Physics High School

Juan makes an adjustment to an electromagnet that causes the electromagnet to lose some of its strength. What did Juan most likely do?

He reduced the number of loops in the wire.
He increased the number of loops in the wire.
He reduced the length of the wire.
He increased the length of the wire.

Answers

Answer 1

Answer:

Its A

Explanation:

Answer 2

To reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

What is electromagnetic field strength?

The strength of an electromagnetic is the effect or force that an electromagnet exerts in a given field.

The strength of an induced emf in a given magnetic field is given by;

emf = NBA/t

where;

N is number of turns of the magnetB is magnetic field strengthA is area of the coil

Decrease in number of turns of the wire, reduces the strength of the magnetic field.

Thus, to reduce the strength of an electromagnet, Juan must  reduced the number of loops in the wire.

Learn more about electromagnet here: https://brainly.com/question/12555869

#SPJ2

Related Questions

Conduction In Everyday Life Examples
at least 5 plz help

Answers

1. Heat transfer from a hot burner on the stove into a pot or pan

2. A metal spoon that gets hot from the boiling water

3. Chocolate candy in your hand that melts because of the heat

4. The wires in your house that conduct electricity

5. Roasting marshmallows, the heat will soften the marshmallow

Answer:

the engine heat from a car you just turned on.

a heater

a pad warmer

a hot pot

using a campfire to roast hot dogs

pls answer quick & an accurate answer will get brainliest

Answers

Answer:

3.766 kg or 3.7 kg

Explanation:

F= M*A equation

A rescue plane wants to drop supplies to isolated mountain climbers on a rocky ridge 235m below. If the plane is traveling horizontally with a speed of 250 km/h (69.4m/s), (a) how far in advance of the recipients ( horizontal distance) must the goods be dropped. (b) Suppose, instead that the plane release the supplies a horizontal distance of 425m in advance of the mountain climbers. What vertical velocity (up or down) should the supplies be given so that they arrive precisely at the climber's position? (c) with what speed do the supplies land in the latter case

Answers

Answer:

Explanation:

For vertical displacement of food-supply

if time taken to reach the ground be t

235 = 1/2 g t²  , initial velocity downwards is zero.

t = 6.92 s

Horizontal displacement of food during this period

= 6.92 x 69.4 m

= 480.25 m .

b )

time required to cover horizontal distance of 425 m

= 425 / 69.4 = 6.124 s  

This time period will be the time of vertical fall of 235 m . Let initial vertical velocity required be u

h = ut + 1/2 gt²

235 = u x 6.124 + .5 x 9.8 x 6.124²

235 = u x 6.124 + 183.76

u = 8.36 m /s

c )

v = u + gt

= 8.36 + 9.8 x 6.124

= 68.37 m /s

This will be vertical component of velocity .

horizontal velocity = 69.4 m /s

resultant velocity = √ ( 68.37² + 69.4²)

= √(4674.45 +4816.36)

= 97.42 m /s

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