ln(x+5) + lnx=5 answer me fast

Answer:

(a)[tex]9z+2=5[/tex]

(b)[tex]21z-11=-4[/tex]

(c)[tex]4z=2-2z[/tex]

Step-by-step explanation:

We are required to construct 3 linear equations starting with the given solution z = 1/3.

Equation 1

[tex]z=\frac{1}{3}[/tex]

Multiply both sides by 9

[tex]9z=\frac{1}{3}\times 9\\9z=3[/tex]

Rewrite 3 as 5-2

9z=5-2

Add 2 to both sides

Our first equation is: [tex]9z+2=5[/tex]

Equation 2

[tex]z=\frac{1}{3}[/tex]

Multiply both sides by 21

[tex]21z=\frac{1}{3}\times 21\\21z=7[/tex]

Rewrite 7 as 11-4

21z=11-4

Subtract 11 from both sides

Our second equation is: [tex]21z-11=-4[/tex]

Equation 3

[tex]z=\frac{1}{3}[/tex]

Multiply both sides by 6

[tex]6z=\frac{1}{3}\times 6\\6z=2[/tex]

Rewrite 6z as 4z+2z

4z+2z=2

Subtract 2z from both sides

Our third equation is: [tex]4z=2-2z[/tex]

Answer:

IT'S NOT -15 FOR SUREEE

Step-by-step explanation:

I Believe it's 15

Answer:

Step-by-step explanation:

Given the relationship between the output as related to the experience t to be Q (t) = 300 - A e^-kt.

From the table, at t = 0, Q(t) = 200, substituting this into he equation to get A we have:

200 = 300 - A e^-k(0).

200 = 300 - A e^-0

200 = 300 - A

A = 300-200

A = 100

Secondly we need to get the constant k by substituting the other condition into the equation. When t = 3, Q(t) = 190

190 = 300 - A e^-k(3)

190 = 300 - 100e^-3k

190-300 = -100e^-3k

-110 = -100e^-3k

e^-3k = -110/-100

e^-3k = 1.1

Taking the natural logarithm of both sides we have;

ln(e^-3k) = ln1.1

-3k = 0.09531

k = 0.09531/-3

k = -0.0318

The function of this form that fits the data can be gotten by substituting A = 100 and k = -0.0318 into the modeled equation given as shown:

Q(t) = 300 - A e^-kt

Q(t) = 300 - 100e^-(-0.0318)t

Q(t) = 300 - 100e^0.0318t

Answer:

174 square cm

Step-by-step explanation:

2(9×4) + 2(6×4)+ 9×6

2(36) + 2(24) + 54

72 + 48 + 54

120 + 54

174

Answer:

z = 1.476

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.86}{2} = 0.07[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.07 = 0.93[/tex], so [tex]z = 1.476[/tex]

The answer is z = 1.476

Answer:

The two equations that can be used to find each of their ages are [tex]x=4 \times y[/tex] and [tex]x+y=60[/tex] .

Step-by-step explanation:

We are given that Mrs. Lang is 4 times as old as her daughter Jill. The sum of their ages is 60 years.

Let the age of Mrs. Lang be 'x years' and the age of her daughter Jill be 'y years'.

Now, according to the question;

                                     [tex]x=4 \times y[/tex]   ----------------- [equation 1]

                                 [tex]x+y=60[/tex]

                                [tex]4y + y = 60[/tex]     {using equation 1}

                                  [tex]5y=60[/tex]

                                   [tex]y=\frac{60}{5}[/tex]

                                   y = 12 years

Now, putting the value of y in equation 1 we get;

                               [tex]x=4 \times y[/tex]

                               [tex]x= 4 \times 12[/tex] = 48 years

Hence, the age of Mrs. Lang is 48 years and her daughter Jill is 12 years old.

Answer:

Mrs. Lang is 48 and her daughter is 12 years old.

Step-by-step explanation:

Answer:

i think option c must be correct because it has formed the grops on the basis of length of time and made the group by random selection.

Answer:

Step-by-step explanation:

to find the answer you have to find the vulume and then divide by 450

Answer:

7 days

Step-by-step explanation:

vol = 20*15*10.5

vol = 3150

how many days  to drink 3150 cu.cm if Ben drinks 450 cu.cm per day?

3150 cu.cm / 450 cu.cm per day = 7 days

Answer:

  6 mL

Step-by-step explanation:

It is a matter of units conversion.

  volume = (mass) × (dose/mass) ÷ (dose/volume)

  (132 lb)/(2.2 kg/lb) × (0.05 mg/kg) / (0.05 mg/0.1 mL) = 6 mL

Answer:

The correct option is (A).

Step-by-step explanation:

The range of a data set is a measure of variability of that data set.

The range is the difference between the maximum and minimum value of the set.

[tex]\text{Range}=\text{Maximum}-\text{Minimum}[/tex]

Since the maximum value is used in the computation of range, changing the maximum value affects the range greatly.

The correct option is (A).

Answer:

D

Step-by-step explanation:

Parallel lines are those that have the same slope, or coefficient of x.

Here, let's calculate the slope of the given line. Slope is the difference in the y-coordinates divided by the difference in the x-coordinates, so given the two coordinates (12, 6) and (0, -4):

slope = m = (-4 - 6) / (0 - 12) = -10 / (-12) = 10/12 = 5/6

So the slope is 5/6. That means the equation we want should also have a slope of 5/6. Already, we can eliminate A, B, and C, leaving D as our answer. But, let's check.

The equation of a line can be written as [tex]y-y_1=m(x-x_1)[/tex], where m is the slope and [tex](x_1,y_1)[/tex] is the coordinates of a given point.

Here, our slope is 5/6 and our given point is (12, -2). So plug these in:

[tex]y-y_1=m(x-x_1)[/tex]

[tex]y-(-2)=(5/6)(x-12)[/tex]

[tex]y+2=\frac{5}{6} x-10[/tex]

[tex]y=\frac{5}{6} x-12[/tex]

This matches D, so we know that it's the correct answer.

~ an aesthetics lover

The answer is D I just took the test

Answer:

[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]

Step-by-step explanation:

Given that:

mass of the object = 2 kg

A force of 5nt is applied to move the object 0.5m from its equilibrium position.

i.e

Force = 5 newton

Stretchin (x) =0.5 m

Damping force = 1 newton

Velocity = 0.25 m/second

The object is pulled to the left until the spring is stretched lm and then released with the initial velocity of 2m/second to the right

SOLUTION:

If F = kx

Then :

5 N = k(0.5 m)

where ;

k = spring constant.

k = 5 N/0.5 m

k = 10 N/m

the damping force of the object sliding on the table is 1 newton when the velocity is 0.25m/second.

SO;

[tex]C \dfrac{dx}{dt}= F_d[/tex]

[tex]C* 0.25 = 1[/tex]

C = [tex]\dfrac{1 \ N }{0.25 \ m/s}[/tex]

C = 4 Ns/m

NOW;

[tex]m \dfrac{d^2x}{dt^2}+ C \dfrac{dx}{dt}+ kx = 0[/tex]

Divide through by m; we have;

[tex]\dfrac{m}{m}\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+ \dfrac{k}{m} x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ \dfrac{C}{m} \dfrac{dx}{dt}+\dfrac{k}{m}x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ \dfrac{4}{2} \dfrac{dx}{dt}+\dfrac{10}{2}x= 0[/tex]

[tex]\dfrac{d^2x}{dt^2}+ 2 \dfrac{dx}{dt}+5x= 0[/tex]

we all know that:

[tex]x(t) = Ae^{(\alpha \ t)}[/tex]  ------ (1)

SO;

[tex]\alpha ^2 + 2\alpha + 5 = 0[/tex]

[tex]\alpha = \dfrac{-2 \pm \sqrt{(4)-(4*5)}}{2}[/tex]

[tex]\alpha = -1 \pm 2i[/tex]

Thus ;

[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]   ------------ (1)

However;

[tex]\dfrac{dx}{dt} = e^{-t}[A \sin (2t)+ B cos (2t)]+ 2e ^{-t} [A \cos (2t)- B \ Sin (2t)][/tex]     ------- (2)

From the question ; we are being told that;

The object is pulled to the left until the spring is stretched 1 m and then released with the initial velocity of 2m/second to the right.

So ;

[tex]x(0) = -1 \ m[/tex]

[tex]\dfrac{dx}{dt}|_{t=0} = 2 \ m/s[/tex]

x(0) ⇒ B = -1

[tex]\dfrac{dx}{dt}|_{t=0} =- B +2A[/tex]

[tex]=- 1 +2A[/tex]

1 = 2A

A = [tex]\dfrac{1}{2}[/tex]

From (1)

[tex]x(t) = e^{-t}[A \sin (2t)+ B cos (2t)][/tex]  

[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)+ (-1) cos (2t)][/tex]

[tex]x(t) = e^{-t}[\dfrac{1}{2} \sin (2t)-cos (2t)][/tex]

Assuming;

[tex]A cos \ \phi = \dfrac{1}{2}[/tex]

[tex]A sin \ \phi = 1[/tex]

Therefore:

[tex]A = \sqrt{\dfrac{1}{4}+1}[/tex]

[tex]A = \sqrt{\dfrac{1+4}{4}}[/tex]

[tex]A = \sqrt{\dfrac{5}{4}}[/tex]

[tex]A ={ \dfrac{ \sqrt5}{ \sqrt4}}[/tex]

[tex]A ={ \dfrac{ \sqrt5}{ 2}}[/tex]

where;

[tex]\phi = tan ^{-1} (2)[/tex]

Therefore;

[tex]x(t) = \dfrac{\sqrt 5}{2}e^{-t} \ sin (2 t - \phi)[/tex]

From above ; the amplitude is ;

[tex]\mathbf{x(t) = \dfrac{ \sqrt 5}{2}e^{-t} }[/tex]

Answer:

Option B - False

Step-by-step explanation:

Critical value is a point beyond which we normally reject the null hypothesis. Whereas, P-value is defined as the probability to the right of respective statistic which could either be Z, T or chi. Now, the benefit of using p-value is that it calculates a probability estimate which we will be able to test at any level of significance by comparing the probability directly with the significance level.

For example, let's assume that the Z-value for a particular experiment is 1.67, which will be greater than the critical value at 5% which will be 1.64. Thus, if we want to check for a different significance level of 1%, we will need to calculate a new critical value.

Whereas, if we calculate the p-value for say 1.67, it will give a value of about 0.047. This p-value can be used to reject the hypothesis at 5% significance level since 0.047 < 0.05. But with a significance level of 1%, the hypothesis can be accepted since 0.047 > 0.01.

Thus, it's clear critical values are different from P-values and they can't be used interchangeably.

Answer:

The test statistic value is, t = -5.245.

The effect size using estimated Cohen's d is 2.35.

Step-by-step explanation:

A paired t-test would be used to determine whether the remedial tutoring has been effective for the statistics tutor's five students.

The hypothesis can be defined as follows:

H₀: The remedial tutoring has not been effective, i.e. d = 0.

Hₐ: The remedial tutoring has been effective, i.e. d > 0.

Use Excel to perform the Paired t test.

Go to Data → Data Analysis → t-test: Paired Two Sample Means

A dialog box will open.

Select the values of the variables accordingly.

The Excel output is attached below.

The test statistic value is, t = -5.245.

Compute the effect size using estimated Cohen's d as follows:

[tex]\text{Cohen's d}=\frac{Mean_{d}}{SD_{d}}[/tex]

                [tex]=\frac{0.54}{0.23022}\\\\=2.34558\\\\\approx 2.35[/tex]

Thus, the effect size using estimated Cohen's d is 2.35.

Answer:

The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:

[tex] z_{\alpha/2}=1.96[/tex]

The margin of error is given by:

[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

And replacing we got:

[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]

And the margin of error for this case would be [tex] ME = 0.07[/tex]

Step-by-step explanation:

For this case we have the following dataset given:

[tex] n= 146[/tex] represent the sample size

[tex] \hat p =0.23[/tex] represent the estimated proportion of interest

[tex] Conf=0.95[/tex] represent the confidence level

The significance level for this case would be [tex]\alpha=1-0.95=0.05[/tex] and the critical value for this case would be:

[tex] z_{\alpha/2}=1.96[/tex]

The margin of error is given by:

[tex] ME = z_{\alpha/2} \sqrt{\frac{\hat p (1-\hat p)}{n}}[/tex]

And replacing we got:

[tex] ME = 1.96 \sqrt{\frac{0.23*(1-0.23)}{146}} =0.0683[/tex]

And the margin of error for this case would be [tex] ME = 0.07[/tex]

Answer:

but I can do it if you want but I don't you too too y u your help and you have time can you

Step-by-step explanation:

guy who was it that you are not going to be able to make it to the meeting tonight but I can tomorrow if you have time can you come to my house

Answer:

16 km due west

Step-by-step explanation:

The bearing of the school p from school q is 16 km due west.

To find the bearing of school q from school p, we have to find the direction that the school q is with respect to school p.

Since p is directly west of q, then it implies that q must be directly east of p.

We now know the direction.

Since the distance from q to p is exactly the same as the distance from p to q, then, the distance from p to q is 16 km.

Hence, the bearing of q from p is 16 km due west.

Answer:

yes it is correct

Step-by-step explanation:

plz give brainliest.

Answer:

slope = 2/5   ,    y-intercept = -30

Step-by-step explanation:

-2x + 5y = -30

5y  = 2x - 30

y = 2/5x - 6

we know that the general form is:

y = (slope)*x + (y- intercept)

so, from our equation, we can say that...

slope = 2/5

y- intercept = -30

The closest we get is the addition property, which was used in step 2. This is a fairly similar idea because subtraction is effectively adding on a negative number. Example: 5-7 = 5+(-7). Though because your teacher is making a distinction between addition property of equality and subtraction property of equality, it's safe to say that the subtraction property is not used.

==========================================================

Explanation:

We're going to be using the slope formula a bunch of times.

Find the slope of the line through points A and C

m = (y2 - y1)/(x2 - x1)

m = (-12-9)/(9-2)

m = -21/7

m = -3

The slope of line AC is -3. The slopes of line AB and line BC must also be the same for points A,B,C to be collinear. The term collinear means all three points fall on the same straight line.

-------

Let's find the expression for the slope of line AB in terms of k

m = (y2 - y1)/(x2 - x1)

m = (k-9)/(4-2)

m = (k-9)/2

Set this equal to the desired slope -3 and solve for k

(k-9)/2 = -3

k-9 = 2*(-3) ..... multiply both sides by 2

k-9 = -6

k = -6+9 .... add 9 to both sides

k = 3

If k = 3, then B(4,k) updates to B(4,3)

-------

Let's find the slope of the line through A(2,9) and B(4,3)

m = (y2 - y1)/(x2 - x1)

m = (3-9)/(4-2)

m = -6/2

m = -3 we get the proper slope value

Finally let's check to see if line BC also has slope -3

m = (y2 - y1)/(x2 - x1)

m = (-12-3)/(9-4)

m = -15/5

m = -3 we get the same value as well

Since we have found lines AB, BC and AC all have slope -3, we have proven that A,B,C fall on the same straight line. Therefore, this shows A,B,C are collinear.

Answer:

Fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.

Step-by-step explanation:

The significant level for this case study is 5% - 0.05. If the results gotten is less than the significance level, we reject the null hypothesis, but if greater, we fail to reject the null hypothesis.

In this case study, the p-value is 0.10 which is a lot higher than 0.05, thus we will fail to reject the null hypothesis because the p-value =0.10 is more than the significance level α=0.05.

Answer:

C.

Step-by-step explanation:

When two lines are parallel, their slopes are the same.

Since the slope of line l is 2/7, the slope of its parallel line m must also be 2/7.

The answer is C.

Answer:

C. 2/7

Step-by-step explanation:

Parallel lines are lines that have the same slopes.

We know that line l is parallel to line m.

Therefore, the slope of line l is equal to the slope of line m.

[tex]m_{l} =m_{m}[/tex]

We know that line l has a slope of 2/7.

[tex]\frac{2}{7} =m_{m}[/tex]

So, line m also has a slope of 2/7. The answer is C. 2/7

Answer:

5i² - 25ij +ji-5j²

Step-by-step explanation:

Use distributive property

Answer:

Step-by-step explanation:

A = (5i+j)

B = (i-5j)

A × B is

( 5i + j) ( i - 5j)

Expand

We have

5i² - 25ij + ij - 5j²

The final answer is

5i² - 24ij - 5j²

Hope this helps you.

Answer:

Hello!

______________________

Peter samples her class by selecting 5 girls and 7 boys. This type of sampling is called?​

This type of sampling is called Stratified.

Hope this helped you!

:D

Answer:

a) 4 cm

b) 5 cm

c) 10 cm

Step-by-step explanation:

The side lengths of the reflected square are equal to the original, and the distance from the axis(2) also remains the same.  From there, it is just addition.

Hope it helps <3

Answer:

A) 4

B) 5

C) 10

Step-by-step explanation:

edge2020

Answer:

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

Step-by-step explanation:

The margin of error of a confidence interval is given by:

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

z is related to the confidence level. The higher the confidence level, the higher the values of z, and thus, we wider the confidence interval is.

In this question:

The narrower C.I. is the 95%, and the wider is the 99%. So

(25.53, 37.87): 95% CI

(23.59, 39.81): 99% CI

Answer:

1  [tex]\mu = 100[/tex]

2 [tex]\sigma = 16[/tex]

3 [tex]\mu_x = 100[/tex]

4 [tex]\sigma _{\= x } = 2.309[/tex]

Step-by-step explanation:

From the question

    The population mean is  [tex]\mu = 100[/tex]

    The standard deviation is [tex]\sigma = 16[/tex]

     The sample mean is  [tex]\mu_x = 100[/tex]

     The sample size is  [tex]n = 48[/tex]

     The mean standard deviation is  [tex]\sigma _{\= x } = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values

     [tex]\sigma _{\= x } = \frac{16 }{\sqrt{48} }[/tex]

     [tex]\sigma _{\= x } = 2.309[/tex]