Lars is standing near the edge of a 90-meter cliff. He throws a ball upward, but does not catch it, and it falls to the bottom of the cliff face. From when he threw the ball upward to when it hit the ground below, 5.55 seconds passed. What was the initial vertical velocity of Lars' throw?
a. -43 m/s
b. -11 m/s
c. 43 m/s
d. 11 m/s

Answers

Answer 1

Answer:

c. 43 m/s

Explanation:

Given the following data;

Displacement, S = 90 meters

Time, t = 5.55 seconds

To find the initial velocity;

We would use the second equation of motion given by the formula;

[tex] S = ut + \frac {1}{2}at^{2}[/tex]

Where;

S represents the displacement or height measured in meters. u represents the initial velocity measured in meters per seconds. t represents the time measured in seconds. a represents acceleration measured in meters per seconds square.

We know that acceleration due to gravity is -9.8m/s² because the direction is downward.

Substituting into the equation, we have;

[tex] 90 = u*5.55 + \frac {1}{2}*(-9.8)*5.55^{2}[/tex]

[tex] 90 = u5.55 - 4.9*30.8025[/tex]

[tex] 90 = u5.55 - 150.93225[/tex]

Rearranging the equation, we have;

[tex] u5.55 = 90 + 150.93225[/tex]

[tex] u5.55 = 240.93225[/tex]

[tex] u = \frac {240.93225}{5.55}[/tex]

Initial velocity, u = 43.41 ≈ 41 m/s


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Answer: friction has no role to play in this case. because friction usually occurs between to parts which come in contacts. examples (a)our joints in the human body (b)two mechanical parts (shafts).

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Answer:

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Explanation:

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Answer:

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plz help will give brainlest! if you cant help, well, merry christmas!
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Answers

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Answers

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Answers

4 seconds i have attached my work

Time taken to reach height is 4 seconds.

Given that;

Velocity of cannon ball = 80 m/s

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part 1 of 2
A neutron in a reactor makes an elastic
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Assume: The mass of the atomic nucleus is
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Answer:

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