It takes 5000 J of work to lift a crate to a height of 5 m in 10 s of time.. Calculate the power.

Answers

Answer 1

Answer:

P = 500 W

Explanation:

Given that,

Work done to lift a crate to a height of 5 m is 5000 J

It takes 10 s

We need to find the power of the crate. We know that power is the rate of doing work. Mathematically, it can be given by :

[tex]P=\dfrac{W}{t}\\\\P=\dfrac{5000}{10}\\\\P=500\ W[/tex]

So, the power of the crate is equal to 500 W.


Related Questions

How was our galaxy formed?

Answers

Answer:

according to big bang theory our galaxy was formed 13billion years ago and then made the stars and galaxies we see today. ... The universe began as a very hot, small, and dense superforce (the mix of the four fundamental forces), with no stars, atoms, form, or structure (called a "singularity).

100 cm cubic of water is mixed with 50 centimetres cubic of concentrated acid of density 1.2 gram per centimetre cube assuming no change in volume find the average density of the mixture the density of water is 1.0 gram per centimetre cube​

Answers

Answer:

Average Density = 1.07 g/cm³

Explanation:

The average density of the whole mixture is given by the following formula:

[tex]Average\ Density = \frac{mass\ of\ whole\ mixture}{volume\ of\ whole\ mixture}[/tex]

where,

volume of whole mixture = volume of water + volume of acid

volume of whole mixture = 100 cm³ + 50 cm³ = 150cm³

mass of whole mixture = mass of water + mass of acid

mass of whole mixture = (volume of water)(density of water) + (volume of acid)(density of acid)

mass of whole mixture = (100 cm³)(1 g/cm³) + (50 cm³)(1.2 g/cm³)

mass of whole mixture = 160 g

Therefore,

[tex]Average\ Density = \frac{160\ g}{150\ cm^3}[/tex]

Average Density = 1.07 g/cm³

Explain one inference scientists made about the interior of the Earth based on seismic waves. Use the words S & P waves in your answer. Use the word refract/bend in your answer

Answers

Answer:

"An earthquake radiates P and S waves in all directions and the interaction of the P and S waves with Earth's surface and shallow structure produces surface waves. Near an earthquake the shaking is large and dominated by shear-waves and short-period surface waves."  please rephrase this in your own words.

Explanation:

Im not sure if this helps but credits to: eqseis.geosc.psu.edu › Notes › waves_and_interior

14. Earth goes around the sun at an astonishing speed of about -hold your breath-107 460 643 meters per second. *
1 point
True
False
15. A car is moving around an oval track at a constant speed of 20km/h. Is it accelerating? *
1 point
True
False

Answers

Answer: 14 speed of Earth around Sun I see 30 km/s. FALSE

15. Because car is in circle track, direction of velocity changes

And car is in accelerating motion. direction of acceleration points to

The centre of the circle. RIGHT

Explanation:

A 100 N force is applied to move an object a horizontal distance of 5 meters at constant speed in 10 seconds. How much power is done?

Answers

Answer:

50 W

Explanation:

Given :

Force applied = 100 NDistance covered = 5 metresTime = 10 seconds

To find :

Power

Solution :

For calculating power, we first need to know about the work done.

[tex] \bf \boxed{Work = Force \times displacement} [/tex]

Now, substituting values in the above formula;

Work = 100 × 5

= 500 Nm or 500 J

We know that,

[tex]\bf \boxed{Power=\dfrac{Work\:done}{Time\: taken}}[/tex]

Substituting values in above formula;

Power = 500/ 10

= 50 Nm/s or 50 W

Hence, power = 50 W .

5. What is the frequency of a sound wave when the speed of the sound is 340 m/s and has a wavelength of 1.21 m? 263 Hz 281 Hz O 328 Hz O 346 Hz​

Answers

Answer:

281 Hz

Explanation:

I am so so sorry if this is wrong. But good luck and have a good day

Explain why a sound becomes louder as you move closer to the source of the sound.​

Answers

Answer:

The wavelength of frequency of the sound are closer to each other

Or

The frequency of the sound increases as it moves towards you

how does electricity work?​

Answers

Answer:Electricity works by getting a bunch of conductor elements together and creating a flow of electron-stealing patterns through them. This flow is called a current. ... Once you can control the direction the electrons are going, you can use them to power or charge anything from a light bulb to your TV to your electric car.

Explanation:trust

A 12kg aluminum box is sliding along a horizontal steel surface while experiencing a rightward applied force of 60N. The box has a displacement of 20m. What is the Net Force acting on the box? *

A.)60N
B.)117.72N
C.)4.67 N
D.)-55.33N

Answers

The answer would be D sorry if wrong

A 10cm3 sample of copper has a density of 897g/cm3. What is the mass of the sample?

Answers

Question:-

A 10cm³ sample of copper has a density of 897g/cm³. What is the mass of the sample ?

Answer:-

Given:-

Density of sample of copper is 897g/cm³.

Volume of sample of copper is 10cm³.

To Find:-

The mass of the sample.

Solution:-

We know,

[tex] { \boxed{\bf{\rm \red {Mass \: = \: Density \: × \: Volume}}}} [/tex]

So, Mass = 897g/cm³ × 10cm³

Mass = 8970 g

The mass of the sample is 8970 g. [Answer]

Suppose you needed to push a 1,500-N sofa up a frictionless ramp with a 30° angle. How much force would you have to apply to the sofa?Show your work below.

Answers

Answer:

1299N

Explanation:

GIven data

Weight W= 1500N

Angle Ф= 30°

The applied force up the frictionless ramp is gotten by applying the formula below

F= WcosФ

substitute

F=1500 cos 30

F = 1500*0.8660

F= 1299N

Hence the applied force is 1299N

Amy pulls a spring with a spring constant k = 100 stretching it from its rest length of 0.10 m to 0.2

Answers

Answer:

Elastic potential energy  E = 0.5 J

Explanation:

Let us assume we have to find the elastic potential energy stored in the spring.

Given: k = 100

change in the length of the spring x = 0.2-0.1 = 0.1 m

Elastic potential energy

E = [tex]\frac{1}{2} kx^2[/tex]

plugging the values we get

[tex]E = 0.5\times100\times0.1^2\\=0.5 J[/tex]

Hence, Elastic potential energy  E = 0.5 J

Amy pulls a spring with a spring constant k = 100 N/m, stretching it from its rest length of 0.10 m to 0.20 m.

What is the elastic potential energy stored in the spring?

Answer: 0.5 J

What is the answer for this question?

Answers

Answer:

6 watts

Explanation:

hours against watts

I'm not sure though

The magnetic field of a bar magnet Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. a Always points from north to south, whether we look outside the magnet or inside the magnet. b Always points from south to north, whether we look outside the magnet or inside the magnet. c Points from north to south outside the magnet, but south to north inside the magnet. d Points from south to north outside the magnet, but north to south inside the magnet.

Answers

Answer:

A: Always points from north to south, whether we look outside the magnet or inside the magnet

Explanation:

When we freely suspend a bar magnet, it's magnetic field will always rest in the north to south direction due to the fact that the Earth's magnetic south pole usually lies in the direction of the geographic north while the Earth's magnetic north pole usually lies in the direction of the geographic south.

Now, we all know that in magnets, like poles will repel and unlike poles will attract. What this now means is that the magnet will always point from the north to the south direction.

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

Answers

Correct question:

Manny walked a total of 3 miles. The reference point used to calculate the total distance that he walked was the same as the ending point. Which describes where Manny most likely walked?

a. from the bottom of a hill to the top

b. on a circular nature trail

c. on a sidewalk from his house to the mall

d. from the beginning of a straight track to the end

Answer:

b. on a circular nature trail

Explanation:

As it is mentioned that Manny that his reference point from where she started is same as ending point meaning that she moved in a circular path making point B correct answer.

Answer:

on a circular nature trail

Explanation:

under which conditions do both convex and concave mirrors form virtual images state whether or not each can form a real image if the mirror can form a real image describe how this occurs

Answers

Answer:

Explanation:Concave mirror​s can make a real image.when the object is away from the mirror it is called real image and when the object is closer to the mirror it is called virtual mirror.

In the example of a hammer hitting a nail, which is hit harder? the nail, the hammer, or they both hit equally?

Answers

Answer:

both hit qaulity

Explanation:

Newton's Third Law says that every interaction involves two forces - in this case (1) hammer pushes nail, and (2) nail pushes hammer. When a hammer hits a nail, Newton's Third Law says that the force that the hammer exerts on the nail is exactly the same size as the force the nail exerts on the hammer.

An effect analogous to two-slit interference can occur with sound waves, instead of light. In an open field, two speakers placed 1.19 m apart are powered by the same function generator producing sine waves at 1,163 Hz frequency. Assume that the speed of sound is 340 m/s. A student walks along a line 12.5 m away and parallel to the line from one speaker to the other speakers. She hears an alternating pattern of loud and quiet, due to constructive and destructive interference. What is the distance between the central maximum and the first maximum (loud) position along this line in m

Answers

Answer:

3.04 m

Explanation:

The interference by diffraction of waves is noticeable only when the dimension of the opening through which the wave is passing through is comparable to the wavelength of the passing wave.

It is given that :

Distance between two speakers, d = 1.19 m

Speed of sound,  v = 340 m/s

The frequency is f = 1163 Hz

Distance the student walk along the line of the speaker, D = 12.5 m

We know the wavelength of the sound produced by the speakers is given by :

[tex]$\lambda=\frac{v}{f}$[/tex]

  [tex]$=\frac{340}{1163}$[/tex]

  = 0.29 m

Now the distance between the central maximum and the first maximum position is given by :

[tex]$y=\frac{\lambda D}{d}$[/tex]

  [tex]$=\frac{0.29 \times 12.5}{1.19}$[/tex]

 = 3.04 m

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