Answer: The formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
Explanation:
Decomposition of hydrated manganese sulphate is given by:
[tex]MnSO_4.xH_2O\rightarrow MnSO_4+xH_2O[/tex]
Molar mass of [tex]MnSO_4[/tex] = 151.0 g/mol
According to stoichiometry:
(151.0+18x) g of [tex]MnSO_4.xH_2O[/tex] decomposes to give 151.0 g of [tex]MnSO_4[/tex]
Thus 45.91 g of [tex]MnSO_4.xH_2O[/tex] decomposes to give= [tex]\frac{ 151.0}{151.0+18x}\times 45.91g[/tex] of [tex]MnSO_4[/tex]
Also we are given : 37.07 g of [tex]MnSO_4[/tex] is produced
Thus we can equate the two equations:
[tex]\frac{ 151.0}{151.0+18x}\times 45.91=37.07[/tex]
[tex]x=2[/tex]
Thus the formula of the hydrate is [tex]MnSO_4.2H_2O[/tex]
What is the concentration of a solution with a
volume of 2.5 liters containing 660 grams of
calcium phosphate Ca3(PO4)2 ?
Answer:
660gx Imol = 2.1278 mol 310.189 2.5L 1.85 m).
Explanation:
The number of moles of 660 grams of calcium phosphate is 2.127. Then the molarity of the solution of 2.5 liter volume is 0.85 M.
What is molarity ?Molarity is a common term used to express the concentration of a solution. It is the ratio of number of moles of solute particles to the volume of solution in liters. Hence, its unit is mol/L or molar.
The molarity of a solution is a colligative quantity as well as temperature dependent.
Given,
molar mass calcium phosphate, Ca₃(PO₄)₂ =310.18 g/mol
Then,
no.of moles of calcium sulphate in 660 g = 660 g/310.18 g/mol = 2.127 moles
volume of solution = 2.5 L
Molarity = no.of moles of solute/ volume of solution in L
M = 2.127 moles/ 2.5 L
= 0.85 M.
Therefore, the molarity of the given solution is 0.85 molar.
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What is the name of this molecule?
Answer:
pentanoic acid
Explanation:
it has 5 carbon atoms which gives it the parent name pent, and its attached to the ester group
PLEASE HELP!!
A scientist places a pH meter in a sample of concentrated potassium hydroxide (KOH). The scientist slowly adds nitric acid (HNO3) to the KOH and monitors the pH. Describe how the pH and hydronium ion concentration will change in the solution as the acid is added.
Answer:
pH of the solution will decrease & hydronium ion concentration will increase in the solution as the acid is added.
Explanation:
What is 2AI(s) + FeO3(s) = Ai2O3(s) + 2Fe(s)
Answer:
it's a double displacement Reaction.
What is the other product for this reaction? Hbr + NaOH —> ( select 2)
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Answer: HBr + NaOH = nabr + h2o
Explanation:
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What substance is oxidized in the following reaction? 4HCl + MnO2 → Cl2 + 2H2O + MnCl2
Answer:
Cl⁻ was oxidized.
Explanation:
4HCl + MnO₂ → Cl₂ + 2H₂O + MnCl₂Oxidation can be defined as the process in which the oxidation number of a substance increases.
On the left side of the equation, Cl has a charge of -1 (in HCl); while on the right side of the equation Cl has a charge of 0 in Cl₂.
Thus, Cl⁻ was oxidized.
What type of solution would have a pH of 8 ?
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Answer: Weak base
Explanation:
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Answer and Explanation:
Solutions that have a pH of 8 would be considered a Weak Base.
This is because a weak base is a base that, upon dissolution in water, does not dissociate completely.
Solutions/liquids that have a pH higher than a pH of 7 are basic solutions, while solutions/liquids that have a pH lower than a pH of 7 are acidic solutions.
When the pH level is closer to 7, it is weak, and when it is far from 7, like if it is 1 or 12, then it is a strong acid/base.
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This timeline woulchre useful to someone who was writing a report titled
When sodium hydroxide NaOH dissociates in water, the oxygen atoms on the hydroxide anions will interact with:
Answer:
Hydroxide ions ( OH−) are negatively charged, and the formal negative charge is on the oxygen atom. Since opposite charges attract, the oxygen atoms will interact with the positive end of water's dipole.
Explanation:
If 220 mL of a 12.0 M HCl solution is diluted to 1000 mL, what will be the concentration of the new solution?
Answer:
2.64 M
Explanation:
Use the dilution equation M1V1 = M2V2, where:
M1 = 12.0 M HCl
V1 = 220 mL HCl
M2 = ?
V2 = 1000 mL HCl
(12.0 M HCl)(220 mL HCl) = M2(1000 mL HCl)
M2 = 2.64 M HCl
Potassium chlorate, a common oxidizing agent in fireworks and matchheads, undergoes a solid-state disproportionation reaction when heated:
4KClO3 (s) ⟶ Δ3KClO4 (s) + KCl (s).
Use ΔHf ° and S° values to calculate ΔG_sys ° (which is ΔGrxn °) in kJ at 25°C for this reaction.
Answer:
Explanation:
[tex]\text{From the information given:}[/tex]
[tex]\text{The chemical reaction is : } 4 KClO_{3(s)} \to 3 KClO_{4(s)} + KCl_{(s)}[/tex]
[tex]\text{To find} \ \Delta G^0_{rxn}\ \text{using the formula}: \\ \\ \Delta G^0_{rxn} = \sum n_p \times \Delta _f G^0 (Products) - \sum n_R \times \Delta _fG^0 ( Reactants) \\ \\ where; n_p = \text{no of moles of products } \ and; \\ \\ n_R = \text{no of moles of reactants }[/tex]
[tex]\implies G^0_{rxn} = 3 \times \Delta _fG^0 [KClO_4{(s)}] + \Delta_fG^0[KCl_{(s)}] - 4 \times \Delta _f G^0 [ KClO_3 (s) ][/tex]
[tex]\Delta _fG^0 \ values \ at \ 25^0 \ C (298 \ K) are\ given \ as:\\\\ \Delta _fG^0 [KClO_4(s)] = -303.09 \ kJ \\ \\ \Delta _fG^0 [KCl(s) ] = - 409.14 \ kJ \\ \\ \Delta_f G^0 [KClO_3_{(s)}] = -296.25 \ kJ \\ \\ replacing \ the \ above \ values \ into \ equation (1) ; then:\\ \\ \\\Delta G^0_{rxn} = 3 *(-303.09) + (-409.14) - 4*(-296.25) \ kJ \\ \\ = (-909.27 - 409.14 + 1185) \ kJ \\ \\ = -133.41 \ kJ \\ \\ \mathbf{\Delta G^0_{rxn} = -133.4 \ kJ }[/tex]
The standard free energy change of the reaction is -133 kJ.
From the reaction equation, we have; 4KClO3 ⇄ 3KClO4 (s) + KCl (s). The standard free energy of formation of each specie is given below;
ΔG°f KClO3 = -296.35 kJ
ΔG°f KClO4 = -303.09 kJ
ΔG°f KCl = -409.14 kJ
Hence;
ΔG°rxn = [3(-303.09)] + ( -409.14)] - [(4( -296.35))]
ΔG°rxn = (-909.27) + (-409.14) - (-1185.4)
ΔG°rxn = -133 kJ
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Solution remained colorless.
During the experimentation, the test tube was gently heated in a Bunsen burner flame for 60 seconds. What was the reason for this specific
procedure?
A)
Heating was done to initiate the combustion of the metal in water.
B)
Heating was done to confirm that no chemical reaction would take
place in acid
0
Heating was done to precipitate the chemical change in each test
tube containing water
D)
Heating helped released the hydrogen contained in water
molecules so students would have a positive H+ test.
what is another name for horse
Answer:
Mount, Charger, Colt, Pony, and Folt
Explanation:
Answer:
A stallion or a mare
Explanation:
If a mechanical wave has a frequency of 0.147 Hz and a wavelength of 12.05 m, what is the velocity of the wave? (round to the hundredths place)
Answer:
0.147 Hz because I took the test
The velocity of a wave is the product of its frequency and wavelength. The velocity of wave with 0.147 Hz and 12.05 m is 1.77 m/s.
What is frequency ?The frequency of a wave is the number of wave cycles per unit time. Frequency is the inverse of time period of the wave. It is inversely proportional to the wavelength. Unit of frequency is Hz which is equivalent to s⁻¹.
The wavelength of a wave is the distance between two consecutive crests or troughs. The wavelength λ, and frequency ν of a wave is related to the velocity v of the wave as follows:
v = νλ
Given that,
frequency = 0.147 Hz
wavelength = 12.05 m
then, velocity = 0.147 Hz × 12.05 m = 1.77 m/s.
Therefore, the velocity of the mechanical wave is 1.77 m/s.
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Identify the type of reaction.
Al + MgSO4 = Al2(SO4)3 + Mg
Answer: its combustion
Explanation:
is oxygen a beginning substance or ending substance?
If anyone could help I’d appreciate it
Answer: 2.00 mol
Explanation:
The balanced chemical equation is:
[tex]2H_2(g)+O_2(g)\rightarrow 2H_2O(g)[/tex]
According to stoichiometry :
2.00 moles of [tex]H_2[/tex] require = 1.00 moles of [tex]O_2[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will require=[tex]\frac{1}{2}\times 2.00=1.00moles[/tex] of [tex]O_2[/tex]
Thus both will act as limiting reagents and will be fully consumed.
2.00 moles of [tex]H_2[/tex] will form = 2 moles of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2[/tex] will form = [tex]\frac{2}{2}\times 2.00=2.00moles[/tex] of [tex]H_2O[/tex]
Thus 2.00 moles of [tex]H_2O[/tex] will be produced from the given masses of both reactants.
Which contains the greatest number of moles of oxygen atoms?
Answer:
B. OR C.
Explanation:
So, 1 mol of ethanol, C2H5OH contains 1 mol of atoms of O; 1 mol of formic acid, HCO2H contains 2 moles of atoms of O; and 1 mol of water, H2O contains 1 mol of atoms of O.
Answer: So, of the three compounds given, formic acid, HCO2H, contains the greatest number of moles of oxygen atoms.
Chromium is manufactured by heating a mixture of chromium(III) oxide with aluminium powder.
Cr2O3(s) + 2Al(s) → 2Cr(s) + Al2O3(s)
a=Calculate the mass of aluminium needed to react with 50 g of Cr2O3.
b=Calculate the mass of chromium produced from 50 g of Cr2O3.
c=Calculate the mass of chromium produced from 5 kg of Cr2O3.
d=Calculate the mass of chromium produced from5 tonnes of Cr2O3.
Note: 1 tonne = 1,000,000 g
Ar: Cr = 52, O = 16, Al = 27
A 20 mL sample of human urine was found to have 10 mg of
urea during analysis. The molar mass of urea is 60.1 g/mol.
Calculate the molarity of urea in the given sample.
Solid iron is mixed with a solution of copper (I) nitrate to form iron (III) nitrate solution and metal copper. (what is the equation)
Answer:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3Cu
Explanation:
Solid Iron = FeCopper (I) nitrate = CuNO₃ (Nitrate, NO₃⁻, always has a charge of -1).Iron (III) nitrate = Fe(NO₃)₃ (That way the compound has an overall neutral charge)Metal Copper = CuWriting the equation using symbols leaves us with:
Fe + CuNO₃ → Fe(NO₃)₃ + CuIt is not balanced yet. Now we balance the NO₃ species on the left side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + CuFinally we balance the Cu species on the right side:
Fe + 3CuNO₃ → Fe(NO₃)₃ + 3CuA student places 2 mL of 2% ethanolic silver nitrate solution into test tube. They add 2 drops of an unknown compound into the test tube while gently mixing. After five minutes, the student heated the test tube in a water bath and a white precipitate formed. They added 2 drops of 1 M nitric acid to the mixture which was cooled to room temperature and still noticed the precipitate did not dissolve in response to the nitric acid. What compound is most likely the unknown
Answer:
hi
Explanation:
i am smart but i need this app cuz some are realy hard
Mass of watch glass + filter paper = 105.98 g
Mass of watch glass + filter paper + crystallized product = 109.03 g
Mass of uncrystallized product (show work) =
Mass of methyl benzoate = 3.08 g
Volume of nitric acid used = 2.0 mL
Theoretical yield based on each of the starting materials
(Please use two Dimensional Analysis (DA) equations, one for the maximum amount of product obtainable from the amount of methyl benzoate you used and the other from the concentrated nitric acid, then use the lesser of the two to determine the Limiting Reagent; you must determine the number of moles in 2.00 mL of concentrated nitric acid [concentration 69.0% (w/w), and density (1.42 g/mL)].
Required:
a. Identity of the Limiting reagent (LR) based on the above two DA equations = __________
b. Max amount of product obtainable from the LR = ___________
c. Mass of the product you obtained: ____________
Answer:
Explanation:
Mass of uncrystallized product = (Mass of watch glass + filter paper + crystallized product) - (Mass of watch glass + filter paper)
Mass of uncreystaliized product = 109.03 gm - 105.98 gm
Mass of uncrystaliized product = 3.05 gm
For methyl benzoate;
mass = 3.08 g
no of moles = 3.08 g/ 136.15 g/mol = 0.0226 mole
It is possible for the formation of 1 mole of nitro methyl benzoate from a mole of methyl benzoate.
moles of nitro methyl benzoate that can be formed from 0.0226 moles of methyl benzoate = 0.0226 moles
∴
mass of nitro methyl benzoate = 0.0226 mol × 181.15 gm /mol
mass of nitro methyl benzoate = 4.098 gm
For HNO_3 solution:
mass = 1.42 gm/ml × 2.0 ml
mass = 2.84 gm
Mass of HNO3 in 2.84 gm solution[tex](69\% w/w)= 2.84 gm * \dfrac{69}{100 }[/tex]
= 1.9596 gm
Moles of HNO3 = [tex]\dfrac{ 1.9596 \ gm }{ 63.01 gm /mol}[/tex]
= 0.0311 mole
1 mol of HNO_3 can be formed from 1 mole of nitro methyl benzoate
Thus; moles of nitro methyl benzoate that can be formed from 0.0311 mole of HNO_3 = 0.02256 mole
The mass for nitro methyl benzoate can now be determined as:
= 0.0311 mole × 181.5 gm/mole
= 5.634 gm
Since the mass formed from methyl benzoate is lesser, then methyl benzoate serves as the limiting reagent.
The mass obtainable from the LR = 4.098 gm
Which of the different components of smog depicted in the graph are most likely released from automobile exhaust?
A
A and B
B
B and C
с
A, B, and C
D
B, C, and D
Answer:
B, B and C
Explanation:
The two components (AA, hydrocarbons and BB, nitrogen oxide) are most likely released from automobile exhaust.
What is Smog?This is referred to a type of air pollution which could be from carbon emission etc and reduces the visibility.
(AA, hydrocarbons and BB, nitrogen oxide peaked midmorning when traffic is highest which means they were most likely released from automobile exhaust?.
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Unit 4.2 quiz chemistry
The correct value of m, n, x and y to obtain a balanced equation is?
m B2O3(s) + n HF(l) → x BF3(g) + y H2O(l)
a.
m=1, n=1, x=1 and y=1
b.
m=1, n=6, x=2 and y=3
c.
m=1, n=1.5, x=1 and y=1
d.
m=2, n=12, x=4 and y=6
Answer:
d
Explanation:
answer d makes the equation balance
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 300 cm3, the pressure is 180 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?
Answer:
The gas is decreasing at a rate of 50 cubic centimeters per minute.
Explanation:
The Boyle's Law is represented by the following expression:
[tex]P\cdot V = k[/tex] (1)
Where:
[tex]P[/tex] - Pressure, in kilopascals.
[tex]V[/tex] - Volume, in cubic centimeters.
[tex]k[/tex] - Proportionality constant, in kilopascal-cubic centimeters.
By definitions of rate of change and implicit differentiation, we derive the following differential equation:
[tex]\dot P \cdot V + P\cdot \dot V = 0[/tex] (2)
Where:
[tex]\dot P[/tex] - Rate of change of the pressure, in kilopascals per minute.
[tex]\dot V[/tex] - Rate of change of the volume, in cubic centimeters per minute.
Then, we clear the rate of change of the volume within (2):
[tex]P\cdot \dot V = -\dot P\cdot V[/tex]
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
If we know that [tex]P = 180\,kPa[/tex], [tex]\dot P = 30\,\frac{kPa}{min}[/tex] and [tex]V = 300\,cm^{3}[/tex], then the rate of change of the volume is:
[tex]\dot V = -\left(\frac{\dot P}{P} \right) \cdot V[/tex]
[tex]\dot V = -50\,\frac{cm^{3}}{min}[/tex]
The gas is decreasing at a rate of 50 cubic centimeters per minute.
1/5 divided by 3/4 fraction
Answer:
4/15
Explanation:
we can write out an equation by doing (1/5 ÷ 3/4) and then switch the sign to multiplication and we can keep the first fraction the same (in this case 1/5) and then we flip the second fraction BUT when we flip the second fraction upside-down we have to change the symbol to multiplication (1/5x4/3)
then after that all we do is multiply the denominators and numerators :)
1 x 4 = 4
_______
5 x 3 = 15
answer would be 4/15
How can you determine if elements have the same properties?
Answer:
You will know if elements have the same properties if they are in the same column (up and down) on the periodic table.
Explanation:
Ex: Lithium and a hydrogren has the same properites bcause they are both on the same line/column. Columns are up and down the table and rows are left and right. Hope this helps
which answer? Is this
Answer:
law of segregation
have a good day!
Explanation: