List the Basic Skill And Experiments​

Answers

Answer 1

Answer:

Observing. This is the most basic skill in science. ...

Communicating. It is important to be able to share our experiences. ...

Classifying. After making observations it is important to notice similarities, differences, and group objects according to a purpose. ...

Inferring. ...

Measuring. ...

Predicting.Explanation:

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Related Questions

Calculate the molarity of the two solutions.
The first solution contains 0.350 mol of NaOH in 1.05 L of solution.
molarity:

The second solution contains 14.3 g of NaCl in 879 mL of solution.
molarity:

Answers

1. 0.33 M

2. 0.278 M

Further explanation

Molarity is a way to express the concentration of the solution

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

[tex]\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}[/tex]

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

1. 0.350 mol of NaOH in 1.05 L of solution.

n=0.35

V=1.05 L

Molarity :

[tex]\tt M=\dfrac{0.35}{1.05}=0.33[/tex]

2. 14.3 g of NaCl in 879 mL of solution.

mol NaCl(MW=58.5 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{14.3~g}{58.5~g/mol}=0.244[/tex]

Molarity :

[tex]\tt M=\dfrac{0.244}{0.879~L}\\\\M=0.278[/tex]

explain how to convert the moles to litters and litters to moles

Answers

Converting from volume (liters) to moles: Divide your initial volume by the molar volume constant, 22.4 L. Converting from moles to volume (liters): Multiply your mole value by the molar volume constant, 22.4L.

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Answers

Answer:

No because a straw is plastic look at it by this was, the energy used to create one metal straw is roughly equivalent to creating 90 plastic straws, and also produces carbon emissions equivalent to 150 plastic straws. This may not seem like a lot, but in order to offset the environmental impact of creating a metal straw, it must be used over 150 times

Explanation:

Which of these elements has the highest first ionization energy?
a) As
b) Ga
c) Bi
d) Cs
e) K

Answers

Answer:

Cesium (Cs)

Explanation:

This eliment has an ionization energy of 3,8939

A voltaic cell is constructed that is based on the following reaction:
Sn2+(aq)+Pb(s)→Sn(s)+Pb2+(aq).
If the concentration of Sn2+ in the cathode compartment is 1.00 M and the cell generates an emf of 0.16 V , what is the concentration of Pb2+ in the anode compartment?

Answers

Answer: The concentration of Pb2+ in the anode compartment is [tex]1.74\times 10^{-6}M[/tex]

Explanation:

[tex]Sn^{2+}(aq)+Pb(s)\rightarrow Sn(s)+Pb^{2+}(aq)[/tex]

Here Pb undergoes oxidation by loss of electrons, thus act as anode. Sn undergoes reduction by gain of electrons and thus act as cathode.

[tex]E^0=E^0_{cathode}- E^0_{anode}[/tex]

Where both [tex]E^0[/tex] are standard reduction potentials.

[tex]E^0_{[Sn^{2+}/Sn]}=-0.14V[/tex]

[tex]E^0_{[Pb^{2+}/Pb]}=-0.13V[/tex]

[tex]E^0=E^0_{[Sn^{2+}/Sn]}- E^0_{[Pb^{2+}/Pb]}[/tex]

[tex]E^0=(-0.14-(-0.13)V=-0.01V[/tex]

Now using Nernst Eqn :

[tex]E=E^0-\frac{0.059}{n}\log\frac{[Pb^{2+}]}{[Sn^{2+}]}[/tex]

[tex]0.16=(-0.01)-\frac{0.059}{2}\log\frac{[Pb^{2+}]}{[1.00]}[/tex]

[tex]0.17=-0.0295\log\frac{[Pb^{2+}]}{[1.00]}[/tex]

[tex]-5.76=\log\frac{[Pb^{2+}]}{[1.00]}[/tex]

[tex]1.74\times 10^{-6}=\frac{[Pb^{2+}]}{[1.00]}[/tex]

[tex][Pb^{2+}]=1.74\times 10^{-6}[/tex]

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Answers

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What is the cation in the chemical formula MnSe?

Answers

Answer:

Mn

Explanation:

The cation in the chemical formula MnSe is the Mn specie.

A cation is a positively charge ion or radical. Such an ion has lost electrons and this leaves a net positive charge on them. The Mn is the cationMost metals forms cations as they readily lose electrons due to their large atomic radius. Se is the anion as it will carry a negative chargeMost non-metals are anions

How much heat is needed to increase the temperature of 15g of water from 10°C to 30°C? The specific heat of water is 4.18 (J/g °C).

Answers

Answer:

H=mc∆T

H=15×4.18×20

H=1254J

454 grams of isomaltitol, C12H24O11, was combusted in a furnace completely in an excess oxygen. The products of this reaction are water and carbon dioxide. What is the theoretical yield (in kilograms) of water produced from this reaction?

Answers

The theoretical yield (in kilograms) of water produced from this reaction : 0.285 kg

Further explanation

Reaction

2C₁₂H₂₄O₁₁ + 25O₂ → 24CO₂ + 24H₂O

mass of C₁₂H₂₄O₁₁ - isomaltitol = 454 g

mol C₁₂H₂₄O₁₁(MW=344.31 g/mol) :

[tex]\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{454}{344.31 g/mol}\\\\mol=1.319[/tex]

mol H₂O based on C₁₂H₂₄O₁₁ as limiting reactant(O₂-oxygen as an excess)

From the equation above, mol ratio of C₁₂H₂₄O₁₁  : H₂O = 2 : 24, so mol H₂O:

[tex]\tt mol~H_2O=\dfrac{24}{2}\times 1.319=15.828[/tex]

then mass H₂O (MW=18 g/mol) :

[tex]\tt mass=mol\times MW\\\\mass=15.828\times 18=284.904~g=0.285~kg[/tex]

A 9.70-g piece of solid CO 2 is allowed to sublime in a balloon. The final volume of the balloon is 1.00 L at 298 K. What is the pressure of the gas inside the balloon?
a. 5.39 atmb. 2.37  102 atmc. 2.52 atmd. 0.186 atme. none of these

Answers

Answer:

a. 5.39 atm

Explanation:

Pressure = ?

Volume = 1 L

Temperature = 298 K

Mass = 9.70g

The formular relating these variables is the ideal gas equation;

PV = nRT

where R = gas constant = 0.082057 L.atm.K-1.mol-1

n can be obtained from the formular below;

n = mass / molar mass = 9.70 / 44

n = 0.2205 mol

P = nRT / V

P = 0.2205 * 0.082057 * 298 / 1

P = 5.392 atm

The correct option is option A.

Xenon tetrafluoride has two sets of lone pairs of electrons. What should be the relative positions of the two sets of lone pairs?Why?

Answers

Answer: Two equatorial positions so as to minimize the repulsion.

Explanation:

Formula used for calculating number of electrons :

[tex]\frac{1}{2}[V+N-C+A][/tex]

where,

V = number of valence electrons present in central atom  = 8

N = number of monovalent atoms bonded to central atom = 4

C = charge of cation  = 0

A = charge of anion  = 0

Now we have to determine the hybridization of the [tex]XeF_4[/tex]   molecule.

[tex]\frac{1}{2}[8+4-0+0]=6[/tex]

Bond pair electrons = 4

Lone pair electrons = 2

The number of electrons are 6 that means the hybridization will be [tex]sp^3d^2[/tex] and the electronic geometry of the molecule will be octahedral.

The molecular geometry will be square planar as two alternate positio ns will be occupied by lone pair of electrons so as to minimize the repulsion.

Which two factors often determine the type of rock that is formed by a process?
A.The type of material that is present at the beginning of the process
B.The amount of time the process of rock formation takes
C.The season in which the rock formation process ends
D.Whether the process takes place north or south of the equator

Answers

Answer:

A and B

Explanation:

Trust me I just did it on a p e x

Answer: he’s correct it’s d and b for me but it’s the same answers

Explanation:

Please help me I need these answers

Answers

Answer:

Q8) True

Q9) First ionization energy

Q10) Metal oxides

Explanation:

A common property of group one elements (alkali metals) is their combination with water to form basic solutions. E.g 2K(s)+2H2O(l)→2KOH(aq)+H2​(g).

The distance of the outermost electron in the atom from the nucleus is inversely related to the first ionization energy. As the distance between the outermost electron and the nucleus in group 17 elements gets larger, the corresponding first ionization energies of elements in the group gets smaller.

Group 1 elements can combine with oxygen to give metal oxides. E.g  4K + O2 --> 2 K2O

Sodium carbonate reacts with silver nitrate according to the following balanced equation: Na2CO3 (s) + 2 AgNO3 (aq) → Ag2CO3 (s) + 2 NaNO3 (9) If 3.60 g of Na2CO3 is allowed to react with 5.14 g of AgNO3, what mass of Na2CO3 will remain at the end of the reaction?
a) 2.01 g
b) 1.54 g
c) 0.423 g
d) 0.0150 g
e) 0g

Answers

Answer:

a) 2.01 g

Explanation:

Na₂CO₃ (s) + 2AgNO₃ (aq) → Ag₂CO₃ (s) + 2NaNO₃

First we convert 0.0302 mol AgNO₃ to Na₂CO₃ moles, in order to calculate how many Na₂CO₃ moles reacted:

0.0302 mol AgNO₃ * [tex]\frac{1molNa_2CO_3}{2molAgNO_3}[/tex]  = 0.0151 mol Na₂CO₃

So the remaining Na₂CO₃ moles are:

0.0340 - 0.0151 = 0.0189 moles Na₂CO₃

Finally we convert Na₂CO₃ moles into grams, using its molar mass:

0.0189 moles Na₂CO₃ * 106 g/mol = 2.003 g Na₂CO₃

The closest answer is option a).

3. Gasoline, coal, batteries, and logs all have chemical energy. When they burn that chemical energy will be transformed into energy.​

Answers

Answer:

Thermal energy

Explanation:

When gasoline, coal, batteries and logs are all burn they transform chemical energy to thermal energy.

The chemical energy is the energy held between chemical chains and bonds within an atom.

When they combust, they release thermal energyChemical energy is a potential energy. The thermal energy is a kinetic energyIt increase the average motion of the particles in the mediumThe breaking bond when produces heat which is a form of thermal energy.

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Answers

32 h this is because this problem


Which of thes statements about heating up land and water is true

Answers

Answer:

b its radiant energy that heats up the earth.

Explanation:

Answer:

The answer is D

Explanation:

Heat from the Earth's core and radiation from the Sun is transferred to the surface of the Earth by conduction. The warm land and water radiates infrared, some of which is absorbed by the atmosphere, adding to its thermal energy.

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol. How much energy is produced by burning 0.8210 g of naphthalene?

Answers

The energy produced by burning : -32.92 kJ

Further explanation

Delta H reaction (ΔH) is the amount of heat change between the system and its environment

(ΔH) can be positive (endothermic = requires heat) or negative (exothermic = releasing heat)

The enthalpy and heat(energy) can be formulated :

[tex]\tt \Delta H=\dfrac{Q}{n}\rightarrow n=mol[/tex]

The enthalpy of combustion of naphthalene (MW = 128.17 g/mol) is -5139.6 kJ/mol.

The energy released for 0.8210 g of naphthalene :

[tex]\tt Q=\Delta H\times n\\\\Q=-5139.6~kJ/mol\times \dfrac{0.8210~g}{128.17~g/mol}~\\\\Q=-32.92~kJ[/tex]

A container at STP contains 64.0O grams of oxygen. How many liters of O2(g) are in the container?

Answers

Answer:

44.80

Explanation:

17. Which of the following represent the correct net ionic equations from the double replacement reaction of
calcium nitrate and potassium phosphate?
a. Caaq) + PO43- (aq) → CaPO4(s)
b. Q Ca2+ (aq) + 3 PO43- (aq) → Caz(PO4)3(S)
c. 3 Ca2+ (aq) + 2 PO.3(aq) → Caz(PO4)2(S)
d. 2 NO3(aq) + Ca2+
+ Ca(NO3)2(S)

Answers

Answer:

D. 2 NO3(aq)+Ca2+

Explanation:

Reaction of calcium nitrate and potassium phosphate produce calcium phosphate and potassium nitrate. The net ionic equation for this is written as : [tex]3 Ca^{2+} (aq) +2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s)[/tex]. Thus option C is correct.

What is double displacement reaction?

In a double displacement reaction, two species or groups in reactant side are displaced in the products.

In a balanced chemical equation, all the reactants have to be in proper stochiometric ratio and the states of all species are mentioned in brackets.

In an ionic equation all the ions and charges are balanced both side and the number of each elements on both side too. The net ionic equation represents the formation of a solid product from its ions.

The balanced molecular equation and complete ionic equation are written for the given  reaction below:

[tex]3 Ca (NO_{3})_{2} (aq)+ 2K_{3} PO_{4} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s) + 6 KNO_{3}(aq)[/tex]

[tex]3 Ca^{2+} (aq) +6 NO_{3}^{-} + (aq)+ 6K^{+} + (aq) 2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s) + 6 NO_{3}^{-} (aq)+ 6K^{+} (aq)[/tex]

Now when the same species on both side is cancelled, then the net ionic equation is written as:

[tex]3 Ca^{2+} (aq) +2PO_{4} ^{3-} (aq) \rightarrow Ca_{3}(PO_{4} )_{2} (s)[/tex]

Therefore, the correct et ionic equation is option c.

To learn more about ionic equations, refer the link below:

https://brainly.com/question/15467511

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Which gas law is represented by the following equation: P1/T1 = P2/T2
O none of these
Avogadro's law
Charles's law
Gay-Lussac's law
Boyle's law

Answers

Answer:

none of these

Explanation:

The expression:

      P1/T1 = P2/T2 is a derivative of the combined gas law.

From the combination of the Boyle's and Charles's law, if the volume is taken to be constant, the pressure of the given mass of gas is directly proportional to the absolute temperature.

This is how the expression

      P1/T1 = P2/T2 was obtained.

Using the van der waals equation, the pressure in a 22.4 L vessel containing 1.50 mol of chlorine gas at 0.00 c is____________atm. (a= 6.49L^2-atm/mol^2, b=0.0562 L/mol)
A. 1.50
b. 0.676
c. 0.993
d. 1.48
e. 1.91

Answers

Answer:

D. 1.48atm

Explanation:

Van der waals equation is given as:

(P +an²/v²) (v - nb) = nRT

Where;

P = pressure (atm)

V = volume (L)

R = gas constant (0.0821 Latm/molK)

a and b = gas constant specific to each gas

T = temperature (K)

n = number of moles

According to the given information; V = 22.4L, T = 0.00°C (273.15K), R = 0.0821 Latm/molK, a = 6.49L^2-atm/mol^2, b = 0.0562 L/mol, n = 1.5mol

Hence;

(P + 6.49 × 1.5²/22.4²) (22.4 - 1.5×0.0562) = 1.5 × 0.0821 × 273.15

(P + 6.49 × 2.25/501.76) (22.4 - 0.0843) = 33.638

(P + 0.0291) (22.316) = 33.638

22.316P + 0.649 = 33.638

22.316P = 33.638 - 0.649

22.316P = 32.989

P = 32.989/22.316

P = 1.478

P = 1.48atm

When 80.0 mL of a 0.812 M barium chloride solution is combined with 40 mL of a 1.52 M potassium sulfate solution, 10.8 g of barium sulfate precipitates. What is the % yield of this reaction

Answers

Answer:

76.1%

Explanation:

The reaction that takes place is:

BaCl₂ + K₂SO₄ → BaSO₄ + 2KCl

First we determine how many moles of each reactant were added:

BaCl₂ ⇒ 80 mL * 0.812 M = 64.96 mmol BaCl₂ K₂SO₄ ⇒ 40 mL * 1.52 M = 60.8 mmol K₂SO₄

Thus K₂SO₄ is the limiting reactant.

Using the moles of the limiting reactant we calculate how many moles of BaSO₄ would have been produced if the % yield was 100%:

60.8 mmol K₂SO₄ * [tex]\frac{1mmolBaSO_4}{1mmolK_2SO_4}[/tex] = 60.8 mmol BaSO₄

Then we convert that theoretical amount into grams, using the molar mass of BaSO₄:

60.8 mmol BaSO₄ * 233.38 mg/mmol = 14189.504 mg BaSO₄14189.504 mg BaSO₄ / 1000 = 14.2 g BaSO₄

Finally we calculate the % yield:

% yield = 10.8 g / 14.2 g * 100 %% yield = 76.1%

You are asked to write observations about a 100g sample of Nitrogen-16 before it decays , but you running late. In order to make observations, you require at least 5g of material Can make observations you are 57 seconds late to the lab?

Answers

Answer:

You can not make the observation in the lab

Explanation:

We must know the amount of Nitrogen-16 that remains after 57 seconds before we can make our conclusion.

Hence, from;

N/No = (1/2)^t/t1/2

Where;

N = amount of Nitrogen-16 present after 57 seconds

No = 100g of Nitrogen-16 originally present

t = 57 seconds

t1/2 = half life of Nitrogen-16 which is 7.13 seconds

Substituting values;

N/100 = (1/2)57/7.13

N/ 100 =(1/2)^8

N/100 = 1/256

256N = 100

N = 100/256

N = 0.39 g

You can not make the observation because you need at least 5g of Nitrogen-16 and only 0.39 g is left after 57 seconds.

The minimum amount of sample required has been 5 grams, while the remaining sample has been 0.39 grams. Thus, it has not been possible to make the observations.

The half life can be defined as the time required for the sample to reduce to half of its initial concentration. The half life can be given as:

Amount remained = Initial amount [tex]\rm \times\;\dfrac{1}{2}^\dfrac{time}{Half-life}[/tex]

The half life of nitrogen 16 has been 7.13 second.

The initial concentration of the sample has been 100 grams.

The concentration of sample remained after 57 seconds has been:

Amount remained = 100 [tex]\rm \times\;\dfrac{1}{2}^\dfrac{57\;sec}{7.13\;sec}[/tex]

Amount remained = 0.39 grams.

The amount of sample remained after 57 seconds has been 0.39 grams.

The amount of sample required for the analysis has been 5 grams, after 57 seconds only 0.39 grams of sample has been remaining. Thus, the student will not be able to made analysis of nitrogen-16.

For more information about the sample decay, refer to the link:

https://brainly.com/question/1831303

Calculate the percent composition of Carbon in the
compound shown below. Record your answer with two
decimal places.
C18H18010

Answers

Answer:54.82%

Explanation:

Percentage of carbon = mass of carbon in that compound/ mass of the compund *100

216/394*100 = 54.82%

. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams of ethyl benzene are required to obtain 244 g of benzoic acid

Answers

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid

Theoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

2.00 moles benzoic acid * [tex]\frac{1molEthylBenzene}{0.4molBenzoicAcid}[/tex] = 5.00 moles ethyl benzene

Finally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:

5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene

The thermite reaction ,
Fe2O3(s)+2Al(s)⟶2Fe(s)+Al2O3(s),ΔH∘=−851.5kJ/mol
is one of the most exothermic reactions known. Because the heat released is sufficient to melt the iron product, the reaction is used to weld metal under the ocean. How much heat is released per mole of Al2O3produced? How does this amount of thermal energy compare with the energy released when 2 mol of protons and 2 mol of neutrons combine to form 1 mol of alpha particles?

Answers

Answer:

Explanation:

1) The ΔH shows the heat of reaction of the reaction illustrated in the question and the negative sign shows the reaction is an exothermic reaction, meaning heat is released in this reaction. The amount of heat released in this reaction is 851.5 kilojoules per mole of Al₂O₃ produced.

2) The thermal energy of this reaction is however very low when compared to the energy released when 2 moles of protons and 2 moles of neutrons combine to form 1 mole of alpha particles. This is because, the reaction illustrated in the (1) above is a normal chemical reaction while the one that involves the protons and neutrons (as described in this section 2) is a nuclear reaction which involves large amount of energy. Nuclear reactions usually involve way larger amount of energy than ordinary chemical reactions.

which of the following is the best definition for volume
a. solids are the only matter with volume
b. all energy has volume
c. volume is the three-dimensional size of an object
d. gases do not have volume

Answers

Answer:

C

Explanation:

I hope that helps!!! it kinda gave you the answer though

I believe the answer is c

1. A football player throws a football 30 meters/second2 using 600 Newtons of force What
was the mass of the football?

Answers

Answer:

20 kg

Explanation:

The mass of the football can be found by using the formula

[tex]m = \frac{f}{a} \\ [/tex]

f is the force

a is the acceleration

From the question we have

[tex]m = \frac{600}{30} = \frac{60}{3} \\ [/tex]

We have the final answer as

20 kg

Hope this helps you

Can someone help me with number 5:/

Answers

So to answer this question first let's decribe precision vs accuracy.

Precision in this case means exact and accurate; in this scenario all of the dots next to each other mean that it is highly precise.

Whereas Accuracy means aiming for the middle of the circle in this case. Thus   the accuracy is low, but the precision is high.

TLDR: It is highly precise but not accurate.

Look up "Accuracy vs. Precision: What’s the Difference?" for a better detailed example and solution.

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