Answer:
C ( 11 , -11 )
Step-by-step explanation:
Solution:-
We are given two points in the cartesian coordinate system as:
A ( 3 , -5 ) B ( 13 , -15 )
The point C lies on the line segment from A to B. The ratio of segment given is:
AC / AB = 4 / 5
To solve such type of problems. We will use vector equation of line AC.
To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:
d = OB - OA
d = < 13 , -15 > - < 3 , -5 >
d = < 10 , -10 >
The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:
< x , y > = OA + s*d
< x , y > = < 3, -5 > + s* < 10 , -10 >
The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.
So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:
< x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >
< x , y > = < 3 , -5 > + < 8 , -8 >
< x , y > = < 11 , -11 > ... Answer
Determine what type of study is described. Explain. Researchers wanted to determine whether there was an association between high blood pressure and the suppression of emotions. The researchers looked at 1800 adults enrolled in a Health Initiative Observational Study. Each person was interviewed and asked about their response to emotions. In particular they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10. Each person's blood pressure was also measured. The researchers analyzed the results to determine whether there was an association between high blood pressure and the suppression of emotions.
Answer:
Experimental Study
Step-by-step explanation:
In an experimental study, the researchers involve always produce and intervention (in this case they were asked whether their tendency was to express or to hold in anger and other emotions. The degree of suppression of emotions was rated on a scale of 1 to 10) and study the effects taking measurements.
These studies are usually randomized ie subjects are group by chance.
As opposed to observation studies, where the researchers only measures what was observed, seen or hear without any intervention on their parts.
A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.49.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)
Answer:
(a) matched pair design
(b) n = 30
(c) Reject the null hypothesis.
Step-by-step explanation:
The complete question is:
A researcher records the amount of time (in minutes) that parent child pairs spend on social networking sites to test whether they show any generational differences. From the following findings in APA format, interpret these results by stating the research design used (repeated measures or matched pairs), the sample size, the decision, and the effect size. Parents spend significantly less time on social networking sites compared their children (MD = -42 minutes),t(29)=4.021,p<.05,d=0.49.(a) What research design was used? (Repeated measures or matched pairs?)(b) What is the sample size? (n = ?)(c) What is the decision? (Retain or reject the null?)
Solution:
(a)
It s provided that the researcher records the amount of time (in minutes) that parent-child pairs spend on social networking sites.
This implies that the data collected is in the form of paired data.
Thus, the research design that was used was matched pair design.
(b)
Consider the t-statistics provided:
t (29) = 4.021
The number 29 in the bracket is the degrees of freedom.
The degrees of freedom for a matched pair design is,
df = n - 1
Compute the value of n as follows:
df = n - 1
29 = n - 1
n = 29 + 1
n = 30
Thus, the sample size is n = 30.
(c)
The p-value of the test is:
p < 0.05
The p-value of the test is less than the 5% significance level.
This implies that the null hypothesis will be rejected at 5% significance level.
Find the value of x and the value of y. A.x = 15, y = 10 B.x = 20, y = 50 C.x = 50, y = 10 D.x = 50, y = 20
Answer:
X = 50
Step-by-step explanation:
(5x - 100) + (x - 20) = 180 (sum of angle on a straight line is = 180)
5x + x -100 -120 = 180
6x - 120 = 180
6x = 180 + 120
6x = 300
x = 300/6
x = 50
For y
3y + y + 140 = 180
4y = 180 -140
4y = 40
y = 40/4
y = 10
Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145 a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
The question is incomplete! Complete question along with answer and step by step explanation is provided below.
Question:
Professor Sanchez has been teaching Principles of Economics for over 25 years. He uses the following scale for grading. Grade Numerical Score Probability A 4 0.090 B 3 0.240 C 2 0.360 D 1 0.165 F 0 0.145
a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)
c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)
Answer:
a. Cumulative Probability Distribution
Grade P(X ≤ x)
F 0.145
D 0.310
C 0.670
B 0.910
A 1
b. P(at least B) = 0.330
c. P(pass) = 0.855
Step-by-step explanation:
Professor Sanchez has been teaching Principles of Economics for over 25 years.
He uses the following scale for grading.
Grade Numerical Score Probability
A 4 0.090
B 3 0.240
C 2 0.360
D 1 0.165
F 0 0.145
a. Convert the above probability distribution to a cumulative probability distribution. (Round your answers to 3 decimal places.)
The cumulative probability distribution is given by
Grade = F
P(X ≤ x) = 0.145
Grade = D
P(X ≤ x) = 0.145 + 0.165 = 0.310
Grade = C
P(X ≤ x) = 0.145 + 0.165 + 0.360 = 0.670
Grade = B
P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 = 0.910
Grade = A
P(X ≤ x) = 0.145 + 0.165 + 0.360 + 0.240 + 0.090 = 1
Cumulative Probability Distribution
Grade P(X ≤ x)
F 0.145
D 0.310
C 0.670
B 0.910
A 1
b. What is the probability of earning at least a B in Professor Sanchez’s course? (Round your answer to 3 decimal places.)
At least B means equal to B or greater than B grade.
P(at least B) = P(B) + P(A)
P(at least B) = 0.240 + 0.090
P(at least B) = 0.330
c. What is the probability of passing Professor Sanchez’s course? (Round your answer to 3 decimal places.)
Passing the course means getting a grade of A, B, C or D
P(pass) = P(A) + P(B) + P(C) + P(D)
P(pass) = 0.090 + 0.240 + 0.360 + 0.165
P(pass) = 0.855
Alternatively,
P(pass) = 1 - P(F)
P(pass) = 1 - 0.145
P(pass) = 0.855
Describe the transformations.
PLSSS PEOPLE I NEED HELP
Answer:C
Step-by-step explanation:
The vertical line test
There are 7 students in a class: 5 boys and 2 girls.
If the teacher picks a group of 4 at random, what is the probability that everyone in the group is a boy?
Answer:
4/7
Step-by-step explanation:
5+2=7
7 children
4 boys Out of 7 children
Answer:1/7
Step-by-step explanation:
Khan academy
The number of degrees of freedom for the appropriate chi-square distribution in a test of independence is a. k – 1. b. A chi-square distribution is not used. c. number of rows minus 1 times number of columns minus 1. d. n – 1.
Answer:
Option C
Step-by-step explanation:
The chi square test of independence is used to determine if there is a significant association between two categorical variables from a population.
It tests the claim that the row and column variables are independent of each other.
The degrees of freedom for the chi-square are calculated using the following formula: df = (r-1) (c-1) where r is the number of rows and c is the number of columns.
Express it in slope-intercept form.
Answer:y=3/2x-3
Step-by-step explanation: the slope of the graph is (y2-y1)/(x2-x1)
If we take points (0,-3) (2,0) the slope would be (0--3)/(2-0) = 3/2
And the y-intercept of the slope is -3
What does the denominator of this rational expression represent? Jessica is organizing a guided tour of the rain forest. The average profit per person that the touring company makes is given by the rational expression , where is the number of people going on the tour.
Complete Question
Jessica is organizing a guided tour of the rain forest. The average profit per person that the touring company makes is given by the rational expression 18x+35/x, where x is the number of people going on the tour. What does the denominator of this rational expression represents?
Answer:
Number of people going on the tour
Step-by-step explanation:
Given that the average profit per person [tex]=\dfrac{18x+35}{x}[/tex]
[tex]\text{Average}=\dfrac{\text{Sum of Total Items}}{\text{Number of Items}}[/tex]
Therefore:
[tex]\text{Average Profit}=\dfrac{(18x+35)\text{ profit}}{x\text{ persons}}[/tex]
The denominator, x represents the number of people going on the tour.
Answer:
btw 35/x represents epresents a fixed cost, like a cover charge for the tour, that is not affected by the number of people attending the tour. So, the quotient 35/x represents the profit that the tour company makes from the cover charge per person.
Step-by-step explanation:
PLATO
I NEED HELP PLEASE, THANKS! :)
Answer:
68
Step-by-step explanation:
The number of chips tested is the integral of the rate over the specified time interval: t = 2 to 6.
[tex]\displaysyle n=\int_2^6{-3t^2+16t+5}\,dt=\left.-3\dfrac{t^3}{3}+16\dfrac{t^2}{2}+5t\right|_2^6\\\\=-(6^3-2^3) +8(6^2-2^2)+5(6-2)=-(216-8)+8(32) +5(4)\\\\=-208+256+20=\boxed{68}[/tex]
The technician can test 68 chips in that time period.
i have a question what is 2 plus 2 i will really live it if you respond
Hi there! Hopefully this helps!
------------------------------------------------------------------------------------------------
2 + 2 = 4.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
You can simply find this answer by getting two of your fingers on your left hand, getting two MORE fingers of your right hand, and counting them. You will end up with 4.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
You could multiply 2 two times, like this:
2 x 2 = 4.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
You could split the numbers into parts and add them back together, like this:
2 = 1 + 1.
+
2 = 1 + 1.
=
1 + 1 + 1 + 1 = 4.
Answer:
4
Step-by-step explanation:
problem is if you dont have a fingers... you cant physically count 2 + 2
anyway... just add them using your brain = 2 + 2 makes 4
Among 20 golden hamster litters recorded, there was a sample mean of =7.72 baby hamsters, with a sample standard deviation of s=2.5 hamsters per liter. Create a 98% confidence interval for the mean number of baby hamsters per liter.
Answer:
[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]
[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]
Step-by-step explanation:
For this case we have the following info given:
[tex]\bar X= 7.72[/tex] represent the sample mean
[tex]s= 2.5[/tex] represent the sample deviation
[tex] n=20[/tex] represent the sample size
The confidence interval is given by:
[tex] \bar X \pm t_{\alpha/2} \frac{s}{\sqrt{n}}[/tex]
The confidence interval is 98% and the significance level is [tex]\alpha=0.02[/tex] the degrees of freedom are given by:
[tex] df= n-1 = 20-1=19[/tex]
And the critical value would be:
[tex] t_{\alpha/2}= 2.539[/tex]
And replacing we got:
[tex] 7.72 -2.539 \frac{2.5}{\sqrt{20}} =6.30[/tex]
[tex] 7.72 +2.539 \frac{2.5}{\sqrt{20}} =9.14[/tex]
The 98% confidence interval is between 6.42 hamsters per liter to 9.02 hamsters per liter
Mean (μ) = 7.72, standard deviation (σ) = 2.5, sample size (n) = 20, Confidence (C) = 98% = 0.98
α = 1 - C = 0.02
α/2 = 0.01
The z score of α/2 is the same as the z score of 0.49 (0.5 - 0.01) which is equal to 2.326.
The margin of error E is:
[tex]E = Z_\frac{\alpha }{2} *\frac{\sigma}{\sqrt{n} } \\\\E=2.326*\frac{2.5}{\sqrt{20} } =1.3[/tex]
The confidence interval = (μ ± E) = (7.72 ± 1.3) = (6.42, 9.02)
Hence the 98% confidence interval is between 6.42 hamsters per liter to 9.02 hamsters per liter
Find out more at: https://brainly.com/question/24131141
Is the area of this shape approximately 24 cm* ? If not give the correct area.
311
101
True
False
Answer:
19.2 feet square
Step-by-step explanation:
We khow that the area of an octagon is :
A= 1/2 * h * P where h is the apothem and p the perimeter
A= (1/2)*1.6*(3*8) = 19.2 feet square[10 points] A manufacturer wants to design an open box having a square base and a surface area of 108 square inches. What dimensions will produce a box with maximum volume?
Answer:
6 inches square by 3 inches high
Step-by-step explanation:
For a given surface area, the volume of an open-top box is maximized when it has the shape of half a cube. If the area were than of the whole cube, it would be 216 in² = 6×36 in².
That is, the bottom is 6 inches square, and the sides are 3 inches high.
_____
Let x and h represent the base edge length and box height, respectively. Then we have ...
x² +4xh = 108 . . . . box surface area
Solving for height, we get ...
h = (108 -x²)/(4x) = 27/x -x/4
The volume is the product of base area and height, so is ...
V = x²h = x²(27/x -x/4) = 27x -x³/4
We want to maximize the volume, so we want to set its derivative to zero.
dV/dx = 0 = 27 -(3/4)x²
x² = (4/3)(27) = 36
x = 6
h = 108/x² = 3
The box is 6 inches square and 3 inches high.
_____
Comment on maximum volume, minimum area
In the general case of an open-top box, the volume is maximized when the cost of the bottom and the cost of each pair of opposite sides is the same. Here, the "cost" is simply the area, so the area of the bottom is 1/3 the total area, 36 in².
If the box has a closed top, then each pair of opposite sides will have the same cost for a maximum-volume box. If costs are uniform, the box is a cube.
Evaluate. Write your answer as a fraction or whole number without exponents. 7^–1 =
Answer:
1/7 = 0.142857... repeating
Step-by-step explanation:
7^(-1) = 1/(7^1) =1/7 = 0.142857... repeating
Answer:
[tex] \frac{1}{7} [/tex]Solution,
[tex] {7}^{ - 1} \\ = \frac{1}{ {7}^{1} } \\ = \frac{1}{7} [/tex]
Laws of indices:Law of zero index:[tex] {x}^{0} = 1[/tex]
Product law of indices:[tex] {x}^{m} \times {x}^{n} = {x}^{m + n} [/tex]
( powers are added in multiplication of same base)
Power law of indices:[tex] {( {x}^{m} )}^{n} = {x}^{m \times n} [/tex]
law of negative index:[tex] {x}^{ - m} = \frac{1}{ {x}^{m} } [/tex]
Root law of indices:[tex] {x}^{ \frac{p}{q} } = \sqrt[q]{ {x}^{p} } [/tex]
[tex]( \frac{x}{y} ) ^{n} = \frac{ {x}^{n} }{ {y}^{n} } [/tex] [tex] {(xy)}^{m} = {x}^{m} {y}^{m} [/tex][tex] \sqrt[n]{x} = x \frac{1}{n} [/tex]Hope this helps ....
Good luck on your assignment...
A common assumption in modeling drug assimilation is that the blood volume in a person is a single compartment that behaves like a stirred tank. Suppose that the blood volume is a four-liter tank that initially has a zero concentration of a particular drug. At time t 0, an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500 mg/L. The inflow rate is 0.06 L/min. Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.
a) Write an initial value problem that models the mass of the drug in the blood for t20.
b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.
c) What is the steady-state mass of the drug in the blood?
d) After how many minutes does the drug mass reach 90% of its stead-state level?
Answer:
a) [tex]\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}[/tex]
b) [tex]\mathbf{x = 2000 - 2000e^{-0.015t}}[/tex]
c) the steady state mass of the drug is 2000 mg
d) t ≅ 153.51 minutes
Step-by-step explanation:
From the given information;
At time t= 0
an intravenous line is inserted into a vein (into the tank) that carries a drug solution with a concentration of 500
The inflow rate is 0.06 L/min.
Assume the drug is quickly mixed thoroughly in the blood and that the volume of blood remains constant.
The objective of the question is to calculate the following :
a) Write an initial value problem that models the mass of the drug in the blood for t ≥ 0.
From above information given :
[tex]Rate _{(in)}= 500 \ mg/L \times 0.06 \ L/min = 30 mg/min[/tex]
[tex]Rate _{(out)}=\dfrac{x}{4} \ mg/L \times 0.06 \ L/min = 0.015x \ mg/min[/tex]
Therefore;
[tex]\dfrac{dx}{dt} = Rate_{(in)} - Rate_{(out)}[/tex]
with respect to x(0) = 0
[tex]\mathbf{\dfrac{dx}{dt} = 30 - 0.015 x}[/tex]
b) Solve the initial value problem and graph both the mass of the drug and the concentration of the drug.
[tex]\dfrac{dx}{dt} = -0.015(x - 2000)[/tex]
[tex]\dfrac{dx}{(x - 2000)} = -0.015 \times dt[/tex]
By Using Integration Method:
[tex]ln(x - 2000) = -0.015t + C[/tex]
[tex]x -2000 = Ce^{(-0.015t)[/tex]
[tex]x = 2000 + Ce^{(-0.015t)}[/tex]
However; if x(0) = 0 ;
Then
C = -2000
Therefore
[tex]\mathbf{x = 2000 - 2000e^{-0.015t}}[/tex]
c) What is the steady-state mass of the drug in the blood?
the steady-state mass of the drug in the blood when t = infinity
[tex]\mathbf{x = 2000 - 2000e^{-0.015 \times \infty }}[/tex]
x = 2000 - 0
x = 2000
Thus; the steady state mass of the drug is 2000 mg
d) After how many minutes does the drug mass reach 90% of its stead-state level?
After 90% of its steady state level; the mas of the drug is 90% × 2000
= 0.9 × 2000
= 1800
Hence;
[tex]\mathbf{1800 = 2000 - 2000e^{(-0.015t)}}[/tex]
[tex]0.1 = e^{(-0.015t)[/tex]
[tex]ln(0.1) = -0.015t[/tex]
[tex]t = -\dfrac{In(0.1)}{0.015}[/tex]
t = 153.5056729
t ≅ 153.51 minutes
Help me please! I need an answer!
Answer: [tex]\bold{\dfrac{b_1}{b_2}=\dfrac{3}{2}}[/tex]
Step-by-step explanation:
Inversely proportional means a x b = k --> b = k/a
Given that a₁ = 2 --> b₁ = k/2
Given that a₂ = 3 --> b₂ = k/3
[tex]\dfrac{b_1}{b_2}=\dfrac{\frac{k}{2}}{\frac{k}{3}}=\large\boxed{\dfrac{3}{2}}[/tex]
PLEASE HELP!!! You want to distribute 7 candies to 4 kids. If every kid must receive at least one candy, in how many ways can you do this? (it's not 15)
Answer: 20
Step-by-step explanation:
I guess that we want to distribute all the 7 candies between 4 kids
We have 3 options:
first 3, 2, 1 and 1. (the number of candies that each kid gets)
The possible permutations in this case:
if we leave the 3 fixed, the ones do are equal, so the permutations are only given by the change in the kid that gets 2 candies, we have 3 permutations for this.
And for the fixed 3, we have 4 possible places where we can fix it, so the total number of combinations is:
c = 3*4 = 12.
and the second option is (2, 2, 2, 1)
Here the only change is the kid that gets only one candy, we have 4 options in this case:
c = 4.
the third option is (4, 1, 1, 1)
Here the only change is the kid that gets 4 candies, and we have 4 options for this, so we have 4 combinations:
c = 4.
Then the total number of possible combinations is:
C = 12 + 4 + 4 = 20
Identifico el nombre de la propiedad a la que hacen referencia las siguientes expresiones:
Hacen falta las expresiones para poder responder a tu pregunta, estuve investigando y adjuntaré una imagen que hace referencia a tus preguntas, espero no equivocarme.
Si este es el caso, son 9 expresiones y el nombre de cada propiedad es:
1. Inverso aditivo (Sumar un número por su opuesto el resultado es 0)
2. Ley conmutativa (El orden de los factores no altera el producto)
3. Ley asociativa (Agrupar los términos sin alterar el resultado)
4. Ley de la identidad, (Sumar un número con 0 se obtiene el mismo número)
5. Ley distributiva (La misma respuesta cuando multiplicas un conjunto de números por otro número que cuando se hace cada multiplicación por separado)
6. Ley distributiva
7. Ley distributiva
8. Ley asociativa
9. Ley conmutativa
Estimate the area under the graph of f(x)=2x^2-12x+22 over the interval [0,2] using four approximating rectangles and right endpoints.
Answer:
The right Riemann sum is 21.5.
The left Riemann sum is 29.5.
Step-by-step explanation:
The right Riemann sum (also known as the right endpoint approximation) uses the right endpoints of a sub-interval:
[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].
To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using right endpoints you must:
We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].
Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]
Now, we just evaluate the function at the right endpoints:
[tex]f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5\\\\f\left(x_{4}\right)=f(b)=f\left(2\right)=6[/tex]
Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\frac{1}{2}(16.5+12+8.5+6)=21.5[/tex]
The left Riemann sum (also known as the left endpoint approximation) uses the left endpoints of a sub-interval:
[tex]\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_0)+f(x_1)+2f(x_2)+...+f(x_{n-2})+f(x_{n-1})\right)[/tex], where [tex]\Delta{x}=\frac{b-a}{n}[/tex].
To find the Riemann sum for [tex]\int_{0}^{2}\left(2 x^{2} - 12 x + 22\right)\ dx[/tex] with 4 rectangles, using left endpoints you must:
We have that a = 0, b = 2, n = 4. Therefore, [tex]\Delta{x}=\frac{2-0}{4}=\frac{1}{2}[/tex].
Divide the interval [0,2] into n = 4 sub-intervals of length [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\left[0, \frac{1}{2}\right], \left[\frac{1}{2}, 1\right], \left[1, \frac{3}{2}\right], \left[\frac{3}{2}, 2\right][/tex]
Now, we just evaluate the function at the left endpoints:
[tex]f\left(x_{0}\right)=f(a)=f\left(0\right)=22\\\\f\left(x_{1}\right)=f\left(\frac{1}{2}\right)=\frac{33}{2}=16.5\\\\f\left(x_{2}\right)=f\left(1\\\right)=12\\\\f\left(x_{3}\right)=f\left(\frac{3}{2}\right)=\frac{17}{2}=8.5[/tex]
Finally, just sum up the above values and multiply by [tex]\Delta{x}=\frac{1}{2}[/tex]:
[tex]\frac{1}{2}(22+16.5+12+8.5)=29.5[/tex]
I need help plz someone help me solved this problem I need help ASAP! I will mark you as brainiest!
Answer: k = -9
Step-by-step explanation:
kx² - 12x - 4 = 0
In order to have exactly one solution, it must be a perfect square.
Assume k is negative and factor out a negative 1.
-1(kx² + 12x + 4) = 0
[tex]\bigg(\sqrt{kx^2}+\sqrt4\bigg)^2=0\\\\[/tex]
The middle term = 12x [tex]= 2(\sqrt{kx^2})(\sqrt4)[/tex]
12x = 4x√k
3 = √k
9 = k
-1(9x² + 12x + 4) = 0
-9x² - 12x - 4 = 0
k=-9
Suppose that g(x) = f(x) - 2. Which statement best compares the graph of
g(x) with the graph of f(x)?
A. The graph of g(x) is shifted 2 units to the left.
B. The graph of g(x) is vertically stretched by a factor of 2.
C. The graph of g(x) is shifted 2 units up.
D. The graph of g(x) is shifted 2 units down.
Answer:
D. The graph of g(x) is shifted 2 units down
Step-by-step explanation:
Since we are modifying b in f(x) = mx + b, we are dealing with vertical movement up and down. Since it is -2, we are moving down 2.
For the triangle show, what are the values of x and y (urgent help needed)
we just have to use the Pythagoras theorem and then calculate the value of x and y.
Tommy has "n" friends and he wants to give each friend 5 pencils. Write an expression to show how many pencils pencils Tommy will share.
Answer:
5n
Step-by-step explanation:
Think about it:
If Tommy has 4 friends (n = 4), then he will have to give 5 pencils to each person. The total number of pencils is 5 * n or 5 * 4 = 20.
Similarly, if Tommy has 0 friends (I can relate), then he will have to give 5 pencils to each of his imaginary friends. The total number of pencils he has to give out to his real friends is 5 * n or 5 * 0 = 0.
Betty tabulated the miles-per-gallon values for her car as 26.5, 28, 30.2, 29.6, 32.3, and 24.7. She wants to construct the 95% two-sided confidence interval. Which value should Betty use for the value of t* to construct the confidence interval?
Answer:
Betty should use T = 2.571 to construct the confidence interval
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 6 - 1 = 5
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 5 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.571
Betty should use T = 2.571 to construct the confidence interval
graph y=8 sec1/5 Ø the answers are graphs I am just unsure of how to answer
Answer:
Use a graphing calc.
Step-by-step explanation:
If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
Answer:
25%
Step-by-step explanation:
George is 33[tex]\frac{1}{3}[/tex]% ([tex]\frac{100}{3}[/tex]%) richer than Pete. Let Pete's percentage of wealth be 100%.
Thus George percentage of wealth = 100% + [tex]\frac{100}{3}[/tex]%
= [tex]\frac{400}{3}[/tex]%
= 133[tex]\frac{1}{3}[/tex]%
Pete's percent poorer than George can be determined by;
= [tex](\frac{100}{3})[/tex] ÷ [tex](\frac{400}{3} )[/tex] × 100
= [tex](\frac{100}{3})[/tex] × [tex]\frac{3}{400}[/tex] ×100
= 0.25 × 100
= 25%
Pete is 25% poorer than George.
For the following data at the near-ground level, which location will residents likely see dew on their lawns in the morning? Group of answer choices City C: Dew Point Temperature = 25°F, expected low Temperature = 20°F City A: Dew Point Temperature = 65°F, expected low Temperature = 60°F City B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
Answer: CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
Step-by-step explanation:
CITY C: Dew Point Temperature = 25°F, expected low Temperature = 20°F
CITY A: Dew Point Temperature = 65°F, expected low Temperature = 60°F
CITY B: Dew Point Temperature = 45°F, expected low Temperature = 50°F
city B is going to have dew on their lawn in the morning as the dew point temperature is less than the lowest temperature.
When surface temperature drops, eventually reaching the dew point, atmospheric water vapor condenses to form small droplets on the surface. Thus dew will be formed as the conditions are suitable only for city B.
A small combination lock on a suitcase has 3 wheels, each labeled with the 10 digits from 0 to 9. If an opening combination is a particular sequence of 3 digits with no repeats, what is the probability of a person guessing the right combination?
Answer:
0.14% probability of a person guessing the right combination
Step-by-step explanation:
A probability is the number of desired outcomes divided by the number of total outcomes.
The order in which the numbers are selected is important. For example, 1,3,2 is a different combination than 3,1,2. So we use the permutations formula to solve this question.
Permutations formula:
The number of possible permutations of x elements from a set of n elements is given by the following formula:
[tex]P_{(n,x)} = \frac{n!}{(n-x)!}[/tex]
Desired outcomes:
One right combination, so [tex]P = 1[/tex]
Total outcomes:
10 numbers from a set of 3. So
[tex]P_{(10,3)} = \frac{10!}{(10-3)!} = 720[/tex]
What is the probability of a person guessing the right combination?
[tex]p = \frac{D}{T} = \frac{1}{720} = 0.0014[/tex]
0.14% probability of a person guessing the right combination