Jenny predicted that she would sell 12 bracelets, but she actually sold 16 bracelets. Which expression would find the percent error?

Answers

Answer 1

Answer:

12/16 which would be a -25% error

Step-by-step explanation:

Percent Error =  

12-16/16

=

-4/16

=

-25%

Answer 2

Answer:

the answer is d

Step-by-step explanation:


Related Questions

find sin 2a and cot 2a:

Answers

Answer:

[tex]sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cot(2\alpha ) = \frac{16511}{18720}[/tex]

Step-by-step explanation:

[tex]\text{if } cos(\alpha)=\frac{12}{13}\\\text{That must mean we have a triangle with base 12, and hypotenuse 13.}\\\text{Using Pythagoras, we can determine the base of the triangle must be 5.}\\a^2+b^2=c^2 \text{, where c is the hypotenuse and a, b are the two other sides.}\\c^2-b^2=a^2\\\sqrt{c^2-b^2}=a\\\sqrt{13^2-12^2}=\sqrt{169-144}=\sqrt{25}=5\\\text{Therefore, }sin(\alpha) = \frac{5}{12}\\sin(2\alpha)=2sin(\alpha )cos(\alpha)\\\text{(From double angle formulae identities)}\\[/tex]

[tex]sin(2\alpha )=2(\frac{5}{12})(\frac{12}{13})=\frac{10}{13}\\cos(2\alpha )=cos^2(\alpha)-sin^2(\alpha)\\cos(2\alpha )=(\frac{12}{13})^2-(\frac{5}{12})^2=\frac{16511}{24336}\\cot(2\alpha)=\frac{cos(2\alpha)}{sin(2\alpha)}=\frac{\frac{16511}{24336}}{\frac{10}{13}}=\frac{16511}{18720}[/tex]

heleeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeeep

Answers

Answer:

3.625 is ans

Step-by-step explanation:

4.5+0.25_+1.125=3.625

Step-by-step explanation:

this is your answer sis ...

Please answer I’m not good with math

Answers

angleGEF, the first option!!

Answer: A

Step-by-step explanation:

it's easy

If f(x) = squareroot x + 5 and g(x) = -4x + 4,
which statement is true?
Click on the correct answer.
3 is in the domain of fºg.
3 is not in the domain of fºg.

Answers

Answer:

3 is not in the domain of [tex]f\circ g[/tex].

Step-by-step explanation:

The given functions are

[tex]f(x)=\sqrt{x+5}[/tex]

[tex]g(x)=-4x+4[/tex]

We need to check whether 3 is in the domain of [tex]f\circ g[/tex] or not.

[tex]f\circ g=f(g(x))[/tex]

[tex]f\circ g=f(-4x+4)[/tex]     [tex][\because g(x)=-4x+4][/tex]

[tex]f\circ g=\sqrt{(-4x+4)+5}[/tex]     [tex][\because f(x)=\sqrt{x+5}][/tex]

[tex]f\circ g=\sqrt{-4x+9}[/tex]

This function is defined if

[tex]-4x+9\geq 0[/tex]

[tex]9\geq 4x[/tex]

[tex]\dfrac{9}{4}\geq x[/tex]

It means domain of the function [tex]f\circ g[/tex] is [tex](-\infty,\dfrac{9}{4}][/tex].

[tex]3\notin (-\infty,\dfrac{9}{4}][/tex]

Therefore, 3 is not in the domain of [tex]f\circ g[/tex].

X/5-2=11 what is the solution

Answers

Answer:

x=65

Step-by-step explanation:

x/5 - 2 = 11

x/5= 11+2

x/5=13

x=13×5

x=65

Answer:

X = 55 is the answer.

Step-by-step explanation:

Question = x/5 - 2 = 11

1. Isolate the variable

x/5 - 2 = 11

    + 2   + 2

x/5 = 11

2. Remove the fraction

x/5 = 11

*5      *5

3. Simplify

x = 55

The answer is x = 55.

Hope this helped,

Kavitha

What is the distance between the points (-3, 9) and (5, 1)? Round to the
nearest tenth, if necessary.

Answers

Answer: 11.3

Step-by-step explanation:

To find the distance, we will need the distance formula.

[tex]D=\sqrt{(x_{2}-x_{1} ) ^2+(y_{2}-y_{1})^2 }[/tex]

Since we know our x and y, we can plug them into this equation.

[tex]D=\sqrt{(5-(-3))^2+(1-9)^2}[/tex]

[tex]D=\sqrt{(8)^2+(-8)^2}[/tex]

[tex]D=\sqrt{64+64}[/tex]

[tex]D=\sqrt{128}[/tex]

[tex]D=11.3[/tex]

The distance between the points is 11.3.

What is (-i)5?
A -1
B 1
C -I
D i

Answers

Answer:

-i^5=-i

Step-by-step explanation:

rewrite the equation ;

i^4=1

I^4 *-i = 1*-i=-i

Out of all the red heads how many are boys give answer as a fraction

Answers

Answer:

3 boys may be answer of this question

Answer:

19/44

Step-by-step explanation:

19 boys

25 girls

19+25=44 (red hair)

19/44

What is the product of Three-fourths and Negative StartFraction 6 over 7 EndFraction?
Negative StartFraction 7 over 8 EndFraction
Negative StartFraction 9 over 14 EndFraction
StartFraction 9 over 14 EndFraction

Answers

Answer:

[tex]-\frac{9}{14}[/tex]

Step-by-step explanation:

[tex]\frac{3}{4}*-\frac{6}{7}\\\\\frac{3}{2} *\frac{3}{7} \leftarrow \text{Cross Cancel Common Factor}\\\\ -\frac{3*3}{2*7}\\\\-\frac{9}{14}[/tex]

Answer:

negative 9/14

Step-by-step explanation:

what is the range of the function?

Answers

Answer:

Range { 2,4,9,16}

Step-by-step explanation:

The range of the function is the output of the system

Range { 2,4,9,16}

Answer:

Step-by-step explanation:

Range is ll the y-points the outputs {2,4,9,16}

Triangles D E F and P Q R are shown. Given that StartFraction D F Over P R EndFraction = StartFraction F E Over R Q EndFraction = three-halves, what additional information is needed to prove △DEF ~ △PQR using the SSS similarity theorem? DE ≅ PQ ∠D ≅ ∠P StartFraction D E Over E F EndFraction = three-halves StartFraction D E Over P Q EndFraction = three-halves

Answers

Answer:

The correct option is;

DE/PQ = 3/2 which is StartFraction DE Over PQ Endfraction = three-halves

Step-by-step explanation:

The information given bout the triangles are;

DF/PR = FE/RQ = 3/2

Therefore since the given sides of triangle DEF are 3/2 times the sides of triangle PQR, the given sides of triangle DEF have been scaled 3/2 times to get the given sides of triangle PQR

Therefore, to prove that ΔDEF ~ ΔPQR, the ratio of the third side of triangle DEF, that is DE, to the third side of triangle PQR, which is PQ must be three-halves.

Answer:

The answer is  DE/PQ = 3/2 or D.

Step-by-step explanation:

Just did it on edge. hope you do good :)

Cecilia made an envelope to mail a letter. She colored the regular trapezoid flap on the bottom of the envelope blue, as shown. What is the area of the blue flap of the envelope? 14 Inches squared 18 Inches squared 45 Inches squared 90 Inches squared

Answers

Answer:

The correct option is:

14 inches

Step-by-step explanation:

The question is incomplete because the picture of the flap is not shown in the question nor the measurements are given. First lets complete the question. The figure was this question is attached below.

We can see that the bottom width of the trapezoid is 9 inches, the top width of the trapezoid is 5 inches, and it has a height of 2 inches.

The area of trapezoid is given as:

Area = ((Top width + Bottom width)/2) · h

Area = ((9+5)/2) · 2

Area = (14/2) · 2

Area = 7 · 2

Area = 14 inch²

Answer:

14

Step-by-step explanation:

Complete the equation of the line through (-6,-5) (−4,−4) PLZ HELP !!!

Answers

Answer: y=1/2x−2

Step-by-step explanation:

please answer these 2 question correctly and get marked brainliest

Answers

Answer:

See below.

Step-by-step explanation:

46.

Theorem:

The measure of an exterior angle of a triangle equals the sum of the measures of the remote interior angles.

The 100-deg angle is an exterior angle whose remote interior angles are angles E and F.

m<E + m<F = 110

5x + 6x = 110

11x = 110

x = 10

m<E = m<FEG = 5x = 5 * 10 deg = 50 deg

Answer: C. 50 deg

47.

A is not true since we know that 5x + 6x must equal 110, not 70.

Answer:

<FEG=50

A. is wrong

Step-by-step explanation:

For the first question, we know <F &<E are remote interior angles which add up to 110 (exterior angle)

so:

[tex]5x+6x+110\\11x=110\\x=10[/tex]

so:

[tex]5x= 5(10)\\FEG=50[/tex]

Now using what we know, we can determine that A. is wrong since 5x+6x is 110° not 70°

Hope this helps!

A shoe store marks up the wholesale cost of all shoes they sell by 20%. Calvin wants to buy a pair of shoes that has a price tag of $145. What was the wholesale cost of the shoes?

Answers

The sell price is the wholesale price plus 20%

Divide the sell price by 1.2 ( 100% + 20%)

145 / 1.2 = 120.83

The wholesale price is $120.83

Answer:

The wholesale price is $120.83

Which of the following is a solution of the system

x - 2y < 4 and y > – 2x – 5?

1. (1, - 4)
2. (-8,2)
3. (0,0)
4. (-3,0)

Answers

Answer:

Answer B

Step-by-step explanation:

1.  (1, -4) is NOT a solution because (1) - 2(-4) < 4 is false.

2.  (-8, 2):  -8 - 2(2) < 4 is true, and in simplified form is -12 < 4 (true)  We must check whether this point (-8, 2) ALSO satisfies y > -2x - 5:

2 > -2(-8) - 5.  Yes, this is true, so the given point satisfies both inequalities in Answer B.

There are only red,blue and green counters in a bag. There are 6 red counters,4 blue counters and 8 green counters. Matt takes a counter from the bag at random a) What is the probability that the counter is red.Give your answer in a fraction. b) What is the probability that the counter is not blue.Give the answer as a fraction. pls help.

Answers

Answer:

a) 1/3

b) 7/9

Step-by-step explanation:

The first part asks for the probability that Matt takes the red counter.

There are 6 red counters out of total 6+4+8 = 18 counters.

6/18

Simplify the fraction.

= 1/3

The second part asks for the probability that the counter is not blue.

The counters that are blue are 4. Not blue becomes 18-4 = 14. 14 red or green counters out of total 18.

14/18

= 7/9

Answer:

Total outcome =  6 + 4 + 8 = 18

a) Probablity that the counter is red = 6/18 = 1/3

b) Probablity that the counter is blue = 14/18 = 7/9

there is two images guys so don get confused PLZ HALP

Answers

Answer:

C) 105

Step-by-step explanation:

The box plot suggests that about 50% of hight schools in orange county have more than 105 band members.

This can be inferred from the boxplotvprovided in the attachment. 50% refers to the median of the distribution which is denoted by the vertical line dividing the box into two. Tracing the vertical line to the horizontal label marked from 70 to 150, the vertical line falls on the 105 mark. Hence the value of the median or 50th percentile

Which is a valid prediction about the continuous function
f(x)?
f(x) < 0 over the interval (-00, 0).
f(x) > 0 over the interval (-1,00).
f(x) > 0 over the interval [-1, 1].
f(x) < 0 over the interval (0, 2).
pls hurry

Answers

Answer:

Option C.

Step-by-step explanation:

Note: In option C interval should be (-1,1) instead of [-1,1].

From the given table it is clear that the value of f(x) is 0 at x=-1 and x=1.

The value of f(x) is negative over the interval [tex](\infty,-1)\text{ and }(1,\infty)[/tex]. So,

[tex]f(x)<0[/tex] over the interval [tex](\infty,-1)\text{ and }(1,\infty)[/tex]

The value of f(x) is positive over the interval [tex](-1,1)[/tex]. So,

[tex]f(x)>0[/tex] over the interval [tex](-1,1)[/tex]

Therefore, the correct option is C.

help me please(2 + 3 • 2 + 3²) - 4²

Answers

Answer:

1

solution,

[tex](2 + 3 \times 2 + {3}^{2} ) - {4}^{2} \\ = (2 + 6 + 9) - 16 \\ = 17 - 16 \\ = 1[/tex]

Hope this helps...

Good luck on your assignment...

Answer:

1

Step-by-step explanation:

Multiply  

3  by  2 . 2 + 6 + 3 2 − 4 2 Raise  3  to the power of  2 . 2 + 6 + 9 − 4 2 Raise  4 to the power of  2 . 2 + 6 + 9 − 1 ⋅ 16 Multiply  − 1  by  16 . 2 + 6 + 9 − 16

Simplify by adding and subtracting.

Add  2  and  6 . 8 + 9 − 16 Add  8  and  9 . 17 − 16  Subtract  16  from  17 .

1

A portion of the Quadratic Formula proof is shown. Fill in the missing reason. Statements Reasons ax2 + bx + c = 0 Given ax2 + bx = −c Subtract c from both sides of the equation x squared plus b over a times x equals negative c over a Divide both sides of the equation by a x squared plus b over a times x plus the quantity b over 2 times a squared equals negative c over a plus the quantity b over 2 times a squared Complete the square and add the quantity b over 2 times a squared to both sides x squared plus b over a times x plus the quantity b over 2 times a squared equals negative c over a plus b squared over 4 times a squared Square the quantity b over 2 times a on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a end quantity squared equals negative 4 times a times c over 4 times a squared plus b squared over 4 times a squared Find a common denominator on the right side of the equation x squared plus b over a times x plus the quantity b over 2 times a squared equals b squared minus 4 times a times c all over 4 times a squared Add the fractions together on the right side of the equation quantity x plus b over 2 times a end quantity squared equals b squared minus 4 times a times c all over 4 times a squared ? Rewrite the perfect square trinomial as a binomial squared on the left side of the equation Take the square root of both sides of the equation Multiply both sides of the equation by 2 Square the left side of the equation

Answers

Answer:

Find a common denominator on the right side of the equation

Step-by-step explanation:

I was taking the test and couldn't find the answer to this question anywhere so let me help you out...  

abidemiokin provided a wonderful step-by-step explanation for solving the formula, but left out the actual answer for the question which is what I'm here for. I read through abidemiokin's explanation and reviewed my options before choosing the best answer. As you see in step 5 of my edited version of abidemiokin's explanation the missing step is there. In the provided question we see steps 1,2, 3, and 4 being identical to those in the explanation below. From this, it is clear the next step (step 5) would be the next step, and as it is one of the options we can trust that it is correct.

(If you still have doubts then trust the fact that I took the test and the answer I provided above was indeed correct.)

Given the quadratic equation ax²+bx+c = 0, to derive the quadratic formula from the equation, the following steps must be followed;

ax²+bx+c = 0

Step 1: Subtract c from both sides

ax²+bx+c-c = 0-c

ax²+bx = -c

Step 2: Divide both sides of the equation by a

ax²/a + bx/a = -c/a

x² + bx/a = -c/a

Step 3: Complete the square and add the quantity (b/2a)² times a squared to both sides

x² + bx/a +  (b/2a)² = -c/a +  (b/2a)²

Step 4: Square the quantity  b/2a on the right side of the equation

x² + bx/a +  (b/2a)² =  -c/a +  b²/4a²

Step 5: Find a common denominator on the right side of the equation which is 4a²

x² + bx/a +  (b/2a)² =  -4ac/4a² +  b²/4a²

Step 6: Add the fractions together on the right side of the equation

x² + bx/a +  (b/2a)² =  (-4ac+  b²)/4a²

Note: The fraction at the right-hand side of the equation is to be added together not multiplied as shown in the question.

Step 7: The equation on the left is to be written as a perfect square as shown

(x+b/2a)² =  (-4ac+  b²)/4a²

Step 8: Take the square root of both sides

√(x+b/2a)² = √ (-4ac+  b²)/4a²

(x+b/2a) =  √(-4ac+  b²)/2a

Step 9: subtract b/2a from both sides

x+b/2a - b/2a =  -b/2a + √(-4ac+  b²)/2a

x =  -b/2a + √(-4ac+  b²)/2a

Step 10: Add the fractions together on the right-hand side

x =  -b±√(-4ac+  b²)/2a

This gives the required equation

Answer: A  Find a common denominator on the right side of the equation

Step-by-step explanation: Took the test of FLVS


Help me please I wold appreciated it

Answers

Answer:

BD=7

ED=5

BE=7

AD=10

AE=5

Step-by-step explanation:

given CD = 7 you use that to find BD and BE because CD´s line length is the same as BD and BE

given BC = 5 you use that to find ED and AE and AD because BC is the same length as ED (they create the same triangle) and than given AE also equals 5 you add ED and AE to get AD

hope this helps

'15 points in total for brainliest and correct answer, please answer ASAP'
What is the area of the shaded portion if the area of the circle is 56 sq cm?

Answers

Answer:

14cm² is the area of the shaded region

Step-by-step explanation:

recognize that those two small triangles plus that arc area is equal to 1/4 of the area of the circle.

56 / 4 = 14cm

Rahim is constructing a proof to show that the opposite angles of a quadrilateral inscribed in a circle are supplementary. Which step would be the third step in his proof, given the following information?

Answers

Answer:

B

Step-by-step explanation:

The option (A) (1/2)mQRS = ∠T is correct because the measure of an inscribed angle is one-half the measure of its intercepted arc.

What is a circle?

It is described as a set of points, where each point is at the same distance from a fixed point (called the centre of a circle)

We have:

Rahim is constructing a proof to show that the opposite angles of a quadrilateral inscribed in a circle are supplementary.

From the central angle theorem:

(1/2)mQRS = ∠T because the measure of an inscribed angle is one-half the measure of its intercepted arc.

Thus, the option (A) (1/2)mQRS = ∠T is correct because the measure of an inscribed angle is one-half the measure of its intercepted arc.

Learn more about circle here:

brainly.com/question/11833983

#SPJ2

A jumbo chocolate bar with a rectangular shape measures 13 centimeters in length, 7 centimeters in width, and 2 centimeters in thickness. Due to escalating costs of cocoa, the management has decided to reduce the volume of the bar by 20 %. To accomplish this reduction, management decides that the new bar should have the same 2 centimeter thickness, but the length and width of each should be reduced by an equal number of centimeters. What should be the dimensions of the new candy bar?

Answers

Answer:

Reduce every dimension except thickness by 20%.

The requried new dimensions of the candy bar are approximately 3.4775 cm in length, 2 cm in width (maintained), and 2 cm in thickness.

To find the dimensions of the new candy bar after reducing the volume by 20%, we need to determine the reduction in length and width.

Let's start by calculating the original volume of the candy bar using the formula: volume = length × width × thickness.

Original volume = 13 cm × 7 cm × 2 cm = 182 cm³

Since the management wants to reduce the volume by 20%, we need to find 20% of the original volume and subtract it from the original volume.

20% of 182 cm³ = 0.2 × 182 cm³ = 36.4 cm³

Reduced volume = 182 cm³ - 36.4 cm³ = 145.6 cm³

Now, we need to determine the new dimensions while maintaining the 2 cm thickness.

Let's assume the reduction in length and width is x cm for both dimensions.

The new volume can be calculated using the formula:
volume = (length - x) × (width - x) × thickness.

Setting this equal to the reduced volume, we have:

(13 - x) × (7 - x) × 2 = 145.6

Simplifying and rearranging the equation, we get:

(91 - 20x + x²) = 72.8

x² - 20x + 18.2 = 0

Using the quadratic formula, we can solve for x:

[tex]x = \dfrac{-(-20)\pm \sqrt{(-20)^2- 4(1)(18.2)}} {2(1)}\\x = \dfrac{20 \pm \sqrt{400 - 72.8}} {2}\\x =\dfrac {20 \pm \sqrt{327.2}} {2}[/tex]

x ≈ (20 ± 18.09) / 2

Taking the positive value, we have:

x ≈ (20 + 18.09) / 2

x ≈ 19.045 / 2

x ≈ 9.5225

Since the dimensions cannot be negative, we discard the negative value.

Therefore, the reduction in length and width is approximately 9.5225 cm.

To find the new dimensions, we subtract this value from the original length and width:

New length = 13 cm - 9.5225 cm ≈ 3.4775 cm

New width = 7 cm - 9.5225 cm ≈ -2.5225 cm (discard as it is negative)

Therefore, the new dimensions of the candy bar are approximately 3.4775 cm in length, 2 cm in width (maintained), and 2 cm in thickness.

Learn more about dimensions here:

https://brainly.com/question/31154493

#SPJ4

Answer the question now fast

Answers

Answer:

second and third choice

Step-by-step explanation:

supplamentary = add up to be 180

)Bentley had $40 in birthday money in her piggy bank. She spent $10 on new flip-flops, then got $20 for her allowance and did not spend any of that money for 1 week. Finally, she spent $15 on new sunglasses. Which part of the scenario is best represented by a linear increasing interval? Bentley has $40 in her piggy bank. Bentley spent $10 on new flip flops. Bentley got $20 for her allowance. Bentley spent $15 on sunglasses.

Answers

Answer:

Bentley got $20 for her allowance.

Step-by-step explanation:

Ordered pair for this point? (The point is circled in Blue)

Answers

Answer:

( -3, 1)

........

Answer:

(-3, 1)

Step-by-step explanation:

The point lies on the line x = -3.

The point lies on the line y = 1.

Where both lines intersect, that is the coordinate.

(x, y)

(-3, 1)

PLZ HELP!! HURRY!!!30POINTS!!

Answers

Answer & Step-by-step explanation:

6. At a bus interchange, a number of passengers boarded a bus. At the first
bus stop, of the passengers alighted the bus and 6 people boarded the
bus. At the 2nd bus stop, of the passengers alighted and 10 passengers
boarded the bus. There were 24 passengers on the bus when it left the
2nd bus stop. How many passengers boarded the bus at the interchange?​

Answers

Answer:

The answer is given below

Step-by-step explanation:

Let the number of passengers that boarded the bus at the interchange be x.

At the first  bus stop, 1/4 of the passengers alighted the bus and 6 people boarded the  bus.

Therefore The number of passengers when the bus left the first bus stop = [tex]x-\frac{1}{4}x +6=\frac{3}{4}x+6[/tex]

At the 2nd bus stop, 8/15 of the passengers alighted and 10 passengers  boarded the bus.

Therefore The number of passengers when the bus left the second bus stop

[tex]=\frac{3}{4}x+6-\frac{8}{15}( \frac{3}{4}x+6)+10=\frac{3}{4}x+6-\frac{8}{20}x-3.2+10\\\\=\frac{7}{20}x+12.8[/tex]

Given that there were 24 passengers on the bus when it left the  2nd bus stop

[tex]\frac{7}{20}x+12.8=24\\7x+256=480\\7x=480-256\\7x=224\\x=32[/tex]

Therefore 32 passengers boarded the bus at the interchange

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