How many of the planets have an orbital period of less than one Earth year?
Since orbital period depends on how far you are from the sun, planets closer to the sun have a orbital period less than one earth year.
These planets are Mercury and Venus
Identify the specific element that corresponds to each of the following electron configuration 1s2, 2s2, 2p6,3s2, 3p6
Explanation:
It's argon
As argon has atomic number 18 so it's configuration is
1s2, 2s2, 2p6,3s2, 3p6
Hope it will help :)❤
The given electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
Each number and letter in the electron configuration corresponds to a specific electron orbital and the number of electrons present in that orbital.
In this case, the electron configuration indicates that:
The first shell (n=1) has 2 electrons in the 1s orbital.
The second shell (n=2) has 2 electrons in the 2s orbital and 6 electrons in the 2p orbital.
The third shell (n=3) has 2 electrons in the 3s orbital and 6 electrons in the 3p orbital.
By adding up the total number of electrons (2 + 2 + 6 + 2 + 6), we find that the configuration represents 18 electrons. The element that has 18 electrons is argon, which has an atomic number of 18.
Therefore, the electron configuration 1s2, 2s2, 2p6, 3s2, 3p6 corresponds to the element argon (Ar).
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The picture below shows a NASA image of the Oort cloud, a sphere of objects that are thought to surround Earth's solar system at a distance of up to one light-year from the Sun.
If the Oort cloud does exist, which of the following could explain why the objects in it may have formed this spherical shape?
A
They are held in orbits by the Sun's gravitational force.
B
They are held in Earth's solar system by Neptune's magnetic field.
C
They float freely in space because the Sun's gravitational force is too weak to hold them in orbit.
D
They are held in stationary positions around Earth's solar system by other stars in space.
The gravitational pull of the Sun keeps them in their orbits. The gravitational pull of the Sun and surrounding stars combined is most likely what gives the Oort cloud its spherical shape.
What does NASA's Oort Cloud mean?The Oort Cloud is a spherical layer of ice objects that is thought to be located between 2,000 and 100,000 astronomical units (AU) from our Sun, a star.
What makes it the Oort Cloud?The Oort cloud, so named after the Dutch astronomer Jan Oort who first confirmed its existence, is a collection of objects with a combined mass estimated to be 10-100 times that of Earth that are less than 100 km (60 miles) across and maybe trillions in number.
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Write the Ksp expression for the sparingly soluble compound cobalt(II) sulfide, CoS. If either the numerator or denominator is 1, please enter 1.
Answer:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary to write the chemical equation for this reaction as shown below:
[tex]CoS(s)\rightleftharpoons Co^{2+}(aq)+S^{2-}(aq)[/tex]
Thus, since solids are not included in equilibrium expressions, we can set this one up as follows:
[tex]Ksp=\frac{[Co^{2+}][S^{2-}]}{1}[/tex]
Regards!
What is the mole ratio of O2 to NH3?
Equal molar quantities of Ca2 and EDTA (H4Y) are added to make a 0.010 M solution of CaY2- at pH 10. The formation constant for CaY2- is 5.0 x 1010 and the fraction of unprotonated EDTA (Y4-) is 0.35 at pH10. Calculate the concentration of free Ca2 in this solution.
Answer:
the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
Explanation:
Given the data in the question;
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
Formation constant Kf
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = 5.0 × 10¹⁰
Now,
[[tex]y^{4-[/tex]] = [tex]\alpha _4CH_4Y[/tex]; ∝₄ = 0.35
so the equilibrium is;
[tex]Ca^{2+[/tex] + [tex]H_4Y[/tex] ⇄ [tex]CaY^{2-[/tex] + 4H⁺
Given that; [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] { 1 mol [tex]Ca^{2+[/tex] reacts with 1 mol [tex]H_4Y[/tex] }
so at equilibrium, [tex]CH_4Y[/tex] = [tex]Ca^{2+[/tex] = x
∴
[tex]Ca^{2+[/tex] + [tex]y^{4-[/tex] ⇄ [tex]CaY^{2-[/tex]
x + x 0.010-x
since Kf is high, them x will be small so, 0.010-x is approximately 0.010
so;
Kf = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]y^{4-[/tex]] ) = [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ [tex]CaY^{2-[/tex] / ( [[tex]Ca^{2+[/tex]][[tex]\alpha _4CH_4Y[/tex]] ) = 5.0 × 10¹⁰
⇒ 0.010 / ( [x][ 0.35 × x] ) = 5.0 × 10¹⁰
⇒ 0.010 / 0.35x² = 5.0 × 10¹⁰
⇒ x² = 0.010 / ( 0.35 × 5.0 × 10¹⁰ )
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 0.010 / 1.75 × 10¹⁰
⇒ x² = 5.7142857 × 10⁻¹³
⇒ x = √(5.7142857 × 10⁻¹³)
⇒ x = 7.559 × 10⁻⁷
Therefore, the concentration of free Ca2⁺ in this solution is 7.559 × 10⁻⁷
What is the coldest temperature ever achieved?
Answer:
The lowest natural temperature ever directly recorded at ground level on Earth is −89.2 °C
-273.144 degrees celsius. This is close to 'absolute zero', which is equal to -273.15 degrees celsius
Explanation:
In the lab, a 156 g sample of unknown compound KClOx was completely decomposed to produce 50.4 L of O2 (g) at STP and an unknown amount of KCl. What is the value of X
Answer:
2
Explanation:
Step 1: Write the generic decomposition reaction
KClOₓ ⇒ KCl + O₂
Step 2: Calculate the moles of O₂
At STP, 1 mole of an ideal gas occupies 22.4 L.
50.4 L × 1 mol/22.4 L = 2.25 mol
Step 3: Calculate the mass corresponding to 2.25 moles of O₂
The molar mass of O₂ is 32.00 g/mol.
2.25 mol × 32.00 g/mol = 72 g
Step 4: Determine the value of x
Every 156 g of KClOₓ there are 72 g of oxygen. The mass percent of O is:
%O: 72 g/156 g × 100% = 46.2%
In KClO, the mass percent of O is: 32.00 g/90.5 g × 100% = 35.4%
In KClO₂, the mass percent of O is: 64.00 g/138.5 g × 100% = 46.2%
Then, x = 2
Question 1
3 pts
TI
Which part(s) of the following ground state electron configuration holds the valence
electrons?
At
o
1s22s22p63523p4
ОЗр
03s
O2s
O 35 and 3p
Answer:
3s and 3p
Explanation:
From the question given above, the following data were obtained:
Electronic configuration =>
1s² 2s²2p⁶ 3s²3p⁴
Location of valence electron =?
From the electronic configuration given above, we can see clearly that the atom has three (3) shells.
Valence electron(s) are located at the outer most shell of an atom.
The outer most shell of the atom above is 3s and 3p.
Therefore, 3s and 3p will contain the valence electron(s)
How many moles of RbNO2 are present in a sample with 3.4 x 1024 particles?
Answer:
5.6 mol
Explanation:
n = N/NA
n: number of moles
N: number of particles
NA: Avogadro's constant
n = 3.4×10²⁴/6.02×10²³ mol^-1 = 5.6 mol
determine the mass fraction of iron in its compounds:
Please!
Answer:
Fe(NO₃)₃ = 0.23; FeCl₃ = 0.34
Explanation:
Mass fraction is defined as the ratio between the mass of iron in 1 mol of the compound and the mass of the complete compound.
In Fe(NO₃)₃ there is just 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 241.86g/mol. Thus, mass fraction is:
55.845g/mol / 241.86g/mol =
Fe(NO₃)₃ = 0.23In FeCl₃ there is 1 atom of Fe that has a molar mass of 55.845g/mol. The molar mass of this compound is 162.2g/mol. Thus, mass fraction is:
55.845g/mol / 162.2g/mol =
FeCl₃ = 0.34Calculate the total energy (in kJ) absorbed when 50.5 g of ice at -15.0°C is converted into liquid water at 65.0 °C.
Answer:
The total energy absorbed is 32.171 kilojoules.
Explanation:
The total energy absorbed by the ice is the sum of the sensible heat of ice and water and the latent heat of fusion of the water, that is:
[tex]Q = m\cdot [c_{i}\cdot (T_{2}-T_{1})+L_{f} + c_{w}\cdot (T_{3}-T_{2})][/tex] (1)
Where:
[tex]m[/tex] - Mass of the ice, in kilograms.
[tex]c_{i}[/tex] - Specific heat of ice, in kilojoules per kilogram-degree Celsius.
[tex]c_{w}[/tex] - Specific heat of water, in kilojoules per kilogram-degree Celsius.
[tex]L_{f}[/tex] - Latent heat of fusion, in kilojoules per degree Celsius.
[tex]T_{1}[/tex] - Initial temperature of water, in degrees Celsius.
[tex]T_{2}[/tex] - Fusion point of water, in degrees Celsius.
[tex]T_{3}[/tex] - Final temperature of water, in degree Celsius.
[tex]Q[/tex] - Total energy absorbed, in kilojoules.
If we know that [tex]m = 50.5\times 10^{-3}\,kg[/tex], [tex]c_{i} = 2.090 \,\frac{kJ}{kg\cdot^{\circ}C}[/tex], [tex]c_{w} = 4.180\,\frac{J}{kg\cdot ^{\circ}C}[/tex], [tex]L_{f} = 334\,\frac{kJ}{kg}[/tex], [tex]T_{1} = -15\,^{\circ}C[/tex], [tex]T_{2} = 0\,^{\circ}C[/tex] and [tex]T_{3} = 65\,^{\circ}C[/tex], then the total energy absorbed is:
[tex]Q= (50.5\times 10^{-3}\,kg)\cdot \left[\left(2.090\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (15\,^{\circ}C) + 334\,\frac{kJ}{kg}+ \left(4.180\,\frac{kJ}{kg\cdot ^{\circ}C} \right)\cdot (65\,^{\circ}C)\right][/tex][tex]Q = 32.171\,kJ[/tex]
The total energy absorbed is 32.171 kilojoules.
True or False
Low temperatures lead to faster dissolution rates compared to high temperatures
Answer:
false
Explanation:
this is because , high temperature speeds up the the random motion of particles which leads to high dissolution
Select three forms of non-renewable energy.
Biomass
Peat
Nuclear
Gas
Answer: Biomass, Nuclear and Gas are the three forms of non- renewable energy.
Explanation:
orbital hauny dump bell shape is...
a Sorbital il p-orbital 1 ild-orbital pulf orbital
Answer: the orbital with a hauny dump bell shape is the p- orbital.
Explanation:
An orbital can be defined as part of the nucleus of an atom that consists of an electron of maximum given energy. The shape of this part gives the shape of the orbitals. There are different types of orbitals which include:
--> s-orbitals: This is the type of orbital in which the probability of finding electron is the same in all directions usually at a given distance form the nucleus. Therefore the s-orbitals are SPHERICAL in shape about the nucleus and are non- directional.
--> d-orbitals: This is said to have a clover shape. This is because the electron is pushed out four times during the rotation when an opposite spin proton aligns gluons with three spin-aligned protons.
--> p-orbitals: This is said to have a DUMP-BELL shape. This is because there are three similar p-orbitals which are arranged mutually at right angles to each other along x,y, and z axes. All the three p-orbitals are of the same energy level.
Evaluate each of the statements below. Select those that accurately describe the role of genes and chromosomes in
the process of inheriting a specific trait. Choose ALL that apply.
-0)
A)
Chromosomes are made of DNA.
B)
There are 26 pairs of chromosomes in humans.
C)
Alleles are the different forms of a gene that can exist.
D)
Chromosomes contain genes that control the inheritance of traits.
E)
Genes are made of chromosomes and contain all of the genetic information
for an organism.
Answer:
HEY CAN YOU POST YOUR LAST QUESTION AGAIN? CAUSE I HAVE THE ANSWER
Using what you know about the structures of the amino acid side chains and the mechanisms presented in this chapter, which of the following amino acid side chain may play the following roles in an enzymatic mechanism: a. participate in proton transfer, b. act as a nucleophile
Answer:
a. participate in proton transfer - His
b. acts as a nucleophile - Ser
Explanation:
Enzymes are regulated because they are proteins. They are categorize based on how they catalyze. Heat weakens and inactivates the enzymes because of non covalent interaction. His amino acid participate in proton transfer because it is able to act as an acid as well as a base while Ser amino acid can act as nucleophile.
1. (8pt) Using dimensional analysis convert 600.0 calories into kilojoules
2. (8pts) how much heat and kilojoules is needed to raise the temperature of 236 g of silver from 8.5°C to 34.9°C? (Cag = 0.24 J/g°C)
Answer:
1. 2.510kJ
2. Q = 1.5 kJ
Explanation:
Hello there!
In this case, according to the given information for this calorimetry problem, we can proceed as follows:
1. Here, we consider the following equivalence statement for converting from calories to joules and from joules to kilojoules:
[tex]1cal=4.184J\\\\1kJ=1000J[/tex]
Then, we perform the conversion as follows:
[tex]600.0cal*\frac{4.184J}{1cal}*\frac{1kJ}{1000J}=2.510kJ[/tex]
2. Here, we use the general heat equation:
[tex]Q=mC(T_2-T_1)[/tex]
And we plug in the given mass, specific heat and initial and final temperature to obtain:
[tex]Q=236g*0.24\frac{J}{g\°C} (34.9\°C-8.5\°C)\\\\Q=1495.3J*\frac{1kJ}{1000J} \\\\Q=1.5kJ[/tex]
Regards!
Which of the following statements describes a double displacement reactions?
Answer:
D
Explanation:
hope this helped and sorry if it didn't but I wish you luck:D
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to its final temperature is 200 J/K. What is the final temperature of the gas
Answer:
668.9K is the final temperature
Explanation:
The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:
ΔS = n*Cv*ln (T2/T1)
Where ΔS is change in entropy = 200J/K
n are moles = 20.0mol
Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)
T2 is final Temperature and T1 initial temperature = 300K
Replacing:
ΔS = n*Cv*ln (T2/T1)
200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)
0.80186 = ln (T2/300K)
2.23 = T2 / 300K
668.9K is the final temperatureAir movement and weather conditions are influenced by
A The Moon
B. Altitude
C. Thermal Energy
Answer:
The moon
Explanation:
The answer is A; Sorry i put the wrong answer by accident. I was trying to get to another question.
Give the answer below brainliest!!!
A. The moon influences the air movement
A gas system has volume, moles and temperature of 1.52 L, 0.52 moles and 203K, respectively. What is the pressure in atm?
Answer:
P = 5.70 atm
Explanation:
Use PV = nRT
In this case, R = 0.0821 L·atm/mol·K (because we are finding the pressure in atm)P(1.52 L) = (0.52 moles)(0.0821)(203 K)
P = 5.701628947 atm
What are anti-oxidants? Why are they added to fat and oil containing food?
Answer:
A substance that protects cells from the damage caused by free radicals (unstable molecules made by the process of oxidation during normal metabolism). Free radicals may play a part in cancer, heart disease, stroke, and other diseases of aging.
Write an equation for sodium chloride and sodium oxide
Answer:
Explanation:
The Chemical Equation for each one of these compounds would be the following
Sodium Chloride: NaCl
This compound contains 1 Sodium atom and 1 Chlorine atom
Sodium Oxide: Na₂O
This compound contains 2 Sodium atoms and 1 Oxygen atom.
To prepare 250mL of calcium chloride solution with a molar concentration of 1.20mol/L, what mass of calcium chloride would be required?
Answer:
33.30 grams of CaCl2 will be required
Explanation:
Given,
Volume of solution, V= 250 ml
Molarity of solution, M= 1.20 mol/L
Molecular mass of CaCL2, S= 40+(35.5 X 2)= 111
We know,
Required mass, W= SVM/1000
Now,
W = (111 X 250 X 1.20)/1000
= 33300/1000
= 33.30
Therefore, 33.30 grams of Calcium Chloride will be required.
How many L of 3.0 M H2SO4 solution can be prepared by using 100.0 mL OF 18 M H2SO4?
Answer:
[tex]V_2=600mL[/tex]
Explanation:
Hello there!
In this case, according to this dilution process, it is possible for us to solve this problem via the following equation:
[tex]V_2M_2=V_1M_1[/tex]
Thus, since we were given the initial and final concentrations but just the initial volume, we calculate the final one as shown below:
[tex]V_2=\frac{V_1M_1}{M_2}\\\\ V_2=\frac{100.0mL*18M}{3.0M}\\\\V_2=600mL[/tex]
Regards!
If g of chlorine gas occupies a volume of mL at a particular temperature and pressure, what volume will g of chlorine gas occupy under the same conditions
The complete question is as follows: If 1.04 g of chlorine gas occupies a volume of 872 mL at a particular temperature and pressure, what volume will 2.08 g of chlorine gas occupy under the same conditions ?
Answer: A volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
Explanation:
Given: [tex]Mass_1[/tex] = 1.04 g, [tex]V_{1}[/tex] = 872 mL
[tex]Mass_2[/tex] = 2.08 g, [tex]V_{2}[/tex] = ?
As molar mass of chlorine is 35.5 g/mol.
Number of moles is the mass of a substance divided by its molar mass.
Hence, moles of chlorine present in 1.04 g chlorine gas is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{1.04 g}{35.5 g/mol}\\= 0.029 mol[/tex]
Also, moles of chlorine present in 2.08 g chlorine gas is calculated as follows.
[tex]Moles = \frac{2.08 g}{35.5 g/mol}\\= 0.058 mol[/tex]
Formula used to calculate the volume occupied by 2.08 g of chlorine gas is as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}[/tex]
Substitute the values into above formula as follows.
[tex]\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\\\frac{872 L}{0.029 mol} = \frac{V_{2}}{0.058 mol}\\V_{2} = 1744 L[/tex]
Thus, we can conclude that a volume of 1744 L will 2.08 g of chlorine gas occupy under the same conditions.
It is well-known that carbon dioxide, CO2, has a much greater density than air. In fact,
CO2 gas can displace air, which is why there are regulations in place that limit the
amount of dry ice allowed in elevators. In other words, do not get trapped in an
elevator, or any enclosed space, with someone who is transporting dry ice. Calculate
the pressure exerted by the CO2 gas, in atm, if the density was measured to be 1.983
g/L on a day where the temperature is 22.165 °C.
Answer: The pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092
Explanation:
According to the ideal gas equation:'
[tex]PV=nRT[/tex]
P = Pressure of the gas = ?
V= Volume of the gas
T= Temperature of the gas = [tex]22.165^0C=(273+22.165)K=295.165K[/tex] (0°C = 273 K)
n= moles of gas = [tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]
R= Value of gas constant = 0.0821 Latm/K mol
[tex]P=\frac{mRT}{MV}[/tex] as [tex]Density=\frac{mass}{Volume}[/tex]
[tex]P=\frac{dRT}{M}[/tex] where d is density
[tex]P=\frac{1.983g/L\times 0.0821Latm/Kmol\times 295.165K}{44g/mol}=1.092atm[/tex]
Thus pressure exerted by the [tex]CO_2[/tex] gas, in atm is 1.092
The steps of preparing 2M solution of NaOH
Answer:
And 500 mL of 2M NaOH solution contains 80.02g NaOH=40.0 g of NaOH .
Explanation:
So, If we mix 40.0 g of NaOH with enough distilled water to make 500 mL, we will get a 2.00 M NaOH solution.
I hope this answers help you! :>help please
A gas in a sealed container has a pressure of 125 kPa at a temperature of 303K. If the temperature in the container is increased to 487K, what is the new pressure?
A 201kpa
B 200kpa
C 400kpa
D 78kpa
Answer:
A. 201 kPa
Explanation:
We can solve this problem by using Boyle's law, which states:
P₁T₂ = P₂T₁Where subscript 1 stands for the initial Pressure and Temperature, while 2 stands for the final conditions. That means that in this case:
P₁ = 125 kPaT₂ = 487 KP₂ = ?T₁ = 303 KWe input the data:
125 kPa * 487 K = P₂ * 303 KAnd solve for P₂:
P₂ = 201 kPa