Answer:
=-0.809
Step-by-step explanation:
3x^2+5x+7=0 complete the square
3x^2+5x=-7 divide both sides by 3
x^2+5/3 x = -7/3 to complete the square add term(b/2)^2=((5/3)/2)²=25/36
X^+5/3 x+25/36=-7/3 +25/36 factorize
(x+5/6)²= -59/36
x+5/6= + or - √59/36
solution for x= -5/6-√59/6i (u) OR -5/6+√59/6i (v)
u/v + v/u=(-5/6-√59/6i)/(-5/6+√59/6i) +(-5/6+√59/6i)/(-5/6-√59/6i)=-17/21
=-0.809
Answer:
[tex]\large \boxed{\sf \ \ \ -\dfrac{17}{21}=-0.80952... \ \ \ }[/tex]
Step-by-step explanation:
Hello,
First of all we can verify that 0 is not a solution of the equation so that we can divide by u or v
[tex]\dfrac{v}{u}+\dfrac{u}{v}=\dfrac{u^2+v^2}{uv}=\dfrac{(u+v)^2-2uv}{uv}=\dfrac{(u+v)^2}{uv}-2[/tex]
And we know that
[tex]u+v=-\dfrac{5}{3}\\\\uv=\dfrac{7}{3}\\\\\\as \ \ (x-u)(x-v)=x^2-(u+v)x+uv[/tex]
So it comes
[tex]\dfrac{v}{u}+\dfrac{u}{v}=\dfrac{5^2*3}{7*3^2}-2=\dfrac{25-42}{21}=-\dfrac{17}{21}=-0.80952...[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Lines AB and CD are parallel. If ∠3 measures (3x + 20)°, and ∠4 measures 70°, which equation could be used to solve for x
Answer:
(3x + 20)° + 70° = 180°
Step-by-step explanation:
Please help urgently ❤️❤️❤️
Greetings from Brasil...
Here we have application of Trigonometry
COS β = adjacent side ÷ hypotenuse (H)
bringing to our problem....
COS A = AC ÷ H
But we dont have AC.... We have to use Pitagoras:
AB² = AC² + BC²
AC² = AB² - BC²
AC = √(AB² - BC²)
AC = √(10² - 8²)
AC = √(100 - 64)
AC = √36
AC = 6So
COS A = AC ÷ H ⇔ COS A = AC ÷ AB
COS A = 6/10
COS A = 3/5Answer: B) 3/5
Step-by-step explanation:
Cos = adjacent/hypotenuse
Thus, the cos is AC/AB.
Because of Pythagorean Theorem, AC^2=AB^2-BC^2. Let AC be x.
[tex]x^2=10^2-8^2\\x^2=100-64\\x^2=36\\x=6[/tex]
Thus, the cos is 6/10, or 3/5
$70 discounted to $63
Answer:
10% off
Step-by-step explanation:
When $70 is discounted to $63, you can multiply 70 times 0.1 to get 7 which 70-63=7. To make 0.1 to a percentage, multiply by 100 to get 10%.
Hope this helps!!! PLZ MARK BRAINLIEST!!!
Write as an algebraic expression and simplify if possible: *150% of 50% of z whoever answers the fastest gets brainliest
Answer:
3z/4
Step-by-step explanation:
Here, we start by calculating the 50% of z
mathematically, that would be 50/100 * z = 50z/100 = z/2
Now we want to calculate the 150% of this.
That would be 150/100 * z/2 = 150z/200 = 3z/4
18.2 divided by 18 what’s the answer??
Answer:1.0111111111
Step-by-step explanation:
18.2 - 18 = .2-18 =1.0111111
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
f(x) = 2(x –3)²
Step-by-step explanation:
f(x) = 2x² – 12x + 18
The vertex form of the above expression can be obtained as follow:
f(x) = 2x² – 12x + 18
Factorise
f(x) = 2(x² – 6x + 9)
Next, we shall simplify x² – 6x + 9 by factorisation method.
This is illustrated below:
x² – 6x + 9
Multiply the first term i.e x² and last term i.e 9 together. The result is 9x².
Next, find two factors of 9x² such that their sum will result to the 2nd term i.e –6x in the expression above.
The factors are –3x and –3x
Next, replace –6x with –3x and –3x in the equation above as shown below:
x² – 6x + 9
x² – 3x –3x + 9
Factorise
x(x – 3) –3(x –3)
(x –3)(x –3)
(x –3)²
f(x) = 2x² – 12x + 18
f(x) = 2(x² – 6x + 9)
f(x) = 2(x –3)²
Therefore, the vertex form of the function f(x) = 2x² – 12x + 18 is
f(x) = 2(x –3)²
If $a$ and $b$ are integers, such that $a\not= 0$ and $b\not= 0$ and $a^2$ and $b^2$ have at most two digits, what is the greatest possible difference between the squares of $a$ and $b?$
Answer:
80
Step-by-step explanation:
t is important to note that a square of any non-zero integer is positive, and therefore there is no advantage in using negative integers instead of positive integers to attain the greatest difference of squares. So we will not consider negative integers.
The greatest value of a^2 - b^2 occurs when a^2 is at its largest and b^2 is at its smallest.
The larger a, the larger a^2:
8 ^ 2 = 64
9 ^ 2 = 81
10 ^ 2= 100
Since a^2 can have at most two digits, a=10 is too large, and so a=9 is the largest integral value of a we can use.
Now, b^2 is at its smallest when b is closest to zero on the number line (the further b gets from zero, the larger its square becomes):
2 ^ 2 = 4
1 ^ 2 =1
0 ^ 2 = 0
Remember to go back to the original problem sometimes, to make sure you are taking everything into account. It states b doesn't =0, and therefore the b=1 is the closest b can get to zero as an integer. So, the greatest difference between b^2 and a^2 is when b=1 and a=9, giving the result:
a^2-b^2 =9^2-1^2 =81-1= 80.
So, 80 is your answer.
I need help with solving this problem 4x-c=k
Answer:
x=1/4c+1/4k
Step-by-step explanation:
4x-c=k
move c over
4x=c+k
then divide by 4
x=1/4c+1/4k
hope this helps
Please help this is a new topic for me.
Answer:
last answer
Step-by-step explanation:
P' (2, -4)
Q' (-2, -5)
R' (1, -8)
Answer:
C. P'(2, -4) Q'(-2, -5) R'(1, -8)
Step-by-step explanation:
When you reflect something across the y-axis you change (x,y) to (-x,y).
For each point, change the x to a negative x.
P(-2, -4) --> P'(2, -4)
Q(2, -5) --> Q'(-2, -5)
R(-1, -8) --> R'(1, -8)
Hope this helps. If you have any follow-up questions, feel free to ask.
Have a great day! :)
If one- tenth of a number is added to 2, the result is half of that number, find the number. A. 2.5 B. 3.3 C. 4.2 D. 5.0
Answer:
D. [tex]\boxed{x = 5}[/tex]
Step-by-step explanation:
Let the number be x
Condition:
[tex]\frac{1}{10} x + 2 = \frac{1}{2} x[/tex]
[tex]\frac{x}{10} -\frac{x}{2} = -2\\LCM = 10\\Multiplying \ both \ sides \ by \ 10\\x - 5(x) = -2(10)\\x -5x = -20\\-4x = -20[/tex]
Dividing both sides by -4
x = 5
Answer:
[tex]\boxed{5.0}[/tex]
Step-by-step explanation:
Let the number be [tex]x[/tex].
1/10 of x is added to 2, the result is half of x.
[tex]2+\frac{1}{10} x=\frac{1}{2} x[/tex]
[tex]2=\frac{1}{2} x-\frac{1}{10} x[/tex]
[tex]2=\frac{2x}{5}[/tex]
[tex]10=2x[/tex]
[tex]\frac{10}{2} =x[/tex]
[tex]5=x[/tex]
The number is 5.0
Does this graph show a function? Explain how you know.
5
-5
-5
A. No; there are y-values that have more than one x-value.
B. No; the graph fails the vertical line test.
C. Yes; the graph passes the vertical line test.
D. Yes; there are no y-values that have more than one x-value.
Answer:
Option (C).
Step-by-step explanation:
To check a graph whether it's a function or not we use a vertical line test. In this test first we draw a vertical line on the given graph. If this line intersects the graph at more than one point, the graph is not a function.
In the given parabola, opening upwards passes the vertical line test.
Therefore, this graph shows a function.
Option (C) will be the answer.
Option (c) Yes; the graph passes the vertical line test. And
(d) Yes; there are no y-values that have more than one x-value are correct options. Hence, a given graph is a function.
This is a graph of [tex]y = x^2[/tex]
Which is a graph of parabola.
To determine the given graph is a function or not, we do a vertical line test.
The vertical line test says that if a vertical line intersects a graph more than once, then that graph is not a function. And in this case, y-values have more than one x-values.
Let’s draw a vertical line in the given graph (attached below)
We see that the vertical line touches the graph only at once. That’s why it is a function, and so there are no y-values that have more than one x-value.
Hence, the given graph is a function and option (3) and (4) are correct options.
Learn more about graphs here:
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Suppose $600 is compounded yearly for 20 years. If no other deposits are made, what rate is needed for the balance to triple in that time? Round your answer to the nearest hundredth of a percent.
Answer:
5.65%
Step-by-step explanation:
Principal=$600
Time=20 years
FV=600*3=$1800
n=1
r=?
r= n[(A/P)^1/nt - 1]
=1{(1800/600)^ 1/1*20 - 1}
={(3)^1/20-1}
=3^0.05-1
=1.0565-1
=0.0565
rate=0.0565*100
=5.65% to the nearest hundredth percent
Simplifying Rational Expressions: I need answers for both 7 and 8 below. Answers for just one or the other is also fine.
Answer:
1. Option A 2. Option DStep by step explanation
1. [tex] \frac{1}{1 - x} + \frac{x}{ {x}^{2} - 1} [/tex]
Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex] to rewrite the fractions
[tex] - \frac{1}{x - 1} + \frac{x}{(x - 1)(x + 1)} [/tex]
Write all numerators above the Least Common Denominator ( X - 1 ) ( X + 1 )
[tex] \frac{ - (x + 1) + x}{(x - 1)(x + 1)} [/tex]
When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression
[tex] \frac{ - x - 1 + x}{(x - 1)(x + 1)} [/tex]
Using [tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex] , simplify the product
[tex] \frac{ - x - 1 + x}{ {x}^{2} - 1 } [/tex]
Since two opposites add up to zero, remove them from the expression
[tex] \frac{ - 1}{ {x}^{2} - 1} [/tex]
So, Option A is the right option.
___________________________________
2.
[tex] \frac{ {x}^{2} - x - 12}{ {x}^{2} - 16} - \frac{1 - 2x}{x + 4} [/tex]
Write - X as a difference
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{ {x}^{2} - 16 } - \frac{1 - 2x}{x + 4} [/tex]
Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression
[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor the expression
[tex] \frac{x(x + 3) - 4(x + 3)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Factor out X+3 from the expression
[tex] \frac{(x + 3)(x - 4)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]
Reduce the fraction with x-4
[tex] \frac{x + 3}{x + 4} - \frac{1 - 2x}{x + 4} [/tex]
Write all the numerators above the common denominator
[tex] \frac{x + 3 - ( 1- 2x)}{x + 4} [/tex]
When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression
[tex] \frac{x + 3 - 1 + 2x}{x + 4} [/tex]
Collect like terms
[tex] \frac{3x + 3 - 1}{x + 4} [/tex]
Subtract the numbers
[tex] \frac{3x + 2}{x + 4} [/tex]
Undefined at,
X + 4 = 0
Move constant to R.H.S and change its sign
[tex]x = 0 - 4[/tex]
Calculate
[tex]x = - 4[/tex]
So, the answer is :
[tex] \frac{3x + 2}{x + 4} [/tex] , undefined at X = -4 and 4
Hope this helps..
Best regards!!
work out the shaded area.
plzzzz
Answer:
Shaded area: 70cm^2
Step-by-step explanation:
Whole=120cm^2
White Square=
10-2.5-2.5=5
12-1-1=10
5✖️10=50cm^2
Whole-white=70cm^2
The electromotive force V of an alternating current circuit at time t can be describe by the
following function, where V is volts and t is in seconds. V(t) = 220sin(180πt). How many cycles
will the circuit run through in 1 minute?
Answer:
5400 cycles
Step-by-step explanation:
You have the following function:
[tex]V(t)=220sin(180\pi t)[/tex]
where t is in seconds.
In order to find the number of cycles in 1 minute, you first calculate the frequency of the function, which is given by:
[tex]f=\frac{180\pi}{2\pi}=90s^{-1}[/tex]
The number of cycles is then given by:
[tex]n=ft=(90s^{-1})(60s)=5400\ cycles[/tex]
There are 5400 cycles in 1 minute
The x-coordinate of the intersection point of Line B D and Line C E is StartFraction 2 (a + c) Over 3 EndFraction. y = (StartFraction b Over a minus c EndFraction)x − (StartFraction 2 b c Over a minus 2 c EndFraction) y = (StartFraction b Over a minus 2 c EndFraction) (StartFraction 2 (a + c) Over 3 EndFraction) minus (StartFraction 2 b c Over a minus 2 c EndFraction) y = (StartFraction b Over a minus 2 c EndFraction) (StartFraction 2 (a + c) Over 3 EndFraction) minus (StartFraction 6 b c Over 3(a minus 2 c) EndFraction) y = StartFraction 2 b (a + c) minus 6 b c Over 3 (a minus 2 c) EndFraction y = StartFraction 2 a b + 2 b c minus 6 b c Over 3 (a minus 2 c) EndFraction What is the y-coordinate? StartFraction b c Over 3 EndFraction StartFraction 2 b Over 3 EndFraction StartFraction 2 b c Over 3 EndFraction StartFraction a b c Over 3 EndFraction
Answer:
y = 2b/3
Step-by-step explanation:
The x-coordinate of the intersection point of Line B D and Line C E is at [tex]\frac{2(a+c)}{3}[/tex]. Given that:
[tex]y=\frac{b}{a-2c}x -\frac{2bc}{a-2c} \\\\The\ y\ coordinate\ can\ be \ gotten\ by\ substituting\ the \ value\ of\ x\ and\ simplifying.\\ Substituting\ x:\\\\y=\frac{b}{a-2c}(\frac{2(a+c)}{3} ) -\frac{2bc}{a-2c}[/tex]
[tex]Simplyfing\ the\ parenthesis\\y=\frac{2b(a+c)}{3(a-2c)} -\frac{2bc}{a-2c}\\\\y=\frac{2ab+2bc}{3(a-2c)} -\frac{2bc}{a-2c}\\\\Simplyfying\ using\ LCF\\y=\frac{2ab+2bc-6bc}{3(a-2c)}\\\\y=\frac{2ab-4bc}{3(a-2c)}\\\\Factorizing:\\\\y=\frac{2b(a-2c)}{3(a-2c)}\\\\y=\frac{2b}{3}[/tex]
The y-coordinate of the intersection point of Line B D and Line C E is at [tex]\frac{2b}{3}[/tex].
Answer:
b
Step-by-step explanation:
What is 7/35 converted into a decimal??
Answer:
0.2
Step-by-step explanation:
it works out to be 0.2 as a decimal and 20% as a percentage.
Answer:
.2
Step-by-step explanation:
Karim sent a chain email to 10 of his friends. The number of people who got the email increases by a factor of 1.4 every week. Write a expression that give the number of people who got the email after 6 weeks?.
Answer:
10x1.4^6
Step-by-step explanation:
here are members on the board of directors for a certain non-profit institution. a. If they must elect a chairperson, first vice chairperson, second vice chairperson, and secretary, how many different slates of candidates are possible? b. If they must form an ethics subcommittee of four members, how many different subcommittees are possible?
Answer: 1320; 495
Step-by-step explanation:
Explanation is in the attachment file
Hurry help plz exam 05 :The following sphere has a diameter of 11 inches.
What is the volume of the sphere? Use 3.14 for it and round your answer to the nearest tenth.
O 5,572.5 in^3
O 696.6 in^3
O 174.1 in^3
O 126.6 in^3
Answer:
696.6 in³
Step-by-step explanation:
The formula for the volume of a sphere is 4/3πr³
The diameter of 11 in. is given. Therefore, the radius is 5.5 (11/2 = 5.5).
1. Set up the equation
4/3(3.14)(5.5³)
2. Solve
= 696.6 in³
Answer:
[tex]\boxed{Volume = 696.9 \ in.^3}[/tex]
Step-by-step explanation:
Diameter = 11 inches
Radius = 5.5 inches
Volume of sphere = [tex]\frac{4}{3} \pi r^3[/tex]
Where r = 5.5 inches
Volume = [tex]\frac{4}{3} (3.14)(5.5)^3[/tex]
Volume = [tex]\frac{4}{3} (3.14)(166.375)[/tex]
Volume = [tex]\frac{2090.7}{3}[/tex]
Volume = 696.9 in.³
YoIn a sale, the normal price of a book is reduced by 30%. The sale price of the book is £2.80 Work out the normal price of the book.
Answer: £4
Step-by-step explanation:
From the question, we are informed that when the normal price of a book is reduced by 30%, then the sale price of the book is £2.80.
Since the normal price of a book is reduced by 30%, that means the book is sold at (100% - 30%) = 70% of its normal price.
Let the normal price of the book be y.
70% of y = £2.80
70/100 × y = £2.80
0.7 × y = £2.80
0.7y = £2.80
y = £2.80/0.7
y = £4
The normal price of the book is £4.
identify the coefficient of X
1. 2x
2. -5x
3. 49x
4. -6x²
5. 3xy²
Answer:
2
-5
49
-6
3
Step-by-step explanation:
Coefficient is a number, value or item that serves as a measure of some property or characteristic.
or in other words a number that is added in front of a term.
Hope this helps ;) ❤❤❤
Evaluate the following: 3 to the power 2 ÷ (2 + 1). 2 3 4 5
Answer:
3
Step-by-step explanation:
A collection of 108 coins containing only quarters and nickels is worth $21. A table titled Coin Collection showing Number of Coins, Value, and Total. The first row shows Nickels, and has n, 0.05, and 0.05 n. The second row shows, Quarters, and has q, 0.25, and 0.25 q. The third row shows total, and has not entries. Which value could replace q on the chart? 21 108 21 – n 108 – n
Answer:
q = 108-n
Step-by-step explanation:
Given: 108 coins containing only quarters and nickels
q = 108-n
since total number of coins is 108, and n= number of nickels
If you want to know how many of each kind of coin, read on:
First solve the number of quarters and nickels.
If all 108 coins are quarters, the value is 108*0.25 = $27
Since this value exceed the actual by 27-21 = $6,
we replace a number of quarters by nickels.
Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.
So it will take 6/0.2 = 30 replacements.
Therefore there are 108-35 = 78 quarters and 30 nickels.
The solution is : q = 108-n, is the value could replace q on the chart.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
Given:
108 coins containing only quarters and nickels
q = 108-n
since total number of coins is 108, and n= number of nickels
If you want to know how many of each kind of coin, read on:
First solve the number of quarters and nickels.
If all 108 coins are quarters, the value is 108*0.25 = $27
Since this value exceed the actual by 27-21 = $6,
we replace a number of quarters by nickels.
Each replacement will reduce the value by 25 - 5 = 20 cents = 0.2 dollars.
So it will take 6/0.2 = 30 replacements.
Therefore there are 108-35 = 78 quarters and 30 nickels.
The solution is : q = 108-n, is the value could replace q on the chart.
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Clarise evaluated this expression.
(66.3 – 14.62) ÷ 0.6 – 0.22
(51.68) ÷ 0.6 – 0.22
(51.68) ÷ 0.42
51.68 ÷ 0.16
32.3
Which errors did Clarise make?
Answer:
(66.3-14.62)/0.6-0.22
(51.68)/0.6-0.22
(51.68/0.6)-0.22
(86.14667)-0.22
85.92667
Simplify.
N4 x N7 over n5
Answer:
[tex]n^6[/tex].
Step-by-step explanation:
[tex]n^4 * \frac{n^7}{n^5}[/tex]
= [tex]n^4 * n^{7 - 5}[/tex]
= [tex]n^4 * n^2[/tex]
= [tex]n^{4 + 2}[/tex]
= [tex]n^6[/tex].
Hope this helps!
Jim's living room is 23 feet wide and 25 feet long. He wants to put a border around the top of the room. The cost of the border is $1.00 per foot. How much will it cost to buy enough of the border to go around the room?
Answer:
$96.00
Step-by-step explanation:
Perimeter formula, 2w+2l
2(23)+2(25)=96 feet
1$ per foot
96 feet,
so $96
Answer:
I think it 96.00
Step-by-step explanation:
Please help, thanks :) (Question is attached below)
Answer:
Step-by-step explanation:
the upper left graph is the correct answer
because "... or equal to" always represents a filled dot, while just "greater/less than" represents blank dot
linear system please help 60 points * please please please help will give brainlist
Answer:
1. a. b = - 8
b. x = 8
c. x = 11
d. x = 5
2. 12 soccer balls and 8 basketballs can be purchased.
Step by step explanation
a. [tex] - 14 + 6b + 7 - 2b = 1 + 5b[/tex]
Calculate the sum
[tex] - 7 + 6b - 2b = 1 + 5b[/tex]
Collect like terms
[tex] 7 + 4b = 1 + 5b[/tex]
Move variable to L.H.S and change it's sign
Similarly, Move constant to R.H.S and change its sign
[tex]4b - 5b = 1 + 7[/tex]
Collect like terms
[tex] - b = 8[/tex]
Change the signs on both sides of the equation
[tex]b = - 8[/tex]
-----------------------------------------------------------------
b. [tex] \frac{5x + 10}{ - 6} = - 5[/tex]
Apply cross product property
[tex]5x + 10 = - 5 \times ( - 6)[/tex]
Multiply the numbers
[tex]5x + 10 = 30[/tex]
Move constant to R.H.S and change its sign
[tex]5x = 30 - 10[/tex]
Calculate the difference
[tex]5x = 20[/tex]
Divide both sides of the equation by 5
[tex] \frac{5x}{5} = \frac{20}{5} [/tex]
Calculate
[tex]x = 4[/tex]
----------------------------------------------------------------
c. [tex] - 15 = \frac{ - 8x - 17}{7} [/tex]
Apply cross product property
[tex] - 15 \times 7 = - 8x - 17[/tex]
Multiply the numbers
[tex] - 105 = - 8x - 17[/tex]
Swap the sides of the equation
[tex] - 8x - 17 = - 105[/tex]
Move constant to R.H.S and change its sign
[tex] - 8x = - 105 + 17[/tex]
Calculate
[tex] - 8x = - 88[/tex]
Change the signs on both sides of the equation
[tex]8x = 88[/tex]
Divide both sides of the equation by 8
[tex] \frac{8x}{8} = \frac{88}{8} [/tex]
Calculate
[tex]x = 11[/tex]
------------------------------------------------------------------
D. [tex]5 = 6x + 5(x - 10)[/tex]
Distribute 5 through the parentheses
[tex]5 = 6x + 5x - 50[/tex]
Collect like terms
[tex]5 = 11x - 50[/tex]
Swap both sides of the equation
[tex]11x - 50 = 5[/tex]
Move constant to R.H.S and change its sign
[tex]11x = 5 + 50[/tex]
Calculate the sum
[tex]11x = 55[/tex]
Divide both sides of the equation by 11
[tex] \frac{11x}{11} = \frac{55}{11} [/tex]
Calculate
[tex]x = 5[/tex]
------------------------------------------------------------------
2.
Solution,
No.of students in soccer = x
No.of students in basketball = y
Total no.of students = 20
i.e x + y = 20 → equation ( i )
Cost of soccer ball = $ 7
Cost of basketball = $ 10
Total budget = $ 164
i.e 7x + 10 y = 165 → equation ( ii )
In equation ( i ),
x + y = 20
Move 'y' to R.H.S and change its sign
x = 20 - y
Put the value of x in equation ( i )
[tex]7(20 - y) + 10y = 164[/tex]
[tex]140 - 7y + 10y = 164[/tex]
[tex]3y = 164 - 140[/tex]
[tex]3y = 24[/tex]
[tex]y = \frac{24}{3} [/tex]
[tex]y = 8[/tex]
Now, put the value of y in equation ( i ) ,
x + y = 20
[tex]x + 8 = 20[/tex]
[tex]x = 20 - 8[/tex]
[tex]x = 12[/tex]
Hence, 12 soccer balls and 8 basketballs can be purchased.
Hope this helps...
Best regards!!
Answer:
1. b = -8
2. x = 8
3. x = 11
4. x = 5
hope that helpwd
Help please you need to find the rise in the blue triangle. Thank you!!
Answer:
12.65
Step-by-step explanation:
In the case of the blue triangle, to calculate the rise, which would be the increase, therefore it would be the hypotenuse formed by the arrow.
We have to Pythagoras is:
h ^ 2 = a ^ 2 + b ^ 2
In this case:
a (x-axis) = 4
b (y-axis) = 12
replacing:
h ^ 2 = 4 ^ 2 + 12 ^ 2
h ^ 2 = 160
h = 12.65
Which means that the rise in the blue triangle is 12.65 units