let f(x)=x^2 +2 and g(x)=1-3x. find each function value: (fg)(-1)
Answers
Answer:
12
Step-by-step explanation:
so basically
(x^2+2)*(1-3x)=-3x^3+x^2-6x+2
now plug in -1
-3(-1)^3+(-1)^2-6(-1)+2=12
hope this helped :)
The correct value of (fg)(-1) is "12". A further solution of the given query is provided below.
Given functions are:
[tex]f(x) = x^2+2[/tex]
[tex]g(x) = 1-3x[/tex]
Now,
⇒ [tex](fg) = (x^2+2)(1-3x)[/tex]
By applying multiplication, we get
[tex]=x^2+2-3x^3-6x[/tex]
[tex]=-3x^3+x^2-6x+2[/tex]...(equation 1)
By substituting the value "-1" in place of "x" in equation 1, we get
⇒ [tex](fg)(-1) = -3(-1)^3+(-1)^2-(6)(-1)+2[/tex]
[tex]=-3(-1)+1+6+2[/tex]
[tex]=3+1+6+2[/tex]
[tex]=12[/tex]
Thus the right answer is (fg)(-1) = 12.
Learn more:
https://brainly.com/question/10057660
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[tex]\huge\text{Hey there!}[/tex]
[tex]\large\text{\bf{{(10-343)-2\times6}}}\\\bold{Do\ PEMDAS}\\\bold{PEMDAS\ is....}\\\bold{Parentheses}\\\bold{Exponents}\\\bold{Multiplication}\\\bold{Division}\\\bold{Addition}\\\bold{Subtraction}}[/tex][tex]\\\bold{Do\ PEMDAS}\\\\\bold{PEMDAS\ is....\downarrow}\\\\\bold{Parentheses}\\\bold{Exponents}\\\bold{Multiplication}\\\bold{Division}\\\bold{Addition}\\\bold{Subtraction}}[/tex]
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~[tex]\frak{Amphitrite1040:)}[/tex]
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Answers
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Answers
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Step-by-step explanation:
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Hoped it help!
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I hope this helps and have a great day!
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Answers
Answer:
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Answers
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______________________________
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Answers
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12x^7+7x^6-10x^5