Instructions: Find the missing length indicated.
I NEED HELP, NO LINKS PLEASE
can you explain please

Answer:

x = 292.2 pounds (£)

Step-by-step explanation:

Write and solve an equation of ratios:

 € 1        £0.72

--------- = ----------

€410         x

Cross-multiplying, we get:

x = 292.2 pounds (£)

Answer: 38.5%

Step-by-step explanation:

it decreased by 38.5%

formula for it is (value 2 - value 1)/value 1 * 100 = so (800-1300)/1300*100 = -500/1300*100 = -0.384615 * 100 = -38.4615 = -38.5 (round off) = 38.5 decrease

Answer: 106 km/h,2.5 hr

Step-by-step explanation:

Given

The train travels 315 km in the same time car travels 265 km

The average speed of the train is 20 kmph faster than car

Suppose, speed of the car is v and it travels 265 km in t hours

[tex]\therefore \dfrac{315}{v+20}=\dfrac{265}{v}\\\\\Rightarrow 315v=265\left (v+20\right)\\\\\Rightarrow 315v=265v+5300\\\Rightarrow 50v=5300\\\Rightarrow v=106\ km/h[/tex]

Time taken to travel is

[tex]\Rightarrow t=\dfrac{265}{106}}\\\\\Rightarrow t=2.5\ h[/tex]

Answer:

(--2, 6)

Step-by-step explanation:

Plugging -2 into the equation, you get -2(-2)^2-4(-2)-10 which is 6. This makes the coordinate (-2,6)

Answer:

300

Step-by-step explanation:

Answer:

V≈9424.78in³

Step-by-step explanation:

Solution

V=πr2h=π·102·30≈9424.77796in³

Answer:

84in^2

Step-by-step explanation:

area = l*w

12*7=84

Answer:

The temperature was -8.5

Step-by-step explanation:

Subtraction

Answer:

the term arc is used for a portion of a circle along its circumference. The size of the arc is usually given by the size of the angle subtended by the arc at the center or the length of the arc. The angle subtended at the center is also known as the angle measure of an arc or informally the arc measure.

Step-by-step explanation:

Answer:

A) 64°

Step-by-step explanation:

By intersecting secants theorem:

[tex] m\angle ACB = \frac{1}{2} (m\widehat {AS} - m\widehat {BD}) [/tex]

[tex] 35\degree = \frac{1}{2} (134\degree - m\widehat {BD}) [/tex]

[tex] 70\degree =134\degree - m\widehat {BD} [/tex]

[tex] m\widehat {BD} =134\degree - 70\degree[/tex]

[tex] m\widehat {BD} =64\degree[/tex]

Answer:

11

Step-by-step explanation:

All you have to do is plug in a. In this case, a=3.

21/a+4

21/(3)+4

21/3+4

7+4

11

If this helps please mark as brainliest

Answer:

11

Step-by-step explanation:

Follow the order of operations, PEMDAS.

First, divide, then add. Plug in 3 for a in the given expression:

21/(3) + 4

Divide, then add:

(21/3) + 4

7 + 4 = 11

11 is your answer.

~

Answer:

34 pounds

Step-by-step explanation:

51 pounds of plum = 27 quarts

x pounds of plum   = 18 quarts

(cross multiply)

27x = 918

divide both sides by 27

x=34 pounds

Answer:

8x+14

Step-by-step explanation:

Answer:

c = 110-degrees

b = 70-degrees

Step-by-step explanation:

for c:

linear pair which means it equals 180-degrees

70 + c = 180 *subtract 70 from both sides*

c = 110

for b:

vertical angles are equal

b = 70-degrees

Answer:

d=90°

e=81°

f=99°

Step-by-step explanation:

To find f

180-81

=99

Answer:

d = 90°

e = 81°

f = 99°

Step-by-step explanation:

Have a nice day!

Answer:

(y-5)^2=14(x+7/2)

Step-by-step explanation:

The equation for a parabola with a focus at (0,5) and a directrix at x = -7 is (y - 5)² = 14 (x + 3.5).

A parabola is a two dimensional figure on a plane which is U shaped and any point on the parabola is at an equal distance from a fixed point called focus and a fixed line called directrix.

Given,

Focus of the parabola at (0, 5).

Directrix is x = -7.

The parabola is horizontal parabola since the directrix is a vertical line.

Equation of the parabola is of the form,

(y - k)² = 4p (x - h)

Here (h, k) is the vertex.

Vertex of the parabola is the mid point of focus (0, 5) and the point (-7, 5).

(h, k) = ([tex]\frac{0 + -7}{2}[/tex], 5) = (-7/2, 5)

Now, p is the distance from vertex to focus.

p = 0 - -7/2 = 7/2 = 3.5

So the equation is,

(y - 5)² = 4× 3.5 (x - -3.5)

(y - 5)² = 14 (x + 3.5)

Hence the equation is (y - 5)² = 14 (x + 3.5).

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Answer:

it's 10 cemetery in a two way too far and far from a lot for

The volume of irregular solid is 45239 mm^3

Given
 for cylinder,
radius = 6mm and length = 400 mm

Volume, is defined as the ratio of the mass of object to its density.

since if the cylinder is melted to sphere the volume remains the constant
so.
volume of an irregular solid = volume of cylinder
= πr^2l
= 3.14 x 6^2 x 400
= 45239 mm^3

Thus, the required volume of of irregular solid is 45239 mm^3

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Answer:

I don't understand your language

Step-by-step explanation:

Step-by-step explanation:

18 and 5 are both missing if that's what you mean

Answer:

D. 360

Step-by-step explanation: It's being multiplied by plus one more every time you move on to a new term.

So 2*3=6, 6*3=18, 18*4=72, 72*5=360

Answer:

68, 97, 81, 96, 84.2

Step-by-step explanation:

16. The minimum of the data is the smallest value. Take the smallest stem value and find its smallest leaf value, you'll get 68.

17. Take the largest stem value and find its largest leaf value. That's 97.

18. Counting the number of values, there are 10 values here. So you need to look at the mean of the 5th and 6th values. (80 + 82) ÷ 2 = 81

19. Mode: the most frequently occurring value. All values in this dataset are unique except for the two 96s in the last row, hence 96 is the mode.

20. Add all values and divide your result by the number of values.

(68+75+77+79+80+82+92+96+96+97) ÷ 10 = 84.2

Hence 84.2 is your mean.

71

Step-by-step explanation:

that it is not 0 because i am a teacher mrs.brainly so there is the thing

Answer:

120

Step-by-step explanation:

Answer:

1. 170.083 in³

2. 126π in³

3. 92.106 m³

4. 2412.74 in³

5. 612π m³ and 1922 m³

Step-by-step explanation:

1.

Cylinder:

[tex]V = \pi r^{2}h[/tex]               *Plug in numbers*

[tex](3.14)(2.5)^{2}(7)[/tex]         *Square 2.5*

[tex](3.14)(6.25)(7)[/tex]        *Solve*

≈ [tex]137.375in^{3}[/tex]

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(2.5)^{3}[/tex]         *Cube 2.5*

[tex]\frac{\frac{4}{3}(3.14)(15.625)}{2}[/tex]         *Divide by 2 and Solve*

≈ [tex]32.7083 in^{3}[/tex]

Add both volumes

[tex]137.375 + 32.7083[/tex] ≈ [tex]170.083in^{3}[/tex]

2.

Cylinder:

[tex]V = \pi r^{2}h[/tex]         *Plug in numbers*

[tex]\pi (3)^{2}(10)[/tex]            *Square 3*

[tex]\pi (9)(10)[/tex]             *Multiply*

[tex]90\pi[/tex]

Sphere:

[tex]V = \frac{4}{3}[/tex] π [tex]r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (3)^{3}[/tex]                   *Cube 3*

[tex]\frac{4}{3} \pi (27)[/tex]                   *Multiply*

[tex]36\pi[/tex]

Add both Volumes to get total

[tex]90\pi + 36\pi = 126in^{3}[/tex]

3.

Sphere:

[tex]V = \frac{4}{3}\pi r^{3}[/tex]              *Plug in numbers*

[tex]\frac{4}{3} (3.14)(3)^{3}[/tex]            *Cube 3*

[tex]\frac{4}{3} (3.14)(27)[/tex]            *Multiply*

[tex]113.04m^{3}[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]             *Plug in numbers*

[tex]\frac{(3.14)(2)^{2}(5)}{3}[/tex]           *Square 2*

[tex]\frac{(3.14)(4)(5)}{3}[/tex]             *Solve*

[tex]20.93m^{3}[/tex]

Subtract the volumes to get the volume of the blue area

[tex]113.04 - 20.93 = 92.106m^{3}[/tex]

4.

Sphere:

[tex]V = \frac{4}{3} \pi r^{3}[/tex]            *Plug in numbers*

[tex]\frac{4}{3}\pi (8)^{3}[/tex]                 *Cube 8*

[tex]\\\frac{4}{3}\pi (512)[/tex]               *Multiply*

[tex]\\\\\pi (682.6)[/tex]              *Solve*

[tex]2133.66in^{3}[/tex]           *Divide by 2 since it's a hemisphere*

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (8)^{2}(20)}{3}[/tex]              *Square 8*

[tex]\frac{\pi (64)(20)}{3}[/tex]              *Multiply and Divide*

[tex]1340.41 in^{3}[/tex]

Add both volumes

[tex]1072.33 + 1340.41 = 2412.74in^{3}[/tex]

5.

Cylinder:

[tex]V = \pi r^{2}h[/tex]            *Plug in numbers*

[tex]\pi (6)^{2}(16)[/tex]              *Square 6*

[tex]\pi (36)(16)[/tex]             *Multiply*

[tex]576\pi[/tex]

Cone:

[tex]V = \frac{\pi r^{2}h}{3}[/tex]            *Plug in numbers*

[tex]\frac{\pi (6)^{2}3}{3}[/tex]                  *Square 6*

[tex]36\pi[/tex]

Add both volumes

[tex]576\pi + 36\pi = 612\pi m^{3}[/tex]

Alternative: *Multiply π*

[tex]1922m^{3}[/tex]

Answer:

1) 175 [tex]in^2[/tex]

2) 1st option

3) 92 [tex]m^2[/tex]

4) 2412 [tex]in^3\\[/tex]

5) 2nd option

Step-by-step explanation:

[tex]1)\ A = D * Pi = 5 * 3.14 = 15.7\\[/tex]

[tex]2)\ V_{1} = 15.7 * 7 = 109.9[/tex]

[tex]3)\ V_{2} = 4Pi*\frac{R^3}{3} = 12.56*\frac{15.625}{3} = 65.41(6)[/tex]

[tex]4)\ V_1 + V_2 = 65.4 + 109.9 = 175.3[/tex] which is close to 175

[tex]1)\ A = Pi * R^2 = 3.14 * (\frac{6}{2})^2 = 3.14 * 3^2 = 28.26\\[/tex]

[tex]2)\ V_1 = A * h = 28.26 * 10 = 282.6[/tex]

[tex]3)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * (\frac{6}{2})^3 = 113.04[/tex]

[tex]4)\ V_1 + V_2 = 282.6 + 113 = 395.6[/tex] which is very close to 396

[tex]5)\ 396 = 126 * pi[/tex]

[tex]1) V_1 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 2^2 * 5 = 20.9(3)[/tex] =

[tex]2)\ V_2 = \frac{4}{3} * Pi * R^3 = \frac{4}{3} * 3.14 * 3^3 = 113.04\\[/tex]

[tex]3)\ V_2 - V_1 = 113.04 - 20.93 = 92.14[/tex] which is very close to 92

[tex]1)\ V_1 = \frac{\frac{4}{3} * Pi * R^3}{2} = \frac{\frac{4}{3} * 3.14 * 512}{2} = 1,071.786\\[/tex]

[tex]2)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * 3.14 * 64 * 20 = 1,339.733[/tex]

[tex]3)\ V_1 + V_2 = 1072 + 1340 = 2,411 = 2412[/tex]

[tex]1)\ A = Pi * R^2 = 36*Pi\\[/tex]

[tex]2)\ V_1 = 36*Pi * 16 = 576 * Pi\\[/tex]

[tex]3)\ V_2 = \frac{1}{3} * Pi * R^2 * h = \frac{1}{3} * Pi * 36 * 3 = 36 * Pi[/tex]

[tex]4) V_1 + V_2 = 576Pi + 36Pi = 612Pi[/tex]

Answer:

2 hours!

Step-by-step explanation:

Answer:

4.) -1 2/3

Step-by-step explanation:

it means -1.66666666

Answer:

The TV is 64.3 in. wide.

Step-by-step explanation:

a  

2

+(63)  

2

=

\,\,90^{2}

90  

2

Use the Pythagorean Theorem.

a^{2}+3969=

a  

2

+3969=

\,\,8100

8100

Simplify.

-3969\phantom{=}

−3969=

\,\,-3969

−3969

Subtract 3969 from both sides.

a^{2}=

a  

2

=

\,\,4131

4131

\sqrt{a^{2}}=

a  

2

​  

=

\,\,\pm\sqrt{4131}

±  

4131

​  

Square root both sides.

a=

a=

\,\,64.272855...

64.272855...

Simplify. Ignore negative root, as length must be positive.

a\approx

a≈

\,\,64.3

64.3

Round to the nearest tenth.

The rectangle TV's width is determined by the formula W = 64.3 inches.

The formula determines a rectangle's diagonal.

From the Pythagoras Theorem , The hypotenuse² = base² + height² , and

Diagonal of a Rectangle = √ ( Length )² + ( Width )²

Given data ,

Let D represent the diagonal of the rectangular TV.

D is now equal to 90 inches.

Let the TV's rectangle size be 63 inches.

Let W be the TV's rectangular width.

And , Diagonal of a Rectangle = √ ( Length )² + ( Width )²

D² = L² + W²

90² = 63² + W²

Subtracting 63² on both sides of the equation , we get

W² = 90² - 63²

On simplifying the equation , we get

W² = 4131

Taking square roots , we get

W = √4131 inches

W = 64.3 inches

Thus , W is equal to 64.3 inches.

Hence, the rectangular TV is 64.3 inches wide.

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Answer:

hope this helps

Step-by-step explanation:

Strawberry = 14

blueberry = 14

cherry = 7

chocolate = 7

apple = 14