It’s either C or D? Please help

9514 1404 393

Answer:

  10, (x+4), (x -1)

Step-by-step explanation:

The given volume expression can be factored as ...

  V = 10x² +30x -40

  = 10(x² +3x -4)

  = 10(x +4)(x -1)

The expressions representing length, width, and height might be ...

  10, (x+4), (x -1)

Answer:

A

Step-by-step explanation:

The pattern is blue red blue red

+

The pattern is vertical horizontal vertical horizontal

Answer:

A.

The second figure adds another red horizontal line to the first. The third adds a vertical blue line to the second. The fourth must add a red horizontal line to the third.

Answer:

$9

Step-by-step explanation:

The linear system is going to be:

16m + 13s + 29c = $419

26m + 19s + 45c = $649

6m + 11s + 0c = $96

I don't really know why it is bringing up the determinant, all you need to do is put this into reduced row echelon form.  I personally used a calculator for this, but it could be done painstakingly by hand.

RREF gives me:

m=5

s=6

c=9

So a chocolate milkshake is $9

Answer:

The signs will be + and -

Step-by-step explanation:

Required

The signs in the parenthesis of difference of two squares

Let the expression be:

[tex](x^2 - a^2)[/tex]

Expand

[tex]x^2 - a^2 = x^2 -ax + ax - a^2[/tex]

Factorize

[tex]x^2 - a^2 = x(x -a) + a(x - a)[/tex]

Factor out x - a

[tex]x^2 - a^2 = (x +a)(x - a)[/tex]

See that the sign in front of a is + and - in the parentheses

Answer:

I'm pretty sure it's either 3.1 or 4.1

Step-by-step explanation:

Answer:

x = (571 ± √186217) / 18

x ≈ 7.74840677368558702303.. or 55.69603767075885742140..

x ≈ 7.75 or 55.70

Step-by-step explanation:

y = -9x² + 571x – 3884.

x = (-b ± √b² – 4ac) / 2a

x =

(-(571) ± √((571)² – 4((-9) × (-3884))) / 2(-9)) →

(-571 ± √(326041 – 4(34956))) / -18) →

(-571 ± √(326041 – 139824)) / -18) →

(-571 ± √(186217)) / -18 →

(571 ± √186217) / 18 →

Answer:

hope it helps

Answer:

Step-by-step explanation:

1. replace variables with the integers they represent.  2-5(3)

2. multiply 5 * 3 = 15

3. Subtract  2-15

Answer - 13

For the given condition the age of the son will be 69 years.

A mathematical equation asserts the equality of two expressions, which may or may not contain variables or integers. Equations are fundamental concerns, and efforts to rationally address them have served as the primary driving forces behind the creation of mathematics.

Suppose the two-digit number is x,

The father's and son's ages are 10x+y and 10y+x respectively.According to the given condition,

(10x+y) -(10y+x)=27

9x-9y=27

x-y=27/9

x-y=3

The value of x and y will be 4 and 1.

At x=9 and y=6, the age of the son is obtained as,

=10×6+9

=69 years

Thus, the age of the son will be 69 years.

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Answer:

d.

Step-by-step explanation:

tan Ф = opp. / adj. = 15/8

hyp = √(8²+15²) = √289 = 17

sin Ф = opp./ hyp = 15/ 17

Answer:

[tex]36\:\mathrm{in^3}[/tex]

Step-by-step explanation:

The area of a prism is given by the product of the base and the height. In this triangular prism, the area of the either base is:

[tex]A=\frac{1}{2}\cdot 3\cdot 4=6\:\mathrm{in^2}[/tex]

The height is marked as [tex]6[/tex] inches. Thus, the volume of the prism is:

[tex]\frac{1}{2}\cdot 3\cdot 4\cdot 6=\boxed{36\:\mathrm{in^3}}[/tex]

Answer:

The null hypothesis will be rejected

Step-by-step explanation:

The null hypothesis is that people who favour ban on stem cell research is less than or equal to 0.61

The alternate hypothesis is that people who favour ban on stem cell research is greater than 0.61

Proportion of population = 0.61

Total events = 360

Sample size = 554

Sample proportion = 360/554 = 0.649

As per test statistics –  

Z = (p-p0)/sqrt {(p0 (1-p0))/n} = (0.649 -0.61)/ {(0.61 (1-0.61))/554}

= 0.039/0.021

= 1.857

P (Z<1.857) = 1- P (Z<1.857) = 1-0.9664 = 0.0336

So alpha value is 0.064.  

Thus, we will reject the null hypothesis  

Answer:

8ft

Step-by-step explanation:

Radius is the half of the diameter, which is 16ft in this circle. So half the diameter will be 16÷2 which is 8ft.

MARK ME BRAINLIEST :)))

[tex]\huge{\textbf{\textsf{{\color{navy}{An}}{\purple{sw}}{\pink{er}} {\color{pink}{:}}}}}[/tex]

Because,

r = 1 d

ㅤ 2

r = 1 × 16

ㅤ 2

r = 8 ft.

The surface area of the given composite figure will be 384 square cm.

The space occupied by any two-dimensional figure in a plane is called the area. The area of the outer surface of any body is called the surface area.

In the given image we have a composite figure one is a rectangular cuboid and the other is a triangular prism. The surface area will be equal to the sum of all the outer sides of the figure.

The surface area of the triangular shape will be calculated as:-

SA = 2( Area of triangle ) + Area of rectangular surfaces

SA = 2 ( (1/2) B x H )  + (5 x 6 ) + ( 6 x 3  )

SA = ( 3 x 4 ) + (  30 ) + ( 18 )

SA = 12 + 30 + 18

SA = 60 square cm

The surface area of the rectangular cuboid will be calculated as:-

SA = ( 4 x 6 ) + 2 ( 158 x 4 ) + 2 ( 15 X 6 )

SA = 24 + 120 + 180

SA  = 324 square cm

Total surface area will be = 324 + 60 = 384 square cm.

Therefore the surface area of the given composite figure will be 384 square cm.

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Answer:

53.8%

Step-by-step explanation:

Answer:

u already got ur awnser so hi

Step-by-step explanation:

ui

Answer: C D E

Step-by-step explanation:

Answer:

[tex]C.[/tex] 5/7 × 2/3

Step-by-step explanation:

Answer:

[tex]Area = 90.03cm^2[/tex]

Step-by-step explanation:

Given

[tex]s_1 = 14.9[/tex]

[tex]s_2 = 14.7[/tex]

[tex]\theta = 124[/tex] --- angle in between

Required

The area of the plate

Since [tex]\theta = 124[/tex] is between [tex]s_1[/tex] and [tex]s_2[/tex]

The area is:

[tex]Area = \frac{1}{2} * s_1 * s_2 * \sin(\theta)[/tex]

[tex]Area = \frac{1}{2} * 14.9 * 14.7 * \sin(124.7)[/tex]

[tex]Area = \frac{1}{2} * 14.9 * 14.7 * 0.8221[/tex]

[tex]Area = 90.03cm^2[/tex]

Answer: 4

Step-by-step explanation: 16/4 =4 brainlyest plz plz I need it for my rank

Answer:

d.

Step-by-step explanation:

The gradient is -5 meaning that it's going downwards as x increases

The y-intercept is 3

Feel free to mark as brainliest :D

Answer:

1) [tex]2^{\frac{5}{3} }[/tex] = [tex]2^{\frac{5}{3} (3) }[/tex] = [tex]2^{5}[/tex]

2) [tex]2^{\frac{5}{3} }[/tex] = [tex]\sqrt[3]{2^{5} }[/tex] = [tex]\sqrt[3]{32 }[/tex]

3) [tex]2^{\frac{5}{3} }[/tex] = 3.17...

1^2 = 1

2^2 = 4

[tex]2^{\frac{5}{3} }[/tex]  is between 1 and 2 to the power of 2

Answer:

Step-by-step explanation:

Answer:

D. 4 root 113

Step-by-step explanation:

we have to use Pythagorean Theorem which is

a^2 + b^2 = c^2

where a and b are legs of the triangle that are 45° apart and c is the hypotenuse.

now we just plug in our values.

a^2 + (9)^2 = (47)^2

a^2 + 81 = 2209

now we're gonna solve for A (the missing side)

a^2 = 2128

now we square root both sides to undo the square on A

root(a^2) = root(2128)

because 2128 isn't a pretty root, we have to simplify it

a = 4 root(133)

Answer:

(-[tex]\frac{\sqrt{3}}{2}[/tex],-[tex]\frac{1}{2}[/tex])

Step-by-step explanation:

The corresponding point on the unit circle is ( -√3/2 , -1/2).

A unit circle is just a circle that has a radius of 1 unit. A unit circle can be used to define right triangle relationships known as sine, cosine and tangent. These relationships describe how angles and sides of a right triangle relate to one another.

For the given situation,

The radian measure is θ = 7pi/6

In unit circle, the radian θ = [tex]\frac{7\pi }{6}[/tex] lies in the third quadrant and it's equal degree measure is [tex]210[/tex]°.

The corresponding point for this radian measure is

( [tex]\frac{-\sqrt{3} }{2} ,\frac{-1}{2}[/tex] )

Hence we can conclude that the corresponding point on the unit circle is ( -√3/2 , -1/2).

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Answer:

look at the picture i have sent

Answer:

B

Step-by-step explanation:

Answer:

D. 0

Step-by-step explanation:

I calculated logically

Answer:

Solution given:

radius of small circle[r]=16-4.5ft=11.5ft

radius of large circle[R]=16ft

nowcircumference of small circle=2πr=2*3.14*11.5=72.22ft

circumference of large circle=2πR=2*3.14*16=100.48ft

distance that the outside tires must travel to the distance the inside tires must travel in order to make a complete circle

=[tex]\frac{100.48}{72.22}=\frac{32}{23}[/tex]

ratio is 32:23.

The value of x to satisfy the given case is 2.

The mid point theorem states that in a triangle the line segment joining the mid point of two sides is always parallel and equal to half of the length of the third side.

As per the given figure the data is as follows,

The line segment of length 6x + 7 is parallel to the side of a triangle of length 19x - 28 such that it divides other two sides equally.

Apply mid point theorem to obtain,

6x + 7 = 1/2(19x - 28)

=> 19x/2 - 6x = 14 - 7

=> 7x/2 = 7

=> x = 2

Hence, the value of x for the given triangle is 2.

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The median of cumulative frequency is 67.86 and the interquartile range is 32.86.

The mean is "the middle number is sorter, ascending or descending, list of numbers and can be more descriptive of that data set than the average".

The interquartile range is "measure of where the 'middle fifty' is in data set".

According to the question,

Score               Mid value    Frequency       Cumulative frequency

10 ≤ x < 20            15                       1                                 1

20≤x < 30             25                      3                                 4

30≤x < 40             35                      6                                 10

40≤x < 50            45                       15                               25

50≤x < 60            55                       14                               39

60≤x < 70            65                        28                             67

70≤x < 80            75                         18                              85

80≤x < 90            85                         11                               96

90≤x < 100           95                         4                               100

Uniform interval is 10.

a) The median of examination mark

Frequency = 1+3+6+15+14+28+18+11+4 = 100

Median = [tex]l+\frac{(\frac{N}{2} - m )}{f}[/tex] × c       where l = lower limit of the median class, N = total frequency, m = cumulative frequency of the pre median class,

f = frequency of the median class, c = uniform class interval.  

            = 50 + [tex]\frac{\frac{100}{2} - 25 }{14}[/tex]  × 10

            = 50 + [tex]\frac{50 - 25}{14}[/tex]  × 10

            = 50 +[tex]\frac{25}{14}[/tex] × 10

           = 50 + 1.786 × 10

           = 50 + 17.86  

           = 67.86.

Thus, the median of examination mark is 67.86.

b) The number of students score less than 65 marks.

In order to find the number of students score less than 65 marks sum of all frequency below 65.

= 1 + 3 + 6 + 15 + 14

= 39

Thus, the number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks

In order to find the number of students scored between 50 and 80 marks only if add frequency between 50 and 80 marks.

= 14 + 28 + 18 + 11

= 71

Thus, the number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50.

In order to find the number of students failed, given that the pass mark is 50 only if add frequency below 50.

= 1 + 3 + 6 + 15

= 25.

Thus,  the number of students failed, given that the pass mark is 50 is 25.

f) The interquartile range

Interquartile range =  Q₃ - Q₁    [In words, difference between upper quartile range and lower quartile range]

Q₁ =  l₁ + [tex]\frac{\frac{N}{4} - m }{f}[/tex] × c  where l₁ is the lower limit of the Q₁ class, m₁ is the cumulative frequency of the pre median class, f₁ is the Frequency of the Q₁ class, c is the class interval, N  is the total frequency.

[tex]\frac{N}{4}[/tex] = [tex]\frac{100}{4} = 25[/tex]; [tex]\frac{3N}{4}[/tex] = 75

     = 40 + [tex]\frac{25 - 25}{6}[/tex] * 10 = 40

Q₁ = 40

Q₃ = l₃ + [tex]\frac{3\frac{N}{4} - m3 }{f3}[/tex]  × c

   = 60 + [tex]\frac{75 - 39}{28}[/tex] × 10

   = 60 + [tex]\frac{36}{28}[/tex] × 10

   = 60 + 1.2857 × 10

   =   60 + 12.857

   = 72.857

Interquartile range = upper quartile range - lower quartile range

                                 = 72.857 - 40

                                 = 32.8571  ≈ 32.86.

Thus, interquartile range is 32.86.

Hence, a) The median of examination mark is 67.86.

b) The number of students score less than 65 marks is 39.

c) The number of students scored between 50 and 80 marks is 71.

d) The number of students failed, given that the pass mark is 50 below 50 is 25.

f)  The interquartile range is 32.86.

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Answer:

I believe it'll be A and E.

hope this helps!

Answer:

D and E

Step-by-step explanation:

Using the rules of exponents

[tex]\frac{a^{m} }{a^{n} }[/tex] = [tex]a^{(m-n)}[/tex] , [tex]a^{0}[/tex] = 1

Then

[tex]\frac{3^{9} }{3^{9} }[/tex]

= [tex]3^{(9-9)}[/tex]

= [tex]3^{0}[/tex]  → E

= 1 → D