Is the bond length in HCl the same as that in DCl? The wavenumbers of the J = 0  1 rotational transitions for H35Cl and 2H35Cl are 20.8784 and 10.7840 cm–1, respectively. Accurate atomic masses are H = 1.007825 amu, 2H = 2.0140 amu, and 35Cl = 34.96885 amu. Based on this information alone, can you conclude that the bond lengths are the same or different in the two molecules?

Answer:

laboratory use the organic substances dissolve in water methanol or ethanol then Sinha to rise iron chloride solution is added a transient permanent coloration usually purple green or blue indicate the presence of a funnel or an hall

Balanced equation for Fe reacting with [tex]Cl_2[/tex]

[tex]2Fe + 3Cl_2[/tex] → [tex]2FeCl_3[/tex]

Iron filings are small shavings of ferromagnetic material.

When hydrochloric acid (HCl) reacts with iron filings (Fe) a dissolving metal reaction occurs with the Fe being converted to iron chloride ([tex]FeCl_2[/tex]) and hydrogen ([tex]H_2[/tex]).

The balanced equation is:

[tex]Fe + 2HCl[/tex] → [tex]FeCl_2 + H_2[/tex]

Note that reaction only produces [tex]FeCl_2[/tex] and not [tex]FeCl_3[/tex]. To make [tex]FeCl_3[/tex] you have to get more forcing and react Fe with chlorine gas ([tex]Cl_2[/tex]) at elevated temperature.

Since we are balancing equations here, below is the balanced equation for Fe reacting with [tex]Cl_2[/tex] (offered at no extra charge):

[tex]2Fe + 3Cl_2[/tex] → [tex]2FeCl_3[/tex]

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Answer:

[tex]\boxed {\boxed {\sf 155 \ g\ CO}}[/tex]

Explanation:

To convert from moles to mass, the molar mass must be used.

First, write the chemical formula for carbon monoxide. Since the carbon (C) comes first without a prefix, there is 1 carbon atom. The prefix mono- before oxide means 1, so there is also 1 oxygen (O) atom. The formula is CO.

Next, look up their molar masses on the Periodic Table.

Since there is 1 atom of each, the molar masses can be added.

Use this molar mass as a ratio.

[tex]\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]

Multiply by the given number of moles:5.55

[tex]5.55 \ mol \ CO *\frac {28.01 \ g \ CO} {1 \ mol \ CO}[/tex]

The moles of carbon monoxide cancel.

[tex]5.55 * \frac {28.01 \ g \ CO} {1 }[/tex]

Multiply.

[tex]155.4555 \ g \ CO[/tex]

The original measurement of moles has 3 significant figures, so our answer must have the same. For the number we calculated, it is the ones place. The 4 in the tenths place tells us to leave the 5.

[tex]155 \ g\ CO[/tex]

5.55 moles of carbon monoxide is about 155 grams.

Answer:

fire > rocks > air

Answer:

The gravitational potential energy and kinetic energy of this ball should be equal (assuming that there is no energy loss due to friction.)

Explanation:

The ball loses gravitational potential energy as it rolls down the hill. At the same time, the speed of the ball increases, such that the ball gains kinetic energy.

If there is no friction on this ball (and that the ball did not deshape,) all the gravitational potential energy that this ball lost would be converted to kinetic energy.

If the gravitational field strength [tex]g[/tex] is constant throughout, the gravitational potential energy of an object in that gravitational field would be proportional to its height.

If [tex]m[/tex] denote the mass of this ball, the gravitational potential energy ([tex]\rm GPE[/tex]) of this ball at height [tex]h[/tex] would be [tex]{\rm GPE} = (m \cdot g) \cdot h[/tex], which is proportional to [tex]h\![/tex].

The value of [tex]g[/tex] near the surface of the earth is indeed approximately constant (typically [tex]g \approx 9.8\; \rm m \cdot s^{-2}[/tex].)

At halfway between the top and bottom of this hill, the height of this ball would be [tex](1/2)[/tex] of its initial value (the value when the ball was at the top of the hill.) Because the [tex]\rm GPE[/tex] of this ball is proportional to its height, at halfway down the hill, the [tex]\rm GPE\![/tex] of this ball would also be [tex](1/2)\![/tex] its initial value.

However, if there was no friction on this ball (and that the ball did not deshape,) that [tex](1/2)[/tex] of the initial [tex]\rm GPE\![/tex] of this ball was not lost. Rather, these [tex](1/2)\![/tex] of the initial [tex]\rm GPE[/tex] would have been converted to the kinetic energy ([tex]\rm KE[/tex]) of this ball.

Hence, when the ball is halfway down the hill:

[tex]\displaystyle \text{GPE halfway down the hill} = \frac{1}{2}\, \text{Initial GPE}[/tex].

[tex]\begin{aligned}& \text{KE halfway down the hill}\\ &= \text{Initial GPE} - \text{GPE halfway down the hill}\\ &= \text{Initial GPE} - \frac{1}{2}\, \text{initial GPE}\\ &= \frac{1}{2}\, \text{Initial GPE}\end{aligned}[/tex].

Therefore:

[tex]\begin{aligned}& \text{GPE halfway down the hill} \\ &= \frac{1}{2}\, \text{Initial GPE} \\ &= \text{KE halfway down the hill}\end{aligned}[/tex].

In other words, under these assumptions, when this ball is halfway down the hill, the gravitational potential energy and the kinetic energy of this ball would be equal.

Answer:

%Cu = 66.4%

%S = 33.6%

Explanation:

Step 1: Given data

Step 2: Calculate the mass of S

The mass of CuS is equal to the sum of the masses of Cu and S.

mCuS = mCu + mS

mS = mCuS - mCu

mS = 9.56 g - 6.35 g = 3.21 g

Step 3: Calculate the percent by mass of each element

We will use the following expression.

%Element = mElement / mCompound × 100%

%Cu = mCu / mCuS × 100% = 6.35 g / 9.56 g × 100% = 66.4%

%S = mS / mCuS × 100% = 3.21 g / 9.56 g × 100% = 33.6%

Answer:

The lithosphere solid part of the earth's crust

Answer:

ANSWER is E

Explanation:

2H₃PO₄ + 3Ca(OH)₂→ 6H₂O + Ca₃(PO₄)₂

Answer:

First step is to find what the products would be. Since this seems to be a double displacement, you get: H3PO4(aq)+Ca(OH)2(aq)→ H2O(L)+Ca3(PO4)2(s)

You know the products because H has a charge of +1, so PO4 must have a charge of -3, and since OH has a charge of -1, Ca must be +2. Then make each compound have a net charge of 0. H20 is a liquid since aq solutions have liquid water. Ca3(PO4)2 is a solid, use the solubility rules.

Lastly, balance the equation: 2H3PO4(aq)+3Ca(OH)2(aq)→ 6H2O(L)+Ca3(PO4)2(s)

So the salt formed is Ca3(PO4)2

Answer: true

Explanation:

Answer:

because they contains clues about what the earth was like in the past. different rocks from under only certain conditions and even the dullest gray lump of rock.

Answer:

the second one

Explanation:

metal doesn't act like a magnet because the domains don't have a preferred direction of alignment. Magnets are all aligned in a specific direction.

Answer:

just downloud smart

Explanation:

thank me later

Sulfate - SO4^-2

Sulfite - SO3^-2

Hydrogen Sulfate - HSO4-

Answer:

1.25 grams of chlorine.

Explanation:

Hello there!

In this case, since it is possible to define the parts per million of chlorine as the milligrams of chlorine per liters of water, in order to obtain the mass of chlorine in 2500 L, we proceed as follows:

[tex]ppm=\frac{mg}{L}\\\\mg=ppm*L[/tex]

In such a way, we plug in the given 0.500 ppm and 2500 L to obtain (in grams):

[tex]mg=0.500mg/L*2500L\\\\g=1250mg*\frac{1g}{1000mg}\\\\ g=1.25g[/tex]

Best regards!

Answer:

[tex]V_2=2.5m^3[/tex]

Explanation:

Hello!

In this case, according to the Charles' law as a directly proportional relationship between volume and temperature:

[tex]\frac{V_2}{T_2}=\frac{V_1}{T_1}[/tex]

Thus, in order to compute the final volume, V2, we obtain the following expression:

[tex]V_2=\frac{V_1T_2}{T_1}\\\\V_2=\frac{5m^3*300K}{600K}\\\\V_2=2.5m^3[/tex]

Best regards!

Answer:

49.1 g

Explanation:

First we convert 9.67x10²³ atoms of oxygen into moles, using Avogadro's number:

Then we calculate how many P₃O₉ moles there would be with 1.60 O moles:

Finally we convert 0.18 P₃O₉ moles into grams, using its molar mass:

Answer:

Has definite shape and volume

Solids have high melting point

Explanation:

The caliper is a component which is used by a disc brake system for performing its function.

The disc braking system consist of components such as disc/rotor, a brake calliper and brake pads. When the brake pedal is pushed, brake fluid creates pressure that produces friction.

So we can conclude that the caliper is a component which is used by a disc brake system for performing its function.

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Answer:

FALSE!

Explanation:

Gymnosperms do use seeds but are exposed like the pine cones of pines. Angiosperms still have seeds, however, they flower or fruit.

Answer:

False

Explanation:

Answer:

carbon

Explanation:

The properties of carbon forms the basis for all life. Explanation: The atoms of carbon are found in the molecules of all living species.

Answer:

I guess this answer is c

yh

Answer:

b. (Actual yield ÷ theoretical yield) x 100

Explanation:

The percent yield will be a ratio of collected or actual yield to the theoretical yield. Like any percentage, you are determining a part of a whole. You multiply by 100 to convert your decimal answer from the division into a percentage.

Answer:

Increased evaporationof water vapour from sea or land will increase rainfall

Answer:

Explanation:

increased evaporation of water vapor from sea to land will increase rainfall

Answer:

6 volts

Explanation:

Use Ohm's Law:

V = IR

V = (2 amps)(3 ohms) = 6 volts

Answer:

420.7 degrees C

Explanation:

Use the formula V1/T1 = V2/T2 (Charles' Law) to find T2. Make sure to convert  your temperatures to Kelvin by adding 273 to the Celsius temperature.

V1 = 4.50 L

V2 = 10 L

T1 = 39.2 C = 312.2 K

Solve V1/T1 = V2/T2 for T2 and you get T2 = V2T1/V1

T2 = (10 L)(312.2 K) / (4.50 L) = 693.8 K

You can subtract 273 to get the temperature back to Celsius.

T2 = 693.8 - 273 = 420.7 degrees C

Answer:

19.5

Explanation: using dalton law pt=p1+p2+p3...

the total pressure is 37.9 so to get pressure of gas b subtract pressure of gas a from total pressure.37.9-18.4 gas b equals 19.5