Khan academy Help please

The value of x would be 11.

Step-by-step explanation:

We can simply just isolate x in the equation to solve:

2x + 40 = 62

(Subtract 40 from both sides) 2x = 22

(Divide each side by 2) x = 11

Hope this helps! :)

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Explanation:

If we knew the value of x, we would use PEMDAS to evaluate 2x+40 to get some single number value. For instance, if x = 4, then 2x+40 becomes 2(4)+40 which evaluates to 48 when you use PEMDAS.

However, we don't know the value of x. To find x, we follow PEMDAS in reverse to undo everything happening to x.

Note the order in which stuff is happening to x

To undo this, we follow this process in reverse. So we need to undo the "add 40" part first, which was the last thing done. That means we'll subtract 40 from both sides

2x+40 = 62

2x+40-40 = 62-40

2x = 22

Then we undo the "multiply by 2" part. We'll divide both sides by 2

2x = 22

2x/2 = 22/2

x = 11

Let's check the answer.

2x+40 = 62

2(11)+40 = 62 ... x replaced with 11

22+40 = 62

62 = 62

Since we get the same thing on both sides, we get a true equation and this confirms we have the correct x value.

Answer:

Gud morning friend

Step-by-step explanation:

Sorry friend I don't know

Answer:

C is my answer

Thank You

Mark me as Brainilest Answer please ty

see topper. com

Step-by-step explanation:

uyhhghjggg

Answer:

What is the question?

Step-by-step explanation:

Answer:

You can't divide 2 by 7 unless you will round and need a decimal because it will equal 0.28571428571 but if you mean 7 divided by 2 then that would get you 3.5

Step-by-step explanation:

Answer: 12.9

Step-by-step explanation: Divide 39.99 by 31.00 you'll get 1.29, but you slide the decimal over and get 12.9

Answer:

1 1/2

Hope that helps!

Step-by-step explanation:

Step-by-step explanation:

the scale factor is 1

1/1

both triangles are similar and the scale factor is 1/1

....................

Answer:

9.8

Step-by-step explanation:

1.  Move the decimal one space to the right on both the divisor and the dividend.

2.  You should end up with 382.2 divided by 39

3. Answer is 9.8

Answer:

if I am not mistaken.. the median would be 9 and the the mean is also 9.

Step-by-step explanation:

first you order the numbers from least to greatest and the find with is the middle number to find the median.

6,7,8,8,8,9,10,12,13 (answer: 9)

To find the mean you will add all of the numbers up and then divide that number by the amount of numbers there are.

1) 6+7+8+8+8+9+10+12+13= 81

2) 81 ÷ 9 =9

Answer:

Mean: 9, Median: 8 Mode: 8

Step-by-step explanation:

MEAN:   The AVERAGE total of all the values divided by the numbers of values.

6 + 7+ 8 + 8 + 8 + 9 + 10 + 12 + 13 = 81        81/9 (set of #'s)= 9

MEDIAN:  The number in the MIDDLE of the list of values.

6, 7, 8, 8, 8, 9, 10, 12, 13         So, the middle value is 8

MODE:   The number that appears the most.

6, 7, 8, 8, 8, 9, 10, 12, 13         So, 8 appears 3 times.

Hope this helps!

what kind of idiotic question is that

does a idiot teacher exists?

Answer:

If they won 90 out of 162, they won 55.(5)% of their games.

Step-by-step explanation:

I assume they WON 90 of the 162 games.

90/162 = 45/81 = 15/27 = 5/9

5/9 = 55.(5)%; (because 1/9 = 11.(1)%)

Answer:

55.56%

Step-by-step explanation:

1. Put into a fraction = 90/162

2. Simplify = 5/9

3. Calculate the fractions value by dividing the numerator by the denominator.

4. Multiply the answer by 100

5. Simplify

Hopefully this helps!

Answer:

[tex]\alpha =1.76\ rad/s^2[/tex]

Step-by-step explanation:

Given that,

Initial angular speed of the skater, [tex]\omega_i=4.5\pi\ rad/s[/tex]

Final angular speed of the skater, [tex]\omega_f=7.2\pi\ rad/s[/tex]

Time interval, t = 4.8 s

We need to find her average angular acceleration  during this time interval. Let [tex]\alpha[/tex] be the average acceleration of the skater. So,

[tex]\alpha =\dfrac{\omega_f-\omega_i}{t}\\\\\alpha =\dfrac{7.2\pi -4.5\pi}{4.8}\\\\\alpha =1.76\ rad/s^2[/tex]

So, her angular acceleration is [tex]1.76\ rad/s^2[/tex].

Answer:

hello there im sam and im going to help you with your answer.

Step-by-step explanation:

so you take the 156,000 and subtract it to 120,000 and you will get 36,000 and thats how much she owes the bank.

Answer:

where is the picture to show ????

Answer:

x=9/4

Step-by-step explanation:

Answer:

Step-by-step explanation:

1074/100

1.074*10

0.1074*10

107.4/10

10740/1000

Answer:

21> 2x+ 15

Step-by-step explanation:

The expression is 21 > 15+ 2x

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

Twenty-one is greater than the sum of fifteen and two times a number​

let the number be x.

two times a number​ = 2x

and, sum of fifteen and two times a number​ = 15 + 2x

So, Twenty-one is greater than the sum of fifteen and two times a number​

21 > 15+ 2x

Hence, the expression is 21 > 15+ 2x.

Learn more about algebra here:

https://brainly.com/question/24875240

#SPJ2

Answer:

A.) the number of fencers that do not use the foil as their main weapon

B.) X : 0, 1, 2, 3,..., 21

C.) X ~ p(X) ; 21 ~ 0.4

D.) 21 ~ 0.4

E.) 0.0895

F.) Yes. The probability of all 21 fencers not using the foil as their main weapon is small (less than 1%)

Step-by-step explanation:

A.) since it is reported that 60% of fencers use the foil as their main weapon ;

The random variable (x) : number of fencers that do not use foil as their main weapon ;

( 100% - 60%) = (1 - 0.6) = 0.4

B.) values that X may take on :

Sample size = 21 ;

X : 0, 1, 2,..., 21

The distribution of X

X ~ B ; X ~ p(X) ; 21 ~ 0.4

Part (d) How many fencers are expected to not use the foil as their main weapon?

X * p(x)

21 * 0.4

= 8.4

= 8 (nearest whole number)

Part (e) Find the probability that eleven do not use the foil as their main weapon.

P(x = 11)

Using the binomial probability relation :

P(x =x) = nCx * p^x * (1 - p)^(n - x)

P(x = 11) = 21C11 * 0.4^11 * 0.6^10

P(x = 11) = 0.0895

Part (f) Based on numerical values, would you be surprised if all 21 did not use foil as their main weapon?

P(x = 21) = 21C21 * 0.4^21 * 0.6^0

P(x = 21) = < 0.00001 ( approximately 0)

Hence, based on this very low value which is almost equal to 0 ; it will be surprising if all 21 do not use foil as their main weapon

Step-by-step explanation:

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Answer: y=-3x+20

Step-by-step explanation:

Point slope formula = y-y1=m(x-x1)

y-2=-3(x-6)

y-2=-3x+18

y-2+2=-3x+18+2

y=-3x+20

Standard form is 3x+y =20

Answer:

C

Step-by-step explanation:

Answer:

C. 344 square centimeters

Answer:

Plz use english language so that we all can understand and solve it..

Step-by-step explanation:

and i am sry bcoz i can't understand your language

Answer:

14w + 14y - 28

Step-by-step explanation:

-7(-2w - 2y + 4)

Distributive:

14w + 14y - 28

good luck, hope this helps :)

Answer:

Step-by-step explanation:

151.2

Answer:

c) N(.47, .09)

Step-by-step explanation:

Options to the question are "a) N(.30, .10), b) N(.30, .09). c) N(.47, .09), d) N(.47, .008), e) N(.30, .008)"

Pο = 47% = 0.47

n = 30

Mean = Pο = 0.47

S.D = Pο(1-Pο) / n

S.D = 0.47 * 0.53 / 30

S.D = 0.09

Thus, the percentage of sleeping statistics of students follows a Normal distribution with mean = 0.47 and S..D = 0.09

This question is incomplete, the complete question is;

A rocket accelerates by burning its onboard fuel, so its mass decreases with time. Suppose the initial mass of the rocket at liftoff (including its fuel) is m, the fuel consumed at rate r, and the exhaust gases are ejected with constant velocity v(sub e) [relative to the rocket]. A model for the velocity of the rocket at time t is given by the equation:

v(t) = -gt - v(sub e) ln [(m-rt)/m]

where g is the acceleration due to gravity, and t is not too large. If g = 9.8 m/s^2, m = 30,000 kg, r = 160 kg/s, and v(sub e)= 3000 m/s, find the height of the rocket one minute after liftoff.

Answer:

the height of the rocket one minute after liftoff is 14.8441 km

Step-by-step explanation:

Given the data in the question;

Velocity of the rocket at time t is;

v(t) = -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex])

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] = ₀∫⁶⁰(  -gt - [tex]V_{e\\}[/tex] ln( [tex]\frac{m-rt}{m}[/tex]) )dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] ₀∫⁶⁰In( [tex]\frac{m-rt}{m}[/tex]) dt

= -g([tex][\frac{t^{2} }{2}]^{60}_0[/tex]  - [tex]V_{e\\}[/tex] [ t In( [tex]\frac{m-rt}{m}[/tex]) + [tex]\frac{m}{r}[/tex] - t - mr[tex]\frac{1}{r^{2} }[/tex] In |m-rt| [tex]]^{60}_0[/tex]

= -g([tex][\frac{60^{2} }{2}][/tex]  - [tex]V_{e\\}[/tex] [ 60 (In(1 -  [tex]\frac{60r}{m}[/tex])-1) + [tex]\frac{m(In(m^{2})-In((m-60r)^2))) }{2r}[/tex] ]

we input our given values; g=9.8 m/s², m=30000 kg, Ve = 3000 m/s, r = 160 kg)

= -9.8([tex][\frac{60^{2} }{2}][/tex]  - 3000 [ 60 (In(1 - [tex]\frac{60(160)}{m}[/tex])-1) + [tex]\frac{30,000(In(30,000^{2})-In((30,000-60(160))^2))) }{2(160)}[/tex] ]

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 m

we convert to kilometer

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14844.10 ÷ 1000

[tex]\int\limits^t_0 {v(t)} \, dt[/tex] =  14.8441 km

Therefore, the height of the rocket one minute after liftoff is 14.8441 km

9514 1404 393

Answer:

Step-by-step explanation:

The mnemonic SOH CAH TOA reminds you of the applicable ratios:

  Tan = Opposite/Adjacent   ⇒   tan B = CA/CB = 12/5

  Cos = Adjacent/Hypotenuse   ⇒   cos B = BC/BA = 5/13

  Sin = Opposite/Hypotenuse   ⇒   sin B = AC/AB = 12/13