 1: Define
2.3 × 10²⁴ formula units KNO₃
Step 2: Identify Conversions
Avogadro's Number
Molar Mass of K - 39.10 g/mol
Molar Mass of N - 14.01 g/mol
Molar Mass of O - 16.00 g.mol
Molar Mass of KNO₃ - 39.10 + 14.01 + 3(16.00) = 101.11 g/mol
Step 3: Convert
[tex]2.3 \cdot 10^{24} \ formula \ units \ KNO_3(\frac{1 \ mol \ KNO_3}{6.022 \cdot 10^{23} \ formula \ units \ KNO_3} )(\frac{101.11 \ g \ KNO_3}{1 \ mol \ KNO_3} )[/tex] = 386.172 g KNO₃
Step 4: Check
We are given 2 sig figs. Follow sig fig rules and round.
386.172 g KNO₃ ≈ 390 g KNO₃
ASAP PLZ HELP I WILL MARK BRAINLIEST Based on the diagram, what can you conclude about the pole of the magnet? O It is a south pole because the field lines spread out from this end. O It is a north pole because the field lines spread out from this end, O It is a south pole because the field lines enter the magnet at this end. O It is a north pole because the field lines enter the magnet at this end.
Answer:C
Explanation:I took the test
Answer:
It is a south pole because the field lines enter the magnet at this end.
Explanation:
If I Gave A Pig Bacon Would He Eat It ?
6b
Which of the following is a starting compound during
cellular respiration?
Answer: Oxygen and glucose.
Explanation:
Oxygen and glucose are both reactants in the process of cellular respiration. The main product of cellular respiration is ATP; waste products include carbon dioxide and water.Jun 1, 2020
How many moles of copper are in 6,000,000 atoms of copper?
Answer: There will be 9.9632 × 10⁻¹⁸ moles of Copper in 6,000,000 atoms of Copper.
How is continental crust different from oceanic crust?
A: Oceanic crust is thicker and more dense.
B: Oceanic crust is thinner and more likely to sink.
C: Continental crust is thicker and more likely to sink.
D: Continental crust is more dense and lighter.
Answer:
b
Explanation:
google lol ur welcome
B: Oceanic crust is thinner and more likely to sink.
what is the balanced equation for naphthalene and sulphur?
napthalene: C10H8 sulphur: S02
Explanation:
C10H8
Which is one advantage of using a reflecting telescope instead of a refracting telescope?
Reflecting telescopes are less expensive.
Reflecting telescopes produce clearer images.
Reflecting telescopes require only concave lenses.
Reflecting telescopes usually take up less space.
Answer:
Reflecting telescopes take up less space, is the suitable answer.
Answer:
B, or 2: Reflecting telescopes produce clearer images.
Explanation:
Took the test
A mixture is prepared using 27.00 mL of a 0.0758 M weak base (pKa=4.594) , 27.00 mL of a 0.0553 M weak acid (pKa=3.235) and 1.00 mL of 1.25×10−4 M HIn and then diluting to 100.0 mL, where HIn is the protonated indicator. The absorbance measured at 550 nm in a 5.000 cm cell was 0.1102 . The molar absorptivity (????) values for HIn and its deprotonated form In− at 550 nm are 2.26×104 M−1cm−1 and 1.53×104 M−1cm−1 , respectively. What is the pH of the solution?
Answer:
pH = 4.164
Explanation:
The first process is to find the initial moles for the base (B) & the acid (HA)
i.e.
[tex]= \dfrac{27 mL \times 0.0758 \ moles \ \ of \ B}{1000 \ mL}[/tex]
[tex]=0.0020466[/tex]
[tex]\simeq 2.047\times 10^{-3} \ moles \ of \ B[/tex]
[tex]= \dfrac{27 mL \times 0.0553 \ moles \ \ of \ HA}{1000 \ mL}[/tex]
[tex]=0.0014931[/tex]
[tex]\simeq 1.493\times 10^{-3} \ moles \ of \ HA[/tex]
The acid with base reaction is expressed as;
HA + B → A⁻ + HB⁺
to 1.493 × 10⁻³ 2.047 × 10⁻³ - -
- 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³ 1.493 × 10⁻³
0 5.54 × 10⁻⁴ 1.493 × 10⁻³ 1.493 × 10⁻³
From observation; both the acid & base weak
Given that:
The pKa for base = 4.594
The pKa for acid = 3.235
Recall that;
pKa = -log Ka
So; Ka = [tex]\mathbf{10^{-Ka}}[/tex]
By applying this:
For Base; Ka = [tex]10^{-4.594}[/tex] = 2.5468 × 10⁻⁵
For Acid: Ka = [tex]10^{ -3.235}[/tex] = 5.821 × 10⁻⁴
After the reaction; we have the base with its conjugate acid & conjugate base of acid; Thus, since the conjugate acid of the base possesses a higher value of K, it is likely it would be the one to define the pH of the solution.
By analyzing the system, we have:
HB⁺ + H₂O ↔ B + H₃O⁺
[tex]\dfrac{1.493\times 10^{-3}}{0.1 \ L}[/tex] [tex]\dfrac{5.54\times 10^{-4}}{0.1 \ L}[/tex]
to 0.01493 M 0.00554 M
- x x x
0.01493 - x 0.00554 - x x
Thus;
[tex]2.5468 \times 10^{-5} = \dfrac{(0.00554 -x)\times x}{(0.01493-x)}[/tex]
Using the common ion effect;
0.00554 - x [tex]\simeq[/tex] 0.00554 &
0.01493 - x [tex]\simeq[/tex] 0.01493
∴
[tex]x = \dfrac{2.5468 \times 10^{-5} \times 0.01493}{0.00554}[/tex]
x = [H₃O⁺] = 6.8635 × 10⁻⁵
∴
pH = -log(6.8635 × 10⁻⁵)
pH = 4.164
Find the volume of
this object.
5 cm
5 cm
5 cm
A
15 cm3
B
125 cm3
C
30 cm3
Answer: B. [tex]125\ cm^3[/tex].
The volume of the given object = [tex]125\ cm^3[/tex]
Explanation:
Given : Dimensions of an object : 5 cm x 5 cm x 5 cm [ it is a cube with all equal sides]
Formula to find the volume of a cube = [tex](side)^3[/tex]
[tex]=5^3\ cm^3=125\ cm^3[/tex]
Hence, the volume of the given object = [tex]125\ cm^3[/tex]
Therefore , the correct option is B. [tex]125\ cm^3[/tex].