Juan is three times as old as Gabe and Gabe is six years older than Catherine. If the sum of their ages is 149, how old is each person? Define a variable, write an equation, solve the equation, and answer in a complete sentence. (Remember to clearly show your work on your work page.)

Answers

Answer 1

Answer:

Juan = 93 years.

Gabe = 31 years.

Catherine = 25 years.

Step-by-step explanation:

Let the age of Juan = J

Let the age of Gabe = G

Let the age of Catherine = C

Translating the word problem into an algebraic equation, we have;

[tex] J = 3G[/tex] ..........equation 1

[tex] G = C + 6 [/tex] ........equation 2

[tex] J + G + C = 149 [/tex] ........equation 3

We would solve the linear equations by using the substitution method;

Substituting equation 2 into equation 1;

[tex] J = 3(C + 6)[/tex]

[tex] J = 3C + 18[/tex] ........equation 4

Substituting equation 2 and equation 4 into equation 3;

[tex] (3C + 18) + (C + 6) + C = 149 [/tex]

Simplifying the equation, we have;

[tex] 5C + 24 = 149[/tex]

[tex] 5C = 149 - 24[/tex]

[tex] 5C = 125[/tex]

[tex] C = \frac {125}{5}[/tex]

C = 25 years.

To find G; from equation 2

[tex] G = C + 6[/tex]

Substituting the value of "C" into equation 2, we have;

[tex] G = 25 + 6[/tex]

G = 31 years.

To find J; from equation 1

[tex] J = 3G [/tex]

Substituting the value of "G" into equation 1, we have;

[tex] J = 3 * 31[/tex]

J = 93 years.

Therefore, Juan is 93 years old, Gabe is 31 years old and Catherine is 25 years old.


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=========================================================

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It may not look it, but the given equation is nearly in quadratic form.

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---------------------

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