KFell Fe"(CN), + e + Nat → KNaFe'Fe(CN)6
Fe'l. [Fe(CN)6]z + 4e + 4Na+ Na Fe",[Fe''(CN)613
2NH3 + 60H
N2 + 6H2O + 6e
->
What are the reactants in this reaction? What are the products?

Answers

Answer 1

Answer:

Most common oxidation states: +2, +3

M.P. 1535º

B.P. 2750º

Density 7.87 g/cm3

Characteristics: Iron is a gray, moderately active metal.

Characteristic reactions of Fe²⁺ and Fe³⁺

The [Fe(H2O)6]3+ ion is colorless (or pale pink), but many solutions containing this ion are yellow or amber-colored because of hydrolysis. Iron in both oxidation states forms many complex ions.

Aqueous Ammonia

Aqueous ammonia reacts with Fe(II) ions to produce white gelatinous Fe(OH)2, which oxidizes to form red-brown Fe(OH)3:

Fe2+(aq)+2NH3(aq)+3H2O(l)↽−−⇀Fe(OH)2(s)+2NH+4(aq)(1)

Fe3appt.gif

Aqueous ammonia reacts with Fe(III) ions to produce red-brown Fe(OH)3:

Fe3+(aq)+3NH3(aq)+3H2O(l)↽−−⇀Fe(OH)3(s)+3NH+4(aq)(2)

Fe3bppt.gif

Both precipitates are insoluble in excess aqueous ammonia. Iron(II) hydroxide quickly oxidizes to Fe(OH)3 in the presence of air or other oxidizing agents.

Sodium Hydroxide

Sodium hydroxide also produces Fe(OH)2 and Fe(OH)3 from the corresponding oxidation states of iron in aqueous solution.

Fe2+(aq)+2OH−(aq)↽−−⇀Fe(OH)2(s)(3)

Fe4appt.gif

Fe3+(aq)+3OH−(aq)↽−−⇀Fe(OH)3(s)(4)

Fe4bppt.gif

Neither hydroxide precipitate dissolves in excess sodium hydroxide.

Potassium Ferrocyanide

Potassium ferrocyanide will react with Fe3+ solution to produce a dark blue precipitate called Prussian blue:

K+(aq)+Fe3+(aq)+[Fe(CN)6]4−(aq)↽−−⇀KFe[Fe(CN)6](s)(5)

Fe5a1ppt.gif

With Fe2+ solution, a white precipitate will be formed that will be converted to blue due to the oxidation by oxygen in air:

2Fe2+(aq)+[Fe(CN)6]4−(aq)↽−−⇀Fe2[Fe(CN)6](s)(6)

Fe5a2ppt.gif

Many metal ions form ferrocyanide precipitates, so potassium ferrocyanide is not a good reagent for separating metal ions. It is used more commonly as a confirmatory test.

Potassium Ferricyanide

Potassium ferricyanide will give a brown coloration but no precipitate with Fe3+. With Fe2+, a dark blue precipitate is formed. Although this precipitate is known as Turnbull's blue, it is identical with Prussian blue (from Equation 5).

K+(aq)+Fe+2(aq)+[Fe(CN)6]3−(aq)↽−−⇀KFe[Fe(CN)6](s)(7)

Fe5b.gif

Potassium Thiocyanate

KSCN will give a deep red coloration to solutions containing Fe3+:

Fe+3(aq)+NCS−(aq)↽−−⇀[FeNCS]+2(aq)(8)

Fe5cppt.gif

No Reaction

Cl−, SO2−4


Related Questions

An aluminum atom has 13 protons. If an atom of aluminum has a neutral charge, how many electrons should be moving around outside the nucleus?

Answers

4 electrons should be moving outside the nucleus

Answer:

13

Explanation:

The correct answer is:

13

For an aluminum atom to have a neutral charge, 13 electrons must cancel out the positive charge from the 13 protons.

Which of the following chemical reactions will produce a precipitate?

3 KBr + AlPO4 → K3PO4 + AlBr3

Na2CO3 + CaCl2 → CaCO3 + 2 NaCl

NH4OH + KCl → KOH + NH4Cl

ZnCl2 + Mg2SO4 → ZnSO4 + MgCl2

Answers

Answer:

Na2CO3 + CaCl2 → CaCO3 + 2 NaCl

Explanation:

A double displacement reaction is a type of metathesis reaction in which two reactants exchange ions to form two new compounds. Double displacement reactions usually involve reacting two soluble salts in aqueous solution resulting in the formation of two products: a soluble salt and an insoluble salt that is produced as a precipitate.

If the reaction of two soluble compounds does not produce a precipitate, the reaction does not result in the formation of a product as basically, all the ions are mixed together in the reaction vessel.

From the given reactions above:

1. 3 KBr + AlPO4 → K3PO4 + AlBr3

The reaction does not proceed to product formation as the two products are all soluble salts.

2. Na2CO3 + CaCl2 → CaCO3 + 2 NaCl

The reaction occurs as one of the products, CaCO3 is insoluble as is produced as a precipitate.

3. NH4OH + KCl → KOH + NH4Cl

The reaction does nott occuras the products are all soluble in water.

4. ZnCl2 + Mg2SO4 → ZnSO4 + MgCl2

The reaction does not occur as the products are all soluble in water.

If a dog has a mass of 21.5 kg, what is its mass in the following units? Use scientific notation in all of your answers.

What is the dog’s mass in grams?

What is the dog’s mass in milligrams?

What is the dog’s mass in micrograms?

Answers

Explanation:

use the conversation in the image

S- 2500m
112
VODO
4. Two waves are traveling in the same medium with a speed of 340 m/s. What is the difference in
frequency of the waves if the one has a wavelength of 5.0 m and the other has a wavelength of
0.2 m?

Answers

Answer:

1632 Hz

Explanation:

We'll begin by calculating the frequency of each wave. This can be obtained as follow:

1st wave:

Velocity (v) = 340 m/s.

Wavelength 1 (λ₁) = 5 m

Frequency 1 (f₁) =?

v = λ₁f₁

340 = 5 × f₁

Divide both side by 5

f₁ = 340 / 5

f₁ = 68 Hz

2nd wave:

Velocity (v) = 340 m/s.

Wavelength 2 (λ₂) = 0.2 m

Frequency 2 (f₂) =?

v = λ₂f₂

340 = 0.2 × f₂

Divide both side by 0.2

f₂ = 340 / 0.2

f₂ = 1700 Hz

Finally, we shall determine the difference in the frequency of both waves.

This can be obtained as follow:

Frequency 1 (f₁) = 68 Hz

Frequency 2 (f₂) = 1700 Hz

Difference =?

Difference = f₂ – f₁

Difference = 1700 – 68

Difference = 1632 Hz

how can a scientist make a solution using salt and water?

Answers

Answer:

by boiling water and add the salt

Explanation:

because salt dissolves better if mixed with hot water which makes the process faster and effective

Water molecules pull the sodium and chloride ions apart, breaking the ionic bond that held them together. After the salt compounds are pulled apart, the sodium and chloride atoms are surrounded by water molecules, as this diagram shows. Once this happens, the salt is dissolved, resulting in a homogeneous solution.

Which overall chemical equation is obtained by combining these intermediate equations?

Answers

The common substance among the product(s) of the first equation and among the reactant(s) in the second equation is H2O(g). We can eliminate that as an intermediate. The overall chemical equation will thus be:

CH4(g) + 2O2(g) → CO2(g) + 2H2O(l),

which is the first answer choice.

In essence, all you’re doing here is swapping water vapor for liquid water.

Describe two realistic demands protestors could bring forward in their peaceful protest so that they dont face the same situation in future​

Answers

Answer:

I do not know the Answer I'm just trying to get my point

Explanation:

Thank You

The two realistic demands protestors could bring forward in their peaceful protest include:

Adequate securityProvision of social amenities.

Who is a Protester?

Thus it is referred to an individual which publicly demonstrates opposition to something.One of the roles of the government is to protect lives and properties.

Making realistic demands during a peaceful protest is looked into in most cases.

Read more about Protester here https://brainly.com/question/11505871

There is a bottle of KCl solution: the volume is 35 mL; its molarity is 3.0 M.

After diluting it into final volume 200 mL, what is the molarity (in M) now?

Answers

Answer:

0.525 M

Explanation:

As the problem deals with a dilution process, we can use the following formula:

C₁V₁=C₂V₂

Where subscript 1 stands for initial concentration and volume, while 2 stands for the final conditions. Meaning that in this case:

C₁ = 3.0 MV₁ = 35 mLC₂ = ?V₂ = 200 mL

We input the data given by the problem:

3.0 M * 35 mL = C₂ * 200 mL

And solve for C₂:

C₂ = 0.525 M

How are cells organized?
A: Organs
B: Organelles
C: Tissues

Answers

Answer:

tissues,organs, organelles

Calculate how many grams of sodium acetate you expected to make from your starting amount of sodium bicarbonate (0.5g). This is your theoretical yield.

Equation: NaHCO3 + HC2H3O2 = NaC2H3O2 + H2O + CO2

Answers

I think the answer is D

45. What is the H ion concentration of an aqueous solution
in which the OH-ion concentration is 1 x 10-2 mole
per liter?
A) 1 X 10-14 M
C) 1 x 10-9M
B) 1 x 10-12 M
D) | 10-2M

Answers

Answer:

= 1 X 10⁻⁻¹²M

Explanation:

At 25°C & 1atm [H⁺][OH⁻] = 1 x 10⁻¹⁴ => [H⁺] = 1 X 10⁻¹⁴/[OH⁻] = 1 X 10⁻¹⁴/1 X 10⁻²

= 1 X 10⁻⁻¹²M

Explain in detail how low density polyethylene is made​

Answers

Answer:

Low-density polyethylene is manufactured by the process of the polymerization of ethylene at very high temperatures in a tubular reactor. In this tubular reactor, high-pressure polymerization allows further copolymerization of ethylene with polar co-monomers. The tubular process has an advantage over autoclave process.

Explanation:

please mark brainliest

Plz help me well mark brainliest if you are correct!

Answers

Answer:

c: heat and erosine

Explanation:

What is the atomic number of the atom

Answers

An atomic number is the number above the element in a periodic table.
I’m not sure if that’s what you were asking, I was a bit confused on the wording.

What are 2 comparisons between organisms and music?

Help me fast I put 98 points pls help me no links I am serious.
3rd repost

Answers

They can form of inteqaty

Given a 0.5 M stock solution of aqueous NaCl, how much of the stock solution would you need to make a 50 mL sample of 0.25 M aqueous NaCl solution? How much water would you need to add to the NaCl solution?

Answers

Answer:

25 ml of stock

Explanation:

Molarity x Volume of Concentrated Stock = Molarity x Volume of  Diluted Stock

=> Mc x Vc = Md x Vd => (0.5M)(x) = (0.25M)(50 ml)

=> x = Vc = (0.25M x 50 ml) / (0.50M) = 25 ml of stock

Joan performed a shadow puppet play for her younger brother by shining a flashlight on paper cutouts behind a curtain. What happens to the light from the flashlight?

Answers

Answer:

The light is transmitted through the curtain.

Explanation:

I believe this might be the answer, please comment if it’s incorrect

Knives should be stored in cluttered drawers.
True or false

Answers

It would be false because you could hurt yourself while trying to get something I t he drawer

What is the chemical formula for iodine trichloride?
ОА. ЗІСІ
O B. ICI:
O c. 1, Cl₂
O D. 12C1

Answers

Answer:

I₂CL₆

Explanation:

Answer12C1

Explanation:

In the context of a balanced chemical equation, a____is a number to the lower right of an element or ion within formula and it applies to____. A____is a number to the left of a formula and it applies to_____. Only_____should be added or changed when balancing chemical equations.

Answers

Answer:

Explanation:

The preceding chapter introduced the use of element symbols to represent individual atoms. When atoms gain or lose electrons to yield ions, or combine with other atoms to form molecules, their symbols are modified or combined to generate chemical formulas that appropriately represent these species. Extending this symbolism to represent both the identities and the relative quantities of substances undergoing a chemical (or physical) change involves writing and balancing a chemical equation. Consider as an example the reaction between one methane molecule (CH4) and two diatomic oxygen molecules (O2) to produce one carbon dioxide molecule (CO2) and two water molecules (H2O). The chemical equation representing this process is provided in the upper half of Figure 1, with space-filling molecular models shown in the lower half of the figure.

Iodine shines like metals but is not metal what is its basis​

Answers

Answer:

Iodine is a non-metal, but it is lustrous (lustrous is the property of metal) in nature.

Consider the following scenario
A drought hits the habitat of a semi-aquatic bird population. All ponds dry up, and fish populations decline. There are two groups of birds in the population that differ in leg length and diet. Long-legged birds eat fish, while short-legged birds eat insects. The drought has little effect on insect populations
What is the main selective pressure in this scenario?

Oleg length
Odrought
Ofish population
Oinsect population

Answers

Answer: b

Explanation: jk

What transition energy corresponds to an absorption line at 502 nm?
A. 4.56 x 10-19
B. 1.76 10-19
C. 2.53 x 10-19
D. 3.96 10-19 J

Answers

Answer:

D 3.96 10-19J

Explanation:

I took the test

An amidation reaction is analogous to a(n) __________. View Available Hint(s) An amidation reaction is analogous to a(n) __________. esterification reaction in which an alcohol and a carboxylic acid react to form an ester acid hydrolysis reaction in which an amine is broken up into an amide and an alcohol base hydrolysis reaction in which an amine salt and an alcohol are formed esterification reaction in which an amine and an alcohol combine to make an amide

Answers

Answer:

esterification reaction in which an alcohol and a carboxylic acid react to form an ester

Explanation:

Esterification involves the reaction of  an alcohol and a carboxylic acid  to form an ester. This is an analogue of amidation which involves the reaction of a carboxylic acid with an amine to form an amide.

The relationship between the two reactions is that in both cases, the carbonyl (CO) group of the carboxylic acid is maintained and then bonded to a new moiety in the product. Water is formed in both reactions.

Hence, for esterification;

RCOOH + ROH ------> RCOOR + H2O

For amidation;

RCOOH + RNH2 -------> RCONHR + H2O

How many atoms are in 20.4 g of beryllium

Answers

Answer: sorry i don't know what the answer that question

Use Lewis theory to determine the chemical formula for the compound formed between Mg and Br. Group of answer choices Mg3Br2 Mg2Br3 Mg2Br MgBr2 MgBr

Answers

Answer:

MgBr2

Explanation:

(Mg^2+) + (Br^1-)

For every Mg we need 2 Br to balance out the compound.

Since magnesium has two outer electrons, it can donate one electron each to two bromine atoms having seven outer electrons in order for each of the atoms to have a complete octet.

Since the octet rule states that a stable atom must have eight electrons in its outermost shell, it follows that magnesium could give out two of its outermost electrons to two bromine atoms.

When that happens, each bromine atom which previously had seven electrons now have eight electrons, satisfying the octet rule. The correct formula of the compound is MgBr2.

Learn more: https://brainly.com/question/11527546

The acid ionization equilibrium for the weak acid HF is represented by the equation above. To prepare a buffer with a pH=3.50, a student needs to mix 250.mL of 0.100MHF and 250.mL of 0.100MKF. If the student mistakenly mixes 250.mL of 0.0500MHF and 250.mL of 0.0500MKF, which of the following is the result of this error?

The buffer will have a lower capacity because of the smaller number of moles of HF and F− available to react if an acid or base is added.

The buffer will have a lower capacity because of the smaller number of moles of H F and F with a negative 1 charge available to react if an acid or base is added.


The buffer will have a lower capacity because the smaller amount of HF and F− will lower the pH of the buffer, and buffers of lower pH have a lower buffer capacity.

The buffer will have a lower capacity because the smaller amount of H F and F with a negative 1 charge will lower the p H of the buffer, and buffers of lower p H have a lower buffer capacity.


The buffer will have a higher capacity because a larger proportion of HF and F− will ionize at lower concentrations, resulting in the neutralization of any added acid or base.

The buffer will have a higher capacity because a larger proportion of H F and F with a negative 1 charge will ionize at lower concentrations, resulting in the neutralization of any added acid or base.


The buffer will have the same capacity because the large volume of the buffer solution dilutes any added acid or base

Answers

Answer:

4

Explanation:

From the options provided the result of the error is ( A ) ; The buffer will have a lower capacity because of the smaller number of moles of  HF and F⁻ available to react if an acid or base is added.

Considering the acid ionization equilibrium for the weak acid HF.

A buffer solution is a solution that its PH value remains unchanged when a small amount of acid or base to added to the solution, therefore when the moles of acid or base present in the buffer solution is high enough the buffer solution will have a high buffer capacity. from the mistake of the student the number of moles present is lesser which means that the buffer solution will have a lower capacity

Hence the buffer will have a lower capacity because of the smaller number of moles of HF and F⁻ available to react is an acid or base is added.

learn more : https://brainly.com/question/2131477

What is the name of the structure formed when fertilization occurs?

Answers

Answer:

zygote

Explanation:

I got this online

Answer:

ᘔYᘜOTᗴ:

=> In human fertilization, a released ovum (a haploid secondary oocyte with replicate chromosome copies) and a haploid sperm cell (male gamete)—combine to form a single 2n diploid cell called the zygote.

ʰ ʰˡˢ

[tex] \infty \infty [/tex]

Pls help I need help ASAP!!! Be accurate

Answers

2nd choice is answer
121.2 is the awnser

Using table 3, predict the molecular geometry of the following molecules:
a. The central atom bonded to four substituent atoms and having no lone pair.
b. The central atom bonded to three substituent atoms and having one lone pair.
c. The central atom bonded to two substituent atoms ảnd having
one lone pair.
d. The central atom bonded to two substituent atoms and having no lone pair.

Answers

Answer:

see explanations

Explanation:

a. The central atom bonded to four substituent atoms and having no lone pair.

This is an AX₄ geometry => tetrahedron

b. The central atom bonded to three substituent atoms and having one lone pair.

This is an AX₃E geometry => pyramidal

c. The central atom bonded to two substituent atoms ảnd having

one lone pair.

This is an AX₂E geometry => bent angular

d. The central atom bonded to two substituent atoms and having no lone pair.

This is an AX₂ geometry => linear

_______________________________

Based upon the VSEPR Theory there are 6 parent geometry configurations and associated derived geometries.

Parent geometries  => Derivatives => Examples

linear => AX₂ (BeCl₂)                         trigonal planer => AX₃ (BH₃) => AX₂E (Bent)  (:SnCl₂)tetrahedral => AX₄ (CH₄) => pyrimidal AX₃E (NH₃) => Bent AX₂E₂ (H₂O)trigonal bipyrimidal => AX₅ (PCl₅) => seesaw AX₄E (:SF₄) => T-shaped AX₃E₂ (ClF₃ (T-shaped) => linear AX₂E₃ (XeF₂)octahedral => AX₆ (SF₆) => sqr pyramid AX₅E (IF₅) => sqr planar AX₄E₂ (XeF₄) pentagonal bipyrimidal => AX₇ (ClF₇)

For graphic images of each geometry do an internet search for 'molecular geometry'.

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