Answer:
(g• h) (3) = 26Step-by-step explanation:
g(x) = 2x
h(x) = x² + 4
To find (g• h) (3) first find ( g • h)(x)
To find ( g • h)(x) substitute h(x) into every x in g(x)
That's
( g • h)(x) = 2( x² + 4)
( g • h)(x) = 2x² + 8
Now substitute 3 into ( g • h)(x)
(g• h) (3) = 2(3)² + 8
= 2(9) + 8
= 18 + 8
(g• h) (3) = 26Hope this helps you
Find the value of x for which
A.31
B.43
C.121
D.47
Answer:
The value of x is 31°
Step-by-step explanation:
As we can see, the two angles at the bottom of the shape are base angles. These angles both form right angles which means they both have a measurement of 90°. Knowing this information, we can set up an equation to solve for x.
47 + (x + 12) = 90
47 + x + 12 = 90
Add 12 to 47.
59 + x = 90
Subtract 59 on both sides of the equation.
x = 31
The value of x is equal to 31.
What is the greatest common factor of the polynomial below 12x^2-9x
Answer:
the greatest common factor of this is 3
What are the mathematical names for these shapes
Answer:
Step-by-step explanation:
The top is rectangular pyramid
The second a sphere
The third is a cube
Triangular pyramid is the last
The earth is about 12,760 km in diameter and about 150 million kilometers away from the sun. The nearest stars besides the Sun are about 4.3 light-years away (1 light-year equals = 9.5 times 10 Superscript 12 Baseline km 9.5×1012 km). At a scale of 1 to 10 billion, the Sun would be about the size of a grapefruit. How big and how far away would the Earth be on this scale? How far would the nearest stars (besides the Sun) be? 1
Answer:
Rating of size of earth to sun = 5
Distance of earth from sun = 0.15 billion
The earth is 9.500015*10^12km from the star.
Step-by-step explanation:
Let's assume the grape fruit size is 10.
If from one to one billion the sun gas 10 and the sun is as big as. Double of the earth ,the the earth has 5
The earth is 150 million away from the sun.
In the ratio ofone billion it is = 150000000/1000000000
= 0.15 billion
The distance between a nearest star and the earth would be the distance of the sun to a nearest star plus distance of the earth to the sun
The star is one light year = 9.5*10^12 km From the sun
The earth is= 150 million kilometers from The sun
= 9.5*10^12 km + 1.5*10^8km
= 9.5*10^12 + 0.00015*10^12
=( 9.5+0.00015)*10^12
= 9.500015*10^12km
The earth is 9.500015*10^12km from the star.
Which graph represents the function?
the answer is the bottom left option
John multiplied 400,000 by 7,800 on his calculator. He got the result shown on his calculator display. What is this number in standard form? A calculator screen that shows 3 point 1 2 E 9. A 0.00000000312 B 0.000000312 C 312,000,000 D 3,120,000,000
Answer:
D
Step-by-step explanation:
jtrsytexjgfcgvhjbkjnhgfdsasdfghjhgrertyu
Answer:
Correct answer is D
Step-by-step explanation:
If 10 is added to the maximum value and 10 is subtracted from the minimum value of a set of ages of citizens waiting in line to vote, which of the following is true? a-The mean age and median age are unchanged. b-The mean age changes but the median age does not change. c- The median age changes but the mean age does not change. d-The effect on the mean and median cannot be determined without knowing the other ages. e-None of these.
Answer:
a-The mean age and median age are unchanged.
Step-by-step explanation:
By adding the same you are subtracting, the sum of the ages remains the same. Therefore, the mean remains the same since you are dividing the same total of ages by the same number of people.
The middle number continues to be the middle number, so the median also does not change.
Try an example.
The ages are 30, 40, 50, 60, 70
Mean = (30 + 40 + 50 + 60 + 70)/5 = 250/5 = 50
Median: 50
Now add 10 to the greatest value and subtract 10 from the least value.
The ages now are 20, 40, 50, 60, 80
Mean = (20 + 40 + 50 + 60 + 80)/5 = 250/5 = 50
Median: 50
As you can see, both the mean and the median did not change.
Answer: a-The mean age and median age are unchanged.
Answer:
The mean age and median age are unchanged
Step-by-step explanation:
The median will not change when we alter the lowest and highest values so we can eliminate the answers that say the median changes
The mean is found by adding the values together and dividing by the number of values
If we add 10 and subtract 10, we have not changed the total value before dividing, so the mean does not change
The hardware store where you work charge 80 cents including tax, for a pound of nails. A customer purchases 5 3/4 pound of nails. How much should you charge the customer for nails?
Answer:
4.60
Step-by-step explanation:
multiply 5.75 and 0.80 to get 4.60
Answer:
460
Step-by-step explanation:
x/80 = 5 3/4 or 23/4
23*80= 1,840
1,840/4 = 460
(1 point) A vendor sells ice cream from a cart on the boardwalk. He offers vanilla, chocolate, strawberry, blueberry, and pistachio ice cream, served on either a waffle, sugar, or plain cone. How many different single-scoop ice-cream cones can you buy from this vendor
Answer:
six single scoops icecream cones
a bag contains 6 cherry 3 orange and 2 lemon candies. You reach in and take 3 pieces of candy at random. Find the probability of all lemons
Answer:
0.181818
Step-by-step explanation:
There are total 11 candies. The possibility of combinations is 165 which is found by using computation technique 11C3. It is assumed that order does not matter. There are 3 pieces of candy are selected at random. There are 6C2 which is 15 different ways to select cherry and lemon. There are 30 ways to choose 2 cherry and a lemon combination. The probability is [tex]\frac{30}{165}[/tex] = 0.181818
At an international conference, flags from 8 different countries will be displayed. Of these flags, 4 are from the continent of Africa and 4 flags are from the continent of Europe. The flags will be displayed in a row, alternating between continents. A flag from Africa will be in the first position. In how many ways can the flags be displayed?
Answer:
96 ways
Step-by-step explanation:
Let´s call flags of countries from Africa as A₁, A₂, A₃, A₄, and from Europe as E₁, E₂, E₃ and E₄
We have to display the flags always beginning with one flag from Africa let´s take A₁
For that flag, we have 4! possibilities Then 4! is:
4*3*2*1 = 24
As we have 4 different Flags from Africa, we will have
4*24 = 96 possibilities
Consider the following hypothesis test:
H0:
≤ 50
Ha: > 50
A sample of 55 is used and the population standard deviation is 6. Use the critical value approach to state your conclusion for each of the following sample results. Use = .05.
a. With = 52.5, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
b. With = 51, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
c. With = 51.8, what is the value of the test statistic (to 2 decimals)?
Can it be concluded that the population mean is greater than 50?
Yes or No
Answer:
a. z=3.09. Yes, it can be concluded that the population mean is greater than 50.
b. z=1.24. No, it can not be concluded that the population mean is greater than 50.
c. z=2.22. Yes, it can be concluded that the population mean is greater than 50.
Step-by-step explanation:
We have a hypothesis test for the mean, with the hypothesis:
[tex]H_0: \mu\leq50\\\\H_a:\mu> 50[/tex]
The sample size is n=55 and the population standard deviation is 6.
The significance level is 0.05.
We can calculate the standard error as:
[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{55}}=0.809[/tex]
For a significance level of 0.05, the critical value for z is zc=1.644. If the test statistic is bigger than 1.644, the null hypothesis is rejected.
a. If the sample mean is M=52.5, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{52.5-50}{0.809}=\dfrac{2.5}{0.809}=3.09[/tex]
The null hypothesis is rejected, as z>zc and falls in the rejection region.
b. If the sample mean is M=51, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51-50}{0.809}=\dfrac{1}{0.809}=1.24[/tex]
The null hypothesis failed to be rejected, as z<zc and falls in the acceptance region.
c. If the sample mean is M=51.8, the test statistic is:
[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{51.8-50}{0.809}=\dfrac{1.8}{0.809}=2.22[/tex]
The null hypothesis is rejected, as z>zc and falls in the rejection region.
what is Divide −240 by 8
The division -240 by 8 gives the quotient is -30.
What is Division?The division is one of the four introductory fine operations, the other three being addition, deduction, and addition. In simple words, division can be defined as the splitting of a large group into lower groups similar that every group will have an equal number of particulars. It's an operation used for equal grouping and equal sharing in calculation.
We have to divide -240 by 8.
So, the division is
8 | -240 | 30
24
____
00
Thus, the quotient is -30.
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Emily and George had a farm with a new barn.
True
False
Answer:
true
Step-by-step explanation:
it is so because they are brother and sister
And in the chapter there is that they had farm with a new barn
if in your book lesson there is that they had no farm with a new barn then there will be false
Now did you understood?
Answer:
True
Step-by-step explanation:
Someone help me please pls pls pls
Answer:
There is 9 on each pace and 3 on a row
Step-by-step explanation:
54/6=9
if there is 9 on each side and the same on each side, then it has to be 3 in each row and column. Also, this is a Rubix cube
Please give me brainliest, it really helps! :)
Have a good day!
Please answer this correctly
Answer:
9/49
Step-by-step explanation:
The probability of landing on an even number is 3/7.
Because there are only 3 numbers even out of 7 total numbers.
[tex]3/7 \times 3/7[/tex]
[tex]= 9/49[/tex]
The displacement, d, in millimeters of a tuning fork as a function of time, t, in seconds can be modeled with the equation d = 0.6 sine (3520 pi t). What is the frequency of the tuning fork?
Answer:
The frequency of the tuning fork is 1760 Hz.
Step-by-step explanation:
Suppose we have a sine function in the following format:
[tex]y = A\sin{Bx + C}[/tex]
The period is:
[tex]T = \frac{2\pi}{B}{/tex]
The frequency, in Hz, is:
[tex]F = \frac{1}{T}[/tex]
In this question:
[tex]d = 0.6\sin{3520\pi t}[/tex]
So
[tex]B = 3520\pi, T = \frac{2\pi}{3520} = \frac{2}{3520}, F = \frac{1}{T} = \frac{1}{\frac{2}{3520}} = \frac{3520}{2} = 1760[/tex]
The frequency of the tuning fork is 1760 Hz.
Answer:
its C. 1760 Hz
on edge2020
A Norman window has the shape of a rectangle surmounted by a semicircle. (Thus the diameter of the semicircle is equal to the width of the rectangle.) If the perimeter of the window is 30 ft, find the dimensions of the window so that the greatest possible amount of light is admitted.
The dimensions of the Norman window that admit the greatest possible amount of light are approximately:
Width (w) ≈ 11.72 ft
Height (h) ≈ 2.91 ft
To find the dimensions of the Norman window that admit the greatest possible amount of light, we need to maximize the area of the window. The window consists of a rectangle and a semicircle, so the area is the sum of the areas of both shapes.
Let's assume the width of the rectangle is "w" and the radius of the semicircle is "r".
Since the diameter of the semicircle is equal to the width of the rectangle, the radius "r" is half of "w".
Area of the rectangle = w * h, where h is the height of the rectangle.
Area of the semicircle = (1/2) * π * r²
The perimeter of the window is given as 30 ft, which can be written as:
Perimeter = 2 * (w + h) + π * r + w
Since r = w/2, we can rewrite the perimeter equation as:
Perimeter = 2 * (w + h) + (π/2) * w + w
Perimeter = 2w + 2h + (π/2 + 1) * w
Given that the perimeter is 30 ft, we have:
30 = 2w + 2h + (π/2 + 1) * w
Now, we can express "h" in terms of "w" using the perimeter equation:
h = (30 - 2w - (π/2 + 1) * w) / 2
Next, let's express the area "A" of the window in terms of "w" using the formulas for the area of the rectangle and the semicircle:
Area (A) = Area of rectangle + Area of semicircle
A = w * h + (1/2) * π * r²
A = w * ((30 - 2w - (π/2 + 1) * w) / 2) + (1/2) * π * (w/2)²
A = w * ((30 - 2w - (π/2 + 1) * w) / 2) + (1/2) * π * (w² / 4)
Now, we want to maximize the area "A."
To find the maximum value, we take the derivative of "A" with respect to "w" and set it equal to zero:
dA/dw = (30 - 2w - (π/2 + 1) * w) / 2 + (π/4) * w = 0
Solving for "w":
(30 - 2w - (π/2 + 1) * w) / 2 + (π/4) * w = 0
(30 - 2w - (π/2 + 1) * w) + (π/2) * w = 0
(30 - (2 + π/2) * w) + (π/2) * w = 0
30 - (2 + π/2) * w + (π/2) * w = 0
(30 - 2w) + (π/2 - π/4) * w = 0
30 - 2w + (π/4) * w = 0
(π/4) * w - 2w = -30
w ((π/4) - 2) = -30
w = -30 / ((π/4) - 2)
w ≈ 11.72 ft
Now that we have the value of "w," we can find the value of "h" using the perimeter equation:
Perimeter = 2w + 2h + (π/2 + 1) * w
30 = 2(11.72) + 2h + (π/2 + 1) * (11.72)
30 = 23.44 + 2h + (π/2 + 1) * 11.72
2h = 30 - 23.44 - (π/2 + 1) * 11.72
2h = 6.56 - (π/2 + 1) * 11.72
h = (6.56 - (π/2 + 1) * 11.72) / 2
h ≈ 2.91 ft
So, the dimensions of the Norman window that admit the greatest possible amount of light are approximately:
Width (w) ≈ 11.72 ft
Height (h) ≈ 2.91 ft.
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How long will it take 3800 to grow into 5700 if it’s invested at 6% interest compounded continuously?
Answer:
1234567891234567890
Answer: 25 years
Step-by-step explanation:
t = I / Pr
t = 5700 / ( 3800 × 0.06 ) = 25
t = 25 years
Please help me!!!!!!!!
Step-by-step explanation:
might be option c is a correct answer of your given question
If f()=
X
3 and g(x) = 4x2 + x - 4, find (f+ g)(x).
O A. 4x²
** Ex-1
O B. 6x2 - 7
2
O C. 4x2 +1x-1
D. 4x2 + 3x - 7
o
Answer:
[tex](f + g)(x) = 4x^2 + x - 7[/tex]
Step-by-step explanation:
f(x) = -3
[tex]g(x) = 4x^2 + x - 4[/tex]
To find (f + g)(x), we simply have to find f(x) + g(x) .
[tex](f + g)(x) = f(x) + g(x) = -3 + 4x^2 + x - 4\\\\(f + g)(x) = 4x^2 + x - 4 - 3\\\\(f + g)(x) = 4x^2 + x - 7[/tex]
Please hurry, thanks.
Answer:
-3x-y=5, 15x=10-5y
Step-by-step explanation:
-3x-y=5
*(-5) *(-5)
15x+5y=-25 (1)
15x=10-5y
+5y +5y
15x+5y=10 (2)
impossible (1) and (2)
The average annual cost (including tuition, room, board, books and fees) to attend a public college takes nearly a third of the annual income of a typical family with college-age children (Money, April 2012). At private colleges, the average annual cost is equal to about 60% of the typical family's income. The following random samples show the annual cost of attending private and public colleges. Data are in thousands of dollars.Private Colleges 52.8 30.6 43.2 45.8 45.0 37.8 33.3 50.5 44.0 42.0 Public Colleges 20.3 22.8 22.0 25.8 28.2 18.5 15.6 25.6 24.1 14.4 28.5 21.8 a. Compute the sample mean and sample standard deviation for private and public colleges. Round your answers to two decimal places.
S1 =
S2 =
b. What is the point estimate of the difference between the two population means? Round your answer to one decimal place.
Interpret this value in terms of the annual cost of attending private and public colleges.$
c. Develop a 95% confidence interval of the difference between the annual cost of attending private and pubic colleges.
95% confidence interval, private colleges have a population mean annual cost $ to $ more expensive than public colleges.
Answer:
Step-by-step explanation:
a) For private colleges,
Mean = (52.8 + 30.6 + 43.2 + 45.8 + 45.0 + 37.8 + 33.3 + 50.5 + 44.0 + 42.0)/10 = 42.5
x1 = 42.5 × 1000 = 42500
Standard deviation = √(summation(x - mean)²/n
n = 10
Summation(x - mean)² = (52.8 - 42.5)^2 + (30.6 - 42.5)^2 + (43.2 - 42.5)^2 + (45.8 - 42.5)^2 + (45.0 - 52.5)^2 + (37.8 - 42.5)^2 + (33.3 - 42.5)^2 + (50.5 - 42.5)^2 + (44.0 - 42.5)^2 + (42.0 - 52.5)^2 = 598.56
standard deviation = √(598.56/10 = 7.74
s1 = 7.74 × 1000 = 7740
For public colleges,
Mean = (20.3 + 22.8 + 22.0 + 25.8 + 28.2 + 18.5 + 15.6 + 25.6 + 24.1 + 14.4 28.5 + 21.8)/12 = 22.3
x2 = 22.3 × 1000 = 22300
n2 = 12
Summation(x - mean)² = (20.3 - 22.3)^2 + (22.8 - 22.3)^2 + (22 - 22.3)^2 + (25.8 - 22.3)^2 + (28.2 - 22.3)^2 + (18.5 - 22.3)^2 + (15.6 - 22.3)^2 + (25.6 - 22.3)^2 + (24.1 - 22.3)^2 + (14.4 - 22.3)^2 + (28.5 - 22.3)^2 + (21.8 - 22.3)^2 = 225.96
standard deviation = √(225.96/12 = 4.34
s2 = 4.34 × 1000 = 4340
b) The point estimate is the difference between the sample means
Point estimate = 42500 - 22300 = 20200
The best guess for the difference in population mean annual cost of attending private and public colleges is $20200. The range of the value is determined by the margin of error.
c) Confidence interval = point estimate ± margin of error
Margin of error = z√(s²/n1 + s2²/n2)
Where z is the test score for 95% confidence level from the t distribution table. To find the test score, we would first find degree of freedom, df
df = (n1 - 1) + (n2 - 1) = (10 - 1) + (12 - 1) = 20
From the t distribution table,
z = 2.086
Margin of error = 2.086√(7.74²/10 + 4.34²/12) = 4.84
4.84 × 1000 = 4840
Confidence interval = 20200 ± 4840
The prize in a raffle is a flat-screen TV valued at $350, and 1,000 tickets are sold for a dollar each. Let’s find the expected value if you buy 1 ticket. Find the expected value. Round your answer to two decimal places. Remember a gain would be posit
Answer:
the expected value EV = −$0.65
Step-by-step explanation:
Expected value EV = expected gain - expected loss
Given;
Cost of a ticket L = $1
Probability of losing the ticket P(L)= 999/1000 = 0.999
Cost of a flat screen TV = $350
Expected gain G = $350 - $1 = $349
Probability of winning the TV P(G) = 1/1000 = 0.001
EV = G × P(G) - L × P(L)
Substituting the values;
EV = $349 × 0.001 - $1 × 0.999
EV = −$0.65
the expected value EV = −$0.65
In a random sample of 964 young adults aged 18-29, it was found that 196 of them were married. Construct a 99% confidence interval for the proportion of married young adults aged 18-29.
Answer:
99% confidence interval for the proportion of married young adults aged 18-29.
(0.1779 , 0.2287)
Step-by-step explanation:
Step(i):-
Given sample size 'n' = 964
Given data a random sample of 964 young adults aged 18-29, it was found that 196 of them were married
sample proportion
[tex]p^{-} = \frac{196}{964} = 0.2033[/tex]
Step(ii):-
99% confidence interval for the proportion of married young adults aged 18-29.
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} } ,p^{-} +Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} })[/tex]
[tex](0.2033 -1.96 \sqrt{\frac{0.2033(1-0.2033 ) }{964} } ,0.2033 +1.96\sqrt{\frac{0.2033(1-0.2033 ) }{964} })[/tex]
(0.2033 - 0.02540 , 0.2033 +0.02540)
(0.1779 , 0.2287)
Conclusion:-
99% confidence interval for the proportion of married young adults aged 18-29.
(0.1779 , 0.2287)
The World Issues club has decided to donate 60% of all their fundraising activities this year to Stephen Lewis
Foundation. This foundation was created to help ease the pain of HIV/AIDS in Africa Lewis, a Canadian
works for the United Nations trying to determine ways to stop the spread of this deadly disease from crippling
an entire continent
a. Choose a variable to represent the money earned during fundraising activities and the revenue generated
for the foundation
b. Use these variables to create an equation that will determine the amount of money the foundation will
receive
c. In their latest bake sale, the club raised $72. Calculate the amount the foundation will receive
d. At the end of the year, the World Issues Club mailed a cheque to the foundation for $850. How much
money did they fundraise in total?
Answer:
a. Let the variable be [tex]x[/tex] for the fundraising activities and [tex]M[/tex] as the revenue for foundation.
b. [tex]M =0.60x[/tex]
c. $43.2
d. $1416.67
Step-by-step explanation:
Given that:
The World Issues club donates 60% of the total of their fundraising activities.
Answer a.
Let us choose the variable [tex]x[/tex] to represent the money earned during fundraising activities and [tex]M[/tex] for the revenue generated for foundation.
Answer b.
Foundation will receive 60% of the total of the fundraising activities.
Equation to determine the money that will be received by foundation:
[tex]M = 60\%\ of\ x\\OR\\M = 0.6x[/tex]
Answer c.
Given that x = $72, M = ?
Putting the value of x in the equation above:
[tex]M = 0.6 \times 72\\\Rightarrow \$43.2[/tex]
Answer d.
Given that M = $850, x = ?
Putting the value of M in the equation above to find x:
[tex]850= 0.6 \times x\\\Rightarrow x = \dfrac{850}{0.6}\\\Rightarrow x = \$ 1416.67[/tex]
So, the answers are:
a. Let the variable be [tex]x[/tex] for the fundraising activities and [tex]M[/tex] as the revenue for foundation.
b. [tex]M =0.60x[/tex]
c. $43.2
d. $1416.67
What is the circumference of the circle below? (Round your answer to the nearest tenth.)
Hey there! :)
Answer:
75.4 cm.
Step-by-step explanation:
Formula for the circumference of a circle:
C = 2rπ
Given:
r = 12 cm
Plug this value of r into the equation:
C = 2(12)π
C = 24π
Multiply by π (3.14)
24 × 3.14 = 75.36 cm
Round to nearest tenth:
75.36 ≈ 75.4 cm.
Answer: B
Step-by Step: C=2n
r= 2•n•12= 75.39822
You round it to the nearest tenth, it would be 75.4
What is PI times 4? HELP ASAP
Answer:
12.566370614359172953850573533118
Step-by-step explanation:
The Riemann zeta function for real numbers is defined for all x for which the series ζ(x) = ∑_(n=1)^[infinity] n^-x converges. Find the domain of the function. (Enter your answer using interval notation.)
Answer:
The domain of the function using the interval notation is
written as the missing term
Step-by-step explanation:
Attached is the detailed solution
uniform convergence of sum over n,i, just is the infinite geometrical series with n = 0
note : when X ≤ THIS SUM DIVERGES
for X > 1 ( relation between Zeta functions and Gamma function the sum is convergent
two cards are drawn without replacement from a standard deck of 52 playing cards. what is the probability of choosing a diamond and then without replacement another diamond? express your answer as a fraction or decimal number rounded to four decimal places.
Answer:
1/17
Step-by-step explanation:
There are 13 diamond cards in a standard 52-card deck.
First drawing:
13 diamonds
52 total cards
After the first drawing you already took a diamond, so there are 12 diamonds left out of 51 total cards.
p(diamond and diamond) = 13/52 * 12/51 = 1/4 * 4/17 = 1/17