Lab: Limiting Reactant and Percent Yield
Step 10: Complete Calculations to Fill in the Remainder of the Data Table
Record the difference... answer .71g
.011 moles
Theoretical yield = .014
Percent yield = 79
Are these answers correct? Yes they are I did the lab. Hope these answers help!

In an ecosystem, the best method  for the preservation of water quality is  that humans should cease all recreational and agricultural uses of water resources.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other. Components present include air, water, soil,etc.

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50 g of As[tex]_2[/tex]O[tex]_3[/tex] are titrated with 38.5 mL of KMnO[tex]_4[/tex] to reach the end point. 0.26M is the concentration of the KMnO[tex]_4[/tex]  solution.

Concentration in chemistry refers to the quantity of a material in a certain area. The ratio of the solute within a solution to the solvent or whole solution is another way to define concentration. In order to express concentration, mass in unit volume is typically used.

The solute concentration can, however, alternatively be stated in moles or volumetric units. Concentration may be expressed as per unit mass rather than volume.

5As[tex]_2[/tex]O[tex]_3[/tex](s)+4MnO[tex]_4[/tex]⁻(aq)+9H[tex]_2[/tex]O(l)+12H⁺(aq)⟶10H[tex]_3[/tex]AsO[tex]_4[/tex](aq)+4Mn[tex]_2[/tex]⁺(aq)

the stoichiometry ratio between As[tex]_2[/tex]O[tex]_3[/tex] and MnO[tex]_4[/tex]⁻ is 5:4

0.0126 moles of  As[tex]_2[/tex]O[tex]_3[/tex] will react with 4/5×0.0126 moles = 0.01008moles

0.01008moles of MnO[tex]_4[/tex]⁻ is present in 38mL

concentration of KMnO[tex]_4[/tex]= moles×volume

                                        = 0.010/38×1000

                                        =0.26M

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The acidity or alkalinity of a solution depends upon its hydronium ion concentration and hydroxide ion concentration. The pH scale is introduced by the scientist Sorensen.

The pH of a solution is defined as the negative logarithm to the base 10 of the hydronium ion concentration in moles per litre.

a. Concentration of NaOH = 0.200 M

Concentration of HCl = 0.200 M

Total volume = 50 + 30 = 80 mL = 0.08 L

The neutralization reaction between  NaOH and HCl is:

OH⁻  + H⁺  ---------->  H₂O

Then,

n(H⁺) = 0.03 × 0.200 = 0.006 moles

n(OH⁻) = 0.05 × 0.200 = 0.01 moles

Remaining moles of OH⁻ = 0.01 - 0.006 = 0.004

pOH = -log [OH⁻] = 2.39

pH + pOH = 14

pH = 14 - pOH = 14 - 2.39 = 11.61

b. pH at the equivalence point is about pH 7.

c. Total volume = 0.11 L

n(H⁺) = 0.06 × 0.200 = 0.012 moles

n(OH⁻) = 0.05 × 0.200 = 0.01 moles

Remaining moles of H⁺ = 0.012 -0.01 = 0.002

Concentration of H⁺  is 0.002 M / 0.11 L = 0.01818 moles/L

pH = - log [ H⁺ ]

pH = - log [ 0.01818 ]

pH = 1.74

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The volume of the air when the breath is warm to body temperature (37.0°C) in the lungs is 530.4 mL

First, we shall list out the given parameters from the question. This is given below:

The volume of the breath when it is warm to body temperature (37.0°C)    can be obtained by using Charles' law equation as shown below:

V₁ / T₁ = V₂ / T₂

450 / 263 = V₂ / 310

Cross multiply

263 × V₂ = 450 × 310

263 × V₂ = 139500

Divide both side by 263

V₂ = 139500 / 263

V₂ = 530.4 mL

Thus, the volume is 530.4 mL

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The correct answer is "Particles are more likely to collide with enough energy to form an activated complex," which is the last option, as when the temperature of a reaction increases, the average kinetic energy of the particles increases.

Chemical reactions require a certain amount of energy to occur. This energy is called activation energy. In order for reactant molecules to undergo a chemical reaction, they must overcome the activation energy barrier. This barrier is like a hill that reactants must climb over to reach the product state. One way to provide the energy required to overcome the activation energy barrier is to increase the temperature of the system. This is because temperature is a measure of the average kinetic energy of particles in a system. As the temperature increases, the kinetic energy of the particles also increases. This means that they are moving faster and colliding with greater energy.

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1. The mass (in grams) of FeCl₂ contained in the sample is 14.96 grams

2. The mass (in grams) of KBr present in the solution is 16.66 grams

1. The mass of FeCl₂ contained in the sample can be obtained as shown below:

First, we shall obtain the mole

Mole = molarity × volume

Mole of FeCl₂ = 0.762 × 0.155

Mole of FeCl₂ = 0.118 mole

Finally, we shall determine the mass of FeCl₂ present in the sample. Details below:

Mass = Mole × molar mass

Mass of FeCl₂ = 0.118 × 126.75

Mass of FeCl₂ = 14.96 grams

2. The mass of KBr present in the solution can be obtained as shown below:

First, we shall obtain the mole

Mole = molarity × volume

Mole of KBr = 0.350 × 0.4

Mole of KBr = 0.14 mole

Finally, we shall determine the mass of KBr in the solution. Details below:

Mass = Mole × molar mass

Mass of KBr = 0.14 × 119

Mass of KBr = 16.66 grams

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The balanced  chemical equations with suitable coefficients are 2 Cu(IO₃) + K₂(CO₃) → 2 KIO₃ + Cu₂CO₃, Fe₂(CO₃)₃ + 6 Cs → 3 Cs₂(CO₃) + 2 Fe,

2 NaClO₃ → 2 NaCl + 3 O₂.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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The statement that is true is that It is endothermic and DH equals +91.8 kJ.

We can see that in this case that the heat of the reaction which we cam also call the enthalpy of the reaction is positive. Let us know that when we have a positive enthalpy what we have is an endothermic reaction.

Endothermic reactions are typically observed as a decrease in temperature, as energy is absorbed from the surroundings to fuel the reaction. Examples of endothermic reactions include the melting of ice.

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Missing parts;

Given the balanced equation representing a reaction at 101.3 kPa and 298 K:

N2(g) + 3H2(g) => 2NH3(g) + 91.8 kJ

Which statement is true about this reaction?

(1) It is exothermic and DH equals -91.8 kJ.

(2) It is exothermic and DH equals +91.8 kJ.

(3) It is endothermic and DH equals -91.8 kJ.

(4) It is endothermic and DH equals +91.8 kJ.

The new temperature of the neon gas, with a volume held constant, is approximately -253.6°C.

Gay-Lussac's law states that the pressure exerted by a given quantity of gas varies directly with the absolute temperature of the gas.

It is expressed as;

P₁/T₁ = P₂/T₂

Given that:

Plug the given values into the above formula and solve for the final temperature.

P₁/T₁ = P₂/T₂

P₁T₂ = P₂T₁

[tex]T_2 = \frac{P_2T_1}{P_1}\\ \\ P_2 = \frac{ 0.2 * 293.15}{3}\\ \\P_2 = 19.543 K[/tex]

Now, convert from Kelvin to celsius

P₂ = 19.543K − 273.15

P₂ = -253.6°C

Therefore, the new temperature is -253.6°C.

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The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.

Thus, Colorless and combustible, cyclohexane has a characteristic detergent-like stench that is reminiscent of cleaning products.

The industrial manufacturing of adipic acid and caprolactam, which are building blocks for nylon, uses cyclohexane primarily.

cyclohexanone and cyclohexanol that serves as the starting point for the production of adipic acid and caprolactam, which are both precursors to nylon. Annual production of cyclohexanone and cyclohexanol totals several million kilos.

Thus, A cycloalkane with the chemical formula C6H12 is cyclohexane. Non-polar describes cyclohexane.

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Taking into account the reaction stoichiometry, 3.00713 grams of H₂SO₄ is completely neutralized with 61.37 mL of the NaOH.

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

A sulfuric acid solution is completely neutralized with 61.37 mL (0.06137 L) of the NaOH solution. Assuming the concentration of the NaOH solution is 1.0 M, the moles of NaOH that react is calculated as:

Moles of NaOH reacting = concentration× volume in liters

Moles of NaOH reacting = 1 M× 0.06137 L

Moles of NaOH reacting = 0.06137 moles

Now, the following rule of three can be applied: If by reaction stoichiometry 2 moles of NaOH react with 98 grams of H₂SO₄, 0.06137 moles of NaOH react with how much mass of H₂SO₄?

mass of H₂SO₄= (0.06137 moles of NaOH× 98 grams of H₂SO₄)÷2 moles of NaOH

mass of H₂SO₄= 3.00713 grams

Finally, 3.00713 grams of H₂SO₄ is required.

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The rate expression is k [BF₃]²[NH₃], overall order is 3, rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

The rate expression for this reaction can be written as:

Rate = k [BF₃]^m[NH₃]^n

The method of initial rates can be used to calculate the values of m and n. When we compare experiments 1 and 2, notice that halving the concentration of [NH3] reduces the initial rate of reaction. This suggests that the reaction is first order in terms of [NH3], implying that n = 1.

When comparing experiments 1 and 3, notice that increasing the concentration of [BF3] by a factor of 2.5 increases the initial rate of reaction by a factor of 9.39 (i.e., 2.13/0.227). This shows that the reaction is about second order in relation to [BF3], i.e., m 2.

Therefore, the rate expression for the reaction is:

Rate = k [BF₃]²[NH₃]

The overall order of the reaction is m + n = 3.

Using the data from experiment 4, substitute the values and solve for k:

Rate = k [BF₃]²[NH₃]

1.02 × 10-¹ = k (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.02 × 10-¹ / (3.00 × 10⁻¹)² (1.00 x 10⁻¹)

k = 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹

Therefore, the rate constant k is 1.13 × 10⁻³ mol⁻² dm⁶ s⁻¹.

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Cutting or tearing a strip of cardboard sufficiently large to entirely enclose the Styrofoam cup's mouth. This is the modification for making on the coffee cup calorimeter.

A coffee cup calorimeter without a cover serves as the basic component of a coffee cup calorimeter. A thermometer with its bulb below the water's surface can be inserted through the cup's lid after the cup has been partly filled using an established quantity of water.

The quantity of heat that was either absorbed or generated  throughout the reaction is determined using the alteration in water temperature. Cutting or tearing a strip of cardboard sufficiently large to entirely enclose the Styrofoam cup's mouth. This is the modification for making on the coffee cup calorimeter.

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The product of the gamma decay reaction is 22/10 Ne

Gamma radiation, commonly referred to as gamma decay, is a type of radioactive decay in which an unstable atomic nucleus generates gamma rays, a form of extremely high-energy electromagnetic radiation.

Gamma rays are neutral and have no mass, in contrast to alpha and beta particles, which have mass and charge.

The result of the gamma decay would not alter the parent nuclei thus the product would have the same mass and charge as the parent nucleus.

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The mass in grams of CO₂ in the 5.3 L container at 101 kPa and 280 K is 10.1 grams of CO₂

The mass in grams of CO₂ can be calculated using the Ideal Gas Law equation:

where:

P is pressure = 101 kPa or 0.998 atm

V is volume = 5.3 L

n is the number of moles of gas = ?

R is the molar gas constant = 0.08206 L·atm/(mol·K)

T is the temperature = 280 K

solving for n;

n = PV/(RT)

n = (0.998 atm * 5.3) /(0.08206 * 280 K)

n = 0.229 moles of CO₂

Mass of CO₂ = number of moles * molar mass

molar mass of CO₂ = 44.01 g/mol

mass of CO₂ =  0.229 × 44.01

mass of CO₂ = 10.1 g

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The shape of a graph that shows the velocity in the x direction (v) versus time when the object is accelerating in the x direction would be a curve with a non-zero slope.

The rate at which an object's displacement changes in relation to a frame of reference is its velocity. The direction of the movement of the body or the object is defined by its velocity.

According to the equation v = s/t, velocity (v) is a vector quantity that quantifies displacement (or change in position, s), over the change in time (t).

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Answer: I expect a horizontal line (slope 0). As time increases, the velocity in the x direction stays about the same.

Explanation: Edmentum sample answer

The balanced equation is: Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2

In a balanced chemical equation, the number of atoms of each element is the same on both sides of the equation. Thus, the balanced equation of the reaction is:

Pb(C2H3O2)2 + CO2 + H2O → PbCO3 + 2 HC2H3O2

The coefficients used to balance the equation are:

1 Pb(C2H3O2)2 + 1 CO2 + 1 H2O → 1 PbCO3 + 2 HC2H3O2

After balancing the equation, we can see that one molecule of lead(II) acetate reacts with one molecule of carbon dioxide and one molecule of water to produce one molecule of lead(II) carbonate and two molecules of acetic acid.

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Answer:

Explanation:

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The partial pressure of O₂ is 0.954 atm

The moles O₂ that formed is 0.000859 moles

The mass of NaNO₃ that reacted is 0.146 g.

The balanced chemical equation for the reaction is given below:

Using Dalton's Law of partial pressures:

The partial pressure of O₂ = Total pressure - Partial pressure of water vapor

The partial pressure of O₂ = (0.98 atm) - (0.026 atm)

The partial pressure of O₂ is 0.954 atm

b. Using the ideal gas law to determine the moles of oxygen gas formed:

PV = nRT

Making subject of the formula:

n = PV/RT

n = (0.954 * 0.0230)/(0.0821 * 295.15)

n = 0.000859 moles

Moles of O₂ formed = 0.000859 moles

c. the mass of NaNO₃ that reacted is calculated as follows:

mass NaNO₃ = moles NaNO₃ x molar mass NaNO₃

molar mass NaNO = 84.99 g/mol

From the mole ratio of the reaction, moles of NaNO₃ = 0.000859 moles * 2

moles of NaNO₃ = 0.001718 moles

mass NaNO3 = 0.001718 * 84.99

mass NaNO3 = 0.146 g NaNO₃

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From the calculation, the pH of the solution can be obtained as 0.39.

We first have to obtain the dissociation constant of the solution;

α = √Ka/C

Ka = Cα^2

Ka = 4.9 * 10^-3 * 6

Ka = 0.0294

Then we have that;

0.0294 = [x]^2/[6 - x]

0.0294 * [6 - x] = x^2

0.1764 - 0.0294 x = x^2

x^2 +  0.0294 x - 0.1764 =0

x = 0.41 M

Thus the pH of the solution is;

pH = -log[0.41]

= 0.39

pH is an important parameter in chemistry, biology, and many other fields, as it can affect the behavior and properties of substances and reactions.

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In the region labelled as H, weather fronts are most likely to be located. A weather front comprises a line dividing air masses with various differences in their attributes,

A weather front comprises a line dividing air masses with various differences in their attributes, including air density, winds, temperatures, or humidity. These variations frequently result in disturbed or unstable weather at the boundary.

For instance, although warm fronts usually arrive accompanied by stratiform precipitation with fog, cold fronts can bring belts of thunderstorms with cumulonimbus precipitation and be preceded by squall lines. Dry lines, which are softer humidity gradients, can cause severe weather in the summer. In the region labelled as H, weather fronts are most likely to be located.

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Ba(NO₃)₂ has the following percentage composition: 52.6% Ba, 10.7% N, and 36.7% O.

The molar mass of Ba(NO₃)₂ is:

Ba: 1 x 137.33 g/mol = 137.33 g/mol

N: 2 x 14.01 g/mol = 28.02 g/mol

O: 6 x 16.00 g/mol = 96.00 g/mol

Adding these up gives us a total molar mass of 261.35 g/mol.

The mass percent of each element is then:

Ba: (137.33 g/mol / 261.35 g/mol) x 100% = 52.6%

N: (28.02 g/mol / 261.35 g/mol) x 100% = 10.7%

O: (96.00 g/mol / 261.35 g/mol) x 100% = 36.7%

Therefore, the percentage composition of Ba(NO₃)₂ is: 52.6% Ba, 10.7% N, and 36.7% O.

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There are unique interactions and relationships which are involved in the transportation of energy. The energy which is produced and captured once is distributed throughout various living organisms. This transfer of energy is called the food web.

The decomposers of the food web are known as the organisms which tend to degrade the dead living organisms of an ecosystem. Some examples of decomposers are fungus, bacterium or invertebrates, etc.

The decomposers help in the energy flow of the ecosystem and help in replenishing the fertility of soil through secreting the digestive enzymes over dead plants and animals and provide nutrients to the soil.

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Answer:

The reaction between ferric chloride and potassium hydroxide leads to the formation of ferric hydroxide and potassium. It is a precipitation reaction in which ferric and hydroxide ion on reaction with each other results in the formation of ferric hydroxide as reddish-brown precipitate.

2 M solution of a compound can be made by dissolving 2g of compounds in 1 liter of water. Either by diluting the appropriate volume of a more concentrated solution also known as a stock solution to the desired final volume or by dissolving a known mass of solute in a solvent, solutions of known concentration can be prepared.

For example, when we add one part by weight of powder to 19 parts by weight of the solvent is used to make a 5% solution. For 1% solution, the addition of 1gm of NaCl to 100L of water. which is the final volume of the solution.

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Answer:

Explanation:

i wish i can help

If the weather seems to have a constant pattern that has barely been or has not been changed, you can assume that there will be a greater chance the weather pattern will remain constant, or at least similar to the pattern.