it costs 50p for posting a parcel that weighs 20g. how much does it cost altogether to post 1 parcel weighing 170g and 2 parcels weighing 320g each?

Answers

Answer 1

It would cost 2025p to send one parcel weighing 170g and two parcels weighing 320g each.

In order to find out how much it will cost to send one parcel weighing 170g and two parcels weighing 320g each, we can use the information given to us in the question: it costs 50p to post a parcel that weighs 20g. Using this information, we can create a proportion. We know that 50p is the cost to send a parcel weighing 20g, so if we multiply the weight of the parcel by 2.5, we can find out how much it would cost to send that parcel.

For example, a parcel weighing 50g would cost 125p (50 x 2.5 = 125). To find out how much it would cost to send a parcel weighing 170g, we can use this porpotion: 50p/20g = x/170g

Multiplying both sides by 170g, we get:

x = (50p/20g) * 170gx = 425p

So, it would cost 425p to send a parcel weighing 170g.To find out how much it would cost to send two parcels weighing 320g each, we can use the same proportion:

50p/20g = x/320g

Multiplying both sides by 320g, we get:

x = (50p/20g) * 320gx = 800p

So, it would cost 800p to send two parcels weighing 320g each.

To find out the total cost to send all three parcels, we simply add up the costs:

425p + 800p + 800p = 2025p.

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Related Questions

Find the area of a composite figure.

Answers

The area of the composite figure is 800m²

What is area of a figure?

The area of a figure is the number of unit squares that cover the surface of a closed figure.

Composite geometric figures are made from two or more geometric figures.

The figure consist of a rectangle , a semi circle and a triangle.

Area of the semicircle = 1/2 πr²

= 1/2 × 3.14 × 10²

= 314/2 = 157 m²

Area of the rectangle = l × w

= 25 × 20

= 500m²

area of the triangle = 1/2bh

= 1/2 × 10 × 25

= 25 × 5

= 125 m²

Therefore the area of the composite figure

= 125 + 500 + 175

= 800m²

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In a controlled laboratory experiment, scientists at the University of Minnesota discovered that
25% of a certain strain of rats subjected to a 20% coffee
bean diet and then force-fed a powerful cancer-causing
chemical later developed cancerous tumors. Would we
have reason to believe that the proportion of rats developing tumors when subjected to this diet has increased
if the experiment were repeated and 16 of 48 rats developed tumors? Use a 0.05 level of significance.

Answers

Yes, we would have reason to believe that the proportion of rats developing tumors when subjected to this diet has increased if the experiment were repeated and 16 of 48 rats developed tumors.

To determine whether there is an increase in the proportion of rats developing tumors when subjected to a coffee bean diet, we can conduct a hypothesis test using the 0.05 level of significance.

1. State the hypotheses:

- Null hypothesis (H0): The proportion of rats developing tumors remains the same.

- Alternative hypothesis (Ha): The proportion of rats developing tumors has increased.

2. Identify the test statistic:

We will use a z-test to compare the observed proportion of rats developing tumors with the expected proportion.

3. Set the significance level:

The significance level (α) is given as 0.05.

4. Collect data:

In the original experiment, 25% of rats developed tumors. In the repeated experiment, 16 out of 48 rats developed tumors.

5. Compute the test statistic:

The test statistic formula for comparing proportions is:

z = (p - P) / sqrt(P(1-P)/n)

where p is the observed proportion, P is the hypothesized proportion, and n is the sample size.

Using the observed proportion (16/48 = 0.333), the hypothesized proportion (0.25), and the sample size (48), we can calculate the test statistic.

6. Determine the critical value:

Since we are using a 0.05 level of significance and conducting a one-tailed test (Ha: >), we can find the critical value from the standard normal distribution table. The critical value for a 0.05 significance level is 1.645.

7. Make a decision:

If the test statistic is greater than the critical value, we reject the null hypothesis and conclude that the proportion of rats developing tumors has increased.

8. Calculate the test statistic:

Plugging in the values into the formula, we calculate the test statistic:

z = (0.333 - 0.25) / sqrt(0.25 * 0.75 / 48) = 1.404

9. Compare the test statistic and critical value:

The test statistic (1.404) is less than the critical value (1.645).

10. Make a decision:

Since the test statistic is not greater than the critical value, we fail to reject the null hypothesis. Therefore, we do not have sufficient evidence to conclude that the proportion of rats developing tumors has increased when subjected to this diet.

In summary, based on the given data and conducting a hypothesis test, we do not have reason to believe that the proportion of rats developing tumors has increased if the experiment were repeated and 16 of 48 rats developed tumors.

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