Jerry was given some birthday money He puts the money in an account Every month after that he deposits the same amount of money The equation that models this situation y=50x+75 where y is the amount of money int he account and x is the number of deposits What does the y- intercept means in this situation

Jane is given a $100 gift to start and saves $35 a month from her allowance.

   After 1 month, Jane has saved

   After 2 months, Jane has saved

   After three months, Jane has saved

   and so on

In general, after x months Jane has saved

This means that it makes sense to represent the relationship between the amount saved and the number of months with one constant rate (in this case the constant rate is 35). It makes sense because the amount of money increases by $35 each month. Since the amount of increase is constant, we get constant rate. Also the initial amount is known ($100), so there is a possibility to write the equation of linear function representing this situation.

Step-by-step explanation:

Answer:

1/4 miles

Step-by-step explanation:

Hey there!

Well starting at Campbell and going to Morristown it is 1/4 miles.

Going from Campbell to Clarksville it is 2/4 miles.

So to find the difference we’ll subtract.

2/4 - 1/4

= 1/4 miles

Hope this helps :)

Answer:

Lacy is 13 and Jack is 52

Step-by-step explanation:

In 3 years their ages will add up to 71 so you have to subtract 6 as there are two of them to get 65. Lacy's age is represented by x and since Jack is 4 times older his age is represented by 4x. So added together their age is 5x. So 5x=65. Then 65/5=13. So 13=x. So Lacy is 13 and Jack is 52 as 13x4 is 52.

Answer:

[tex]\displaystyle a=4, b= \frac{25}{4}, \text{ and } k = \frac{125}{2}[/tex]

Step-by-step explanation:

Note that the graph passes through the points: (0, 4), (1, 25), and (1.5, k).

The standard exponential function has the form:

[tex]\displaystyle y = ab^x[/tex]

The point (0, 4) tells us that y = 4 when x = 0. Therefore:

[tex](4) = a(b)^0[/tex]

Since anything raised to zero is one:

[tex]a=4[/tex]

Hence, our function is now:

[tex]y = 4(b)^x[/tex]

The point (1, 25) tells us that y = 25 when x = 1. By substituting:

[tex](25) = 4(b)^{(1)}[/tex]

Solve for b:

[tex]\displaystyle b = \frac{25}{4}[/tex]

Thus, our completed function is:

[tex]\displaystyle y = 4\left(\frac{25}{4}\right)^x[/tex]

To find k, simply substitute 1.5 for x. This yields:

[tex]\displaystyle y = k = 4\left(\frac{25}{4}\right)^{(1.5)}[/tex]

And evaluate. Hence:

[tex]\displaystyle \begin{aligned} k &= 4\left(\frac{25}{4}\right)^{3/2} \\ \\ &= 4\left(\left(\frac{25}{4}\right)^{1/2}\right)^3 \\ \\ &= 4\left(\frac{5}{2}\right)^3 \\ \\ &= 4\left(\frac{125}{8}\right) \\ \\ &= \frac{125}{2}\end{aligned}[/tex]

In conclusion:

[tex]\displaystyle a=4, b= \frac{25}{4}, \text{ and } k = \frac{125}{2}[/tex]

[tex] \Large{ \underline{ \underline{ \bf{ \orange{Solution:}}}}}[/tex]

Let one of those even numbers be x, Then other even number would be x + 2.

According to question,

⇛ Their reciprocal add upto 3/4

So, we can write it as,

⇛ 1/x + 1/x + 2 = 3/4

⇛ x + 2 + x / x(x + 2) = 3/4

⇛ 2x + 2 / x² + 2x = 3/4

Cross multiplying,

⇛ 3(x² + 2x) = 4(2x + 2)

⇛ 3x² + 6x = 8x + 8

⇛ 3x² - 2x - 8 = 0

⇛ 3x² - 6x + 4x - 8 = 0

⇛ 3x(x - 2) + 4(x - 2) = 0

⇛ (3x + 4)(x - 2) = 0

Then, x = -4/3 or 2

☃️ It can't be -4/3 because it is fraction and negative number. So, x = 2

Then, x + 2 = 4

✤ So, The even numbers are 2 and 4.

━━━━━━━━━━━━━━━━━━━━

19. 68 because 90seconds 1hr 30 mons

Answer:

Step-by-step explanation:

We have the equations

4x + 3y = 18   where x = the side of the square and y = the side of the triangle

For the areas:

A = x^2 + √3y/2* y/2

A = x^2  + √3y^2/4

From the first equation x = (18 - 3y)/4

So substituting in the area equation:

A = [ (18 - 3y)/4]^2 + √3y^2/4

A = (18 - 3y)^2 / 16 + √3y^2/4

Now for maximum / minimum area the derivative = 0 so we have

A' = 1/16 * 2(18 - 3y) * -3 + 1/4 * 2√3 y = 0

-3/8 (18 - 3y) + √3 y /2 = 0

-27/4 + 9y/8 + √3y /2 = 0

-54 + 9y + 4√3y = 0

y = 54 / 15.93

= 3.39 metres

So x = (18-3(3.39) / 4 = 1.96.

This is a minimum value for x.

So the total length of wire the square  for minimum  total area is 4 * 1.96

= 7.84 m

There is no maximum area as the equation for the total area is a quadratic with a positive leading coefficient.

The length of the square must be 4 m in order to maximize the total area.

When we put the differentiation of the given function as zero and find the value of the variable we get maxima and minima.

We have,

Length of the wire = 18 m

Let the length of the wire bent into a square = x.

The length of the wire bent into an equilateral triangle = (18 - x)

Now,

The perimeter of a square = 4 side

4 side = x

side = x/4

The perimeter of an equilateral triangle = 3 side

11 - x = 3 side

side = (18 - x)/3

Area of square = side²

Area of equilateral triangle = (√3/4) side²

Total area:

T = (x/4)² + √3/4 {(18 -x)/3}² _____(1)

Now,

To find the maximum we will differentiate (1)

dT/dx = 0

2x/4 + (√3/4) x 2(18 - x)/3 x -1 = 0

2x / 4 - (√3/4) x 2(18 - x)/3 = 0

2x/4 - (√3/6)(18 - x) = 0

2x / 4 = (√3/6)(18 - x)

√3x = 18 - x

√3x + x = 18

x (√3 + 1) = 18

x = 18 / (1.732 + 1)

x = 18/2.732

x = 6.58

x = 7

Thus,

The length of the square must be 7 m in order to maximize the total area.

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Answer:

x = 20°

Step-by-step explanation:

So when I learned it we called it the exterior angle theorem not the angle sum theorem but here goes.

Since exterior angle = 110 Degrees,

--> The Inner 2 angles's sum = 110 Degrees

so, 70 + 2x = 110

=> 2x = 40

x = 20

x = 20°

Hope this helps!

Answer:

6:9

Step-by-step explanation:

Answer:

6 and 9

Step-by-step explanation:

according to the question, the nos. are 2x and 3x.

then, (2x+3)/(3x+3)=3/4

therefore, 4(2x+3)=3(3x+3)

8x+12=9x+9

12-9=9x-8x

3=x

therefore the nos. are 2×3=6 & 3×3=9

Answer from Gauth math

Answer:

A

Step-by-step explanation:

based on line p and q

Answer: p || q

Or A

Step-by-step explanation:

good luck

Responder:

| AB | = 12m

Explicación paso a paso:

Verifique el diagrama en el archivo adjunto.

En el diagrama, se puede ver que el lado FC es igual al lado FB de acuerdo con el triángulo isósceles FBC.

Además, el lado FB es igual a AB ya que son paralelos entre sí.

De la declaración anterior, | FC | = | FB | y | FB | = | AB |

Esto significa | FC | = | FB | = | AB |

Por lo tanto desde | FC | = 12 m, | AB | = 12 m ya que ambos lados son iguales.

De ahí el lado | AB | se mide 12m

[tex]13ab^3+39a^2b^5\\\\\boxed{\boxed{\boxed{13ab^3(1+3ab^2)}}}\\\\[/tex]

Brazil number one.

Answer:

there's no answer for that equation

Step-by-step explanation:

Maximum = 62

Median = (34+37+39+32+48+45+53+62+58+61+60+41)/12= 47.5≈48

quartile

In increasing order

32, 34, 37, 39, 41, 45, 48, 53, 58, 60, 61, 62

Upper quartile= (58+60)/2 = 59

Lower quartile= (37+39)/2 = 38

Minimum= 32

Answer:

X+6

Step-by-step explanation:

Sum means Addition.

16x²+40xy + 25y²

(4x+5y) (4x+5y)

(4x+5y)²

I hope I helped you^_^

The function is always positive.

(0,5) is the y-intercept, since the graphed line never crosses the x axis, there is no x-intercept.

The function is positive and  greater than 4 for all values of x

Not sure what the actual choices are on a couple of the questions. The choices would help answering.

Answer:

12 , 19 , 26 , 33

Here, n+7

12+7=19

19+7=26

So,

26+7=33

Hope you understand ❣

Step-by-step explanation:

12 , 19 , 26 , ?

Given

___________

a1= 12

a2= 19

a3 = 26

d= ?

a4 = ?

––——————

we can solve this by using formula from Ap .

But for this we have to find d

As we know that

common difference(d) = a2-a1 = 19 -12

= 7

so difference after every no is 7 so

a4 = a3 + d

= 26 +7

= 33

So 33 is ur answer mate

Hope it helps

Answer:

The 95% confidence interval is  [tex]10.5 < \mu <13.3[/tex]

Step-by-step explanation:

From the question we are told that

     The  sample size is  [tex]n = 41[/tex]

      The  sample mean is  [tex]\= x = 11.9 \ hr[/tex]

       The standard deviation is  [tex]\sigma = 4.5[/tex]

For  a  95% confidence interval the confidence level is  95%

Given that the confidence level is 95% then the level of significance can be mathematically represented as

                  [tex]\alpha = 100 - 95[/tex]

                  [tex]\alpha = 5 \%[/tex]

                  [tex]\alpha = 0.05[/tex]

Next we obtain the critical values of  [tex]\frac{\alpha }{2}[/tex] from the normal distribution table

     The values is

                             [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

Generally the margin of error is mathematically represented as

                             [tex]E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{ \sqrt{n} }[/tex]

substituting values

                           [tex]E = 1.96 * \frac{ 4.5 }{ \sqrt{41} }[/tex]  

                           [tex]E = 1.377[/tex]

The 95% confidence interval is mathematically represented as

          [tex]\= x - E < \mu < \= x - E[/tex]

substituting values

         [tex]11.9 - 1.377 < \mu <11.9 + 1.377[/tex]

         [tex]10.5 < \mu <13.3[/tex]

Complete Question

Statistics professors believe the average number of headaches per semester for all students is more than 18. From a random sample of 15 students, the professors find the mean number of headaches is 19 and the standard deviation is 1.7. Assume the population distribution of number of headaches is normal.the correct conclusion at [tex]\alpha =0.001[/tex] is?

Answer:

There is no sufficient evidence to support the professor believe

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 18[/tex]

     The sample size is  [tex]n = 15[/tex]

      The sample mean is  [tex]\= x = 19[/tex]

      The standard deviation is  [tex]\sigma = 1.7[/tex]

      The level of significance is  [tex]\alpha = 0.001[/tex]

The null hypothesis is  [tex]H_o: \mu = 18[/tex]

The  alternative hypothesis is  [tex]H_a : \mu > 18[/tex]

 The critical value of the level of significance from the normal distribution table is    

         [tex]Z_{\alpha } = 3.290527[/tex]

The test hypothesis is mathematically represented as

           [tex]t = \frac{\= x - \mu }{ \frac{\sigma}{ \sqrt{n} } }[/tex]

substituting values  

         [tex]t = \frac{ 19 - 18}{ \frac{1.7}{ \sqrt{15} } }[/tex]

         [tex]t = 2.28[/tex]

Looking at the value of  t and  [tex]Z_{\alpha }[/tex] we can see that [tex]t < Z_{\alpha }[/tex] so we fail to reject the null hypothesis.

This mean that there is no sufficient evidence to support the professor believe

Answer:

3 only

Step-by-step explanation:

Consider the statement, "The two cities with the highest number of respondents, both show more support for candidate A." In the total column, the two highest number of respondents are 471 and 463 which represent Carsonville and Appleton. For Carsonville, the number of respondents who prefer candidate A is 205, which is less than the number of respondents who prefer candidate B, 266. Therefore, this statement is not true.

Consider the statement, "The number of people who support candidate B in Carsonville is twice the number of people who support candidate B in New Thomas." In the table, the number of people who support candidate B in Carsonville is observed to be 266 and the number of people who support candidate B in New Thomas is 138. Since 266 is not equal to twice 138, this statement is not true.

Consider the statement, "More residents of Center City responded to the poll than the number who responded from New Thomas." In the total column, it can be observed that 350 people responded to the poll in Center City and 318 people responded to the poll in New Thomas. Since, 350 is greater than 318, this statement is true.

Consider the statement, "Overall, more residents support candidate A than candidate B." The bottom row of the table represents the total number of responses for each candidate. The number of people supporting candidate A is 797, which is less than the number of people supporting candidate B, 805. So, this statement is not true.

Therefore, the true statement is III only.

More residents of the center city responded to the pole than the number who responded from New Thomas, which is the only correct option. Option B. is correct.

Data given in the table shows the data of elections between two candidates among the different cities.

Statistics is the study of mathematics that deals with relations between comprehensive data.

I.The two cities with the highest number of respondents both show more support for candidate A. This statement is false because carsonville is the second highest support for A but it does not show more support for candidate A.

II.The number of people who support candidate B in Carsonville is twice the number of people who support candidate B in New Thomas. It is false

III. More residents of Center City responded to the pole than the number who responded from New Thomas. It is true.

IV. Overall, more residents support candidate A than candidate B. it is also false.

Thus, more residents of the center city responded to the pole than the number who responded from New Thomas, which is the only correct option. Option B. is correct.

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Answer:

A

Step-by-step explanation:

f(x) = 1/(x-3)+7

f(x)-7=1/(x-3)

x=1/(f(x)-7)+3

f^-1(x)=1/(x-7)+3, where x≠7

The correct answer is option (a)  [tex]f^{-1}(x)= \frac{1}{x-7} +3[/tex] where [tex]x\neq 7[/tex].

The domain of a function is the complete set of possible values of the independent variable

Given [tex]f^{}(x)= \frac{1}{x-3} +7[/tex]

Let

[tex]y= \frac{1}{x-3} +7[/tex]

⇒y-7= 1/x-3

⇒x-3 =1/y- 7

⇒ [tex]x= \frac{1}{y-7} +3[/tex]

hence option a is correct

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Answer: C. 41

Step-by-step explanation:

[tex]-\left(31+2\right)+7^2-\left(-5^2\right)[/tex]

[tex]=-33+7^2-\left(-5^2\right)[/tex]

[tex]\left(-5^2\right)=-25[/tex]

[tex]=-33+7^2-\left(-25\right)[/tex]

[tex]7^2=49[/tex]

[tex]=-33+49-\left(-25\right)[/tex]

[tex]-33+49=16[/tex]

[tex]=16-\left(-25\right)[/tex]

[tex]\mathrm{Apply\:rule\:}-\left(-a\right)\:=\:+a[/tex]

[tex]16+25=41[/tex]

Answer:

x = 2(sqrt26) or x = 10.1980390272...

Step-by-step explanation:

Right triangles can be solved using Pythagorean theorem, where the legs are squared and added together to get the hypotenuse's length squared.

If we set up the equation:

11^2 + x^2 = 15^2

which is

121 + x^2 = 225

subtract 121 from both sides

x^2 = 104

sqrt  both sides

x = 2(sqrt26), or x = 10.1980390272...

Answer:

Using Pythagoras theorem

c²=a²+b²

(15)²=x² +(11)²

225=x²+ 121

-x²=121-225

-x²=-104

multiply both sides by (-1)

x²=104

x=✓104

x=10ft

Step-by-step explanation:

yah kaun se language mein likha hai aapane

Step-by-step explanation:

(AUB)' means they are all outside the set A and B so thats 0. Hope it helps

Answer:

The slope of Function 2 (m=1.1) is greater than the slope of Function 1 (m=1).  

Step-by-step explanation:

First, note that p is essentially the y and that r is the x. Thus, to make this easier to see, convert p to y and r to x. Thus:

[tex]y=x+7[/tex]

From the above equation, we can determine that the slope is 1. Thus, the slope of Function 1 is 1.

To find the slope of the table, simply use the slope formula. Use any two points. I'm going to use the points (0,8) and (10,19). Let (0,8) be x₁ and y₁, and (10,19) be x₂ and y₂. Therefore:

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{19-8}{10-0}=11/10=1.1[/tex]

Thus, the slope of Function 2 is 1.1.

1.1 is greater than 1.

Thus, the slope of Function 2 is greater than the slope of Function 1.

Answer:

Function 2 has the greater slope

Step-by-step explanation:

Answer:

Step-by-step explanation:

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[tex]\boxed{\sf (a+b)^2=a^2+b^2+2ab}[/tex]

Now

[tex]\\ \sf\longmapsto x+\dfrac{1}{x}=12[/tex]

[tex]\\ \sf\longmapsto \left(x+\dfrac{1}{x}\right)^2=12^2[/tex]

[tex]\\ \sf\longmapsto x^2+2\times x\times \dfrac{1}{x}+\left(\dfrac{1}{x}\right)^2=144[/tex]

[tex]\\ \sf\longmapsto x^2+\dfrac{1}{x^2}+2=144[/tex]

[tex]\\ \sf\longmapsto x^2+\dfrac{1}{x^2}=144-2=142[/tex]

Answer:

122

Step-by-step explanation:

x+1/x = 12

x + 1 = 12x

x = 1/11

（1/11）² + 1 / （1/11）² = 1/121 +1 /1/121 = 122

Answer:

hope this help you a lot

have a great day