Incorrect Question 44 A patient is exhibiting elevated heart rate and blood pressure. The doctor prescribes the patient a beta-blocker medication. Identify the correct statement. The beta-blocker bind

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Answer 1

Beta-blockers bind to beta-adrenergic receptors and help reduce elevated heart rate and blood pressure.

Beta-blockers are a class of medications that work by binding to beta-adrenergic receptors in the body. These receptors are located in various tissues, including the heart and blood vessels. By binding to these receptors, beta-blockers block the effects of epinephrine (adrenaline) and other stress hormones. This leads to a reduction in heart rate and the force of contraction of the heart, as well as a decrease in the constriction of blood vessels.

In the case of a patient exhibiting elevated heart rate and blood pressure, the doctor prescribes a beta-blocker medication to help normalize these physiological parameters. By binding to beta-adrenergic receptors, the beta-blocker medication reduces the responsiveness of the heart to stress hormones. This results in a decrease in heart rate, which helps to lower blood pressure. Additionally, beta-blockers can also relax the blood vessels, further contributing to the reduction in blood pressure.

It is important to note that beta-blockers are commonly used in the treatment of various cardiovascular conditions, such as hypertension (high blood pressure), angina (chest pain), and certain arrhythmias (abnormal heart rhythms). They are prescribed based on individual patient characteristics and may have other effects and considerations that need to be taken into account. Therefore, it is essential for patients to follow the prescribed dosage and consult with their doctor for any specific concerns or questions related to beta-blocker medications.

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Related Questions

Which of the following statements about the sodium potassium pump is correct? a. The sodium-potassium pump is a symporter that results in a net negative charge outside the cell. b. The sodium-potassium pump uses an existing proton gradient to drive the movement of sodium and potassium ions. c. The sodium-potassium pump is an antiporter that results in a net negative charge inside the cell. d. The sodium-potassium pump transports Na+ and K+ across the plasma membrane in the same direction at the expense of ATP hydrolysis. e. The sodium-potassium pump moves sodium out of the cell and co-transports protons into the cell, which is the source of energy for the movement of the potassium into the cell.
In relation to the energetics of filament sliding during muscle contraction, which of the following statements are correct. (many choice, select all that apply) a. Energy is provided by ATPase activity in the myosin head. b. Release of bound ADP is followed by binding of another ATP c. The release of the ATP sets the stage for another cycle
d. Absence of ATP prevents dissociation of cross-bridges causing a contracted state

Answers

The correct statement about the sodium potassium pump is option e, "The sodium-potassium pump moves sodium out of the cell and co-transports protons into the cell, which is the source of energy for the movement of the potassium into the cell."

Sodium-potassium pump

The sodium-potassium pump, also known as the Na+/K+ AT

Pase, is an enzyme responsible for maintaining the ion gradient across the plasma membrane of almost all living cells. The sodium-potassium pump transports three Na+ ions out of the cell while bringing two K+ ions into the cell. Therefore, it creates an electrical potential and concentration gradient across the cell membrane, with more Na+ outside the cell and more K+ inside the cell.

The sodium-potassium pump is an antiporter that results in a net negative charge inside the cell. It moves ions against their concentration gradients, requiring energy in the form of ATP hydrolysis. The sodium-potassium pump moves sodium out of the cell and co-transports protons into the cell, which is the source of energy for the movement of the potassium into the cell. Option e is the correct statement about the sodium-potassium pump.

Related to the energetics of filament sliding during muscle contraction, all the options a, b, c, and d are correct. The ATPase activity in the myosin head provides energy, the release of bound ADP is followed by binding of another ATP, the release of the ATP sets the stage for another cycle, and the absence of ATP prevents dissociation of cross-bridges causing a contracted state. All of these statements are correct.

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Which of the following is/are true statements regarding transcription in prokaryotes and eukaryotes? (choose all that apply) The template strand of DNA that gets "read" during transcription is the base-paired complement of the mRNA sequence. Prokaryotes commonly have functionally related genes clustered together in the genome. Eukaryotes use DNA polymerase to transcribe genes. Prokaryotes use RNA polymerase to transcribe genes. Eukaryotes commonly have functionally related genes clustered together in the genome.

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The following statements are true regarding transcription in prokaryotes and eukaryotes:The template strand of DNA that gets "read" during transcription is the base-paired complement of the mRNA sequence.Prokaryotes use RNA polymerase to transcribe genes.Eukaryotes use RNA polymerase II and III to transcribe genes.Prokaryotes commonly have functionally related genes clustered together in the genome.Eukaryotes commonly have functionally related genes clustered together in the genome.

Transcription is the process through which genetic information is transferred from DNA to RNA. The process happens through the synthesis of an RNA molecule that complements one of the strands of DNA, known as the template strand. The process happens in both prokaryotic and eukaryotic cells, but some differences exist. Here are the following statements regarding transcription in prokaryotes and eukaryotes:Prokaryotes use RNA polymerase to transcribe genes.Eukaryotes use RNA polymerase II to transcribe protein-coding genes and RNA polymerase III for the transcription of tRNA and some other small RNA genes.

The template strand of DNA that gets "read" during transcription is the base-paired complement of the mRNA sequence. This statement is true for both prokaryotes and eukaryotes. During transcription, the RNA polymerase reads the template strand in the 3' to 5' direction and creates a complementary RNA molecule in the 5' to 3' direction.Prokaryotes commonly have functionally related genes clustered together in the genome. This statement is true.

The organization of prokaryotic genes in an operon allows for coordinated control of gene expression and the regulation of metabolic pathways. Eukaryotes commonly have functionally related genes clustered together in the genome. This statement is also true. Eukaryotic genes often occur as clusters on chromosomes, which helps regulate gene expression, and ensures that related genes are transmitted together during cell division.

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cystic fibrosis is a recessive autosomal disorder in which the CFTR gene is not functional. a couple has a child with CF
1. what is the probability that they will have a second child who is a boy and has CF?
2. In a strange twist of fate, siblings of both parents have married. what is the probability that this couple will have an affected child?

Answers

The probability that a couple who has one child with cystic fibrosis will have a second child who is a boy and has CF is **1 in 4**.

Cystic fibrosis is a recessive genetic disorder, which means that a child must inherit two copies of the CF gene, one from each parent, in order to develop the disease. If both parents are carriers of the CF gene, they each have a 25% chance of passing the gene on to each child.

**2.** If siblings of both parents have married, the probability that this couple will have an affected child is **25%**.

This is because the couple is more likely to be carriers of the CF gene if they are related. If both parents are carriers, there is a 25% chance that each child will inherit the gene and develop cystic fibrosis

The probability of a second child with CF is 1 in 4

Cystic fibrosis is a recessive genetic disorder. If both parents are carriers, there is a 25% chance that each child will inherit the gene and develop the disease.

In the case of a couple whose siblings have married, the probability that both parents are carriers is increased. This is because siblings are more likely to share genes than unrelated individuals. As a result, the probability of a second child with CF in this situation is 25%.

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Purpose an explanation for why during the history of the discovery of viruses they were first called filterable agents, then they were thought to be chemicals and finally, why were they able to finally be identified and given a name. – think about this as it relates to technological advancements

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Throughout history, the discovery of viruses has been a subject of immense importance. Originally, scientists were unsure of what viruses were, and their initial discovery in the late 19th century led to several different theories on what they were and how they worked.

The first theory that came about was that viruses were filterable agents. This theory came about after scientists discovered that some viruses could pass through very fine filters that could not filter out bacteria. They were thought to be so small that they were able to pass through these filters. However, it was not until the early 20th century that scientists realized that viruses were not simply filterable agents, but rather they were actually biological entities. Scientists discovered that viruses were composed of proteins and nucleic acids, which were not chemicals. This realization was due in part to the technological advancements of the time. Scientists were able to use electron microscopes to study viruses and were able to observe their structure, which was similar to that of cells. Finally, in the mid-20th century, viruses were able to be identified and given names because of the development of new methods for studying them.

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You have identified a very potent and specific inhibitor of the mitochondrial ATP synthase which can completely inhibit this enzyme. Consider a liver cell carrying out the oxidation of glucose under aerobic conditions. Suppose we added the potent inhibitor mentioned above to the liver cell, which of the following statement(s) is/are FALSE? Check all that apply.
ATP production in the cell will quickly drop to zero. The rate of glucose consumption by this cell will decrease sharply. The rate of oxygen consumption will increase. The citric acid cycle will speed up to compensate. Determine whether the following statement is TRUE or FALSE. Electrons from NADH flow through Complex I, Complex II, Q, Complex III, Cytochrome c, Complex IV and arrive at O2. O True O False

Answers

Adding the potent inhibitor of the mitochondrial ATP synthase to a liver cell under aerobic conditions results in a decrease in the rate of glucose consumption by this cell and the citric acid cycle will slow down instead of speeding up. In addition to that, the rate of oxygen consumption will decrease and ATP production in the cell will also decrease.

Hence, option A is the correct option as it states that ATP production in the cell will quickly drop to zero which is FALSE. Option B is FALSE because as ATP is not being produced, the rate of glucose consumption will decrease as the cell tries to regulate the metabolism of glucose. Similarly, option C is FALSE because the rate of oxygen consumption will decrease due to the lack of ATP production. Lastly, option D is FALSE because the citric acid cycle will slow down instead of speeding up to compensate for the loss of ATP production. Electrons from NADH flow through Complex I, Complex II, Q, Complex III, Cytochrome c, Complex IV and arrive at O2 is a TRUE statement. Hence, option TRUE is the correct option.

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What is Digital Breast Tomosynthesis in details? and State its advantages compare with FFDM in details too

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Digital Breast Tomosynthesis (DBT) is an advanced imaging technology that creates three-dimensional images of the breast by taking multiple low-dose X-ray images from various angles and combining them into a single image.

The images are displayed on a computer monitor and can be viewed in a way that allows a radiologist to examine the breast tissue layer by layer. DBT is an advanced imaging technique that improves the accuracy of mammography, especially in the case of dense breasts.
The advantages of Digital Breast Tomosynthesis over Full-Field Digital Mammography (FFDM) are as follows:
1. Improved accuracy: DBT has a higher accuracy rate than FFDM in detecting breast cancer.
2. Better visualization: DBT creates 3D images that provide better visualization of the breast tissue, making it easier for radiologists to identify abnormalities.
3. Reduced recall rates: DBT has been shown to reduce the number of false positives and unnecessary recalls compared to FFDM, which can reduce patient anxiety and the need for additional imaging tests.
4. Better detection of small lesions: DBT can detect smaller lesions that may be missed by FFDM, improving the overall sensitivity of breast cancer screening.
5. Reduced radiation exposure: Although DBT requires more images to be taken, the radiation dose is similar to that of FFDM and is within safe limits.

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Starting from an Acetyl-CoA primer, if you allowed the first SIX (6) cycles of fatty acid synthesis to proceed ahead, and THEN added an INHIBITOR of b-Ketoacyl-CoA Reductase, what fatty acid intermediate would accumulate?
DRAW the structure below.

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After six cycles of fatty acid synthesis, the accumulation of a 10-carbon saturated fatty acid, palmitate (CH3(CH2)14COOH), would occur upon inhibiting beta-Ketoacyl-CoA Reductase.

The buildup of fatty acid intermediate would be a 10-carbon saturated fatty acid known as palmitate if the first six cycles of fatty acid synthesis are allowed to continue and then an inhibitor of beta-Ketoacyl-CoA Reductase is introduced.

The structure of palmitate is as follows:

CH3(CH2)14COOH is the chemical structure.

Please take note that while I have supplied the chemical formula and stated that it is a saturated fatty acid with 16 carbon atoms, I am unable to directly depict structures in this text-based format.

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if a person shows an intermediate phenotype, such as that observed in a person who is heterozygous for familial hypercholesterolemia, this indicates the pattern of inheritance to be .

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The intermediate phenotype observed in a person who is heterozygous for familial hypercholesterolemia indicates an incomplete dominance pattern of inheritance.

Incomplete dominance refers to a pattern of inheritance where the heterozygous genotype results in an intermediate phenotype between the two homozygous genotypes. In the case of familial hypercholesterolemia, the condition is typically inherited in an autosomal dominant manner, meaning that a single copy of the mutated gene is sufficient to cause the disease. However, when an individual is heterozygous for familial hypercholesterolemia, meaning they have one normal copy of the gene and one mutated copy, they exhibit an intermediate phenotype.

In familial hypercholesterolemia, the mutated gene leads to impaired clearance of low-density lipoprotein (LDL) cholesterol from the bloodstream, resulting in high levels of LDL cholesterol. Homozygous individuals, who have two copies of the mutated gene, exhibit severe hypercholesterolemia and are at high risk for cardiovascular disease. Heterozygous individuals, on the other hand, have a milder form of hypercholesterolemia and a lower risk for cardiovascular complications compared to homozygotes. This intermediate phenotype is characteristic of incomplete dominance, where the presence of one normal allele partially compensates for the effects of the mutated allele, leading to an intermediate phenotype in terms of disease severity.

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A patient has a condition that results in an extreme deficiency
of chloride in the body. As a result, you would expect the
concentration of bicarbonate to increase in parietal cells of the
stomach. TR

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Yes, the statement is true, when the body undergoes a condition that results in an extreme deficiency of chloride, the concentration of bicarbonate increases in the parietal cells of the stomach.

The parietal cells are located in the stomach lining and are responsible for the secretion of hydrochloric acid (HCl) to help with digestion. The secretion of HCl requires the presence of chloride ions, which are exchanged for bicarbonate ions. The chloride/bicarbonate exchanger is a protein that is responsible for exchanging chloride and bicarbonate ions. In the case of a chloride deficiency, the chloride/bicarbonate exchanger is unable to work correctly. As a result, the concentration of bicarbonate increases in the parietal cells to compensate for the loss of chloride ions.

A condition that results in an extreme deficiency of chloride in the body can lead to an increase in the concentration of bicarbonate in the parietal cells of the stomach. The chloride/bicarbonate exchanger protein is responsible for exchanging chloride and bicarbonate ions in the stomach lining. The exchange of these ions is necessary for the secretion of hydrochloric acid.

In the case of a chloride deficiency, the chloride/bicarbonate exchanger cannot function correctly. To compensate for the loss of chloride ions, the concentration of bicarbonate increases in the parietal cells of the stomach. This increase in bicarbonate helps to maintain the proper pH level of the stomach to facilitate digestion.

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Explain how environmental factors can influence phenotype and
provide examples. (please answer as a long answer question)

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Environmental factors play a crucial role in influencing the phenotype, which refers to the observable characteristics of an organism.

One way environmental factors can influence phenotype is through gene expression. Gene expression refers to the activation or deactivation of specific genes in response to environmental cues. Environmental factors can trigger changes in gene expression by influencing the accessibility of DNA, modifying the activity of enzymes involved in gene regulation, or altering the availability of certain signaling molecules. This, in turn, can lead to variations in phenotype.

An example of how environmental factors influence phenotype is seen in the development of height in humans. While genetics plays a significant role in determining height potential, nutrition during childhood and adolescence can have a profound impact. Adequate nutrition promotes optimal growth and development, allowing individuals to reach their full height potential. In contrast, malnutrition or insufficient caloric intake during critical growth periods can lead to stunted growth and shorter stature.

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In addition to detecting protein-ligand interactions for
the identification of possible drug candidates, ALIS also enables
further characterization of protein-ligand binding
characteristics. Describe

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ALIS (Autonomous Ligand Identification System) is a computer-aided drug discovery tool. It is capable of identifying possible drug candidates and analyzing protein-ligand binding characteristics.

In addition to detecting protein-ligand interactions, it is also capable of further characterization of protein-ligand binding characteristics. ALIS can determine the mechanism of protein-ligand binding, the position of the ligand in the binding site, and the thermodynamics of the interaction.

One of the most significant benefits of using ALIS is that it can accelerate the drug discovery process. It provides rapid and accurate analysis of protein-ligand binding interactions, and it eliminates the need for lengthy and costly experimental approaches.

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For each protein listed below, identify which of the following "tags" it has:
Plasma membrane protein (e.g., Na+/K+ ATPase)
Lysosomal hydrolase (e.g., acid phosphatase)
ER resident protein (e.g., BiP, PDI)
Secretory protein (e.g., trypsinogen, insulin)
Golgi resident protein (e.g., glycosyl transferase)

Answers

In this question, you need to identify the "tags" for each of the given proteins. Here are the answers

Plasma membrane protein (e.g., Na+/K+ ATPase):

The plasma membrane protein is a type of protein that is embedded in the plasma membrane and has functions related to the plasma membrane.

Na+/K+ ATPase is an example of a plasma membrane protein.

Lysosomal hydrolase (e.g., acid phosphatase):

Lysosomal hydrolase is a type of protein that is localized in the lysosome.

Acid phosphatase is an example of a lysosomal hydrolase.

ER resident protein (e.g., BiP, PDI):

ER resident protein is a type of protein that is localized in the endoplasmic reticulum (ER).

BiP and PDI are examples of ER resident proteins.

Secretory protein (e.g., trypsinogen, insulin):

A secretory protein is a type of protein that is synthesized in the endoplasmic reticulum and is subsequently transported to the Golgi complex, where it is modified and sorted into secretory vesicles for secretion.

Trypsinogen and insulin are examples of secretory proteins.

Golgi resident protein (e.g., glycosyl transferase): Golgi resident protein is a type of protein that is localized in the Golgi complex. Glycosyl transferase is an example of a Golgi resident protein.

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Use this post to discuss any pathology that is related to any of
the topics from this term. For examples there could be discussions
related to cardiovascular disease, hypo- or hyper-secretion of
hormo

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Pathology is a study of diseases, their causes, and their effects on the body, for example, cardiovascular disease such as strokes, hypo-secretion of hormones such as diabetes and hyper-secretion of hormones such as hyperthyroidism.

Pathology is a study of diseases, their causes, and their effects on the body, it includes a wide range of fields such as bacteriology, virology, immunology, and more. A lot of pathologies are associated with various health conditions, for example, cardiovascular disease, hypo- or hyper-secretion of hormones, and so on. Cardiovascular diseases are caused by a buildup of fatty deposits and plaque in the arteries, which restricts blood flow and can lead to heart attacks, strokes, and other serious health problems. Symptoms of cardiovascular disease include chest pain, shortness of breath, and dizziness.

Hypo-secretion of hormones occurs when there is not enough hormone production in the body, this can lead to a range of health problems such as diabetes, hypothyroidism, and more. On the other hand, hyper-secretion of hormones happens when there is an excess amount of hormone production, which can lead to conditions such as hyperthyroidism, Cushing's syndrome, and more. In conclusion, pathologies are closely related to various health conditions and can be caused by different factors. It is important to identify and treat these conditions early to prevent serious health problems.

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Which of the following is NOT a way in which sexual development may differ from "expectation." Adult sex hormone profiles may differ from hormone profiles expected based on sexual anatomy or sex chromosomes. External sexual anatomy may not match internal sexual anatomy. Humans have been documented to produce both sperm and eggs simultaneously. External and/or internal sexual anatomy may different from expectations based on sex chromosomes. Human sex chromosomes can show a wide range of aneuploidies.

Answers

Human have been documented to produce both sperm and eggs simultaneously is NOT a way in which sexual development may differ from "expectation."

Human are a species of highly evolved primates that belong to the genus Homo. They are characterized by their advanced cognitive abilities, complex social structures, and tool-making skills. Humans have a wide range of physical and behavioral traits, including bipedal locomotion, opposable thumbs, and sophisticated language capabilities. They exhibit diverse cultures, societies, and belief systems. Humans have made significant advancements in science, technology, and the arts, shaping the world through their ingenuity and creativity. As social beings, humans thrive on interpersonal connections and have a deep capacity for empathy and cooperation.

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Which choice here represents the highest, and the correct number, of taxa in our current classification scheme? Four Kingdoms Two Domains Eight Kingdoms Three Domains

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The traditional five-kingdom system (Monera, Protista, Fungi, Plantae, Animalia) and the later addition of a sixth kingdom (Chromista) have been largely replaced by the three-domain system

In our current classification scheme, the highest and correct number of taxa is represented by the option "Three Domains." This system, known as the three-domain system, was proposed by Carl Woese in the 1970s and is widely accepted in modern taxonomy.

The three domains are Archaea, Bacteria, and Eukarya. These domains are based on fundamental differences in the cellular structure, biochemistry, and genetic makeup of organisms.

Archaea represents a domain of single-celled microorganisms that are distinct from bacteria in terms of their genetic and biochemical characteristics. They are often found in extreme environments such as hot springs, salt lakes, and deep-sea hydrothermal vents.

Bacteria, also known as Eubacteria, are another domain that includes a vast array of single-celled microorganisms. They are found in various habitats and display a wide range of metabolic capabilities.

Eukarya comprises all organisms with eukaryotic cells, which are characterized by having a true nucleus and membrane-bound organelles. This domain includes plants, animals, fungi, and protists, which are diverse and complex organisms compared to prokaryotes.

The three-domain system revolutionized our understanding of the diversity of life on Earth by highlighting the distinctness of archaea from bacteria and recognizing the fundamental importance of eukaryotes. This classification scheme is supported by extensive genetic and molecular evidence.

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Turn in at the beginning of class on Thursday. Possible 10 points extra credit to the exam score. Describe what must occur for the genome of HIV to replicate into dsDNA in preparation for insertion into the host genome? For full credit, describe all the steps of this replication using reverse transcriptase. What must occur in the MS2 bacteriophage to initiate the packaging of virions? What occurs in the MS2 bacteriophage to ensure that translation and replication do not occur on the same +RNA strand? How is the S1 protein involved in this process? What are differences in which CMV & the ssRNA bacteriophages protect their genomes within the host cell? (remember capsids are removed once in cell)

Answers

Reverse transcriptase is an enzyme which enables RNA to replicate into double-stranded DNA (dsDNA). In order to replicate into dsDNA in preparation for insertion into the host genome, the genome of HIV must undergo several stages.

The steps involved in this process using reverse transcriptase include the following:Firstly, the RNA genome is reverse transcribed into cDNA (complementary DNA) by reverse transcriptase.Secondly, RNase H activity of reverse transcriptase degrades RNA templates, leaving cDNA with short RNA fragments (called tRNA primers).Thirdly, the tRNA primer base pairs with the cDNA. A DNA polymerase extends the primers with new DNA strands until the enzyme reaches the end of the RNA template. This step is repeated multiple times, resulting in the synthesis of a DNA strand.Fourthly, the second DNA strand is synthesized using the first DNA strand as a template. After the process of reverse transcription is complete, the newly synthesized dsDNA genome is inserted into the host genome.The packaging of virions in the MS2 bacteriophage is initiated when the coat protein binds to a specific RNA sequence present in the viral RNA. This binding leads to the formation of a packaging complex that includes the coat protein, RNA, and other viral proteins.In MS2 bacteriophage, translation and replication do not occur on the same +RNA strand because the binding of the coat protein to the RNA sequence that initiates packaging effectively blocks the binding of ribosomes to the RNA strand.

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A dwarf fruit tree is exactly what it sounds like: a smaller version of a fruit tree that is potted and can grow right on your back porch. Cherries, apricots, pears, and peaches are just a few examples of types of dwarf fruit trees you can grow. Although dwarf fruit trees will never grow as large as regular fruit trees, they still have requirements for survival that affect their growth. One of the students claims that the height of a dwarf fruit tree is the result of only genetic factors, but you know that it's the result of BOTH environmental and genetic factors working together.
Explain or how environmental AND genetic factors influence the growth of a dwarf fruit tree
Claim - identify the environmental and genetic factors that influence growth
Evidence - information related to each factor
Reasoning - explain how the evidence is connected
Question is to explain how environmental AND genetic factors influence the growth of a dwarf fruit tree based on Claim, evidence, reasoning format

Answers

Claim: The growth of a dwarf fruit tree is influenced by both environmental and genetic factors.

Evidence:

Environmental Factors:

Soil quality: The type and condition of the soil affect the availability of essential nutrients, water drainage, and root development.

Sunlight exposure: Sufficient sunlight is crucial for photosynthesis, the process by which plants convert light energy into chemical energy for growth and development.

Temperature: Different fruit tree species have specific temperature requirements for optimal growth. Extreme temperatures can inhibit growth or cause damage.

Water availability: Adequate water supply is necessary for maintaining turgor pressure, nutrient uptake, and overall plant health.

Air quality: Air pollution, high humidity, and excessive wind can negatively impact tree growth and health.

Genetic Factors:

Genetic traits: Genetic factors determine the inherent characteristics of a tree, such as growth habit, size, disease resistance, and fruit quality.

Growth regulators: Genes regulate the production and distribution of growth hormones, such as auxins and gibberellins, which influence cell division, elongation, and differentiation.

Root system development: Genetic factors influence root architecture and growth, impacting nutrient absorption and water uptake.

Reproductive characteristics: Genetic factors determine the flowering and fruiting patterns of a tree, affecting its overall growth and productivity.

Reasoning:

The growth of a dwarf fruit tree is the result of both environmental and genetic factors working together. Environmental factors such as soil quality, sunlight exposure, temperature, water availability, and air quality directly impact the tree's ability to acquire necessary resources for growth.

For example, a dwarf fruit tree planted in nutrient-rich soil with optimal sunlight exposure will have better growth potential compared to one planted in poor soil or shaded areas.

At the same time, genetic factors play a significant role in determining the tree's inherent traits and growth characteristics. Genetic factors determine the tree's growth habit, disease resistance, fruit quality, and reproductive patterns.

Through genetic regulation, growth hormones are produced and controlled, influencing cell division, elongation, and differentiation, which are crucial for plant growth.

The interplay between environmental and genetic factors is essential for the growth of a dwarf fruit tree. While the tree's genetic makeup provides the foundation for its growth potential, the environmental conditions determine whether that potential can be fully realized.

The tree's growth will be influenced by both its genetic traits and how those traits interact with the surrounding environment, ultimately shaping its height, overall size, health, and fruit production.

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16. Why does salt accumulate on the ground in arid lands? a) To make the plants taste better. b) Salts rise to the surface from lower sedimentary layers. c) Salt is a byproduct of frost wedging d) The Evaporation of water leaves salts on the ground. 17. The development of basins and ranges is caused primarily by. a) differential erosion of sedimentary rock layers b) intrusive vulcanism c) extrusive vulcanism d) parallel normal faults 18. Mesa and scarp topography is created primarily by a) differential erosion of sedimentary rock layers b) intrusive vulcanism c) extrusive vulcanism d) parallel normal faults 19. Beach sand in San Diego County is primarily a) biogenic b) granitic c) basaltic d) olivine 20. The last stage of coral reef development is the a) tombolo reef b) atoll c) barrier reef d) fringing reef

Answers

Salt accumulate on the ground in arid lands due to the Evaporation of water leaves salts on the ground. Hence option D is correct.

Salt accumulate on the ground in arid lands due to the Evaporation of water leaves salts on the ground. 17. The answer to the question "The development of basins and ranges is caused primarily by" is A) differential erosion of sedimentary rock layers.

18. Mesa and scarp topography is created primarily by A) differential erosion of sedimentary rock layers.19. The answer to the question "Beach sand in San Diego County is primarily" is A) biogenic.20. The last stage of coral reef development is the B) atoll.

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The male and female gonads develop in
A. In the pelvic area and scrotum.
B. In the inguinal area
C. In the pelvic area
D. In an upper part of the abdominal cavity, near the
kidneys.
E. None of the abo

Answers

The male and female gonads, which are the testes and ovaries, respectively, develop in different locations. In males, the testes develop in the inguinal area and descend into the scrotum during fetal development. The correct option is C.

This process is essential for maintaining a lower temperature necessary for sperm production. Therefore, option A, which states that the gonads develop in the pelvic area and scrotum, is incorrect.

In females, the ovaries develop in the pelvic area. They are located within the abdominal cavity, specifically in the upper part, near the kidneys. Thus, option D, which mentions the upper part of the abdominal cavity near the kidneys, is also incorrect.

Therefore, the correct answer is option C, as it accurately states that the male and female gonads develop in the pelvic area.

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Delve deeper DNA sequence analysis is being increasingly used as legal evidence in cases of alleged deliberate infection or negligence! 5. Just as the legal use of DNA fingerprinting techniques has been confused by inappropriately confident statistics, so the use of molecular phylogenetic analysis in court cases will require careful attention to, and clear communication of the confidence limits on molecular phylogenies and date estimates. Will it be possible to give judges and juries a critical understanding of molecular date estimates? What guidelines should be put in place

Answers

Providing judges and juries with a critical understanding of molecular date estimates in legal cases involving DNA sequence analysis is a challenging task.

Clear communication of confidence limits on molecular phylogenies and date estimates is essential. Guidelines should be put in place to ensure accurate interpretation and presentation of molecular data in court.

In cases involving DNA sequence analysis as legal evidence, it is crucial to communicate the limitations and uncertainties associated with molecular date estimates to judges and juries. Just as the use of DNA fingerprinting techniques has faced challenges in terms of misinterpretation and inappropriate statistical confidence, similar issues may arise with molecular phylogenetic analysis in court cases.

To ensure a critical understanding of molecular date estimates, specific guidelines should be established. These guidelines may include the following:

1. Expert Testimony: Qualified experts in the field of molecular biology and DNA analysis should be called upon to provide accurate interpretations of molecular data and explain the confidence limits associated with molecular phylogenies and date estimates.

2. Transparent Reporting: The methodologies used for molecular analysis, including data collection, analysis, and statistical approaches, should be clearly reported. This transparency allows the court to assess the reliability and validity of the data presented.

3. Independent Verification: Independent experts should have the opportunity to review the methodology and results presented by the involved parties to ensure accuracy and consistency.

4. Education and Training: Judges and juries may benefit from specialized training or educational programs that provide a basic understanding of molecular biology concepts, terminology, and the limitations of molecular date estimates.

By implementing these guidelines, the legal system can foster a critical understanding of molecular date estimates, promoting accurate interpretation and presentation of molecular data in court cases involving DNA sequence analysis.

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So-called "perfect" enzymes are limited only by
the work of ribozymes
the rate of diffusion
their cofactors
the toxicity of their intermediates

Answers

"Perfect" enzymes are limited only by the rate of diffusion. "Perfect" enzymes, also known as catalytic perfection, are hypothetical enzymes that operate at the maximum catalytic efficiency possible.

They are designed to carry out catalytic reactions with the highest possible rate of conversion and specificity. The limiting factor that constrains the efficiency of such enzymes is the rate of diffusion.

The rate of diffusion refers to the movement of molecules from an area of higher concentration to an area of lower concentration. In the context of enzymes, it specifically refers to the diffusion of substrates to the active site of the enzyme and the diffusion of products away from the active site.

Even if an enzyme is highly efficient and can rapidly catalyze a reaction, its overall performance can be limited by the rate at which substrates can reach the enzyme's active site through diffusion. Similarly, the release of products from the active site can also be influenced by diffusion.

While ribozymes, cofactors, and toxicity of intermediates can certainly impact enzyme function, the primary limitation for "perfect" enzymes is the rate of diffusion. Enhancing diffusion rates through factors such as optimized cellular environments or structural modifications can potentially maximize the efficiency of these enzymes.

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In the sympathetic nervous system, where are the preganglionic neurons located? a) sacral segments of the spinal cord. b) thoracic and lumbar segments of the spinal cord. c) cerebellum. d) cervical and sacral segments of the spinal cord. e) brain stem.

Answers

The correct answer is Option b) thoracic and lumbar segments of the spinal cord.

In the sympathetic nervous system, the preganglionic neurons are located in the thoracic and lumbar segments of the spinal cord. This corresponds to option b). The sympathetic division of the autonomic nervous system is responsible for the "fight or flight" response, preparing the body for action in response to stress or danger.

The preganglionic neurons originate in the intermediolateral cell column of the spinal cord gray matter, specifically in the lateral horns of the thoracic (T1-T12) and upper lumbar (L1-L2) segments. These neurons are also known as thoracolumbar preganglionic neurons.

After their origin, the preganglionic neurons extend from the spinal cord to form synapses with postganglionic neurons in the sympathetic ganglia. These ganglia are located in close proximity to the spinal cord and form a chain running parallel to it. From the ganglia, the postganglionic neurons extend to innervate various organs and tissues throughout the body.

Therefore, the correct answer is Option b) thoracic and lumbar segments of the spinal cord.

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4. In each of the following scenarios, what is expected to happen to blood flow and/or pressure (likely to increase or decrease)? (3 pts) a. You have a patient who is dehydrated. Their blood pressure

Answers

Dehydration is the state of the body being in a fluid-deficient condition. When this occurs, the body reduces the circulation of blood, causing the blood pressure to fall.

When the body loses too much water, its blood volume decreases, causing the heart to pump blood more quickly in order to maintain blood flow to the essential organs and maintain normal blood pressure.Blood flow to the kidneys is decreased when a person is dehydrated. This indicates that the body's kidneys conserve water by reducing urine output. If dehydration continues, the kidneys will cease producing urine entirely, indicating that the body is in acute renal failure. Urine production may return to normal as the body rehydrates itself.

The decrease in blood pressure caused by dehydration can cause blood flow to the brain to decrease, resulting in dizziness, confusion, and even fainting. As a result, in a dehydrated individual, blood flow and/or pressure are likely to decrease.In conclusion, dehydration results in a decrease in blood flow and pressure, which can be corrected by drinking adequate fluids.

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B →CD USE THE DIAGRAM OF A FOOD WEB ABOVE TO ANSWER QUESTIONS 37-42; EACH LETTER REPRESENTS A SPECIES 37. What represents the producers in the food web? 38. The combined biomass of species A + G + C is probably a. greater than the biomass of B b. less than the biomass of D+E

Answers

The species B represents the producers in the food web. 38. The combined biomass of species A + G + C is probably less than the biomass of D + E.

The diagram of a food web is given below; Each letter in the food web represents a species. 37. The species B represents the producers in the food web. 38. The combined biomass of species A + G + C is probably less than the biomass of D + E. Biomass is the total weight of organisms or organic matter in a particular area. A biomass pyramid is used to describe the biomass present in different trophic levels in a food chain. It is usually found that the biomass decreases as you move higher up the trophic level. A food web is given with species A, B, C, D, E, F, and G in the question.

Biomass of species A, G, and C is combined = A + G + C ... equation 1Let's calculate the biomass of species A, G, and C.Species A = 10 + 5 = 15 gSpecies G = 2 + 8 = 10 g Species C = 3 g Biomass of species A, G, and C = 15 + 10 + 3 = 28 g... equation 2Let's calculate the biomass of species D and E. Species D = 10 + 20 + 2 = 32 g Species E = 15 + 5 = 20 gBiomass of species D and E = 32 + 20 = 52 g... equation 3Therefore, according to the biomass of equation 2 and equation 3, the combined biomass of species A + G + C is less than the biomass of species D + E. Hence, the correct option is b. less than the biomass of D+E.

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Transporters are specialised proteins evolved to facilitate solute movement across membranes.
Describe the therapeutic exploitation of the SLC and P-type family of transporters, making use ofspecific named examples. Identify the pathology the drug is intended to treat and the mechanism/s by which the drug exerts its therapeutic effect.
Could you write more words, because I think this question is hard to understand. So, please write more explanation of it. Thank you so much and really appreciate it!

Answers

Therapeutic exploitation of SLC and P-type family of transporters involves using specific drugs to target these proteins and treat various pathologies. The drugs exert their effects by modulating the transport activity of these proteins, thereby influencing the movement of specific solutes across cell membranes.

The SLC (Solute Carrier) family of transporters consists of various subfamilies involved in the transport of a wide range of solutes, such as ions, sugars, amino acids, neurotransmitters, and drugs. These transporters play crucial roles in maintaining cellular homeostasis and are targeted therapeutically to treat several diseases.

One example of therapeutic exploitation of SLC transporters is the use of selective serotonin reuptake inhibitors (SSRIs) for the treatment of depression. SSRIs, such as fluoxetine (Prozac), act on the serotonin transporter (SLC6A4) and inhibit its reuptake activity. By blocking the reuptake of serotonin, SSRIs increase the concentration of serotonin in the synaptic cleft, thereby enhancing neurotransmission and alleviating depressive symptoms.

Another example involves the SLC12A1 transporter, which mediates the reabsorption of sodium and chloride ions in the kidney. Thiazide diuretics, like hydrochlorothiazide, target this transporter to inhibit its activity, leading to increased excretion of sodium and water. This mechanism is utilized in the treatment of hypertension and edema.

The P-type family of transporters, also known as ATPases, utilize ATP hydrolysis to transport ions across cellular membranes. These transporters are involved in various physiological processes and are potential targets for therapeutic intervention.

An example of therapeutic exploitation of P-type transporters is the use of proton pump inhibitors (PPIs) for the treatment of gastroesophageal reflux disease (GERD) and peptic ulcers. PPIs, such as omeprazole, target the hydrogen/potassium ATPase (H+/K+ ATPase or ATP4A) in the stomach's parietal cells. By irreversibly inhibiting this transporter, PPIs reduce gastric acid secretion, providing relief from acid-related disorders.

In summary, the therapeutic exploitation of SLC and P-type transporters involves using specific drugs to target these proteins and treat various pathologies. The drugs exert their effects by modulating the transport activity of these proteins, influencing the movement of solutes across cell membranes and ultimately alleviating the associated pathologies.

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Ecosystems are based 2 fundamental basic principles. These two
principles involve which specific organisms ?

Answers

The two fundamental basic principles on which ecosystems are based are energy flow and nutrient cycling.

Energy flow is the movement of energy through an ecosystem by feeding and consumption.

Nutrient cycling is the movement of materials essential for life (such as carbon, oxygen, and nitrogen) through the ecosystem.

Both principles involve specific organisms in the ecosystem.

The flow of energy depends on the interactions between producers (organisms that make their food) and consumers (organisms that eat other organisms), while nutrient cycling involves the decomposition of dead organisms and the recycling of nutrients back into the ecosystem by decomposers (organisms that break down organic matter) such as bacteria and fungi. In conclusion, ecosystems are based on two fundamental principles, energy flow and nutrient cycling, which involve specific organisms in the ecosystem.

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1. What is the role of the heart valves (both atrioventricular and semilunar)? 2. What does the heart sound S1 correspond to? What does the heart sound S2 correspond to? 3. Which ventricle is more muscular, the right or the left? Why?

Answers

The right ventricle only needs to pump blood into the pulmonary circulation, which has much lower resistance and therefore requires less force. The left ventricle is also responsible for maintaining systemic blood pressure, which is typically much higher than pulmonary blood pressure.

Role of the heart valves: The heart valves function as one-way flow regulators that are essential to ensuring that blood flows in the correct direction through the heart chambers. The atrioventricular (AV) valves, including the mitral valve on the left and tricuspid valve on the right, help to prevent the backflow of blood from the ventricles into the atria during ventricular contraction. The semilunar valves, including the pulmonary valve on the right and aortic valve on the left, regulate the flow of blood out of the ventricles and into the pulmonary and systemic circulations, respectively.

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Myoglobin is a compact and mainly α - helical protein. The amino acids serine and aspartic acid would be predicted to be: a.Involved in ionic interactions B.At the active site participating in phosphorylation C. Available to interact with the aqueous environment D.Involved in disulfide bond formation E.Buried in the core of the protein

Answers

The amino acids serine and aspartic acid in myoglobin would be predicted to be: Available to interact with the aqueous environment.

As myoglobin is a water-soluble protein, serine and aspartic acid residues would be exposed on the surface of the protein, making them available to interact with the surrounding aqueous environment. These residues can potentially form hydrogen bonds with water molecules or participate in other types of interactions with solvent molecules, ions, or other biomolecules.

In contrast, options A, B, D, and E are less likely for serine and aspartic acid in myoglobin. Ionic interactions (option A) typically involve charged residues, whereas serine and aspartic acid have polar but uncharged side chains. Phosphorylation (option B) usually occurs on specific residues such as serine, threonine, or tyrosine, rather than aspartic acid. Disulfide bond formation (option D) involves the oxidation and linking of cysteine residues, which are not mentioned in the question. Finally, buried residues (option E) typically refer to hydrophobic amino acids found in the core of a protein, whereas serine and aspartic acid are more likely to be exposed to the solvent due to their polar nature.

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2)
a. What experimental evidence supports the idea that a protein’s
structure is determined by its amino acid sequence?
b. In your opinion, what is the most important property provided
by microscopy

Answers

a. The experimental evidence that supports the idea that a protein’s structure is determined by its amino acid sequence is X-ray crystallography. b. In my opinion, the most important property provided by microscopy is the ability to visualize structures at a high resolution.

X-ray crystallography is a technique used to determine the three-dimensional structures of macromolecules, including proteins. The technique involves growing a crystal of the protein of interest and then shining a beam of X-rays onto the crystal. The X-rays scatter off the atoms in the crystal and produce a diffraction pattern, which can be used to reconstruct the structure of the protein. This technique has been used to determine the structures of many proteins, and in each case, the structure has been found to be determined by the amino acid sequence.

Microscopy has revolutionized the way we study cells and other biological structures by allowing us to see things that were previously invisible. Advances in microscopy have made it possible to visualize structures at the nanoscale, which has led to many important discoveries in the field of biology. For example, electron microscopy has been used to visualize the structure of viruses and other small particles, while fluorescence microscopy has been used to track the movement of proteins and other molecules within cells. Overall, the ability to visualize structures at a high resolution has been instrumental in advancing our understanding of the structure and function of biological systems.

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All of the following statements are true about Endogenous catecholamines Except
a. Enter CNS rapidly
b. Are not active orally
c. Rapidly metabolized by COMT and MAO
d. Have short duration of action

Answers

The catecholamines perform various functions in the body, including regulating blood pressure, heart rate, and breathing. The statements given above are all true except one. The statement that is not true about endogenous catecholamines is option B: Are not active orally.

Catecholamines are chemical agents that act as hormones and neurotransmitters. Endogenous catecholamines refer to those hormones that are made inside the body itself. The body produces different catecholamines, including dopamine, epinephrine, and norepinephrine.  Catecholamines are not active orally as they are not absorbed through the digestive system and would not survive metabolism by the liver.

Thus, the only way catecholamines can be administered to humans is through injection. Catecholamines are chemicals that are important for the body to function correctly. They act as hormones and neurotransmitters. Endogenous catecholamines are hormones that the body produces itself. The body creates various catecholamines, including dopamine, epinephrine, and norepinephrine.

These hormones perform many functions in the body, including regulating blood pressure, heart rate, and breathing. The statements given above are all true, except for one. The statement that is not true about endogenous catecholamines is option B: Are not active orally. Catecholamines are not active orally, as they are not absorbed through the digestive system and would not survive metabolism by the liver.

Thus, the only way catecholamines can be administered to humans is through injection. Catecholamines work by binding to receptors in the body. There are two types of receptors, alpha and beta receptors. Epinephrine binds to both of these receptors, whereas norepinephrine binds to only alpha receptors. Catecholamines have a short duration of action, which means that they do not remain active in the body for long. They are rapidly metabolized by COMT and MAO. They enter the CNS rapidly. They cannot be taken orally because they are not absorbed through the digestive system.

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