kam
An object oscillates as it moves along
the x-axis. Its displacement varies with
time according to the equation
x = 3 cos(6pi t + pi/2)

where t is in seconds

What is the frequency of this motion?

Answer:

Sue eats 1/3 of the pizza

Step-by-step explanation:

Answer:

Sue eats 1/3 of the pizza

Step-by-step explanation:

3/3 - 2/3 = 1/3

Answer:

  each coordinate is multiplied by 1/3

Step-by-step explanation:

Each point on the graph is moved to a distance from the origin that is its previous distance multiplied by the scale factor. This means every coordinate value is multiplied by the scale factor.

For example, a coordinate of (3, -9) scaled by 1/3 will become ...

  (1/3)(3, -9) = (1, -3)

__

Additional comment

If your scale factor is 1/3, often you will find that coordinates of the larger image are all multiples of 3. This makes relocating them to 1/3 their original distance fairly easy. Even if they're not, you still move each point to 1/3 its original distance. The new point will be on the line segment joining the center of dilation (the origin) with the original point.

The attached graph is an illustration of dilation by a factor of 1/3.

Answer:

$270 in all

Just multiply 9x20 and 9x10 and add them together

Answer: 4

Step-by-step explanation:

 Slope = -2.000/2.000 = -1.000

 x-intercept = 0/1 = 0.00000

 f-intercept = 0/1 = 0.00000

x = 0

Answer:

Step-by-step explanation:

semi circle: pi(r^2)/ 2

r=3

AREA: 14.14

Actual Product:

4491.9

Estimated Product:

4492

How is it 4492?

4491.9

The 9 is greater than 5 making it go up,

aka, making the 1 turn into a 2.

Answer:

[tex]\frac{3}{25\pi}[/tex] meters per minute

Step-by-step explanation:

Given:

[tex]V=\pi r^2h[/tex]

[tex]r=5[/tex]

[tex]\frac{dV}{dt}=3[/tex]

[tex]\frac{dh}{dt}=?[/tex]

Substitute r=5:

[tex]V=\pi r^2h[/tex]

[tex]V=\pi(5)^2h[/tex]

[tex]V=25\pi h[/tex]

Differentiate both sides:

[tex]\frac{d}{dt}V=\frac{d}{dt}(25\pi h)[/tex]

[tex]\frac{dV}{dt}=25\pi\frac{dh}{dt}[/tex]

Solve for dh/dt:

[tex]3=25\pi\frac{dh}{dt}[/tex]

[tex]\frac{3}{25\pi}=\frac{dh}{dt}[/tex]

Therefore, the height of the water is increasing at a rate of [tex]\frac{3}{25\pi}[/tex] meters per minute.

Answer:

17

Step-by-step explanation:

Answer:

plot 17

Step-by-step explanation:

12-(-5) = 12+5 = 17

Step-by-step explanation:

[tex]30 + 4x + 2 = 80[/tex]

[tex]4x + 32 = 80[/tex]

[tex]4x = 48[/tex]

[tex]x = 12[/tex]

Therefore, the answer is x = 12.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Answer:

1.17m²

Step-by-step explanation:

Total area of cardboard=

[tex]1.6 \times 0.8 = 1.28m {}^{2} [/tex]

Area of circular piece=

[tex]\pi \: r {}^{2} = ( \frac{22}{7} )(0.12) {}^{2} = \frac{198}{4375} m {}^{2} [/tex]

Area of rectangular piece=

[tex]0.2 \times 0.15 = 0.03m {}^{2} [/tex]

Area of 2 triangular pieces=

[tex]2( \frac{1}{2} \times 0.3 \times 0.1) = 0.03m {}^{2} [/tex]

Remaining area of the cardboard= Total area of cardboard - circular piece - 2 triangular pieces

[tex]1.28 - \frac{198}{4375} - 0.03 -0.03 = \frac{21083}{17500} =1.17m {}^{2} [/tex]

Answer:

a is possible

b is not possible

c is possible

Answer:

744

Step-by-step explanation:

Using the binomial distribution, it is found that there is a 0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

For each free throw, there are only two possible outcomes, either he makes it, or he misses it. The results of free throws are independent from each other, hence, the binomial distribution is used to solve this question.

Binomial probability distribution

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

The parameters are:

In this problem:

The probability that he makes exactly 1 is P(X = 1), hence:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 1) = C_{3,1}.(0.9)^{1}.(0.1)^{2} = 0.027[/tex]

0.027 = 2.7% probability that he makes exactly 1 of the 3 free throws.

To learn more about the binomial distribution, you can take a look at https://brainly.com/question/24863377

Answer:

0.03

Step-by-step explanation:

I just did it on Khan

Answer:

Option D is correct.

Explanation:

An obtuse angle is an angle that has more than 90°. In the picture, we can clearly see that ∠XYZ has more than 90°. This is an obtuse angle. ∠XWZ is also more than 90°, so that angle is also classified as an obtuse angle. Hence, Option D is correct.

Hoped this helped.

[tex]BrainiacUser1357[/tex]

Hello there, today you gave us the problem [tex]\frac{17}{20}-\frac{4}{15}[/tex],

Our first step is to give them common denominators, which is [tex]\frac{51}{60}-\frac{16}{60}[/tex], solve it and we get [tex]\frac{35}{60}[/tex] as our answer, which can be simplified down to [tex]\frac{7}{12}[/tex]

Answer:

24%

Step-by-step explanation:

consider bag 1: there are 3 vowel tiles (out of 5) in this bag so the probability of choosing a vowel tile would be 3/5

bag 2: there are 2 vowel tiles (out of 5) in this bag so the probability of choosing a vowel tile would be 2/5

to find the probability of getting two vowel tiles (one from each bag), you multiply these two probabilities together:

3/5 *2/5 to get 6/25 which is equal to 0.24 or 24%

Answer:

[tex]c=\frac{1}{16}[/tex]

Step-by-step explanation:

[tex]f(x)=\sqrt{2x}[/tex]

[tex]f'(x)=\frac{\sqrt{2x}}{2x}[/tex]

[tex]f'(1)=\frac{\sqrt{2}}{2}[/tex]

[tex]f'(c)=\frac{\sqrt{2c}}{2c}[/tex]

[tex]f'(c)=4f'(1)[/tex]

[tex]\frac{\sqrt{2c}}{2c}=4(\frac{\sqrt{2}}{2})[/tex]

[tex]\frac{\sqrt{2c}}{2c}=2\sqrt{2}[/tex]

[tex]\sqrt{2c}=4c\sqrt{2}[/tex]

[tex]2c=32c^2[/tex]

[tex]2=32c[/tex]

[tex]\frac{1}{16}=c[/tex]

Answer:

$6.75

Step-by-step explanation:

Divide 33.75 by 5, they are $6.75 each

[tex](b) ^{2} + {(h)}^{2} = {(x)}^{2} \: \: \: ( by \: \: \: pythagoras \: \: \: theorem)\\ = > {(10)}^{2} + {(10)}^{2} = {(x)}^{2} \\ = > 100 + 100 = {x}^{2} \\ = > 200 = {x}^{2} \\ = > x = \sqrt{200} mm \\ = > x = \sqrt{2 \times 2 \times 2 \times 5 \times 5}mm \\ = > x = 2 \times 5 \sqrt{2} mm \\ = > x = 10 \sqrt{2} mm[/tex]

Answer:

10√2 mm.

Hope you could get an idea from here.

Doubt clarification - use comment section.

Answer:

A and D

Step-by-step explanation:

[tex]20 r + 60t = 20(r+3t) = 4\cdot 5(r +3t)=4(5r +15t)[/tex]

Answer:

30

Step-by-step explanation:

Answer:the answer is a

Step-by-step explanation:

Answer:

[see below]

Step-by-step explanation:

Three less than a number (x) would be: x - 3

"The product of three less than a number and eight" would be 8(x-3).

The product of three less than a number and eight is nine would be:

8(x-3) = 9

[tex]8(x-3) = 9\\\rule{150}{0.5}\\8x - 24 = 9\\\\8x - 24 + 24 = 9 + 24\\\\8x = 33\\\\\frac{8x = 33}{8}\\\\x = \frac{33}{8}[/tex]

Hope this helps.

Answer:

the answer is defently 405

Step-by-step explanation:

so you have 400 and 5 and 400+5=405

Answer:

A.$3,600

Step-by-step explanation:

24,000*15% = 3600

or

24,000*0.15 = 3600

Answer:

A

Step-by-step explanation:

24000x15/100

g(x) as given has no inverse because there are instances of two x values giving the same value of g(x). For instance,

x = -1   ⇒   g(-1) = 4 (-1 + 3)² - 8 = 8

x = -5   ⇒   g(-5) = 4 (-5 + 3)² - 8 = 8

Only a one-to-one function can have an inverse. g(x) is not one-to-one.

However, if we restrict the domain of g(x), we can find an inverse over that domain. Let [tex]g^{-1}(x)[/tex] be the inverse of g(x). Then by definition of inverse function,

[tex]g\left(g^{-1}(x)\right) = 4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]

Solve for the inverse:

[tex]4 \left(g^{-1}(x) + 3\right)^2 - 8 = x[/tex]

[tex]4 \left(g^{-1}(x) + 3\right)^2 = x + 8[/tex]

[tex]\left(g^{-1}(x) + 3\right)^2 = \dfrac{x + 8}4[/tex]

[tex]\sqrt{\left(g^{-1}(x) + 3\right)^2} = \sqrt{\dfrac{x + 8}4}[/tex]

[tex]\left| g^{-1}(x) + 3 \right| = \dfrac{\sqrt{x+8}}2[/tex]

Recall the definition of absolute value:

[tex]|x| = \begin{cases}x & \text{if }x\ge0\\-x&\text{if }x<0\end{cases}[/tex]

This means there are two possible solutions for the inverse of g(x) :

• if [tex]g^{-1}(x) + 3 \ge 0[/tex], then

[tex]g^{-1}(x) + 3 = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]

• otherwise, if [tex]g^{-1}(x)+3<0[/tex], then

[tex]-\left(g^{-1}(x) + 3\right) = \dfrac{\sqrt{x+8}}2 \implies g^{-1}(x) = -3-\dfrac{\sqrt{x+8}}2[/tex]

Which we choose as the inverse depends on how we restrict the domain of g(x). For example:

Remember that the inverse must satisfy

[tex]g\left(g^{-1}(x)\right) = x[/tex]

In the first case above, [tex]g^{-1}(x) + 3 \ge 0[/tex], or [tex]g^{-1}(x) \ge -3[/tex]. This suggests that we could restrict the domain of g(x) to be [tex]x \ge -3[/tex].

Then as long as [tex]x \ge -3[/tex], the inverse is

[tex]g^{-1}(x) = -3+\dfrac{\sqrt{x+8}}2[/tex]

Answer:

3(4-2P) = 6*4

12-6P=24

-6P=24-12

P= 12/-6

P= -2

Answer:

37

Step-by-step explanation:

All angles of a triangle have to add up to 180 degrees

180 - 113 - 30 = 37

37+113+30 = 180