Let the retention factor of species A be 0.5, while the retention factor of species B be 0.3. If species A moves 1.0 cm how far does species B move

Answers

Answer 1

Answer:

The correct answer is - 1.2 cm.

Explanation:

The retention factor is represented by Rf.

Given:

Rf of species A is = 0.5

Rf of species B is = 0.6

Formula:

Rf = distance the compound moves/distance the solvent moves

Rf(A)/Rf(B) = [tex]\frac{distance moved by A/distance moved by solvent}{distance moved by B/distance moved by solvent}[/tex]

Rf(A)/Rf(B) = distance moved by A/distance moved by B

0.5/0.6 = 1/distance moved by B

distance moved by B = 0.5/0.6

= 1.2 cm

Answer 2

The distance traveled by species B if species A moves 1.0 cm is 0.6 cm

The Retention factor [tex]\mathbf{R_f}[/tex] is the ratio of the distance moved by the species by the distance moved by the solvent front.

From the information given:

[tex]\mathbf{R_f(A) = 0.5}[/tex][tex]\mathbf{R_f(B) = 0.3}[/tex]

For specie A;

[tex]\mathbf{0.5 = \dfrac{1.0 \ cm}{distance \ moved \ by \ solvent \ front}}[/tex]

[tex]\mathbf{distance \ moved \ by \ solvent \ front= \dfrac{1.0 \ cm}{0.5}}[/tex]

distance moved by solvent front = 2 cm

For specie B;

The distance traveled by the species B will be:

= 0.3 × 2.0 cm

= 0.6 cm

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