Answer:
a)P(A1) = P( aaa, abc, acb ) = 1/3
P(A2) = P(aaa, bac, cab ) = 1/3
P(A3) = P(aaa, cba, bca ) = 1/3
b) To verify IF A1, A2 and A3 are independent we can see that
P( A1 and A2 and A3 ) = P( aaa ) = 1/9 is not equal to P(A1)P(A2)P(A3)
Step-by-step explanation:
Based on the given conditions The sample space S can be written as
aaa, bbb, ccc, abc, acb, bac, bca, cab,and cba = 9 most likely outcomes
Defining Ai ;which is the event that ith place in the triple is occupied by a
The probabilities of i=1,2,3 can be computed as
P(A1) = P( aaa, abc, acb ) = 1/3
P(A2) = P(aaa, bac, cab ) = 1/3
P(A3) = P(aaa, cba, bca ) = 1/3
P(A1 and A3) = P(A2 and A3 ) = P ( A1 and A3 ) = 1/9
THIS CAN BE EXPRESSED AS
P(A1)P(A2) = P(A2)P(A3) = P(A1)P(A3)
It can observed that
A1, A2, A3 are pair wise independent of each other
to verify this we can see that
P( A1 and A2 and A3 ) = P( aaa ) = 1/9 is not equal to P(A1)P(A2)P(A3)
Of the following points, name all that lie on the same horizontal line? (7,-1) (2,-1) (-3,9) (-3,-1)
Hey there!
If everything is on the same horizontal level, it is at the same elevation, or height. On a graph, the elevation is the y-value. So, if we want the points to on the same horizontal line, they have to have the same y-value.
The points that all share the y-value of -1 are (7,-1), (2,-1), and (-3,-1). Since (-3,9) is at a different y-value it is not on the horizontal line of y=-1.
Have a wonderful day!
Answer:
A (7,-1)
B (2,-1)
D (-3,-1)
Step-by-step explanation:
Well lets plot the following points on a graph first,
A (7,-1)
B (2,-1)
C (-3,9)
D (-3,-1)
Look at the image below ↓
By looking at the graph we can tell that points,
A, B, and D lie on the same horizontal line.
Thus,
points A, B, and D lie on the same horizontal line.
Hope this helps :)
Write the recursive sequence for: 64, 16, 4, 1, ...
Answer:
Use the formula
a
n
=
a
1
r
n
−
1
to identify the geometric sequence.
Step-by-step explanation:
a
n
=
64
4
n
−
1 hope this helps you :)
Answer: The answer is in the steps.
Step-by-step explanation:
f(1)= 64
f(n)=1/4(n-1) n in this case is the nth term.
A sample of 80 Valencia oranges showed a mean weight of 5.5 ounces with a standard deviation of 0.2 ounces. Obtain a 95% confidence interval for the weight of Valencia oranges. [5.495, 5.505 ] [0.195, 0.205] [ 5.456,5.544] [0.156, 0.244 )
Answer:
[ 5.456, 5.544]
Step-by-step explanation:
Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.
The confidence interval of a statistical data can be written as.
x+/-zr/√n
Given that;
Mean x = 5.5 ounces
Standard deviation r = 0.2 ounces
Number of samples n = 80
Confidence interval = 95%
z value (at 95% confidence) = 1.96
Substituting the values we have;
5.5+/-1.96(0.2/√80)
5.5+/-1.96(0.022360679774)
5.5+/-0.043826932358
5.5+/-0.044
= ( 5.456, 5.544) ounces
Therefore the 95% confidence interval (a,b) = ( 5.456, 5.544) ounces
Solve: -1/2+ c =31/4 c=8 c=7 c=33/4 c=29/4
Answer:
c = 29/4Step-by-step explanation:
[tex] - \frac{1}{2} + c = \frac{31 }{4} \\ \\ c = \frac{31}{4} + \frac{1}{2} = \frac{31 - 2}{4} \\ \\ c = \frac{29}{4} [/tex]
Hope this helps you
Given an objective function value of 150 and a shadow price for resource 1 of 5, if 10 more units of resource 1 are added (assuming the allowable increase is greater than 10), what is the impact on the objective function value?
Answer:
The impact on the objective function is that it is increased by 50.
Step-by-step explanation:
In this case we have that the value of the objective function is 150, and they tell us that 10 more units of resource one are added, but they tell us that the shadow price ranges from 1 to 5, therefore:
10 * 5 = 50
Which means that the impact on the objective function is that it is increased by 50.
Work out the circumference of this circle Give your answer in terms of pie and state in units R=14cm Answer= Units=
Answer:
28π cm²
Step-by-step explanation:
Circumference Formula: C = 2πr
Simply plug in r into the formula:
C = 2π(14)
C = 28π or 87.9646
Answer:
28π cm
Step-by-step explanation:
The circumference of a circle has the formula 2πr.
2 × π × r
Where r is the radius.
2 × π × 14
28 × π
= 28π
The circumference is 28π and the unit is centimeters.
Find an equation for the line perpendicular to =−3/2x+5 with y-intercept(0, -15).
Answer:
y = 2x/3 - 15
Step-by-step explanation:
Step 1: Find slope of perpendicular line
Take the negative reciprocal of the other line
m = 2x/3
Step 2: Rewrite equation (You already found b because it gave you y-int)
y = 2x/3 - 15
Find the value of x. Please help! Thanks.
Answer:
[tex]\huge\boxed{x=\sqrt{30}}[/tex]
Step-by-step explanation:
ΔABC and ΔBDC are similar (AAA).
Therefore the corresponding sides are in proportion:
[tex]\dfrac{AC}{BC}=\dfrac{BC}{CD}[/tex]
substitute
[tex]AC=7+3=10\\{BC}=x\\CD=3[/tex]
[tex]\dfrac{10}{x}=\dfrac{x}{3}[/tex] cross multiply
[tex](10)(3)=(x)(x)\\\\30=x^2\\\\x^2=30\to x=\sqrt{30}[/tex]
Tommy is thinking of a number between 800 and 900 He divides it by 4 and there is a remainder of 1 He divides it by 5 and there is a remainder of 1 He divides it by 6 and there is a remainder of 1 He divides it by 7 and there is a remainder of 1
What is Tommy's number?
Answer:
841
Step-by-step explanation:
If the number is divided by 4 and the remainder is 1, the last digit must be 1, 3, 5, 7 or 9.
If the number is divided by 5 and the remainder is 1, the last digit must be 6 or 1.
So we already know the last digit must be 1.
The numbers between 800 and 900, with last digit 1, that divided by 6 have a remainder of 1 are:
811, 841, 871
The numbers between 800 and 900, with last digit 1, that divided by 7 have a remainder of 1 is just 841
So Tommy's number is 841.
Tommy's number is 841.
In this question we must determine first the least common number of 4, 5, 6 and 7, which is the product of these four numbers, that is to say:
[tex]x = 4\times 5\times 6 \times 7[/tex]
[tex]x = 840[/tex]
This is the least number that is divisible both for 4, 5, 6 and 7. Now we add this number by 1 to determine what number Tommy thought:
[tex]y = x + 1[/tex]
[tex]y = 841[/tex]
Tommy's number is 841.
To learn more on divisibility, we kindly invite to check the following verified question: https://brainly.com/question/369266
based off the data of ages of the last six US presidents( 69, 64, 46, 54, 47, and 70) What percentage of presidents ages fall within one standard deviation of the mean? (Round to one decimal place
Answer:
[tex]\bar X=\frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] \bar X= 58.33[/tex]
[tex]s= 10.78[/tex]
Then we can fin the limits for one deviation within the mean like this:
[tex]\mu -\sigma = 58.33-10.78= 47.55[/tex]
[tex]\mu -\sigma = 58.33+10.78= 69.11[/tex]
And then we see that the number of values between the limits are: 69, 64, 54,47 who represent 4 and then the percentage would be:
[tex]\% =\frac{4}{6}*100 =66.7\%[/tex]
Step-by-step explanation:
First we need ot calculate the mean and deviation with the following formulas:
[tex]\bar X=\frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] \bar X= 58.33[/tex]
[tex]s= 10.78[/tex]
Then we can fin the limits for one deviation within the mean like this:
[tex]\mu -\sigma = 58.33-10.78= 47.55[/tex]
[tex]\mu -\sigma = 58.33+10.78= 69.11[/tex]
And then we see that the number of values between the limits are: 69, 64, 54,47 who represent 4 and then the percentage would be:
[tex]\% =\frac{4}{6}*100 =66.7\%[/tex]
Given that IG is perpendicular to FT, which of the following statements is true?
Answer:
B ). IF = IT
Step-by-step explanation:
IG is perpendicular to FT, means that the line IG divides the line FT into two equal parts without remainder.
Line IG does not only divide line FT, it also bisect the arc FT into two equally parts also.
It also divide the segment of the circle FIT into two equal parts.
So to the correct answer to the question, IF = IT
3p-11=19 helpppppppp
Answer:
10Step-by-step explanation:
[tex]3p - 11 = 19[/tex]
Move constant to R.H.S and change its sign
[tex]3p = \: 19 + 11[/tex]
Add the numbers
[tex]3p = 30[/tex]
Divide both sides of the equation by 3
[tex] \frac{3p}{3} = \frac{30}{3} [/tex]
Calculate
[tex]p = 10[/tex]
Hope this helps..
Best regards!!
Answer:
p = 10
Step-by-step explanation:
Solve for p (make p the subject)
3p -11 =19 (add 11 to both sides)
3p = 30 (divide by 3)
p = 10
I HOPE THIS HELPED :)
In 1968, vehicle emission standards allowed
6.3 hydrocarbons released per mile driven. By 1980, the
standards allowed only 0.41 hydrocarbons per mile driven.
What was the rate of change from 1968 to 1980?
Answer:
Step-by-step explanation:
In 1968, vehicle emission standards allowed 6.3 hydrocarbons released per mile driven and by 1980, the
standards allowed only 0.41 hydrocarbons per mile driven. This means that the change in the amount of hydrocarbons released per mile driven as allowed by the vehicle emission standards between 1968 and 1980 is
6.3 - 0.41 = 5.89
Therefore, the percentage rate of change in the amount of hydrocarbons released per mile driven as allowed by the vehicle emission standards between 1968 and 1980 would be
5.89/6.3 × 100 = 93.49%
please answer this fast in 2 minutes
Answer:
(9, -1)
Step-by-step explanation:
Midpoint Formula: [tex](\frac{x1+x2}{2}, \frac{y1+y2}{2} )[/tex]
Since we already have 1 endpoint and the midpoint, all we need to do is set the equation up to find the other endpoint:
12.5 = (16 + x)/2
25 = 16 + x
x = 9
-4 = (-7 + y)/2
-8 = -7 + y
y = -1
Answer:
(9, -1)
Step-by-step explanation:
(16 + x)/2= 12.5
16 + x = 25
x = 9
(-7 + y)/2 = -4
-7 + y = -8
y = -1
Consider the following hypothesis test:
H0:
≤ 50
Ha: > 50
A sample of 55 is used and the population standard deviation is 6. Use the critical value approach to state your conclusion for each of the following sample results. Use = .05.
a. With = 52.5, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
b. With = 51, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
c. With = 51.8, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
Answer:
a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.
b. z=1.24. No, it can not be concluded that the population mean is greater than 50.
c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.
Step-by-step explanation:
We have a hypothesis test for the mean, with the hypothesis:
[tex]H_0: \mu\leq50\\\\H_a:\mu> 50[/tex]
The sample size is n=55 and the population standard deviation is 6.
The significance level is 0.05.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809[/tex]
For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.
a. If the sample mean is M=52.5, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09[/tex]
The null hypothesis is rejected, as z>zc and falls in the rejection region.
b. If the sample mean is M=51, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24[/tex]
The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.
c. If the sample mean is M=51.8, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22[/tex]
The null hypothesis is rejected, as z>zc and falls in the rejection region.
What is the product of all positive factors of 6?
Answer:
36
Step-by-step explanation:
All the factors of 6 are 1, 2, 3, and 6.
The factors are positive.
Find the product.
1 × 2 × 3 × 6
6 × 6 = 36
Answer: 36
Step-by-step explanation:
The positive factors of 6 are 1,2,3 and 6 .
Now to find their product multiply them all together.
1 * 2 * 3 * 6 = 36
replace each star with a digit to make the problem true.Is there only one answer to each problem? ****-***=2
Answer: We have two solutions:
1000 - 998 = 2
1001 - 999 = 2
Step-by-step explanation:
So we have the problem:
****-*** = 2
where each star is a different digit, so in this case, we have a 4 digit number minus a 3 digit number, and the difference is 2.
we know that if we have a number like 99*, we can add a number between 1 and 9 and we will have a 4-digit as a result:
So we could write this as:
1000 - 998 = 2
now, if we add one to each number, the difference will be the same, and the number of digits in each number will remain equal:
1000 - 998 + 1 - 1 = 2
(1000 + 1) - (998 + 1) = 2
1001 - 999 = 2
now, there is a trivial case where we can find other solutions where the digits can be zero, like:
0004 - 0002 = 2
But this is trivial, so we can ignore this case.
Then we have two different solutions.
Priya was busy studying this week and ran 7 fewer miles than last week. She ran 3 times as far as Elena ran this week. Elena only had time to run 4 miles this week. How many miles did Priya run last week?
Answer:Priya ran 19 miles last week
Step-by-step explanation:
4 x 3 = 12
12 + 7 = 19
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimeters and an unknown population mean. A random sample of 15 saplings is taken and gives a sample mean of 308 millimeters. Find the confidence interval for the population mean with a 99%z0.10 z0.05 z0.025 z0.01 z0.0051.282 1.645 1.960 2.326 2.576
Answer:
[tex]296.693\leq x\leq 319.307[/tex]
Step-by-step explanation:
The confidence interval for the population mean x can be calculated as:
[tex]x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }[/tex]
Where x' is the sample mean, s is the population standard deviation, n is the sample size and [tex]z_{\alpha /2}[/tex] is the z-score that let a proportion of [tex]\alpha /2[/tex] on the right tail.
[tex]\alpha[/tex] is calculated as: 100%-99%=1%
So, [tex]z_{\alpha/2}=z_{0.005}=2.576[/tex]
Finally, replacing the values of x' by 308, s by 17, n by 15 and [tex]z_{\alpha /2}[/tex] by 2.576, we get that the confidence interval is:
[tex]308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307[/tex]
Which of the following is the quotient of the rational expressions shown below?
Answer:
Option (1)
Step-by-step explanation:
The given expression in the figure attached is,
[tex]\frac{(2x+5)}{3x}[/tex] ÷ [tex]\frac{(2x-1)}{(2x+1)}[/tex]
We further simplify this expression,
[tex]\frac{(2x+5)}{3x}[/tex] ÷ [tex]\frac{(2x-1)}{(2x+1)}[/tex]
= [tex]\frac{(2x+5)}{3x}\times \frac{(2x+1)}{(2x-1)}[/tex]
= [tex]\frac{2x(2x+1)+5(2x+1)}{3x(2x-1)}[/tex] [By distributive property]
= [tex]\frac{4x^2+2x+10x+5}{6x^{2}-3x}[/tex]
= [tex]\frac{4x^2+12x+5}{6x^2-3x}[/tex]
Therefore, Option (1) will be the answer.
who want brainliest answer these questions
Answer: top left: balanced top right: left side is down
bottom left: right side is down bottom right: left side is down
Step-by-step explanation:
top left top right
left side right side left side right side
2(40) 20(4) 2(4) 3(2)
80 = 80 8 ≠ 6
Balanced down up
bottom left bottom right
left side right side left side right side
2(.75) 4(.5) .8(450) 7.3(.2)
1.5 ≠ 2.0 360 ≠ 1.46
up down down up
I need help with this question.
Answer:
b. 14
Step by step explanation:
If two events are mutually exclusive, why is ? Choose the correct answer below. A. because A and B each have the same probability. B. because A and B cannot occur at the same time. C. because A and B are independent. D. because A and B are complements of each other.
Answer:
B. because A and B cannot occur at the same time.
Step-by-step explanation:
If two events are mutually exclusive, why is ? Choose the correct answer below.
A. because A and B each have the same probability.
B. because A and B cannot occur at the same time.
C. because A and B are independent.
D. because A and B are complements of each other.
What is the solution of the system? {2x+y=15x−y=3 Enter your answer in the boxes. ( , )
Step-by-step explanation:
2x+y=15x-y=3
then u group like terms
2x-15x= -y+y=3
then ur answer
13x=3
Given the parametric equations below, eliminate the parameter t to obtain an equation for y as a function of x { x ( t ) = 5 √ t y ( t ) = 7 t + 4
Answer:
y(x) = (7/25)x^2 + 4
Step-by-step explanation:
Given:
x = 5*sqrt(t) .............(1)
y = 7*t+4 ..................(2)
solution:
square (1) on both sides
x^2 = 25t
solve for t
t = x^2 / 25 .........(3)
substitute (3) in (2)
y = 7*(x^2/25) +4
y= (7/25)x^2 + 4
The demand for Carolina Industries’ product varies greatly from month to month. Based on the past two years of data, the following probability distribution shows the company’s monthly demand: Unit Demand Probability 300 0.20 400 0.30 500 0.35 600 0.15 c. What are the variance and standard deviation for the number of units demanded?
Answer:
The variance is "9475" and standard deviation is "97.3396112".
Step-by-step explanation:
Let's all make the assumption that X seems to be the discrete uniformly distributed random indicating demand for units, and that f(x) has been the corresponding probability.
The expected value of the monthly demand will be:
⇒ [tex]E(X)=\sum_{x} x\times f(x)[/tex]
⇒ [tex]=00\times 0.20+400\times 0.30+500\times 0.35+600\times 0.15[/tex]
⇒ [tex]=445 \ units[/tex]
The variance will be:
⇒ [tex]Var(X)=E(X^2)-{E(X)}^2[/tex]
⇒ [tex]E(X^2)=\sum_{x} x^2\times f(x)[/tex]
[tex]=(300)^2\times 0.20+(400)^2\times 0.30+(500)^2\times 0.35+(600)^2\times 0.15[/tex]
[tex]=207500[/tex]
⇒ [tex]Var(X)=207500 - (445)^2[/tex]
[tex]=9475[/tex]
The standard deviation will be:
⇒ [tex]X=\sqrt{var(X)}[/tex]
[tex]=97.3396112[/tex]
Manueala scored -4 \dfrac12−4 2 1 minus, 4, start fraction, 1, divided by, 2, end fraction points relative to her season average against the China Dragons. She scored 1 \dfrac121 2 1 1, start fraction, 1, divided by, 2, end fraction points relative to her season average against the Canada Moose. Drag the white cards onto the gray rectangle to write an inequality that correctly compares Manueala's relative numbers of points. Which one of the following descriptions is correct? Choose 1 answer: Choose 1 answer: (Choice A) A Manueala scored more points against the China Dragons than against the Canada Moose. (Choice B) B Manueala scored more points against the Canada Moose than against the China Dragons.
Answer:
1 1/2 > - 4 1/2 and Manuela scored more points against the Canada Moose than against the China Dragons.
Fredrick hit 14, 18, 13, 12, 12, 16, 13, 12, 1, and 15 home runs in 10 seasons of play. Which statements are correct? Check all that apply. Fredrick’s data set contains an outlier. The median value is 12 home runs. The mean value is about 12.6 home runs. The median describes Fredrick’s data more accurately than the mean. The mean value stays the same when the outlier is not included in the data set.
Answer:
(a) Yes, Fredrick’s data set contains an outlier.
(b) No, the median value is not 12 home runs.
(c) Yes, the mean value is about 12.6 home runs.
(d) Yes, the median describes Fredrick’s data more accurately than the mean.
(e) No, the mean value doesn't stay the same when the outlier is not included in the data set.
Step-by-step explanation:
We are given that Fredrick hit 14, 18, 13, 12, 12, 16, 13, 12, 1, and 15 home runs in 10 seasons of play.
Firstly, arranging our data set in ascending order we get;
1, 12, 12, 12, 13, 13, 14, 15, 16, 18.
(a) The statement that Fredrick’s data set contains an outlier is true because in our data set there is one value that stands out from the rest of the data, which is 1.
Hence, the outlier value in the data set is 1.
(b) For calculating median, we have to first observe that the number of observations (n) in the data set is even or odd, i.e;
If n is odd, then the formula for calculating median is given by;Median = [tex](\frac{n+1}{2})^{th} \text{ obs.}[/tex]
If n is odd, then the formula for calculating median is given by;Median = [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+(\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]
Here, the number of observations in Fredrick's data set is even, i.e. n = 10.
SO, Median = [tex]\frac{(\frac{n}{2})^{th} \text{ obs.}+(\frac{n}{2}+1)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{(\frac{10}{2})^{th} \text{ obs.}+(\frac{10}{2}+1)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{(5)^{th} \text{ obs.}+(6)^{th} \text{ obs.} }{2}[/tex]
= [tex]\frac{13+13 }{2}[/tex] = 13 home runs
So, the statement that the median value is 12 home runs is not correct.
(c) The mean of the data set is given by;
Mean = [tex]\frac{1+ 12+ 12+ 12+ 13+ 13+14+ 15+ 16+ 18}{10}[/tex]
= [tex]\frac{126}{10}[/tex] = 12.6 home runs
So, the statement that the mean value is about 12.6 home runs is correct.
(d) The statement that the median describes Fredrick’s data more accurately than the mean is correct because even if the outlier is removed from the data set, the median value will remain unchanged but the mean value gets changed.
(e) After removing the outlier, the data set is;
12, 12, 12, 13, 13, 14, 15, 16, 18.
Now, the mean of the data = [tex]\frac{12+12+ 12+ 13+ 13+ 14+ 15+ 16+ 18}{9}[/tex]
= [tex]\frac{125}{9}[/tex] = 13.89
So, the statement that the mean value stays the same when the outlier is not included in the data set is incorrect.
Answer:
Fredrick’s data set contains an outlier.
The mean value is about 12.6 home runs.
The median describes Fredrick’s data more accurately than the mean.
Step-by-step explanation:
If you can help with the explanation I will mark brainpower
Answer:
It is 90º
Step-by-step explanation:
Looking at the picture, we realize that the angle direcly beside it, EGD, is 90º. Now, both angles form a straight line, which equals 180º. 180-90= 90º.
Answer: A 40 B 50 C 90 D 130
where they go: B goes under A, D goes under the whole thing, just like E (although that doesn't want to be answered) and C goes under B
hope this helped
What is the 20th digit in the decimal expansion for the sum of 2/9 and 1/7
Answer:
The 20th digit is 6.
Step-by-step explanation:
1. Add 2/9 and 1/7.
2/9 + 1/7 = 23/63
2. Convert to a decimal.
23 ÷ 63 = 0.365079...
If you continue to divide, you will notice that the number repeat. So, the decimal would be 0.365079365079...
3. Find the 20th digit.
0.365079365079365079365079
Answer:
6
Step-by-step explanation:
Aops question
We have $\frac29 + \frac17 = \frac{14}{63} + \frac{9}{63} = \frac{23}{63}$. Expressing $\frac{23}{63}$ as a decimal using long division, we find $\frac{23}{63}=0.\overline{365079}$. Therefore, every 6th digit after the decimal point is a 9. So, the 18th digit is a 9; the 20th digit is 2 decimal places later, so it is a $\boxed{6}$.
It's in Latex