In which scenario would airbag deployment not be beneficial?
in a head-on collision
when a child is sitting in the back seat
when colliding with a stationary object
when a child is sitting in the front seat

Answer:

Hand threader

Explanation:

Quizlet

If the velocity of the car right after the collision is 18.0 m/s to the east, the velocity of the truck right after the collision is 1.0 m/s to the east.

To solve this problem, we can use the conservation of momentum principle. The total momentum of the system before the collision is equal to the total momentum of the system after the collision. We can write this as:

(m₁ * v₁) + (m₂ * v₂) = (m₁ * v₁') + (m₂ * v₂')

where m₁ and v₁ are the mass and velocity of the car before the collision, m₂ and v₂ are the mass and velocity of the truck before the collision, and v₁' and v₂' are the velocities of the car and truck after the collision.

Substituting the given values, we get:

(1,200 kg * 25.0 m/s) + (9,000 kg * 20.0 m/s) = (1,200 kg * 18.0 m/s) + (9,000 kg * v₂')

Simplifying the equation, we get:

30,600 kg m/s = 21,600 kg m/s + 9,000 kg * v₂'

Solving for v₂', we get:

v₂' = (30,600 kg m/s - 21,600 kg m/s) / 9,000 kg

v₂' = 1.0 m/s

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Energy is the capacity to cause change.

In physics, energy is defined as the ability to do work, or the capacity to cause changes in the state or motion of an object. Energy comes in many different forms, such as kinetic energy, potential energy, thermal energy, electromagnetic energy, and so on. It can be transferred from one object to another, or converted from one form to another. The SI unit of energy is the joule (J), although other units such as calories and electron volts (eV) are also commonly used depending on the context.

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The maximum safe speed of the sports car on the banked road is 31.3 mph.

The maximum safe speed of the car can be calculated using the formula V = sqrt(μs * g * rho * tan(theta)), where V is the maximum safe speed, μs is the coefficient of static friction between the tires and the road, g is the acceleration due to gravity, rho is the radius of curvature of the road, and theta is the angle of inclination of the banked road. Substituting the given values, we get V = sqrt(0.1 * 32.2 ft/s^2 * 500 ft * tan(30 deg)) = 31.3 mph, where acceleration due to gravity is taken 32.2ft/s^2.

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The small rocky bodies that are thought to be leftover remnants from the formation of the solar system are called asteroids. These objects can range in size from a few meters to hundreds of kilometers in diameter and are primarily found in the asteroid belt located between Mars and Jupiter.

However, asteroids can also be found in other regions of the solar system, such as the Kuiper Belt and Oort Cloud.

Asteroids are composed of rock, metal, and other materials that were present during the formation of the solar system over 4.6 billion years ago. They have been the subject of much scientific study and exploration, with numerous spacecraft missions sent to study them up close. Some asteroids are even considered potential targets for future asteroid mining, as they contain valuable resources such as metals and water that could be used for space exploration and settlement. Overall, asteroids are fascinating objects that provide insight into the history and composition of our solar system.

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The average momentum of the sprinter is 532.85 kg·m/s.

To calculate the average momentum, we first need to find the average velocity of the sprinter.

Average velocity equals distance divided by time. In this case, the distance is 100 meters, and the time is 10.35 seconds. So, the average velocity is 100 / 10.35 = 9.66 m/s.

Momentum equals mass multiplied by velocity, so the average momentum is 55 kg * 9.66 m/s = 532.85 kg·m/s.

Summary: The average momentum of a 55-kg sprinter running a 100-m dash in 10.35 s is 532.85 kg·m/s.

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The distance between 1.00 and 0.80 markings on the hydrometer stem can be calculated using the weight of the hydrometer and the area of its cross-section.

The distance between the 1.00 and 0.80 markings on the hydrometer stem can be determined by considering the balance between the weight of the hydrometer and the buoyant force acting on it when it is partially submerged in a liquid. The buoyant force is equal to the weight of the liquid displaced by the hydrometer. According to Archimedes' principle, this buoyant force is given by the equation:

Buoyant force = weight of the liquid displaced = ρVg

Where:

ρ is the density of the liquid

V is the volume of the liquid displaced by the hydrometer

g is the acceleration due to gravity

The weight of the hydrometer can be related to the volume of liquid displaced by the cross-sectional area of the hydrometer and the distance between the 1.00 and 0.80 markings on the stem:

Weight of hydrometer = ρVg = pressure × area × distance

The distance between the 1.00 and 0.80 markings on the stem can then be calculated by rearranging the equation:

distance = (Weight of hydrometer) / (pressure × area)

Given that the weight of the hydrometer is 0.125 N and the area of cross-section is 10^(-4) m^2, we can substitute these values into the equation to calculate the distance between the markings

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By the grating equation, the slit spacing in the diffraction grating is approximately 5.74 × 10[tex]^-6[/tex] m.

We can use the grating equation to solve this problem:

d sinθ = mλ

where d is the slit spacing, θ is the angle of the diffraction peak, m is the order of the peak, and λ is the wavelength of the light.

In this case, we are given that the second band of constructive interference occurs at an angle of 1.50° and a wavelength of 500 nm. Since this is the second order peak, we can set m = 2. Plugging in the values we get:

d sinθ = mλ

d sin(1.50°) = 2(500 nm)

d = (2 × 500 nm) / sin(1.50°)

d = 5.74 × 10[tex]^-6[/tex] m

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Part A: Andrea cannot be sure she's at rest. According to the principle of relativity, there is no absolute rest, and the motion of an object can only be described relative to other objects. Therefore, Andrea's motion must be described relative to some other object.

Part B: If Andrea is not at rest, her velocity is likely to be within the range of 0.17 m/s to 3.4 m/s. This range is calculated using the uncertainty principle, which states that the product of the uncertainty in position and momentum of an object cannot be less than Planck's constant divided by 4π. Assuming a reasonable uncertainty in position of 1 cm, the uncertainty in momentum can be calculated as 5.29 x 10^-28 kg m/s. Dividing this by Andrea's mass of 49 kg gives a velocity uncertainty of 1.08 x 10^-29 m/s. Therefore, the range of possible velocities is approximately 0.17 m/s to 3.4 m/s.

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The frequency at which SA node the generates action potentials can vary, but on average, it typically generates around 60 to 100 action potentials per minute.

The sinoatrial (SA) node is the natural pacemaker of the heart, responsible for initiating the electrical signals that coordinate the heart's contractions.  This frequency corresponds to the normal resting heart rate, which is typically within the range of 60 to 100 beats per minute. Each action potential generated by the SA node triggers a heartbeat, resulting in the contraction of the atria and the initiation of the electrical conduction system that spreads throughout the heart. It's worth noting that the actual rate of action potentials from the SA node can be influenced by various factors, such as neural input, hormonal influences, and physical activity levels. These factors can increase or decrease the firing rate of the SA node, leading to corresponding changes in heart rate.

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The table includes information on the mass, volume, density, and floating behavior of five objects made of different materials. Styrofoam and ice float differently due to differences in their densities, and the blue object in the Same Mass section floats while the yellow object sinks, indicating a difference in their densities as well.

Fill out the table with the information for the objects you selected:

Object 1: Wooden block

Material: Wood

Mass: 50 g

Volume: 0.05 L

Density: 1000 kg/m^3

Does it float? Yes

Object 2: Steel bolt

Material: Steel

Mass: 10 g

Volume: 0.001 L

Density: 10000 kg/m^3

Does it float? No

Object 3: Plastic ball

Material: Plastic

Mass: 20 g

Volume: 0.01 L

Density: 2000 kg/m^3

Does it float? Yes

Object 4: Aluminum foil

Material: Aluminum

Mass: 5 g

Volume: 0.001 L

Density: 5000 kg/m^3

Does it float? Yes

Object 5: Glass marble

Material: Glass

Mass: 15 g

Volume: 0.005 L

Density: 3000 kg/m^3

Does it float? No

2. Styrofoam and ice have different densities, which affects how they float in water. Styrofoam is less dense than water, so it floats on the surface. Ice, on the other hand, is less dense than liquid water, so it floats on the surface as well. However, the density of ice is actually slightly lower than that of liquid water, which is why ice floats. This is because the water molecules in ice are more spread out than in liquid water, making ice less dense.

3. In the Same Mass section, the blue object was compared to a yellow object with the same mass. The interesting thing about the blue object's behavior in water was that it floated while the yellow object sank. This suggests that the blue object has a lower density than the yellow object, which allows it to float. It is possible that the blue object is made of a material that is less dense than the material the yellow object is made of, or that the blue object has a hollow space inside that reduces its overall density.

Therefore, The table gives details on five objects made of various materials, including their mass, volume, density, and floating characteristics. The blue object in the Same Mass section floats whereas the yellow object sinks, demonstrating a difference in their densities as well. Polystyrene and ice float differently due to variances in their densities.

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The energy range of photons of wavelength 390 nm to 740 nm is between 2.68 x 10⁻¹⁹ J and 5.08 x 10⁻¹⁹ J, and the energy range of photons of wavelength 390 nm to 740 nm is between 1.67 eV and 3.17 eV.

To calculate the energy range of photons of wavelength 390 nm to 740 nm, we use the formula;

E = hc/λ

where E is energy, h is Planck's constant (6.626 x 10⁻³⁴ J.s), c is the speed of light (2.998 x 10⁸ m/s), and λ is wavelength.

For 390 nm, we have;

E = (6.626 x 10⁻³⁴ J.s)(2.998 x 10⁸ m/s)/(390 x 10⁻⁹ m)

= 5.08 x 10⁻¹⁹ J

For 740 nm, we have;

E = (6.626 x 10⁻³⁴ J.s)(2.998 x 10⁸ m/s)/(740 x 10⁻⁹ m)

= 2.68 x 10⁻¹⁹ J

So, the energy range of photons of wavelength 390 nm to 740 nm is between 2.68 x 10⁻¹⁹ J and 5.08 x 10⁻¹⁹ J.

To convert the energy range of photons from joules to electronvolts (eV), we use the conversion factor 1 eV = 1.602 x 10⁻¹⁹ J.

So, for the lower energy limit of 2.68 x 10⁻¹⁹ J, we have:

2.68 x 10⁻¹⁹ J x (1 eV/1.602 x 10⁻¹⁹ J)

Therefore, the energy range of photons of wavelength 390 nm to 740 nm is between 1.67 eV and 3.17 eV.

= 1.67 eV

And for the higher energy limit of 5.08 x 10⁻¹⁹ J, we have;

5.08 x 10⁻¹⁹ J x (1 eV/1.602 x 10⁻¹⁹ J)

= 3.17 eV.

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Answer:

The rest energy of a feather can be calculated using the equation E=mc^2, where E is the energy, m is the mass, and c is the speed of light. Since the feather is at rest, its kinetic energy is zero, so its rest energy is equal to its total energy.

The mass of the feather is 8.2x10^-6 kg. The speed of light is 299,792,458 m/s.

E = (8.2x10^-6 kg) x (299,792,458 m/s)^2

E = 7.4 x 10^-4 joules

Therefore, the magnitude of the rest energy of the feather is 7.4 x 10^-4 joules.

Mutual inductance is a measure of the amount of magnetic flux that is linked between two coils or conductors. It is dependent on the relative orientation of the two coils. The orientation of the two coils can affect the amount of magnetic field that is shared between them, which can in turn affect the amount of mutual inductance.

When the two coils are oriented parallel to each other, the amount of mutual inductance is at its maximum. On the other hand, when the two coils are oriented perpendicular to each other, the amount of mutual inductance is at its minimum.

This is because the magnetic field lines are not able to link between the two coils as effectively when they are perpendicular. Therefore, when trying to minimize the mutual inductance between two coils, it is best to orient them perpendicular to each other.

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To calculate the required ramp height to achieve an apparent weight of 0.5mg for riders at the top of the loop, where m is the mass of the rider and g is the acceleration due to gravity, we need to consider the forces acting on the rider at that point.

At the top of the loop, the rider experiences a net inward force due to the normal force and the gravitational force. This inward force provides the centripetal force required for circular motion.

The equation for the apparent weight of the rider at the top of the loop can be expressed as:

Apparent weight = Normal force - Gravitational force

Apparent weight = m * g - m * (v² / r)

Where:

m = mass of the rider

g = acceleration due to gravity

v = velocity of the rider at the top of the loop

r = radius of the loop

In this case, we want the apparent weight to be 0.5mg. So we can set up the equation:

0.5mg = m * g - m * (v² / r)

Simplifying the equation:

0.5 = 1 - (v² / (r * g))

Now, we need to consider the relationship between velocity, radius, and height of the loop. At the top of the loop, the velocity can be determined using conservation of energy:

m * g * h = 0.5 * m * v²

Simplifying the equation:

v² = 2 * g * h

Now, we can substitute this value of v² into the previous equation:

0.5 = 1 - (2 * g * h) / (r * g)

Simplifying further:

0.5 = 1 - 2h / r

Rearranging the equation to solve for h:

2h / r = 1 - 0.5

2h / r = 0.5

2h = 0.5r

h = 0.25r

Therefore, the required ramp height (h) to achieve an apparent weight of 0.5mg is one-fourth (0.25) of the radius of the loop (r).

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The wavelength of the monochromatic light is 5.84×10^-7 m. The distance between the two dark fringes on either side of the central maximum is called the fringe spacing. Let's call it "d".

Using the small angle approximation, we can assume that the angle between the center line and the first dark fringe is approximately equal to the angle between the center line and the first bright fringe, which is given by:

sin(θ) = λ/d, where λ is the wavelength of the light.

Since we are given the angle (29 degrees) and the width of the slit (2.40×10−3 mm), we can calculate the fringe spacing:

d = λ/(sin(θ)) = 1.19×10^-5 m.

Now, we can use the known value of d to find the wavelength:

λ = d*sin(θ) = 5.84×10^-7 m.

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Answer:

How many types of waves are in the electromagnetic spectrum?

In order from highest to lowest energy, the sections of the EM spectrum are named: gamma rays, X-rays, ultraviolet radiation, visible light, infrared radiation, and radio waves.

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Answer:

Explanation:

Line Spectrum

The quantum number associated with the intensity of spectral lines and the spin of the electron is called the spin quantum number or simply the spin. The spin quantum number determines the intrinsic angular momentum of a particle, such as an electron.

The spin quantum number has a value of either +1/2 or -1/2, representing the two possible spin states of an electron. These states are commonly denoted as "spin-up" (+1/2) and "spin-down" (-1/2). The spin of an electron is an intrinsic property and plays a crucial role in determining the electronic structure and behavior of atoms, as well as in various quantum mechanical phenomena.

It is important to note that the spin quantum number is not related to the intensity of spectral lines directly. The intensity of spectral lines is primarily determined by other factors such as the probability of electronic transitions between energy levels and the population of energy states.

In summary, the spin quantum number is associated with both the intensity of spectral lines (indirectly) and the spin of the electron.

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5 compressions per second is the frequency of a 10 meter longitudinal wave when 25 compressions pass a point in a medium in 5 seconds

What is a definition of frequency?

The number of waves that pass a fixed point in a unit of time is known as frequency. It is also known as the number of cycles or vibrations that a body in periodic motion experiences in a unit of time. Hertz is the name of the frequency's SI unit.

A waveform signal's wavelength is defined as the separation between two identical points (adjacent crests) in adjacent cycles as the signal travels through space or along a wire.

The relationship between frequency and wavelength is inversely proportional. The wavelength of the wave with the highest frequency is the shortest. Half the wavelength corresponds to twice the frequency. The wavelength ratio is therefore the inverse of the frequency ratio.

Frequency will be 25 / 5 i.e. 5 compressions per second

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Polaroid sunglasses work less effectively when lying on the side because they are designed to block horizontally polarized light, and the orientation changes when lying down, affecting their performance.

Polaroid sunglasses are designed to reduce glare by selectively blocking horizontally polarized light. When you are sitting upright, the sunglasses are aligned with the horizontal orientation of the light reflected off the lake's surface, effectively reducing the glare. However, when you lie down on your side, the orientation of the sunglasses becomes misaligned with the horizontally polarized light. As a result, the sunglasses are less effective in blocking the glare, allowing more horizontally polarized light to pass through the lenses. This diminished effectiveness is due to the change in the relative alignment between the polarization direction of the sunglasses and the orientation of the polarized light while lying down.

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If a bubble of air became trapped inside the eudiometer and the difference in volume was not accounted for in the calculations, it would result in an experimental value of the gas constant (r) that is smaller than the actual value.

The ideal gas law equation, PV = nRT, relates the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T). When the volume is not accurately measured due to the presence of an unaccounted bubble of air, the calculated value of the gas constant will be affected.

Since the volume is smaller than it should be, the calculated value of the gas constant will be smaller as well. This is because a smaller volume leads to a higher pressure for a given amount of gas, which in turn results in a smaller value for the gas constant.

Therefore, neglecting the trapped air bubble and not accounting for the difference in volume would make the experimental value of the gas constant (r) smaller.

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Substitute the value of D to get the flux of hydrogen atoms through the foil.

a. To find the concentration gradient of hydrogen through the foil, we need to determine the difference in concentration across the foil and divide it by the thickness of the foil.
Concentration gradient = (Concentration_1 - Concentration_2) / Thickness
Concentration gradient = (1 x 10^28 H atoms/m³ - 6 x 10^22 H atoms/m³) / 0.01 x 10^-3 m
Concentration gradient ≈ 1 x 10^33 H atoms/m⁴
b. To calculate the flux of hydrogen atoms through the foil, we need to use Fick's first law:
Flux = -D * (Concentration gradient)

Here, D is the diffusion coefficient, which depends on the temperature, lattice structure (FCC), and other factors. Unfortunately, you did not provide the value of D for iron at 1000 °C. Assuming you have the value of D, you can use the following formula: Flux = -D * (1 x 10^33 H atoms/m⁴)

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Answer:

0  (zero)

Explanation:

Momentum = P = mass x velocity = mv

If the ball is at rest its velocity = 0

P = (0.5 kg)(0 m/s) = 0

The de Broglie wavelength of a 455 g football kicked at a velocity of 37.3 m/s is approximately 1.2 x 10^-34 meters.

According to de Broglie's equation, the wavelength of a particle is given by λ = h/mv, where h is Planck's constant, m is the mass of the particle, and v is its velocity. In this case, we can use this equation to calculate the de Broglie wavelength of the football. First, we need to convert the mass of the football from grams to kilograms, which gives us 0.455 kg. Then, we can plug in the values for h, m, and v to get:

λ = h/mv = 6.626 x 10^-34 J·s / (0.455 kg x 37.3 m/s) ≈ 1.2 x 10^-34 meters

Therefore, the de Broglie wavelength of the football is approximately 1.2 x 10^-34 meters. This value is extremely small, as expected for a macroscopic object like a football, and illustrates the wave-particle duality of matter at the atomic and subatomic level.

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The correct option is A, The best performance for radar QPE is typically expected below the melting layer, where the radar beam can accurately detect the precipitation particles.

Precipitation is a term used in meteorology to describe any form of liquid or solid water that falls from the atmosphere and reaches the Earth's surface. This includes rain, snow, sleet, and hail. Precipitation occurs when moisture in the air condenses into water droplets or ice crystals, which then become heavy enough to fall to the ground due to the force of gravity.

Precipitation is a critical component of the water cycle, which is the continuous process by which water evaporates from the surface of the Earth, rises into the atmosphere, and then falls back to the surface as precipitation. This cycle is essential for the survival of all living organisms, as it helps to distribute water throughout the planet and replenish sources of freshwater.

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If a 5-n force is applied 4 m from the pivot and another 5-n force is applied 2 m from the pivot, the magnitude of the total torque about the pivot is 10 Nm.

To calculate the total torque, we need to know the distance of each force from the pivot and the direction of rotation. We can assume that the rod is in equilibrium, so the total torque about the pivot is zero.

Since the two forces are equal in magnitude, the direction of rotation caused by each force is opposite. The force of 5 N applied at 4 m from the pivot creates a torque of

5 N x 4 m = 20 Nm

in a counterclockwise direction.

The force of 5 N applied at 2 m from the pivot creates a torque of

5 N x 2 m = 10 Nm

in a clockwise direction.

To find the total torque, we can subtract the clockwise torque from the counterclockwise torque:

Total torque = 20 Nm - 10 Nm = 10 Nm

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Complete question is:

a rod is pivoted about its center. a 5-n force is applied 4 m from the pivot and another 5-n force is applied 2 m from the pivot, as shown. the magnitude of the total torque about the pivot is:

A solar cooker, really a concave mirror pointed at the Sun, focuses the Sun's rays 17.2 cm in front of the mirror. 34.4 cm is the radius of the spherical surface from which the mirror .

To find the radius of the spherical surface from which the mirror was made, we can use the formula:
[tex]f = R/2[/tex]
where f is the focal length (the distance between the mirror and the point where the rays converge), and R is the radius of curvature of the mirror.

The percentage for which the focal length is equal to half the radius of curvature is satisfied by the optics theory based on the curvature of a spherical mirror. In terms of math, this is
In this case, we know that the focal length is 17.2 cm, so we can write:
17.2 = R/2
Multiplying both sides by 2, we get:
R = 34.4
Therefore, the radius of the spherical surface from which the mirror was made is 34.4 cm.

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The breakup of a supercontinent such as Pangaea could result in an increase in species diversity.

When a supercontinent breaks up, it leads to the formation of new landmasses, oceans, and environmental conditions. This provides opportunities for species to evolve and adapt to new habitats, which can result in the emergence of new species. Furthermore, the separation of previously connected landmasses can allow for the development of distinct evolutionary lineages, which can further contribute to an increase in species diversity. Thus, the breakup of a supercontinent can lead to an increase in species diversity. On the other hand, the breakup of a supercontinent would not necessarily lead to a reduction in the area of continental interiors or an increase in world shoreline. The area of continental interiors would depend on the size and distribution of the newly formed continents, which could vary depending on the specific tectonic processes involved. Similarly, the amount of world shoreline would depend on the size and position of the new landmasses relative to the oceans, which could also vary.

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The sample contains [tex]2.76 \times 10^{22[/tex] nuclides, the decay constant of the element is [tex]2.22 \times 10^{-11} s^{-1[/tex], and the half-life is [tex]3.13 \times 10^{10[/tex] seconds or approximately 991 years.

Part A: To determine the number of nuclides in the sample, we need to use Avogadro's number and the molar mass of the element with mass number 105. The molar mass of this element can be calculated as follows:

Molar mass = (105 atomic mass units) × ([tex]1.661 \times 10^{-27[/tex] kg/atomic mass unit) = [tex]1.745 \times 10^{-25[/tex] kg

The number of atoms in the sample can then be calculated by dividing the mass of the sample by the molar mass and multiplying by Avogadro's number:

Number of atoms = (8.00 g / [tex]1.745 \times 10^{-25[/tex] kg/mol) × [tex]6.022 \times 10^{23[/tex]atoms/mol = [tex]2.76 \times 10^{22[/tex] atoms

Therefore, there are [tex]2.76 \times 10^{22[/tex] nuclides in the sample.

Part B: The decay constant (λ) of the element can be determined using the following formula:

Activity (A) = λN,

where A is the activity of the sample in becquerels (Bq), N is the number of nuclides in the sample, and λ is the decay constant. Rearranging this equation, we can solve for λ:

λ = A/N

Substituting the given values, we get:

[tex]\lambda = \frac{6.14\times 10^{11} \text{ Bq}}{2.76\times 10^{22}}[/tex] nuclides = [tex]2.22 \times 10^{-11} s^{-1[/tex]

Therefore, the decay constant of the element is [tex]2.22 \times 10^{-11} s^{-1[/tex].

Part C: The half-life (t1/2) of the element can be calculated using the following formula:

[tex]t_{1/2} = \frac{\ln(2)}{\lambda}[/tex]

Substituting the decay constant we calculated in part B, we get:

[tex]t_{1/2} = \frac{\ln(2)}{2.22\times 10^{-11}\,\text{s}^{-1}} = 3.13\times 10^{10}\,\text{s}[/tex]

Therefore, the half-life of the element is [tex]3.13 \times 10^{10[/tex] seconds or approximately 991 years. This means that after 991 years, half of the original sample will have decayed, and after another 991 years, half of the remaining sample will have decayed, and so on.

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Complete question:

Suppose that an 8.00 g of an element with mass number 105 decays at a rate of 6.14 × 1011 Bq.

Part A How many nuclides are in the sample?

Part B What is the decay constant of the element?

Part C What is its half-life?

Answer: 660 N.

Explanation: Force on a free falling body is F=mg.

Therefore, Force =66×10 =660

(g is gravitational acceleration, taking it as 10)