It would take Jack $4$ hours to mow the lawn if he works alone. Fortunately, after he mows for $2$ hours, Jill joins him. They finish mowing $90$ minutes later. How many minutes would it have taken for Jill to mow the entire lawn alone?

Answer:

See below for proof.

Step-by-step explanation:

[tex]\large\boxed{\begin{minipage}{4 cm}\underline{Exponent Rules}\\\\$\sqrt[n]{a}=a^{\frac{1}{n}}$\\\\$(a^b)^c=a^{bc}$\\\end{minipage}}[/tex]

Given functions:

[tex]\begin{cases}f(x) = x^3 + 7\\g(x) = \sqrt[3]{x-7}\end{cases}[/tex]

The composite function f[g(x)] means to substitute the function g(x) in place of the x in function f(x):

[tex]\begin{aligned}f[g(x)]&=[g(x)]^3+7\\&=(\sqrt[3]{x-7})^3+7\\&=((x-7)^\frac{1}{3})^3+7\\&=(x-7)^\frac{3}{3}+7\\&=(x-7)^1+7\\&=x-7+7\\&=x\end{aligned}[/tex]

The composite function g[f(x)] means to substitute the function f(x) in place of the x in function g(x):

[tex]\begin{aligned}g[f(x)]&=\sqrt[3]{f(x)-7}\\&=\sqrt[3]{(x^3+7)-7}\\&=\sqrt[3]{x^3+7-7}\\&=\sqrt[3]{x^3}\\&=(x^3)^{\frac{1}{3}\\&=x^{\frac{3}{3}\\&=x^1\\&=x\end{aligned}[/tex]

Hence proving that the functions are inverses by showing that f(g(x))= x and g(f(x)) = x.

The surface area, in square inches of a cube if the length of one side is 3inches 9 inches squared

A square is a four sided polygon whose all sides are equal.  , A ,  square is a regular quadrilateral, which means that it has four equal sides and four equal angles (90-degree angles is a regular quadrilateral, which means that it has four equal sides and four equal angles (90-degree angles

The area of a squire is given as

Area = s²

Area = 3² = 9 inches ²

In conclusion the square has an area of 9 inches squared

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In the given expression, t-2 (t+5) is incorrect. The correct expression is (t-2)(t+5) = t² + 3t - 10. The error in the original expression is that it is not using the distributive property. The correct way to find the product is by using either distributive property or FOIL method.

The expression (t-2)(t+5) is the product of two binomials. To find the product, we use the distributive property and the FOIL method. The distributive property states that for any two binomials (a+b)(c+d) = ac + ad + bc + bd.

The FOIL method stands for "first, outer, inner, last", and is a mnemonic for the distributive property. To use the FOIL method, we take the first term from the first binomial, the second term from the second binomial, the second term from the first binomial, and the last term from the second binomial.

In your original expression, the error is that there is no operator between the two binomials (t-2) and (t+5), which makes it unclear whether you are trying to multiply them or not. To correct this, you need to add the multiplication operator () between the two binomials, so it becomes (t-2)(t+5).

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Hey there!

Is there any more info you could provide us regarding the question? It seems like there is some missing info to make this question complete.

Answer:

[tex]\textsf{h)} \quad x=6[/tex]

[tex]\textsf{i)} \quad n = 2\ln 2+\dfrac{5}{2}[/tex]

[tex]\textsf{j)} \quad x=\dfrac{5}{4}[/tex]

Step-by-step explanation:

Given equation:

[tex]20\left(\dfrac{1}{2}\right)^{\frac{x}{3}} = 5[/tex]

Divide both sides by 20:

[tex]\implies\left(\dfrac{1}{2}\right)^{\frac{x}{3}} = \dfrac{20}{5}[/tex]

[tex]\implies\left(\dfrac{1}{2}\right)^{\frac{x}{3}} =\dfrac{1}{4}[/tex]

Rewrite 1/4 as (1/2)²:

[tex]\implies\left(\dfrac{1}{2}\right)^{\frac{x}{3}} =\left(\dfrac{1}{2}\right)^2[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{f(x)}=a^{g(x)} \implies f(x)=g(x)[/tex]

[tex]\implies \dfrac{x}{3}=2[/tex]

Multiply both sides by 6:

[tex]\implies x=6[/tex]

Given equation:

[tex]2e^{2n-5} + 4= 36[/tex]

Subtract 4 from both sides:

[tex]\implies 2e^{2n-5} = 32[/tex]

Divide both sides by 2:

[tex]\implies e^{2n-5} = 16[/tex]

Take natural logs of both sides:

[tex]\implies \ln e^{2n-5} = \ln 16[/tex]

[tex]\textsf{Apply the power law}: \quad \ln x^n=n \ln x[/tex]

[tex]\implies (2n-5)\ln e = \ln 16[/tex]

Apply the law ln(e) = 1:

[tex]\implies 2n-5 = \ln 16[/tex]

Rewrite 16 as 2⁴:

[tex]\implies 2n-5 = \ln 2^4[/tex]

[tex]\implies 2n-5 = 4\ln 2[/tex]

Add 5 to both sides:

[tex]\implies 2n = 4\ln 2+5[/tex]

Divide both sides by 2:

[tex]\implies n = 2\ln 2+\dfrac{5}{2}[/tex]

Given equation:

[tex]\log_9x + 2\log_94= \log_920[/tex]

[tex]\textsf{Apply the log power law}: \quad n\log_ax=\log_ax^n[/tex]

[tex]\implies \log_9x + \log_94^2= \log_920[/tex]

[tex]\implies \log_9x + \log_916= \log_920[/tex]

[tex]\textsf{Apply the log product law}: \quad \log_ax + \log_ay=\log_axy[/tex]

[tex]\implies \log_916x= \log_920[/tex]

[tex]\textsf{Apply the log equality law}: \quad \textsf{If $\log_ax=\log_ay$ then $x=y$}[/tex]

[tex]\implies 16x=20[/tex]

Divide both sides by 16:

[tex]\implies x=\dfrac{20}{16}[/tex]

Simplify:

[tex]\implies x=\dfrac{5}{4}[/tex]

1. (a-b)(2ab+b²) results in the difference of two squares. (x-4)(x+4)= x²-16. (a + b)² = a² + 2ab + b²2. Brian's errors areoption b. (Incorrect, it is a square of a binomial.) and e. The middle term of the product is -10x. 3. (2x+6)(2x-6)= 4x²-36. The product of (2x+6) and (2x-6) is 4x²-36.

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The value of x is 17. The solution has been obtained using mid-point theorem of triangle.

What is mid-point theorem of triangle?

The midpoint theorem states, "The line segment of a triangle joining the midpoint of any two sides of the triangle is said to be parallel to its third side and is also half of its length."

Let the triangle be ABC and the line dividing it be PQ

We are given AP = PB and AQ = QC

Now, as per mid-point theorem, PQ is parallel to BC and is also half of its length as the two sides are equal.

Therefore,

x= 34/2

x=17

Hence, the value of x is 17.

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Answer:

C. [tex]f(0)=f(2)[/tex]

Step-by-step explanation:

Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.

The function is not differentiable over [0, 2]. Therefore, the option B is the correct answer.

Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.

The given function is f(x)=x³/3 over [0, 2].

Here, f(0)= 2 and f(2)=2. Hence, according to the Rolle's theorem there should be at least one x for which f'(x)=0.

Now, f'(x)= 3x²/3

0=3x²/3

3x²=0

x²=0

x=0

Therefore, the option B is the correct answer.

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The percent relative average deviation for the data set is 0.30%.

((20.96 - 20.89) + (20.85 - 20.89) + (20.92 - 20.89)) / 3 / 20.89 * 100 = 0.30%

The percent relative average deviation for the given data set can be calculated by first finding the absolute differences between each value and the mean (20.89) then adding those differences together. Once the differences are added, divide that by the mean and multiply by 100. This will give you the percent relative average deviation, which in this case is 0.30%.

The percent relative average deviation for the data set is 0.30%.

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The sampling distribution of the sample proportion of those who will be cured is approximately normal.

In math the term called sampling distribution is defined as the sample proportion of those who will be cured with the skin cream is approximately normal.

Here we have know that a certain skin cream is 80 percent effective in curing a common rash and a random sample of 100 people with the rash will use the cream.

Here we all know that the sampling distribution is the distribution of a statistic calculated from a random sample of data.

Here we also know that  the statistic is the sample proportion of those who will be cured with the skin cream.

And as per the Central Limit Theorem states that the sampling distribution of a statistic will be approximately normal if the sample size is large enough, then the shape of the underlying distribution.

Here we have given that the sample size of 100 people is large enough, then the sampling distribution of the sample proportion of those who will be cured with the skin cream is approximately normal.

Therefore, the correct option is (c) .

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The quadratic function graphed is defined as follows:

y = -x² + 6x - 8.

A quadratic function of roots x' and x'' is defined as follows:

y = a(x - x')(x - x'').

From the graph, the roots of the function are the x-intercepts, which are the values of x for which the graph crosses the x-axis, hence they are given as follows:

x = 2 and x = 4.

Hence:

y = a(x - 2)(x - 4)

y = a(x² - 6x + 8).

In which a is the leading coefficient.

The vertex is at (3,1), meaning that when x = 3, y = 1, hence the leading coefficient a is obtained as follows:

1 = a(3² - 6(3) + 8)

-a = 1

a = -1.

Hence the function is defined as follows:

y = -x² + 6x - 8.

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Note that a complex carbohydrate molecule has more atoms than a glucose molecule.

Glucose is a simple sugar and is composed of 6 carbon atoms, 12 hydrogen atoms, and 6 oxygen atoms. Complex carbohydrates, such as starches and fibers, are made up of multiple glucose molecules linked together, so they have more atoms than a single glucose molecule.

Sugar molecules are joined together in long, complicated chains to form complex carbohydrates.

Foods high in complex carbs include peas, beans, whole grains, and vegetables. In the body, both simple and complex carbohydrates are converted to glucose (blood sugar) and utilized as energy.

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The value of the angles that are in the triangle will be 97°, 51° and 32°.

The first thing to note before solving the question is that the sum of the total angles that are in a triangle is 180°.

In this case, it should be noted that the angles that are given are represented by variables. Therefore, we'll add them together and equate them to 180°. This will be:

18x + 7 + 8x + 11 + 6x + 2 = 180

32x + 20 = 180

Collect the like terms

32x = 180 - 20

32x = 160

Divide

x = 160 / 32

x = 5

First angle = 18x + 7

= 18(5) + 7

= 97°

Second angle = 8x + 11

= 8(5) + 11

= 51°

Third angle = 6x + 2

= 6(5) + 2

= 32°

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A ratio scale is used for measurements that have both a meaningful zero point and also an equal interval between each point. An ordinal scale is used for measurements that rank order items from highest to lowest. A nominal scale is used for measurements that have categories without any order. An interval scale is used for measurements that have an equal interval between each point but do not have a meaningful zero point.

A ratio scale is used for measurements that have both a meaningful zero point and also an equal interval between each point. It is often used for measurements that involve numbers, such as temperature or length. An ordinal scale is used for measurements that rank order items from highest to lowest. This type of measurement can be used to classify student performance on an exam, such as with letter grades (A, B, C, D, and E). A nominal scale is used for measurements that have categories without any order. This is typically used for measurements that involve assigning names or labels to categories, such as gender or ethnicity. An interval scale is used for measurements that have an equal interval between each point but do not have a meaningful zero point. This type of measurement is often used for measurements that involve numbers, such as temperature or time. In this example of classifying student performance on an exam, the ordinal scale is the most appropriate measurement to use.

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Answer:

a= 6/25

Step-by-step explain

because it probably is

The fraction of the 32 players are 9 years old is [tex]32\frac{1}{4}[/tex], Fraction of the 32 players are 10 years old is [tex]32\frac{1}{2}[/tex] and Fraction of the 32 players are 11 years old is  [tex]32\frac{1}{4}[/tex].

A fraction represents a part of a whole.

Given that 32 players showed up for practice today

1 /4 of the players are 9 years old.

1 /2 of the players are 10 years old.

The final 1/ 4 of the players are 11 years old

we have to find the fraction of the 32 players are 9 years old

1/4×32=8

Fraction of the 32 players are 10 years old

1/2×32=16

Fraction of the 32 players are 11 years old

1/4×32=8

Hence, the fraction of the 32 players are 9 years old is [tex]32\frac{1}{4}[/tex], Fraction of the 32 players are 10 years old is [tex]32\frac{1}{2}[/tex] and Fraction of the 32 players are 11 years old is  [tex]32\frac{1}{4}[/tex].

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The distance between two cities, A and B is 1884 miles. The solution has been obtained using the concept of arc of circle.

What is arc of circle?

A circle's arc is referred to as a section or portion of its circumference. A chord of a circle is a straight line that can be created by joining the arc's two ends. A semicircular arc is one whose length is exactly half that of the circle.

We are given that the angle is 27° and radius is 4000 miles

We know that circumference of circle = 2πr

So,

C=2*3.14*4000

C= 25120

Now, to find the length of arc AB,

⇒Arc length = (27° × 25120)/360°

⇒Arc length = 1884

Hence, the distance between two cities, A and B is 1884 miles.

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The complete question is attached below.

Answer:

3.509 hours

Step-by-step explanation:

500 m ÷ 142.4655 m/h = 3.509 h

The indicated side of the triangle of side a = 14 and side b =12.12.

The concept that will be used here is trigonometry. Trigonometry is the branch of mathematics that deals with particular angles' functions and how to use those functions in calculations. There are six popular trigonometric functions for an angle. Sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant are their respective names and acronyms (csc).

From the triangle, of the side a which is the hypothenus:

sin(θ)=opposite/hypothenus

but the angle (θ)

sin30= 7/hypothenus

hypothenus *sin30=7

hypothenus=7/sin30

hypothenus =  a=14

Then we can do that For b:

cos(θ)=b/hypothenus

but hypothenus =14

cos30= b/14

b=14*cos30

b= 12.12

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complete question:

Find the indicated side of the

triangle.

a

30°

b

b = [?][]

The investment amount at each is $2000 at 7% interest and the $4000 remainder at 8%.

One or many equations having the same number of unknowns that can be solved simultaneously called as simultaneous equation. And simultaneous equation is the system of equation.

Given:

A total of $6000 was invested,

part of it at 7% interest and the remainder at 8%.

The total yearly interest amounted to $460.

That means,

we have the system of equations,

x + y = 6000    {equation 1}

0.07x + 0.08y = 460    {equation  2}

Substituting the value of y to the equation 2,

0.07x + 0.08(6000-x) = 460

480 - 0.01x = 460

-0.01x = 460 -480

0.01x = 20

x = 2000

And y = 4000

Therefore, 2000 in 1st account and 4000 in 2nd account.

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Based on proportion, the amount of investment to have an annual interest of $150 at a 5% annual rate is $3,000.

The annual interest is the amount that is paid or received for accepting or giving credit.

The annual interest can be computed as the product of the annual percentage rate and the principal.

Where information for the interest rate and amount is available, the principal is the reciprocal of the interest and rate.

The annual interest rate = 5%

The annual interest (in dollars) = $150

Proportionately, $150 = 5%; therefore, 100%  of $150 = $3,000 ($150/5%)

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Answer:

Step-by-step explanation:

49255-1674.67=47580.33

Answer:

Continuous data is data that can take any value. Height, weight, temperature and length are all examples of continuous data.

An imperfectly elastic ball is projected with the velocity [tex]\sqrt{gh}[/tex]  at an angle α with the horizontal, so that it strikes a vertical wall distant c from the point of projection, and returns to the point of projection.

Then, The Time of flight (T) =   [tex]\frac{2c}{ \sqrt{gh cosa } }[/tex]                

When a ball is projected with the velocity [tex]\sqrt{gh}[/tex]  at an angle α with the horizontal, it follows a parabolic path.

The ball will have a horizontal component of velocity (Vx) =  [tex]\sqrt{gh cosa}[/tex] , and a vertical component of velocity (Vy) = [tex]\sqrt{ghsina}[/tex] .

The ball will travel a horizontal distance equal to c before reaching the wall. The total time of flight (T) for the ball is equal to the time it takes the ball to reach the wall plus the time it takes for the ball to return to the point of projection.

The time it takes for the ball to reach the wall is equal  [tex]\frac{c}{vx}[/tex] , and the time it takes for the ball to return to the point of projection is also equal  [tex]\frac{c}{vx}[/tex].

Since the horizontal component of velocity (Vx) is equal to  [tex]\sqrt{gh cosa}[/tex] ,

the total time of flight (T) is equal to  [tex]\frac{2c}{ \sqrt{gh cosa } }[/tex] .

The correct question is:

An imperfectly elastic ball is projected with velocity √gh at an angle α with the horizontal, so that it strikes a vertical wall distant c from the point of projection, and returns to the point of projection. Then the time of flight is equal to?

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Answer: The bottom one

Step-by-step explanation:

cause ur adding on to the score

Answer:

The answer is the last one

Step-by-step explanation:

Answer:

Step-by-step explanation:

a. No, he can't buy 12 packs of baseball cards because 12 packs * $1.70/pack = $20.40, which is more than $20.

b. Yes, he can buy 30 packs of gum because 30 packs * $0.60/pack = $18.00, which is less than or equal to $20.

c. He will still have $6.75 after he buys 5 packs of bouncy balls because $20.00 - (5 packs * $3.15/pack) = $20.00 - $15.75 = $6.75

In the table you provided, you can see the cost of different numbers of packs of baseball cards, gum and bouncy balls. This can help Dante to decide how much to spend on each item and how much he will save.

The differential equation that best models the growth rate of the rabbit population with respect to time t, where k is a constant is option D) [tex]\frac{dP}{dT}=KP(2400-P)[/tex].

A differential equation is an equation that relates a function and its derivatives to some independent variables. The solution to a differential equation is a function that satisfies the equation and is often used to model physical processes.

Differential equations come in many forms, including ordinary differential equations (ODEs) and partial differential equations (PDEs).

For the population in function of the time, is:

[tex]\frac{dP}{dT}[/tex]

The population P of rabbits on a small island grows at a rate that is jointly proportional to the size of the rabbit population and the difference between the rabbit population and the carrying capacity of the population

Carrying capacity is 2400.

This means that the differential equation is kP(size of the population multiplied by the constant) multiplied by 2400 - P(difference between the population and the carrying capacity).

=> [tex]\frac{dP}{dT}=KP(2400-P)[/tex]

Therefore, The differential equation that best models the growth rate of the rabbit population with respect to time t, where k is a constant is option D) [tex]\frac{dP}{dT}=KP(2400-P)[/tex].

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The given expression x - 6  = 8 - (9+x)  has one solution that is equals to  2.5

What is Algebraic expression ?

An algebraic expression is an expression that contains numbers, variables, and operations, such as addition, subtraction, multiplication, and division. It can also contain exponents and roots. Algebraic expressions can be used to represent a variety of real-world problems, such as finding the volume of a cube or the area of a circle.

Given expression ,

x - 6  = 8 - (9+x)

x-6 = 8-9-x

simplifying the terms,

x-6 = -1-x

shifting -x to LHS and -6 to RHS

we get,

x+x = 6-1

2x = 5

x = 5/2

x = 2.5

Hence, The given expression x - 6  = 8 - (9+x)  has one solution that is equals to  2.5

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True, the classic tradeoff between "guns and butter" states that when a society spends more on national defense, it has less to spend on consumer goods to raise the standard of living.

The production possibility curve, which illustrates the concept of opportunity cost, has a famous economic example known as the "guns-and-butter" curve. One must decide how much of each good to create in a hypothetical economy with only two goods.

An economy must decrease its production of butter (food) as it increases its production of firearms (military spending), and vice versa. According to the guns-and-butter curve, you can only acquire something if you offer something else in exchange.

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