Kyra is framing a square painting with side lengths of (x + 6) inches.

The total area of the painting and the frame has a side length of (2x −

5)

inches.

The material for the frame will cost $0.07

per square inch.

Answers

Answer 1

Complete Question:

Kyra is framing a square painting with side lengths of (x + 6) inches. The total area of the painting and the frame has a side length of (2x - 5) inches. The material for the frame will cost $0.07 per square inch.

Find the cost of the material for the frame is x = 16.

Answer:

The material cost of the frame is: $17.15

Step-by-step explanation:

Given

[tex]L_1 = (x + 6)\ in[/tex] --- Length of painting

[tex]L_2 = (2x - 6)[/tex] --- Frame and Painting

[tex]Cost = \$0.07[/tex] per square inch

Required

The cost of material of the frame

First, we calculate the area of the frame only

This is the difference between the areas of the frame and painting and the area of the painting

[tex]Area = (L_2)^2 - (L_1)^2[/tex]

[tex]Area = (2x - 5)^2 - (x + 6)^2[/tex]

Substitute 16 for x

[tex]Area = (2*16 - 5)^2 - (16 + 6)^2[/tex]

[tex]Area = (27)^2 - (22)^2[/tex]

[tex]Area = 245\ in^2[/tex]

The cost of the painting is:

[tex]Total\ Cost = Unit\ Cost * Area[/tex]

[tex]Total\ Cost = \$0.07 * 245[/tex]

[tex]Total\ Cost = \$17.15[/tex]

Hence, the material cost of the frame is: $17.15


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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Step-by-step explanation:

On average, there are 12 potholes per mile on a particular stretch of the state highway. Suppose the potholes follow a Poisson distribution on the highway. a. Find the probability of finding fewer than two potholes in a quarter-mile stretch of the highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.) b. Find the probability of finding more than one pothole in a quarter-mile stretch of the highway. (Do not round intermediate calculations. Round your final answer to 4 decimal places.)

Answers

Answer:

a) 0.1992 = 19.92% probability of finding fewer than two potholes in a quarter-mile stretch of the highway.

b) 0.8008 = 80.08% probability of finding more than one pothole in a quarter-mile stretch of the highway.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

[tex]P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}[/tex]

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x is the number of sucesses

e = 2.71828 is the Euler number

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a. Find the probability of finding fewer than two potholes in a quarter-mile stretch of the highway.

Mean of 12 potholes per mile, which means that in a quarter-mile stretch, the mean is [tex]\mu = \frac{12}{4} = 3[/tex]

This probability is:

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

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[tex]P(X = 1) = \frac{e^{-3}*(3)^{1}}{(1)!} = 0.1494[/tex]

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0498 + 0.1494 = 0.1992[/tex]

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Answers

Answer:

36.1

Step-by-step explanation:

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Answers

Answer:

x(the number)=3

Step-by-step explanation:

3×3+3squared = 18

Answer:

3x + x^2 = 18

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a. How much warmer is 82 than 40?
b. How much warmer is 82 than -40?
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Answers

Answer:

a. 42

b. 122

a. 57

b. 130

Step-by-step explanation:

For problem A:

because both of these values have positive numbers, just use normal subtraction

82 - 40 = 42 degrees warmer

For problem B:

because we are subtracting a negative number from a positive number, we add both of these numbers because 82 - -40 can also be equal to 82 + 40

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the sentences 30m up a cliff and 87m up a cliff are describing positive values.

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For problem B:

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if the sentences above the surface and below the surface are describing positive and negative values, then there has to be a neutral value ( which is 0)

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by using a number line, you can draw it out like this

below the surface-------------------------the surface----------------------------above the surface

-30--------------------------------------------0--------------------------------------------100

therefore, 100 - - 30 = 100 + 30 = 130

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Answers

Answer:

To be complement sum of angle must be 90°

But to be supplement sum of angle must be 180°

Step-by-step explanation:

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