List or describe 2 chemical properties of gasoline

List Or Describe 2 Chemical Properties Of Gasoline

Answers

Answer 1

Answer:

The typical composition of gasoline hydrocarbons (% volume) is as follows: 4-8% alkanes; 2-5% alkenes; 25-40% isoalkanes; 3-7% cycloalkanes; l-4% cycloalkenes; and 20-50% total aromatics (0.5-2.5% benzene) (IARC 1989). ... Information regarding the chemical identity of gasoline is located in Table 3-l.

Explanation:


Related Questions

Draw the major organic product in the reaction scheme. Be sure to clearly show stereochemistry (if applicable). The starting material is an alkyne where carbon 1 is bonded to cyclopentane and carbon 2 is bonded to H. Step 1 is N a N H 2. Step 2 is C H 3 I. Step 3 is sodium in liquid ammonia. Draw the major organic product.

Answers

Answer:

See answer below

Explanation:

The picture below will show you the final product and mechanism.

In the first step, the NaNH₂ is a strong base, so, this base will substract the hydrogen from carbon 2, to generate a negative charge there, and then, carbon 2 becomes a nucleophyle.

As a nucleophyle it will attack to the CH₃I in the next step, and it will attach to the CH₃.

The second step is just a regular step to reduce the triple bond of the alkyne to alkane or alkene, this will depend on the quantity of the reactant. In this case, an alkene.

Hope this helps,,,,,,k

What occurs when a reaction reaches equilibrium?

1)The concentration of the reactants increases.
2)The concentration of the products increases
3)The rate of the forward reaction is equal to the rate of the reverse reaction
4)The rate of the forward reaction is slower that the rate of the reverse reaction.

Answers

Answer:

3)The rate of the forward reaction is equal to the rate of the reverse reaction

Answer:

The Rate of Forward Reaction is equal to the rate of the reverse reaction.

Explanation:

Hope this helps :)

4. The device shown is a
that's used to measure the heat transferred by a reaction under constant volume.
A. bomb calorimeter
B. reaction vessel
C. thermometer
D. coffee-cup calorimeter

Answers

Answer:

The device shown is a calorimeter that used to measure the heat transfer by a reaction under constant volume.

Explanation:

Which of the following substances can be dissolved in pure water to give a basic solution?

Hydrogen chloride

Sodium bromide

Sodium hydroxide

Sodium chloride

Answers

Maybe the 2nd one??? Not sure

I think it's sodium hydroxide

Explanation:

sodium hydroxide is a base

Under the right conditions aluminum will react with chlorine to produce aluminum chloride.
2 Al + 3Cl2 -> 2 AlCl3
How many grams of aluminum chloride can be produced when 157.0g of aluminum react with excess chlorine?
Answer:775.9 g AlCl3
but what the steps pls help

Answers

Answer:

775.9 g

Explanation:

Step 1: Write the balanced equation

2 Al + 3 Cl₂ ⇒ 2 AlCl₃

Step 2: Calculate the mass corresponding to 157.0 g of Al

The molar mass of Al is 26.98 g/mol.

157.0 g × 1 mol/26.98 g = 5.819 mol

Step 3: Calculate the moles of AlCl₃ produced from 5.819 moles of Al

The molar ratio of Al to AlCl₃ is 2:2. The moles of AlCl₃ produced are 2/2 × 5.819 mol = 5.819 mol.

Step 4: Calculate the mass corresponding to 5.819 moles of AlCl₃

The molar mass of AlCl₃ is 133.34 g/mol.

5.819 mol × 133.34 g = 775.9 g

PLEASE HELP!! ORGANIC CHEMISTRY

A sample of a diatonic gas is loaded into an evacuated bottle at STP. The 0.25 L bottle contains 1.76 grams of the unidentified gas. Calculate the molar mass of the gas. What is the identity of the diatomic gas?

Answers

Answer:

(a) 157.7 g

(b) 7.04 g/dm³

Explanation:

(a) From the question,

According to Avogadro's Law,

1 mole of every gas at STP occupies a volume of 22.4 dm³

But mass of 1 mole of the diatomic gas  = molar mass of the gas.

This Implies that,

The molar mass of the gas at STP occupies a volume of 22.4 dm³

From the question,

If,

0.25 L bottle contain 1.76 g of the gas,

Therefore,

Molar mass of the gas = (1.76×22.4)/0.25

Molar mass of the gas = 157.7 g.

(b) Density of the gas = mass/volume

D = m/v

Given: m = 1.76 g, v = 0.25 L = 0.25 dm³

Therefore,

D = 1.76/0,25

D = 7.04 g/dm³

A bottle labeled 0.01 M HCl is found in the laboratory. Assuming that the HCl is completely ionized calculate the [H+], [OH-] and the pH of the solution. ​

Answers

Answer:

[H⁺] = 0.01 M[OH⁻] = 1x10⁻¹² MpH = 2

Explanation:

The assumption that the HCl is completely ionized means that the original concentration of the acid is equal to [H⁺].

[H⁺] = 0.01 M

With [H⁺], we can calculate [OH⁻], by using the following formula:

[H⁺] * [OH⁻] = 10⁻¹⁴0.01 M * [OH⁻] = 10⁻¹⁴[OH⁻] = 1x10⁻¹² M

Finally we calculate the pH of the solution:

pH = -log[H⁺]pH = 2

If the pH of a solution is 6.96, then the solution is a

Answers

Answer:

acid

Explanation:

solution with pH less than 7 is acid

those with more that 7 is base

those equal to 7  is neutral

What is the concentration of a solution with a volume of 0.900 L that contains 2.05 mol of iron (II) hydroxide?

Answers

Answer:

The concentration is 2.277

Explanation:

The formula for finding the concentration of a solution is C= mole of solute divided by the volume of the solution

Therefore, C= 2.05/0.900

C=2.277

what is the partial pressure of each gas in a 26L container at 27°c that holds 5 moles of carbon dioxide,3.3 moles of nitrogen and 1.5 moles of hydrogen, and has a total pressure of 1.05

Answers

Answer:

pCO₂ = 0.54 atm

pN₂ = 0.35 atm

pH₂ = 0.16 atm

Explanation:

Step 1: Calculate the total number of gaseous moles

The total number of gaseous moles (n) is equal to the sum of the moles of the individual gases.

n = nCO₂ + nN₂ + nH₂ = 5 mol + 3.3 mol + 1.5 mol = 9.8 mol

Step 2: Calculate the partial pressure of each gas

We will use the following expression.

pi = P × χi

where,

pi: partial pressure of the gas i

P: total pressure (1.05 atm)

χi: mole fraction of the gas i

pCO₂ = 1.05 atm × (5 mol/9.8 mol) = 0.54 atm

pN₂ = 1.05 atm × (3.3 mol/9.8 mol) = 0.35 atm

pH₂ = 1.05 atm × (1.5 mol/9.8 mol) = 0.16 atm

_HCN+_CUSO4=_CUSO4+_CU(CN)2​

Answers

2HCN + CuSO4 → H2SO4 + Cu(CN)2
The answer would be :

[0]HCN + CuSO4 = CuSO4 + [0]Cu(CN)2

Thus is because the left-hand side contain Hydrogen, whereas the right-hand side does not. To balance an equation, an element cannot be added. And therefore, Hydrogen must be removed completely, along with Carbon and Nitrogen, as they each formed a chemical bond with hydrogen, and the composition would change if so.

Explanation chemically :

HCN + CuSO4 = CuSO4 + Cu(CN)2

Left-hand side :

1 H
1 C
1 N
1 Cu
1 S
4 O

Right-hand side :

0 H
1 Cu
1 S
4 O
1 Cu
2 C
2 N

Comparison between the two sides :

First:

1 H = 0 H (therefore to balance it, times the left hand side by 0 : (0)(1) H = 0 H = 0 H)

Because we're multiplying the left-hand side hydrogen atom by 0, and it is bonded with Carbon and Nitrogen, Carbon and Nitrogen is multiplied by 0 as well.

(0) H x (0) C x (0) N = (0) HCN = 0

Hydrogen is balanced.

Second :

Left-hand side Carbon and Nitrogen is 0 (0HCN).
Therefore, right-hand side Carbon and Nitrogen must also be 0.

Cu(CN)2

0 should be multiplied to the CN bracket to bring them to 0. However, there is a Cu atom in from of the CN molecule. So the 0 would be placed in front of the Cu atom, like this :

(0) Cu(CN)2.

The 0 in front of the Cu atom ensures that all the atoms will be multiplied by 0

(0 Cu(CN)2 = (0) Cu x (0) (CN)2 = 0

Carbon and Nitrogen are balanced.

Third :

CuSO4 is already balanced as both sides have an equal amount of each atom.

Therefore, the answer is [0] HCN + [1] CuSO4 = [1] CuSO4 + [0] Cu(CN)2




Besides filament-based detectors, what else are sometimes used to find flammable liquids?
A. Radar detectors
B. Dogs
C. Chemical sprays
D. Carbon monoxide detectors

Answers

Answer:

D

Explanation:

can u be my friend i'm new

Besides filament-based detectors, sometimes used to find flammable liquids are carbon monoxide detectors. Hence option D is correct.

What are detector?

Detector are defined as a tool for detecting the presence of radioactivity or electromagnetic waves. Since 1881, metal detectors have been employed for diagnostic purposes. They have been used to identify a wide range of foreign bodies and medical equipment, including bullets, intraocular metallic pieces, ingested coins, and other foreign things. Detecting metallic things quickly may help with diagnosis or therapy.

Carbon monoxide detectors are defined as a tool that looks for carbon monoxide (CO) gas to stop carbon monoxide poisoning. The purpose of CO alarms is to alert you to any unexpected CO buildup in your home. These greater levels of CO may be brought on by fuel-burning appliances that are not properly maintained, installed, or operated, by fireplaces or appliances that draft backward, or by idling cars in garages.

Thus, besides filament-based detectors, sometimes used to find flammable liquids are carbon monoxide detectors. Hence option D is correct.

To learn more about detector, refer to the link below:

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8
What happens to solid waste in the circulatory system?
A it's expelled through the lungs
B
It pumps into the coronary circulation
C
It's dropped off in the kidneys
D
It's deposited in the aorta

Answers

Answer:c it’s dropped off in the kidneys

Explanation:

I took the quiz

The solid wastes are from the circulatory system is expelled to the kidney where, the nitrogenous wastes like urea and uric acid is excreted as urine from the body.

What is circulatory system ?

A circulatory system is an organ system, where the blood is purified and oxygenation of blood takes place. Through circulatory system, the blood reaches throughout the body pumped from the heart through veins.

The organs included in circulatory system are lungs, heart, aorta, veins, blood vessels etc. There are various kinds of blood vessels each having specific functions.

There is a network of blood vessels including arteries and large veins, capillaries that join the venules and other veins. All the nutrients and ions are circulated throughout the body through blood and solid wastes are then expelled to kidney.

Kidney function as a sieve to clean the good fluid from waste products. Uric acid and urea along with water excreated as urine then. Thus, option C is correct.

To find more about circulatory system, refer the link below:

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If 3.13 mol of an ideal gas has a pressure of 2.33 atm and a volume of 72.31 L, what is the temperature of the sample in degrees Celsius?

Answers

Answer:

382.49 C degree Celsius

Explanation:

Hello,

This problem deals with understanding the ideal gas law which hopes to predict how ideal gases might behave in any given condition. I listed the formula below and we are basically just going to solve for temperature by rearranging the equation as seen on the picture (there's also other rearranged ones in case you need to solve for those).

Universal gas constant R has a value of 0.0821 L * atm/(mole * K) when working with these given units so it will be part of this equation. R value changes based on what units you have.

T = PV/nR

   = (2.33) (72.31) / (3.13)(0.0821)

   = 655.64 K

Question is asking temperature in celsius so we employ the formula attached below:

C = K - 273.15

   = 655.64-273.15

    = 382.49 degree Celsius

382.49 degree Celsius is the answer!


At 27.0°C, the volume of a gas is 630 L. At the same pressure, its volume is 92,0 mL at a temperature of

Answers

Answer:

–272.96 °C

Explanation:

From the question given above, the following data were obtained:

Initial temperature (T₁) = 27.0 °C

Initial volume (V₁) = 630 L.

Final volume (V₂) = 92.0 mL

Final temperature (T₂) =?

Next, we shall convert 27.0 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 27.0 °C

Initial temperature (T₁) = 27.0 °C + 273

Initial temperature (T₁) = 300 K

Next, we shall convert 92.0 mL to L. This can be obtained as follow:

1000 mL = 1 L

Therefore,

92 mL = 92 mL × 1 L / 1000 mL

92 mL = 0.092 L

Next, we shall determine the final temperature.

Initial temperature (T₁) = 300 K

Initial volume (V₁) = 630 L.

Final volume (V₂) = 0.092 L

Final temperature (T₂) =?

V₁ / T₁ = V₂ / T₂

630 / 300 = 0.092 / T₂

2.1 = 0.092 / T₂

Cross multiply

2.1 × T₂ = 0.092

Divide both side by 2.1

T₂ = 0.092 / 2.1

T₂ = 0.04 K

Finally, we shall convert 0.04 K to celsius temperature. This can be obtained as follow:

T(°C) = T(K) – 273

Final temperature (T₂) = 0.04 K

Final temperature (T₂) = 0.04 – 273

Final temperature (T₂) = –272.96 °C

Determine the hydroxide ion concentration in
a solution that is 0.00034 M Ca(OH)2.
Answer in units of M.

Answers

Answer:

[tex]0.00068M[/tex]

Explanation:

Hello there!

In this case, according to the ionization of calcium hydroxide, a strong base:

[tex]Ca(OH)_2\rightarrow Ca^{2+}+2OH^-[/tex]

Thus, since there is a 1:2 mole ratio of calcium hydroxide to hydroxide ions, we apply the following proportional factor to obtain:

[tex]0.00034\frac{molCa(OH)_2}{L}*\frac{2molOH^-}{1molCa(OH)_2} \\\\=0.00068\frac{OH^-}{L}\\\\=0.00068M[/tex]

Regards!

When electrons move to a shell closer to the nucleus, energy is released as

Answers

Answer:

it is released as lower energy

lower energy will be the answer

hope it helps!!!!!

Study the reaction.
CH4 + 2O2 → CO2 + 2H2O
If 7.4 moles of carbon dioxide (CO2) form at the end of the reaction, how many moles of methane (CH4) and oxygen gas (O2) entered the reaction?

? moles of methane and
? moles of oxygen gas

Answers

7.4 moles of methane (CH₄)

14.8 moles of oxygen gas (O₂)

Consider the aldol-dehydration reaction. Draw the two possible products of the reaction between benzaldehyde and methylethylketone. (Do not draw the products of the double-condensation.)

Answers

Solution :

An [tex]$\text{aldol condensation}$[/tex] reaction is a type of [tex]\text{condensation reaction}[/tex] in organic chemistry where the enol or an enolate ion reacts with the carbonyl compound and forms a [tex]$\beta$[/tex]-hydroxyaldehyde or a [tex]$\beta$[/tex]-hydroxyketone, and then followed by a dehydration to give conjugated enone.  

Benzaldehyde reacts with methylketone and forms two products:  

Considering the temperature vs. time graph below, how does the temperature at the beginning of a change of state compare with the temperature at the end of the change?

- The temperature is always lower.
- The temperature is always the same.
- The temperature is usually lowest
- The temperature is usually higher.​

Answers

The temperature at the beginning and the end of a change of state correct option is : The temperature is usually the same.

When looking at a temperature vs. time graph during a change of state, such as melting or boiling, the temperature remains constant throughout the duration of the change. This is because during a change of state, the heat energy is used to break the intermolecular bonds rather than increase the temperature. As a result, the temperature remains constant until the entire substance has completed the phase transition.At the beginning of the change of state, the substance is at its melting or boiling point, and the temperature remains constant as the substance absorbs heat energy to transition from a solid to a liquid (melting) or from a liquid to a gas (boiling). At the end of the change of state, the substance has fully transitioned, and the temperature remains constant until all the substance has completely melted or boiled.

The correct option is: The temperature is usually the same.

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The temperature at the beginning of a change is always lower than the temperature at the end of the change option A

Does the temperature increase as the phase change progresses?

The temperature doesn't vary during a phase transition, such as melting or boiling, until the phase change is finished. This is so that intermolecular forces can be broken rather than the average kinetic energy of the particles, which is related to temperature, being increased by the heat energy being applied to the substance.

But the temperature does increase from one point to the other on the heating curve.

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[H+] [OH-] =

NEED HELP ASAP!!!

Answers

Hopes this helps:

Answer: h^2o

If this doesn’t help than I am so sorry that I couldn’t help.

Which equation represents the total ionic equation for the reaction of HNO3 and NaOH?
OH+ + OH -> H2O
O HNO3 + NaOH → NaNO3 + H20
OH + NO3 +Na+ + OH -> Na + NO3 + H20
OH + NO3 + OH →→ NO3 + H20

Answers

Answer:

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

Explanation:

First, we will write the molecular equation for the neutralization reaction between nitric acid and sodium hydroxide.

HNO₃(aq) + NaOH(aq) → NaNO₃(aq) + H₂O(l)

The total ionic equation includes all the ions and the molecular species.

H⁺(aq) + NO₃⁻(aq) + Na⁺(aq) + OH⁻(aq) → Na⁺(aq) + NO₃⁻(aq) + H₂O(l)

Do u believe that you are beautiful/handsome?


Yes or No?

Answers

i think i’m beautiful some days but other days no. Mainly only depends on my mood.

A 251 ml sample of 0.45M HCl is added to 455 mL of distilled water. What is the molarity of the
final solution?

Answers

We are given:

251 mL sample of 0.45M HCl added to 455 mL distilled water

Whack a mole! (finding the number of moles):

We know that in order to find molarity, we use the formula:

Molarity = number of moles / Volume (in L)

so, number of moles is:

Number of moles = Molarity * Volume(in L)

now let's plug the values for the HCl solution to find the number of moles

Number of moles = 0.45M * 0.251 L

Number of moles = 0.113 moles

Time to concentrate (finding the final concentration):

Total final volume = 251 mL + 455 mL = 706 mL = 0.706 L

Number of moles of HCl = 0.113 moles

Molarity = Number of moles / Volume (in L)

Molarity = 0.113 / 0.706

Molarity = 0.16 M

___________________________________________________________

BONUS METHOD TIME!!!

We know the relation:

M1 * V1 = M2 * V2

where M1 and M2 are the initial and final molarities and V1 and V2 are initial and final volumes respectively

notice that I didn't mention that the volume has to be in Liters, that's because of the units being concerned with both sides of the equation, say I have the volume in mL and want to convert both these volumes to L, I would divide both sides by 1000, which would NOT change the overall value

Now, plugging values in this equation

(0.45) * (251) = (251 + 455)* (M2)

112.95 = (706)(M2)

M2 = 112.97/706                                [dividing both sides by 706]

M2 = 0.16 Molar

A compound is 70.0% iron and 30.0% oxygen. Its molecular mass is 479.1 g/mol. Determine the
molecular formula.

Answers

Answer:

[tex]Fe_6O_9[/tex]

Explanation:

Hello there!

In this case, since these problems about formulas, firstly require the determination of the empirical formula, assuming that the given percentages are masses, we can calculate the moles and mole ratio of oxygen to iron as shown below:

[tex]n_{Fe}=70/55.85=1.25\\\\n_O=30/16=1.875[/tex]

In such a way, by rounding to the first whole number we multiply by 8 and divide by 5 to obtain:

[tex]Fe_{2}O_{3}[/tex]

Whose molar mass is 159.69 g/mol and the mole ratio of the molecular to the empirical formula is:

479.1/159.69=3

Therefore, the molecular formulais:

[tex]Fe_6O_9[/tex]

Regards!

What is the total number of moles of O2(g) that must react completely with 5.00 moles of C4H10(g)?

Answers

Answer:

32.5 moles of O2(g) are necessaries for a complete reaction

Explanation:

Based on the reaction of combustion of C4H10(g):

C4H10(g) + 13/2 O2(g) → 4CO2(g) + 5H2O(g)

1 mole of C4H10 needs 13/2 moles O2 for a complete reaction.

That means, the moles of O2 required for a reaction of 5.00 moles of C4H10 are:

5.00 moles C4H10 * (13/2mol O2 / 1mol C4H10) =

32.5 moles of O2(g) are necessaries for a complete reaction

The cation that has the same number of electrons (isoelectronic) as Ne is
None of the listed options
O Na
Mg 2-
All of the listed options
O AI 3-

Answers

Ne is isoelectronic with Na+ ion.

Calculate the molarity of the two solutions.
The first solution contains 0.200 mol of NaOH in 2.00 L of solution.
The second is 15.5G of NaCl in 671mL of solution

Answers

Answer:

a) 0.100 M

b) 0.395 M

Explanation:

a) Calculate the molarity of a solution that contains 0.200 moles of NaOH (solute) in 2.00 L of solution

We will use the following expression for molarity.

[NaOH] = moles of solute / liters of solution

[NaOH] = 0.200 mol/2.00 L = 0.100 M

b) Calculate the molarity for a solution that contains 15.5 g of NaCl (solute, 58.44 g/mol) in 671 mL of solution

We will use the following expression for molarity.

[NaCl] = mass of solute / molar mass of solute × liters of solution

[NaCl] = 15.5 g / 58.44 g/mol × 0.671 L = 0.395 M

How do atoms combine to form all of the diverse types of matter in our universe?




Pls, Help with a good valid answer and explanation. will mark brainliest.

Answers

Answer:

Using electrons.

Explanation:

The properties of matter depend on the types of atoms that matter is made of. Matter can exist in two forms. It can be a pure substance. (ck12.org)

Atoms combine, or bond, using their electrons. When atoms from two or more different elements bond, they form a compound. (resources.finalsite.net) Atoms form chemical bonds with other atoms when there's an electrostatic attraction between them. This attraction results from the properties and characteristics of the atoms' outermost electrons, which are known as valence electrons. (wonderpolis.org)

Something like this??

What is the limiting reactant in the following equation? How much Fe2O3 will be produced if 2.1 g of Fe reacts with 2.1 g of O2?

4 Fe + 3O2 —> 2Fe2O3

Answers

Answer:

Fe is limiting reactant and 3.00g of Fe2O3 will be produced

Explanation:

To solve this question we must convert the mass of each reactant to moles and, using the reaction we can find limiting reactant. With moles of limiting reactant we can find moles of Fe2O3 and its mass as follows:

Moles Fe -Molar mass: 55.845g/mol-

2.1g * (1mol / 55.845g) = 0.0376 moles

Moles O2 -Molar mass: 32g/mol-

2.1g * (1mol / 32g) = 0.0656 moles

For a complete reaction of 0.0656 moles of O2 are needed:

0.0656moles O2 * (4mol Fe / 3 mol O2) = 0.0875 moles Fe

As there are just 0.0376 moles,

Fe is limiting reactant

The mass of Fe2O3 is:

Moles:

0.0376 moles Fe* (2mol Fe2O3 / 4mol Fe) = 0.0188 moles Fe2O3

Mass:

0.0188 moles Fe2O3 * (159.69g / mol) =

3.00g of Fe2O3 will be produced

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