Jada is evaluating 8 × 3 × 4. She doesn't know the product of 24 and 4 off the top of her head, so she decides to multiply 3 by 4 first. Which property is Jada using? PLEASE HELP!!

Answer:

B < -76

Step-by-step explanation:

You start out with writing out the equation

8-1/4b> 27

Then, you subtract 8 from each side, so the -1/4b can be by itself

-1/4b>27-8

-1/4b>19

After that, you want to get rid of that -1/4, so you multiply both sides by -4

This makes the > sign flip to <

So, this makes:

b < -76

Answer:

[tex]5x^5+5xyz+7xy+8x[/tex]

Step-by-step explanation:

When putting an equation in standard form, you always prioritize the term with the most variables - unless terms have a greater exponent.

The prioritization order is:

Exponents

Amount of variables

Value of coefficient

So, [tex]5x^5[/tex] is the only term with an exponent in this expression, so it will go first.

Next up, we have to choose between [tex]8x[/tex], [tex]5xyz[/tex], and [tex]7xy[/tex]. We know that [tex]5xyz[/tex] has more variables than the other ones, so it goes next.

Now we're left with [tex]7xy[/tex] and [tex]8x[/tex]. [tex]7xy[/tex] has more variables than [tex]8x[/tex], so it goes next.

This leaves [tex]8x[/tex] last.

So, the expression becomes [tex]5x^5+5xyz+7xy+8x[/tex].

Hope this helped!

Answer:

b=8

Step-by-step explanation:

Solution steps:

-7b=-56

b=-56 / -57

b=8

Answer:

[tex] \boxed{ \bold{ \huge{ \boxed{ \sf{ b = 8}}}}}[/tex]

Step-by-step explanation:

[tex] \sf{ - 7b = - 56}[/tex]

divide both sides of the equation by -7

[tex] \sf{ \dashrightarrow\frac{ - 7b}{ - 7} = \frac{ - 56}{ - 7} }[/tex]

Calculate

[tex] \dashrightarrow \sf{b = 8}[/tex]

Hope I helped!

Best regards! :D

Answer:

y= -1/2(x) +8

gradient= -1/2

Intercept= 8

Step-by-step explanation:

Let's transform the equation to y -intercept form first

6x - 3y - 15= 0

-3y= -6x+15

Y= -6/-3(x) +(15/-3)

Y= 2x -5

Intercept c= -5

Gradient m =2

Rule of perpendicularity

mm'= -1

m'= -1/m

m' = -1/2

Equation of line of the point (4, 6)

(Y-Y1)/(x-x1)=m'

(Y-6)/(x-4)= -1/2

2(y-6)= -1(x-4)

2y -12 = -x +4

2y= -x +4+12

2y= -x+16

y= -1/2(x) +8

gradient= -1/2

Intercept= 8

Answer:

158

Step-by-step explanation:

10.89-2.99 = 7.90

.5/7.90=158

Answer:

158 songs

Step-by-step explanation:

Monthly membership = 2.99

Each song cost = .05

Total Amount spent after 1 month = 10.89

S = Songs purchased

=> 2.99 + .05S = 10.89

=> 2.99 - 2.99 + .05S = 10.89 - 2.99

=> .05S = 7.9

=> .05S / .05 = 7.9 / .05

=> S = 158

So, she purchased 158 songs that month.

Answer:

$1 for one tube

Step-by-step explanation:

Ratio is 10:10

if you keep on reducing it

you will eventually get to 1:1

Therefore, the answer is $1 for one tube

Answer:

(-1,4)

Step-by-step explanation:

Answer: x=4

Step-by-step explanation:

 -8-x=x-4x

  -8-x=-3x

-x+3x=8

    2x=8

      x=4

Answer:

D

Step-by-step explanation:

If the number is positive, the absolute value is the same as the number. If the number is negative, the absolute value is just a positive version of that number. So the absolute value of 0 is 0, -18 is 18, -31 is 31, and -44 is 44. Out if these, D has the greatest absolute value, so it would be D

Answer:

D. -44.

Step-by-step explanation:

Absolute value of -44:

= |-44| = 44

(2x+8)/6=1/3(x+4)

3(2x+8)=6(x+4)

6x+24=6x+24.

0=0.

∴There are no real solutions.

Answer:

Hope it helped u if yes mark me BRAINLIEST pzllzllzl

Answer:

4

Step-by-step explanation:

0</x/<5

0</1, 2, 3, 4/>5

(1,2,3,4) there are 4 numbers that are greater than 0 and less than 5.

Answer:

8

Step-by-step explanation:

All possible answers are 1,2,3,4,-1,-2,-3, and -4. Since we are using the absolute value here, the opposites of the positive values are also included.

Answer:

Your process is indeed correct!

The full solution is:

[tex]\displaystyle \int\frac{\sin ^3 x}{\sqrt{\cos x}}\, dx= \frac{2}{5} \cos^{{}^{5}\!/\!{}_{2}} x - 2\cos ^{{}^{1}\!/\!{}_{2}}x + C[/tex]

Step-by-step explanation:

We want to evaluate the integral:

[tex]\displaystyle \int \frac{\sin^3(x)}{\sqrt{\cos(x)}}\, dx[/tex]

As you had done, we can rewrite our integral as:

[tex]\displaystyle =\int \frac{\sin(x)(\sin^2(x))}{\sqrt{\cos(x)}}\, dx[/tex]

Using the Pythagorean Identity, this is:

[tex]\displaystyle =\int \frac{\sin(x)(1-\cos^2(x))}{\sqrt{\cos(x)}}\, dx[/tex]

Now, we can make a substitution. Let u = cos(x). Then:

[tex]\displaystyle du = - \sin x \, dx[/tex]

Substitute:

[tex]\displaystyle = \int\frac{1-u^2}{\sqrt{u}} \, \left(- du\right)[/tex]

Simplify:

[tex]\displaystyle = -\int \frac{1}{\sqrt{u}} - \frac{u^2}{\sqrt{u}}\, du[/tex]

Rewrite:

[tex]\displaystyle = -\int u^{{}^{-1}\!/\!{}_{2}} - u^{{}^{3}\!/\!{}_{2}}\, du[/tex]

By the Reverse Power Rule:

[tex]\displaystyle = -\left(2u^{{}^{1}\!/\!{}_{2}} - \frac{2}{5} u^{{}^{5}\!/\!{}_{2}}\right) + C[/tex]

Simplify:

[tex]\displaystyle = \frac{2}{5} u^{{}^{5}\!/\!{}_{2}}-2u^{{}^{1}\!/\!{}_{2}} + C[/tex]

Back-substitute:

[tex]\displaystyle = \frac{2}{5} \cos^{{}^{5}\!/\!{}_{2}} x - 2\cos ^{{}^{1}\!/\!{}_{2}}x + C[/tex]

Answer:

=  - 2 [tex]\sqrt{cos(x)}[/tex] + 2 cos⁵/₂ (x)  + C

                          5

Step-by-step explanation:

∫ sin³ (x)    dx

  [tex]\sqrt{cos(x)}[/tex]

= ∫ sin² (x) sin (x)    dx

   [tex]\sqrt{cos(x)}[/tex]

= ∫ (1 - cos² (x) sin (x)  dx

   [tex]\sqrt{cos(x)}[/tex]

= ∫ - 1 - u²   du

        √u

= ∫ -   1    +  u³/₂   du

        √u

= - ∫   1    du  +  ∫ u³/₂   du

        √u

substitute it back

=  - 2 √u + 2 cos⁵/₂ (x)

                 5

add constant, therefore

=  - 2 [tex]\sqrt{cos(x)}[/tex] + 2 cos⁵/₂ (x)  + C

                         5

Answer:

238,900 miles away

Answer:

238,900

Step-by-step explanation:

Light travels at a speed of 186,282 miles per second, you multiply this number by 1.25 you get your answer.

Answer:

a)

{FVVV,FFVV,VFVV,VVVV,FVFV,FFFV,VFFV,VVFV,FVVF,FFVF,VFVF,VVVF,FVFF,FFFF,VFFF,VVFF}

b)

{FFFV,FFVF,FVFF,VFFF}

c)

{FFFF,VVVV}

d)

{FFFV,FFVF,FVFF,FFFF,VFFF}

e)

{FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

{FFFF}

f)

{FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

{ }

Step-by-step explanation:

a)

The 16 outcomes for a sample of four home mortgages classified as fixed and variable rate are

Sr.No Outcomes

1          FVVV

2         FFVV

3         VFVV

4         VVVV

5         FVFV

6         FFFV

7         VFFV

8         VVFV

9         FVVF

10        FFVF

11         VFVF

12        VVVF

13        FVFF

14        FFFF

15        VFFF

16        VVFF

b)

Let A be the event that exactly three are fixed rate. Thus, event A consists of following outcomes

A={FFFV,FFVF,FVFF,VFFF}

c)

Let B be the event that all four are of same type. The event B consists of either all fixed rate or all variable rate. Thus, event B consists of following outcomes

B={FFFF,VVVV}

d)

Let C be the event that at most one of four is variable rate. The event C consists of less than and equal to one variable rate. Thus, event C consists of following outcomes

C={FFFV,FFVF,FVFF,FFFF,VFFF}

e)

Let union of part(c) and part(d) can be represented as BUC. The union represents all the outcomes in event B and event C.

B∪C={FFFF,VVVV}∪{FFFV,FFVF,FVFF,FFFF,VFFF}

B∪C={FFFV,FFVF,FVFF,FFFF,VFFF,VVVV}

Let intersection of part(c) and part(d) can be represented as B∩C. The intersection represents the common outcomes in event B and event C.

B∩C={FFFF,VVVV}∩{FFFV,FFVF,FVFF,FFFF,VFFF}

B∩C={FFFF}

f)

Let union of part(b) and part(c) can be represented as AUB. The union represents all the outcomes in event A and event B.

A∪B={FFFV,FFVF,FVFF,VFFF}∪{FFFF,VVVV}

A∪B={FFFV,FFVF,FVFF,VFFF,FFFF,VVVV}

Let intersection of part(b) and part(c) can be represented as A∩B. The intersection represents the common outcomes in event A and event B.

A∩B={FFFV,FFVF,FVFF,VFFF}∩{FFFF,VVVV}

A∩B={ }

So intersection of part(b) and part(c) is an empty set as there is no common outcome in these two sets.

Sample of four homes.

The sample of 4 homes is on a mortgage and has been classified as a fixed rate of F and a variable rate of V. The mortgage is thus an agreement between the lender of the money and the borrower. The lender has the right to take away the property.

Thus answer is given below.

Learn more about the sample of four homes.

brainly.com/question/14565659.

Answer:

  33, 11, 24 feet

Step-by-step explanation:

Let s represent the length of the second side. Then the length of the first side is 3s and the length of the third side is s+13. The perimeter is the sum of side lengths:

  (3s) +(s) +(s +13) = 68

  5s = 55 . . . . . subtract 13

  s = 11 . . . . . . . divide by 5

The side lengths are ...

  33, 11, 24 feet

Answer:

Step-by-step explanation:

y + 5 = 1(x - 7)

y + 5 = x - 7

y = x - 12

Step-by-step explanation:

sin(2A)

Use double angle formula:

= 2 sin(A) cos(A)

Use Pythagorean identity.  0 ≤ A ≤ π/2, so cos(A) > 0.

= 2 sin(A) √(1 − sin²(A))

Substitute and simplify.

= 2 (¼) √(1 − (¼)²)

= ½ √(¹⁵/₁₆)

= ⅛ √15

Answer:

34

Step-by-step explanation:

The dead bodies are still in the room.

===================================================

Explanation:

He has 90 feet of fencing overall. This is the perimeter of the rectangle as its the distance around all four sides.

Two of the opposite sides are the width = 15 ft. So we have 15+15 = 30 feet taken up and 90-30 = 60 feet left for the other two opposite sides to add to. Call each of those sides x

x+x = 60

2x = 60

x = 60/2

x = 30

The other side must be 30 feet long.

This rectangle is 30 by 15

perimeter = 30+15+30+15 = 45 + 45 = 90

which helps confirm we have the right answer

---------------

Or you can solve this way

P = 2*(L+W) is the perimeter of a rectangle with length L and width W

Plug in the perimeter P = 90 and the width W = 15. Solve for L

P = 2*(L+W)

90 = 2*(L+15)

2(L+15) = 90

L+15 = 90/2

L+15 = 45

L = 45-15

L = 30

Answer:

10 cm³

Step-by-step explanation:

According to Archimedes, if we place an object in water, the rise of the water in mL will be the volume of the object in cm³.

Without the rock, the water measures 20 mL.

With the rock, the water measures 30 mL.

The change here is [tex]30-20=10[/tex], so 10 cm³ is the volume of the rock.

Hope this helped!

Answer:

a. 17

b. 231

c. 1

d. 23

e. 9

Answer:

(a) How many are there to select 2 pairs of gloves?

10 ways

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

130 ways

Step-by-step explanation:

For the above questions we apply that combination formula

(a) How many are there to select 2 pairs of gloves?

There are 5 pairs of gloves according to the question above, hence:

5C2 = 5!/2! × (5 - 2)!

= 5!/2! × 3!

= 5 × 4 × 3 × 2 × 1/2 × 1 × 3 × 2 × 1

= 10 ways.

Therefore, there are 10 ways to select 2 pairs of gloves

(b) How many ways are there to select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.)

i) A way to select 4 gloves out of 10 gloves =

10C4 = 10!/4! ×(10 - 4)!

= 10!/ 4! × 6!

= 210 ways

ii) In order for 2 of the 4 gloves selected to be a pair, note that we have 5 pairs of gloves hence:

5 × 2⁴

= 80 ways.

Therefore, the number of ways which we can select 4 gloves out of the 10 such that 2 of the 4 make a pair. (a pair consists of any right glove and left glove.) = 210 ways - 80 ways

= 130 ways

Answer:

[tex]y = \frac{9x^2}{2} + c[/tex]

Step-by-step explanation:

Given

[tex]\int\limits^ _[/tex][tex](x + 8x) dx[/tex]

Required

(a) Integrate

(b) Check using differentiation

To integrate, we make use of the following formula;

if

[tex]\frac{dy}{dx} = \int\limits^{} _{} ax^n[/tex]

then

[tex]y = \frac{ax^{n+1}}{n+1}[/tex]

So; [tex]\int\limits^ _[/tex][tex](x + 8x) dx[/tex] becomes

[tex]y = \frac{x^{1+1}}{1+1} + \frac{8x^{1+1}}{1+1} + c[/tex]

[tex]y = \frac{x^{2}}{2} + \frac{8x^{2}}{2} + c[/tex]

[tex]y = \frac{x^{2}}{2} + 4x^2 + c[/tex]

Take LCM

[tex]y = \frac{x^{2} + 8x^2}{2} + c[/tex]

[tex]y = \frac{9x^2}{2} + c[/tex]

To check using differentiation, we make use of

if [tex]y = ax^n[/tex], then

[tex]\frac{dy}{dx} = nax^{n-1}[/tex]

Using this formula

[tex]y = \frac{9x^2}{2} + c[/tex] becomes

[tex]\frac{dy}{dx} = 2 * \frac{9x^{2-1}}{2}[/tex]

[tex]\frac{dy}{dx} = 2 * \frac{9x}{2}[/tex]

[tex]\frac{dy}{dx} =9x[/tex]

[tex]9x = x + 8x[/tex]

So;

[tex]\frac{dy}{dx} = x + 8x[/tex]

Answer:75

Step-by-step explanation:

90-15=75

Answer:

He has 75 tacos left.

90 - 15 = 75.

Answer:

Angle ABC is bisected by BD

BC =Half AC

2 mangle DBC =mangle ABC