3.Which of these is NOT part of the cell theory? * "
all living things are made of cells
Ocells come only from other cells
cells are the smallest living unit of an organism
O all living things have blood cells
Answer:
Cells are the smallest living unit of an organism
Answer:
all living things living things have blood cells
Explanation:
this is because robert hooke did not make this apart of the theory
1. How many liters of water can be produced with 45 moles of sodium hydroxide?
What is a word that means carbon and water
Answer:
When Carbohydrates are burned (decomposed ) they break down into carbon and water.
Explanation:
The formula for glucose sugar is C6H12O6 If the compound is broken down it results in
6C+6H2O six carbon atoms and six water molecules.
An experiment that illustrates this well is to pour concentrated sulfuric acid about 1/3 deep into the volume of graduated sucrose sugar in a beaker about 1/4 full
The sulfuric acid is hydrophilic it will break the sucrose sugar molecule apart. The water will rise as steam above the beaker.
The sugar will turn brown and the a black carbon cone will rise out of the sugar sulfuric acid solution. The carbon cone will rise about the top of the beaker.
This experiment shows that the carbohydrate sugar is made of only Carbon and Water.
Zn(s) + 2 HCl(aq) —> ZnCl2(aq)
+ H2(g)
If a scientist wanted to create 10L of hydrogen gas at RTP, what mass of HCl would they need to start with?
Answer:
First write the balanced equation for the reaction of HCl with Zn (NOTE: the previous answer did NOT do this and thus obtained an incorrect answer)
Zn + 2HCl ==> ZnCl2 + H2(g)
moles of H2 desired: PV = nRT
n = PV/RT = (1 atm)(10L)/(0.0821 Latm/Kmol)(298K)
n = 0.409 mole H2 desired
moles Zn needed:
0.409 moles H2 x 1 mole Zn/2 moles HCl = 0.204 moles Zn needed
mass Zn needed = 0.204 moles Zn x 65.4 g/mol = 13.4 g Zn needed (to 3 sig. figs.)
Explanation:people always get this wrong but i got you
Your uncle complained about feeling weak and dizzy and having experienced
palpitations. The doctor’s diagnosis is that he has hyperthyroidism, which may lead to
goiter. Which of the following ions is related to this disorder?
A. Calcium ion
B. Potassium ion
C. Iodine ion
D. Sodium ion
Answer:
C.Iodine ion
Explanation:
BECAUSE HIS LACK OF IODINE THAT'S WHY HE HAS GOITER
3. What molecule or ion acts as the nucleophile in the base-catalyzed reaction between acetic anhydride and vanillin? A. Vanillin as a neutral phenol B. Vanillin as a phenoxide ion (conjugate base) C. Acetic anhydride D. Sodium hydroxide 4. According to the class notes, the first step in the acid-catalyzed reaction between acetic anhydride and vanillin is: A. Loss of a proton from the alcohol group in vanillin B. Protonation of acetic anhydride C. Protonation of the alcohol group in vanillin D. Departure of water as a leaving group in vanillin FOR QUESTIONS 5 AND 6 USE THE FOLLOWING INFORMATION: • Vanillin (solid) MW = 152.15 g/mol • Acetic anhydride (liquid) MW = 102.04 g/mol • Acetic anhydride density = 1.082 g/mL 5. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the BASE CATALYZED reaction as described in the textbook? A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride B. 45.6 mmol of vanillin and 82 mmol acetic anhydride C. 8.45 mmol of vanillin and 2 mmol acetic anhydride D. 2 mmol of vanillin and 2 mmol acetic anhydride 6. How many mmoles of vanillin and how many mmoles of acetic anhydride are being reacted in the ACID CATALYZED reaction as described in the textbook? A. 23 mmol of vanillin and 102 mmol acetic anhydride B. 11 mmol of vanillin and 1 mmol acetic anhydride C. 1 mmol of vanillin and 10.6 mmol acetic anhydride D. 1 mmol of vanillin and 9 mmol acetic anhydride
Answer:
B
B
A
C
Explanation:
3
B. Vanillin as a phenoxide ion (conjugate base)
4
B. Protonation of acetic anhydride
5
A. 1.97 mmol of vanillin and 8.45 mmol acetic anhydride
6
C. 1 mmol of vanillin and 10.6 mmol acetic anhydride
Determine the molecular formula for a compound that has a molecular mass of 52.0 g/mole
and and is composed of 92.31% carbon and 7.69% hydrogen.
Answer:
C4H4
Explanation:
92.31% of 52.0 g/mol is 48.0012 g/mol
7.69% of 52.0 g/mol is is 3.9988 g/mol
Carbon has a gram-formula mass of about 12, which goes into 48.0012 about 4 times, so there should be 4 atoms of Carbon
Hydrogen has a gram-formula mass of about 1, which goes into 3.9988 about 4 times, so there should also be 4 atoms of hydrogen
A certain substance has a heat of vaporization of 64.08 kJ/mol. At what Kelvin temperature will the vapor pressure be 6.50 times higher than it was at 355 K?
Answer:
[tex]T_2 =388.50K[/tex]
Explanation:
Given
[tex]p_1 = ??[/tex] -- Initial vapour pressure
[tex]p_2 = 6.50p_1[/tex] --- Final vapour pressure
[tex]T_1 = 355K[/tex] ---- Initial temperature
[tex]T_2 = ??[/tex] --- Final temperature
[tex]\triangle _{vap}H = 64.08kJmol[/tex] --- Enthalpy of vaporization
Required
Calculate T2
To do this, we make use of Clausius-Clapeyron equation.
Which states that:
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex]
Where:
[tex]R = 8.314 J.K^{-1}mol^{-1}[/tex] --- Universal Gas constant
[tex]\triangle _{vap}H = 64.08kJmol[/tex]
[tex]\triangle _{vap}H = 64080\ kJmol[/tex]
[tex]ln(\frac{p_2}{p_1}) = \frac{\triangle _{vap}H}{R}(\frac{1}{T_1} - \frac{1}{T_2})[/tex] becomes
[tex]ln(\frac{6.50p_1}{p_1}) = \frac{64080}{8.314}(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(\frac{6.50p_1}{p_1}) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]ln(6.50) = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
[tex]1.872 = 7707.48(\frac{1}{355} - \frac{1}{T_2})[/tex]
Take LCM
[tex]1.872 = 7707.48(\frac{T_2 - 355}{355T_2})[/tex]
[tex]1.872 = 7707.48*\frac{T_2 - 355}{355T_2}[/tex]
[tex]1.872 = \frac{7707.48*(T_2 - 355)}{355T_2}[/tex]
Cross Multiply
[tex]355T_2*1.872 = 7707.48*(T_2 - 355)[/tex]
[tex]664.56T_2 = 7707.48T_2 - 2736155.4[/tex]
Collect Like Terms
[tex]664.56T_2 - 7707.48T_2 =- 2736155.4[/tex]
[tex]-7042.92T_2 =- 2736155.4[/tex]
Make T2 the subject
[tex]T_2 =\frac{- 2736155.4}{-7042.92}[/tex]
[tex]T_2 =388.497299416[/tex]
[tex]T_2 =388.50K[/tex]
The final temperature is 388.50K
The temperature at which the vapor pressure will be 6.50 times higher than it was at 355K is 389 K
The Clausius-Clapeyron Equation is widely used for the determination of the vapor pressure of another temperature, provided we know the vapor pressure at a certain temperature as well as the heat of vaporization.
Given that:
the heat of vaporization [tex]\mathbf{\Delta H_{vap} = 64.08 \ kJ/mol = 64.08 \times 10^3 J/mol}[/tex] the initial temperature T₁ = 355 Kthe final temperature T₂ = ???if the pressure at T₁ = P₁then, the pressure at T₂ = 6.5P₁the universal gas constant = 8.314 J/K/molBy using the Clausius-Clayperon Equation:
[tex]\mathbf{In \Big( \dfrac{P_2}{P_1} \Big) = \dfrac{\Delta H_{vap}}{R} \Big (\dfrac{1}{T_1} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In \Big( \dfrac{6.5P_1}{P_1} \Big) = \dfrac{64.08 \times 10^3 }{8.314} \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{In(6.5)=7707.48 \Big (\dfrac{1}{355} - \dfrac{1}{T_2} \Big) }[/tex]
[tex]\mathbf{1.872 =21.71 - \dfrac{7707.48}{T_2} }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 21.71- 1.872 }[/tex]
[tex]\mathbf{\dfrac{7707.48}{T_2} = 19.838 }[/tex]
[tex]\mathbf{T_2= \dfrac{7707.48}{19.838} }[/tex]
[tex]\mathbf{{T_2}=388.521 \ K }[/tex]
T₂ ≅ 389 K
Learn more about Clausius-Clayperon equation here:
https://brainly.com/question/1077674?referrer=searchResults
why is seawater a better conductor of electricity than freshwater?
Answer:
please refer to the attachment above;)
Answer:
Because it contains Na+ and Cl- ions, Which are conductors of electricity
Explanation:
1) G to H.
2) I to J.
3) J to I.
4) I to H.
3 ..............................
Adaptation for animals that live in the desert
Answer:
have thick fur on feet protecting them from the hot ground; have large, bat-like ears radiate body heat and help keep them cool; have long, thick hair that insulates them during cold nights and protects them from the hot sun during the day; have light coloured fur to reflect sunlight and keep their bodies cools.
Explanation:
I hope this helps!
Use Avogadro's number, 6.02E23, to calculate the number
of particles found in 0.004 moles of carbon dioxide
CO2
Answer:
2.408 × 10²¹ is the correct answer!!The theoretical yield of Baso, is 58.35 g. If 44.34 g of BaSO4 are produced from the reaction shown above, what is the percent yield of Ba50_?
BaCl2(aq)+Na2SO4(aq)—>2NaCl(aq)+BaSO4(s)
a85.17%
b75.99%
c31.67%
d52.03%
Answer:75.99
Explanation:saw it on quizlet
When the theoretical yield of Baso, is 58.35 g And, there is 44.34 g of BaSO4 are produced so the percent yield is option b 75.99%.
Calculation of the percent yield:Since
The theoretical yield of Baso, is 58.35 g. And, there is 44.34 g of BaSO4 are produced
So, here the percent yield is
= Actual yield / theoretical yield
= 44.34 / 58.35
= 75.99%
Hence, the option b is correct.
Learn more about reaction here: https://brainly.com/question/4241156
The process utilized to save an organism's DNA for use in the future is:
A tissue biopsy
B DNA
C clone
D genetic preservation
Answer:
I believe it's D!
Explanation:
B is what is being saved, C is a potential creation of, A is a method.
Help me plsss
What is the mass in grams of H₂ that can be formed from 47.2 grams of NH₃ in the following reaction?
2 NH₃(g) → 3 H₂(g) + N₂(g)
Answer:
8.34
Explanation:
1) how much moles of NH₃ are in the reaction;
2) how much moles of H₂ are in the reaction;
3) the required mass of the H₂.
all the details are in the attachment; the answer is marked with red colour.
Note1: M(NH₃) - molar mass of the NH₃, constant; M(H₂) - the molar mass of the H₂, constant; ν(NH₃) - quantity of NH₃; ν(H₂) - quantity of H₂.
Note2: the suggested solution is not the shortest one.
A first-order decomposition reaction has a rate constant of 0.00683 yr−1. What is the half-life of the reaction?
Answer:
101 years
Explanation:
Use the half life equation, where t1/2 is the half life, and k is the rate constant:
t1/2 = 0.693/k
t1/2 = 0.693/0.00683 yr -1
t1/2 = 101 years
Would the chlorine atom or ion be larger?
Answer:
Chlorine Ion
Explanation:
The chlorine ion is adding 1 valence electron in order to complete its outer most shell. It has a charge of 1- meaning it is adding an electron.
LO
82
KE<200 after three years and Rs.
82. Compound interest. The
A sum of money becomes Rs.
4400 after six years on
is:
400482.82 KF
32017, KF0018?
00018282 KF0018282 KF0018282 K
SKO 282 KF0018282 KF001Non KF0018
018282'KF0018282 KF0018
R 00786 2 KF00182825
0182
500182
82 KF0018282 KF
Answer: Rs. 1,100
Explanation:
Compound interest calculation at three years:
2,200 = Amount * (1 + r) ³
Compound interest at six years.
4,400 = Amount * (1 + r) ⁶
Divide them to eliminate variables:
4,400/ 2,200 = (Amount * (1 + r) ⁶) / (Amount * (1 + r) ³)
2 = (Amount * (1 + r) ³)
If (Amount * (1 + r) ³ is 2 then Amount at 3 years is:
2,200 = Amount * 2
Amount = 2,200 / 2
= Rs. 1,100
Antonio and Addie want to know if perfume fumes affect plant height. They place five identical bean plants in five identical light boxes. In four of the boxes, they place 200 milliliters (mL) of perfume at different distances from the plants, and they make observations twice a week for one month. Which choice best identifies the observation data that should be included in their data table?
Answer:
I think its C I'm sorry if I'm wrong good luck guys!
Explanation:
A rock-climbing group reached the top of Mount Everest in the Himalayan mountains. Mount Everest is about 29,000 feet above sea level and formed by the interaction of two tectonic plates. The group leader was surprised to find fossilized marine organisms on top of the mountain. Which of the following describes the geologic history of Mount Everest?
Answer:
Two tectonic plates had the same density and a collision of the plates pushed the advancing plate that contained fossilized marine organisms upward forming the Himalayan mountains and Mount Everest.
Explanation:
:)
A party balloon contains 5.50 x 10 ^22 atoms of helium gas. What is the mass, in grams of the
helium?
a) 0.365 g He
b) 9.14 x 10^-2 g He
c) 0.365 mol He
d) 9.14 x 10 -2 mol He
Answer:
[tex]\boxed {\boxed {\sf A. \ 0.365 \ g\ He}}[/tex]
Explanation:
1. Convert Atoms to Moles
We must use Avogadro's Number: 6.022*10²³. This is the number of particles (atoms, molecules, ions, etc.) in 1 mole of a substance. In this case, the particles are atoms of helium. We can create a ratio.
[tex]\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}[/tex]
Multiply by the given number of helium atoms.
[tex]5.50 *10^{22} \ atoms \ He *\frac {6.022*10^{23} \ atoms \ He}{1 \ mol \ He}[/tex]
Flip the fraction so the atoms of helium cancel.
[tex]5.50 *10^{22} \ atoms \ He *\frac {1 \ mol \ He}{6.022*10^{23} \ atoms \ He}[/tex]
[tex]5.50 *10^{22} *\frac {1 \ mol \ He}{6.022*10^{23} }[/tex]
[tex]\frac {5.50 *10^{22} \ mol \ He}{6.022*10^{23} }= 0.09133178346 \ mol \ He[/tex]
2. Convert Moles to Grams
We must use the molar mass, which is found on the Periodic Table.
Helium (He): 4.00 g/molUse this as a ratio.
[tex]\frac { 4.00 \ g \ He }{ 1 \ mol \ He}[/tex]
Multiply by the number of moles we calculated. The moles will then cancel.
[tex]0.09133178346 \ mol \ He *\frac { 4.00 \ g \ He }{ 1 \ mol \ He}[/tex]
[tex]0.09133178346*\frac { 4.00 \ g \ He }{ 1 }[/tex]
[tex]0.3653271338 \ g\ He[/tex]
3. Round
The original measurement has 3 significant figures (5, 5, and 0). Our answer must have the same. For the number we calculated, it is thousandth place. The 3 in the ten thousandth place tells us to leave the 5.
[tex]0.365 \ g\ He[/tex]
The mass is 0.365 grams of helium so choice A is correct.
A weather balloon contains 394 L of hydrogen gas at STP. How many moles of hydrogen are present?
Answer:
PV=nRT
STP is 100kPa and 273.15K
PV/RT=n
n=17.3moles
Explanation:
b. If you have 50 grams of Molybdenum-99, how many grams will remain
after 11 days?
Answer:
6.25gm
half life is 66hrs 11 days is 24*11 then take that and divide by 66 to find out how many time it will have halved and half 50 by that many times
Explanation:
If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Molybdenum-99 follows first-order decay.
What is first-order decay?First-order decay means that for a population of atoms (e.g. radioactive), molecules, or anything else, a constant fraction/unit time is converted to something else.
The half-life (th) of Mo-99 is 66 h.
We will find its rate constant (k) using the following expression.
k = ln2 / th = ln2 / 66 h = 0.011 h⁻¹
Next, we will convert 11 days to hours, knowing that 1 day = 24 h.
11 d × 24 h/1 d = 264 h
If we start with 50 g of Mo-99, we can calculate the remaining mass after 264 h using the following expression.
[tex][Mo] = [Mo]_0 \times e ^{-k \times t} }\\\\[Mo] = 50g \times e ^{-0.011 h^{-1} \times 264 h} } = 2.7 g[/tex]
where,
[Mo] is the final amount of Mo-99.[Mo]₀ is the initial amount of Mo-99.t is the elapsed time.If you have 50 grams of Molybdenum-99, after 11 days, 2.7 g will remain.
Learn more about first-order decay here: https://brainly.com/question/14478152
1. Mixing Water at Two Temperatures
a. One flask contains 150.0 g water at 20.0 °C. A second flask contains 350.0 g water at 95.0 °C. If the two water samples are mixed, what will the final temperature of the water be?
-Assume that the density of water it 1.000 g/cm^3
-The specific heat capacity for water is 4.184 J/g °C
Answer:
[tex]T_f=72.5\°C[/tex]
Explanation:
Hello!
In this case, since this a problem in which the cold water is heated by the hot water, we can write:
[tex]Q_{hot}+Q_{cold}=0[/tex]
Thus, by plugging in the mass, specific heat and temperatures, we obtain:
[tex]m_{hot}C_{hot}(T_f-T_{hot})+m_{cold}C_{cold}(T_f-T_{cold})=0[/tex]
Now, we can also write:
[tex]m_{hot}(T_f-T_{hot})+m_{cold}(T_f-T_{cold})=0[/tex]
Then, after applying some algebra, it is possible to obtain:
[tex]T_f=\frac{m_{hot}T_{hot}+m_{cold}T_{cold}}{m_{hot}+m_{cold}}[/tex]
If we plug in, we obtain:
[tex]T_f=\frac{350.0g*95.0\°C+150.0g*20.0\°C}{350.0g+150.0g}[/tex]
[tex]T_f=72.5\°C[/tex]
Best regards!
PLEASE HELP!! DIMENSIONAL ANALYSIS USING METRIC CONVERSIONS!!!
I am so confused and am so lost despite all the videos i’ve tried watching, please help!!
Answer: Simpe its 1
Explanation:I took that quiz before hope this helps :)
How do you find the concentration of spectator ions?
Answer:
A spectator ion is an ion that does not take part in the chemical reaction and is found in solution both before and after the reaction. In the above reaction, the sodium ion and the nitrate ion are both spectator ions. The equation can now be written without the spectator ions.
Explanation:
What is the equation to calculate speed?
Answer:
speed = distance ÷ times
Answer:
speed is distance divided by time, hope this helps
The center part of an atom is called the
Answer: Nucleus (Hope it is Right!)
Please help :) hope you have a good day
Have a wonderful day :) thanks for the points
which of these is not a process of chemical weathering?
1.cracked sidewalk.
2.wearing away of the inscriptions on a New York City Monument.
3.Rusty Nail.
4.dissolving of limestone which makes caves.