Listed following are some distinguishing characteristics of comets, meteors, and asteroids. Match these to the appropriate category of objects.

Substances in order of increasing vapor pressure at a given temperature is SF4 < SF6 < SiH4

Which has highest vapor pressure?

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In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

Titration is also known as titrimetry is a technique where a solution of known concentration is used to calculate the concentration of the unknown solution. Titration is a laboratory technique.

The point at which the indicator changes the color is known as Endpoint.

Thus from the above conclusion we can say that In the endpoint when the indicator changes color it gives the information that the acid is neutralized by the base.

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Answer:

1.15 moles H₂

Explanation:

To find the moles of H₂ gas, you need to use the Ideal Gas Law equation. The equation looks like this:

PV = nRT

In this equation,

-----> P = pressure (atm)

-----> V = volume (L)

-----> n = moles

-----> R = Ideal Gas Constant (0.08206 L*atm/mol*K)

-----> T = temperature (K)

Before you can plug the given values into the equation and simplify, you need to convert Celsius to Kelvin.

P = 0.923 atm                     R = 0.08206 L*atm/mol*K

V = 29.6 L                           T = 17.0 °C + 273.15 = 290.15 K

n = ? moles

PV = nRT

(0.923 atm)(29.6 L) = n(0.08206 L*atm/mol*K)(290.15 K)

27.3208 = n(23.809709)

1.15 = n

Answer:

L = mol solute / M

Explanation:

To rewrite the equation for liters (L), you need to:

M = mol solute / L                              <----- Given equation

M x L = mol solute                             <----- Multiply both sides by L

L = mol solute / M                              <----- Divide both sides by M

Answer:

10.2 °C

Explanation:

If all other variables are held constant, you can find the new temperature using the Charles' Law equation. The equation looks like this:

V₁ / T₁ = V₂ / T₂

In this equation, "V₁" and "T₁" represent the initial volume and temperature. "V₂" and "T₂" represent the final volume and temperature. You can find the new temperature by plugging the given values into the equation and simplifying.

V₁ = 122 mL                     V₂ = 50 mL

T₁ = 25 °C                        T₂ = ? °C

V₁ / T₁ = V₂ / T₂                                         <----- Charles' Law equation

122 mL / 25 °C = 50 mL / T₂                    <----- Insert values

4.88 = 50 mL / T₂                                     <----- Divide 25 from 122

4.88 x T₂ = 50 mL                                    <----- Multiply both sides by T₂

T₂ = 10.2 °C                                             <----- Divide both sides by 4.88

Sodium represents by the (Na).

Filling out the table below following the outlined order:

An element can be defined as a substance that can not be broken down into simpler substances.

An element serves as a building blocks for compounds and mixtures.

In conclusion, each element and its property as requested in the table are given above.

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The mass of solid is 76.905 g.

Given that,

Total volume of solid and liquid = 81.0 mL

Mass of liquid = 40.5 g

Density of liquid = 0.865 g/mL

Density of solid = 2..25 g/mL

We need to calculate the volume of liquid

Using formula of density

[tex]Density = Mass/volume(V_{l} } )\\\\volume(V_{l} )=Mass/Density[/tex]

Put the value into the formula

[tex]V_{l} = 40.5/0.865\\\\V_{l} = 46.82 mL[/tex]

We need to calculate the volume of solid

Volume of solid = Total volume of solid and liquid- volume of liquid

[tex]V_{s} =81.0-46.82\\\\V_{s} =34.18 mL[/tex]

We need to calculate the mass of solid

[tex]P_{s}=M_{s} /V_{s} \\\\M_{s} =P_{s}V_{s}[/tex]

Using formula of density

Put the value into the formula

[tex]M_{s}=2.25 X 34.18\\\\M_{s}=76.905 g[/tex]

Hence, The mass of solid is 76.905 g.

A substance's density (more accurately, its volumetric mass density; sometimes known as specific mass) is its mass per unit volume. The most common symbol for density is (the lower case Greek letter rho).

There are three types of Density:

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The free energy is always negative and the dissolution is feasible when enthalpy is negative and entropy is positive. Option A

Water is known as the universal solvent. Water is a polar substance hence it is often used to dissolve polar substances. It has a dipole and being that there is a high degree of electronegativity difference between the oxygen and the hydrogen atoms in water, it is feasible that the degree of hydrogen bonding between the two is high.

We know that dissolution is favored when there will be an increase in entropy as a result of that, that is; if more particles will appear. Now we know that ΔG = ΔH - TΔS.

Given the equation above, it then follows that the free energy is always negative and the dissolution is feasible when enthalpy is negative and entropy is positive. Option A

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The amount, in grams, of carbon tetrachloride that would be present, will be 22.99 grams.

For every one mole of any substance, there are 6.022 x [tex]10^{23}[/tex] atoms of particles. This is according to Avogadro.

Now, there are 9 x [tex]10^{22[/tex] particles in this particular carbon tetrachloride.

If 1 mole = 6.022 x [tex]10^{23}[/tex] particles

Then,

9 x [tex]10^{22[/tex] particles =  9 x [tex]10^{22[/tex] x 1/6.022 x [tex]10^{23}[/tex] particles

                       = 0.1495 moles

Carbon tetrachloride has the chemical formula CCl4 and has a molar mass of 153.82 g/mol.

Recall that: mole = mass/molar mass

Hence, mass = mole x molar mass.

Mass of 0.1495 moles CCl4 = 0.1495 x 153.82 = 22.99 grams

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V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.

The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.

The word based equation is

Vanadium(V) oxide + Hydrogen gas → Vanadium (III) oxide + Water

Now write the chemical equation

V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l)

Reactant side                Product side

V = 2                                V = 2

O = 5                                O = 5

H = 4                                 H = 4

We can see that the number of atoms on reactant side is equal to the number of atoms on product side. So the given equation is balanced.

Thus from the above conclusion we can say that V₂O₅ (s) + 2H₂ (g) → V₂O₃ (s) + 2H₂O(l) is the balanced chemical equation for the reaction of solid vanadium(V) oxide with hydrogen gas to form solid vanadium(III) oxide and liquid water.

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2.7 is the chlorine dosage for this well, expressed in parts per million.

Unlike municipal water, well water does not go through a water treatment facility. That implies that it could be contaminated with poisons like lead, coliform bacteria, volatile chemical compounds, and others. chlorination in well water is done to fulfill the role that chlorine plays in municipal sources' water disinfection processes.

It is advised to start with a chlorine concentration of 50 to 100 parts per million (ppm).

Bacterial pollutants are eliminated from well water, well casings, holding tanks, and the entire water delivery system via shock chlorination. To shock chlorinate, a well driller with a license is trained.

Algae have been linked to green water, and they may thrive in both surface water and groundwater wells even in the absence of sunshine. Algae can color the water in both the pre-and post-decomposition stages with a variety of hues, including green, brown, and reddish.

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Answer:

terminal

Explanation:

When a hydrogen atom is part of a molecular structure, it is always a terminal atom.

The molarity of the zinc chloride solution will be 0.089 M

Mole of 7.24 g ZnCl2 = 7.24/136.286 = 0.5312 mol

Total volume of water used in preparing the solution = 300 + 300 = 600 mL

Molarity of the solution = mole/volume = 0.5312/0.6 = 0.089 M

The molarity of the zinc chloride solution is, therefore, 0.089 M

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The list of acceptable species of wood materials used in aircraft structure is found in Table 1-1 on Page 1-2 of AC 43.13-1B.

Construction of Aircraft with Wood There are four types of wood that are frequently used in the manufacture of aircraft. These include Douglas fir, Sitka spruce, birch, and ash. Additionally, gabon, mahogany, balsa, and pine serve specific purposes. Softwood Sitka Spruce grows in both Canada and the United States of America.

Contrary to popular opinion, Howard Hughes' Spruce Goose was made of birch, not spruce, despite the fact that Sitka spruce is the most often used wood in airplanes. Spruce is regarded as the best natural material for building aircraft because it has one of the highest strengths-to-weight ratios.

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Green, because it has less volume and less amount of matter.

Density is the mass of a material substance per unit volume. d = M/V, where d is density, M is mass, and V is volume, is the formula for density. Grams per cubic centimeter are a typical unit of measurement for density.

Because it enables us to predict which compounds will float and which will sink in a liquid, density is a crucial notion. If an object's density is lower than the liquid's, it will often float.

The dimensions of two colored cubes.

Red: 4 12

Green: 3 10

density = mass/volume

so compare

[tex]12/4^{3}[/tex] and [tex]10/3^{3}[/tex]

None of the choices is the real reason. But is the closest. It is green because 10/27 > 12/64

But red would have been denser for a side of 3.9, and green would still have had less volume and less matter.

Green, because it has less volume and less amount of matter.

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A photon has an energy of 2.88 × 10⁻¹⁸ J. The energy into eV is 17.97 eV.

The energy which is carried by a single photon is called Photon energy.

It is expressed as:

E = hf

where,

E = Photon energy

h = Planck's energy

f = Wave frequency

To convert J into eV

E(eV) = E(J) × 6.241509 × 10¹⁸

         = 2.88 × 10⁻¹⁸ × 6.241509 × 10¹⁸

         = 17.97 eV

Thus from the above conclusion we can say that A photon has an energy of 2.88 × 10⁻¹⁸ J. The energy into eV is 17.97 eV.

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Answer:

Mn₁O₂

Explanation:

To find the empirical formula, you need to (1) determine how many grams of each element are within the compound, then (2) convert grams to moles (via the atomic masses of each element), and then (3) determine the mole-to-mole ratio of each element.

(Step 1)

Because the percents add to equal 100%, we can say that each percent is the mass of each element.

63% Mn ----> 63 grams Mn

37% O ----> 37 grams O

(Step 2)

We need to convert each mass to moles using the atomic masses. The atomic masses are a ratio comparing the mass of each element per every 1 mole.

Atomic Mass (Mn): 54.983 g/mol

Atomic Mass (O): 15.998 g/mol

63 grams Mn                 1 mole
----------------------  x  -------------------------  =  1.15 moles Mn
                                 54.983 grams

37 grams O                1 mole
--------------------  x  ------------------------  =  2.31 moles O
                               15.998 grams

(Step 3)

You can find the mole-to-mole ratio of each element in the compound by dividing the calculated mole values by the smallest mole value. In this case, since 1.15 moles was the smallest value calculated, it should be the divisor. The resulting amounts are the subscripts within the empirical formula.

1.15 moles Mn / 1.15 moles  =  1 moles Mn

2.31 moles O / 1.15 moles  =  2 moles O

Ratio of MnO = 1:2

This make the empirical formula: Mn₁O₂

Halogens are rarely found in native state because halogens are highly reactive.  

The group 17 elements are known as Halogen group. These elements include Fluorine, Chlorine, Bromine, Iodine and Astatine. Halogens react with metals to form salts. Halogens are non metals. Halogens are highly reactive and halogens are never found in pure form. Halogens not occur in free state.

Halogens have seven valence electrons in the outermost shell. The electronic configuration of Halogen is ns² np⁵.

Thus from the above conclusion we can say that Halogens are rarely found in native state because halogens are highly reactive.

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3 NADH + [tex]1FADH_{2}[/tex] + 1GTP (=ATP)  is used during Krebs Cycle in every  acetyl CoA

The pyruvate is important chemical compound in the biochemistry.The pyruvate is primary used as transporter of carbon atoms into the mitochondria and do complete oxidation of this  carbon atoms into carbon dioxide.

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Answer:

73.68 J

Explanation:

To find the energy absorbed by nickel, you need to use the following equation:

Q = mcΔT

In this equation,

-----> Q = energy (J)

-----> m = mass (g)

-----> c = specific heat (J/g°C)

-----> ΔT = change in temperature

The change in temperature is found by subtracting the initial temperature from the final temperature. You can plug the given values into the equation and simplify to find the energy absorbed.

m = 10.0 g

c = 0.120 J/g°C

ΔT = 63.4 °C - 2.0 °C = 61.4 °C

Q = mcΔT

Q = (10.0 g)(0.120 J/g°C)(61.4 °C)

Q = 73.68  J

The energy profile representing the reaction of the formation of NO2  is energy profile B; option D.

An energy profile diagram is a diagram which illustrates in the form of a graph the energy changes that occur as reactant molecules react to form products.

An energy profile has energy of the molecules plotted on the y-axis and the reaction pathway or the reaction progress on the x-axis.

The shape of an energy profile depends on whether the reaction is an endothermic or exothermic reaction.

An exothermic reaction will have the energy of reactants higher than that of products, whereas an endothermic reaction will have the energy of products higher than the reactants.

The formation of NO2 is an endothermic reaction which requires 33.1kJ/mol of energy to complete.

Therefore, the energy profile representing the reaction is energy profile B.

In conclusion, an energy profile diagram shows energy changes that occur in a reaction graphically.

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Answer:

E) 9.0

Explanation:

pH = -log [1×10^-9] = 9

Hydrocarbons (typically petroleum products), which separate in water and have a Specific Gravity of less than one, represent a significant hazard to firefighters. Why?

Any member of the class of organic chemical compounds known as hydrocarbons only includes the atoms carbon (C) and hydrogen (H). The hydrogen atoms bond to the carbon atoms in a variety of ways to create the compound's structural framework.

Although there could be thousands of different hydrocarbon molecules in a given crude oil, these descriptions only focus on the type of hydrocarbon that predominates in the combination. Typically, each sort of molecule can be found in all naturally occurring crude oils.

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Answer:

Pb(NO3)2 + 2NaCl = 2NaNO3 + PbCl2

Reaction at anode

2 Br-​ (aq) -----> Br2 (g) + 2e-

The product formed at the anode is Br2 (g).

In chemistry and production, electrolysis is a technique that makes use of direct electric present-day (DC) to power an otherwise non-spontaneous chemical response.

Electrolysis is commercially crucial as a degree inside the separation of factors from clearly going on sources including ores the usage of an electrolytic cell.

The voltage that is wanted for electrolysis to occur is called the decomposition capacity. The word "lysis" way to split or break, so in phrases, electrolysis would imply "breakdown via power".

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A symbol of magnesium, Mg, with two dots representing two free electrons. The correct option is D.

Magnesium is represented by Mg.

Magnesium has an atomic number of 12. Thus the electron configuration will be 2,8,2.

This means that there are two valence electrons in every Mg atom.

Therefore, the electron do diagram would be the symbol of the element with two dots representing the two valence electrons.

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Answer:

Two dotted M

Explanation:

Answer:

can you be more clear with your question :

The mass of the solution will be 4,394 mg

The mass percent of a component in a solution can be derived as follows:

Mass percent = mass of component/total mass of solution x 100%

In this case, the mass percent of KCN in the solution is 0.208 and the mass of KCN is 914 mg.

The mass of the 0.208% KCN solution will be:

                           914/0.208 = 4,394 mg

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