Answer: b) A positive charge is moved toward a positive charge.
How much force must a 40,000 W engine exert to get a car up to 75 m/s?
Edit: Answer - 533N
Answer:
Force = 533.33N
Explanation:
Given the following data;
Power = 40000watt
Velocity = 75m/s
To find the force;
[tex] Power = force * velocity [/tex]
Making force the subject of formula, we have;
[tex] Force = \frac {Power}{velocity}[/tex]
[tex] Force = \frac {40000}{75} [/tex]
Force = 533.33N
A motorcyclist sees a branch in the road and hits the brakes, slowing down at -6.42 m/s. if it takes him 2.85 seconds to stop, what was his starting velocity?
Use the definition of average acceleration:
a = ∆v / t
If v is the starting speed, then ∆v = 0 - v, so solve for v :
-6.42 m/s² = (0 - v) / (2.85 s)
v = (6.42 m/s²) (2.85 s)
v ≈ 18.3 m/s
A ball is released from a hot air balloon moving downward with a velocity of
-10.0 meters/second and a height of 1,000 meters. How long did it take the ball to reach the surface of Earth? Given: g = -9.8 meters/second2.
A
11.2 seconds
B.
12.1 seconds
C.
13.3 seconds
D.
13.5 seconds
E.
14.2 seconds
Una curva de radio R = 75 [m] tiene un peralte hecho de tal forma que un auto andando a v1 = 35 [m/s] no derrape incluso con el piso congelado (sin roce). ¿Cuál es el coeficiente de roce estático mínimo necesario entre las ruedas y el pavimento para que, en un día seco y soleado, el auto no derrape cuando avanza a v2 = 118 [m/s]?
Answer:
053.
Explanation:
Given that the radius of curvature of the path, R = 75 m.
Speed of the car on that path , [tex]v_1 = 35 m/s[/tex]
The centripetal force,[tex]F_c[/tex] acting on the body having mass, m, when it moves with the velocity v on curved path having radiusR
Ris[tex]F_c = mv^2/R[/tex]
Gravitational force, [tex]F_g[/tex] = mg.
Let tha angle of superelevation is [tex]\theta.[/tex]
As the car does not skid even with zero friction, so
[tex]mg\sin\theta = (mv_1^2)/2 \cos\theta[/tex]
[tex]\Rightarrow \tan\theta = v_1^2/2g=\cdots(i)[/tex]
On sunny day, let the minimun static friction coefficient between the wheels and the pavement is [tex]\mu.[/tex]
As [tex]v_2[/tex] = 118 m/s is greater than v_so the car tends to skid in upper direction and the frictional
force,f, will acts is downward direction.
As there is no skidding, so
[tex]f+ mg\sin\theta= (m(v_2)^2)/R\cos\theta[/tex]
[tex]\Rightarrow f=(m(v_2)^2)/R\cos\theta - mg\sin\theta[/tex]
where [tex]f= \mu N.[/tex]
[tex]So, \mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{N} \cdots(ii)[/tex]
Where N is the normal reaction can be determined by balancing the force in perpendicular direction of the plane.
[tex]N= mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta[/tex]
From equation (ii)
[tex]\mu = \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g\tan\theta+v^2/R}{v_2^2\tan\theta+g}[/tex]
[tex]= \frac {(m(v_2)^2)/R\cos\theta - mg\sin\theta}{mg\cos\theta+\frac {m(v_2)^2}{R}\sin\theta}[/tex]
[tex]=\frac{-g(v_1^2/2g)+v^2/R}{v_2^2(v_1^2/2g)+g}[/tex]
[tex]= \frac{v_2^2/R-v_1^2/R}{g+v_2^2/R\times v_1^2/Rg}[/tex]
[tex]=\frac{118^2/75-35^2/75}{9.81+118^2/75\times 35^2/(75\times 9.81)}[/tex]
=0.53
Hence, the minimum coefficient of friction is 0.53.
state three ways of conserving energy
energy drinks
sitting
watching TV
Answer:
use natural lights
turn off electrical appliances..if not in use
check your wires every next Month
A car traveling at 25 m/s speeds up to 30 m/s over a period of 5 seconds. The average acceleration of the car is?
Answer:
a= 1 m/s^2
Explanation:
Average acceleration can be found by dividing the change in velocity by the time.
a= ΔV/t
The change in velocity is the difference of the final velocity and initial velocity.
ΔV= final velocity - initial velocity
The final velocity is 30 m/s and the initial velocity is 25 m/s
ΔV= 30 m/s- 25 m/s
ΔV= 5 m/s
The time is 5 seconds.
Now we know the two values.
ΔV= 5 m/s
t= 5 s
Substitute the values into the formula.
a= 5 m/s / 5 s
Divide.
a= 1 m/s/s
a= 1 m/s^2
The average acceleration of the car is 1 meter per second squared.
A motorbike is traveling to the left with a speed of 27.0 m s 27.0 s m 27, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, end fraction when the rider slams on the brakes. The bike skids 41.5 m 41.5m41, point, 5, start text, m, end text with constant acceleration before it comes to a stop. What was the acceleration of the motorbike as it came to a stop?
Answer:
Explanation:
Initial velocity , u = 27 m/s
displacement before stop, s = 41.5 m .
final velocity, v = 0
acceleration a = ?
v² = u² + 2 a s
0 = 27² + 2 x a x 41.5
a = - 27² / 2 x 41.5
= - 8.78 m /s
function Of The glottis
Answer:
Their function is to produce sound by allowing the free edges of the folds to vibrate against one another and also to act as the laryngeal sphincter when they are closed.
What is the voltage drop across the 10.0 Ω resistor?
Answer:
its 120 C
Explanation:
its 120 C
The voltage drop across the 10.0 Ω resistor is c)120V
What is voltage drop in a circuit ?Voltage drop is the decrease of electrical potential along the path of a current flowing in an electrical circuit.
since , all three resistors 10Ω , 20 Ω and 30Ω are in series combination
this implies that voltage drop across each resistor will be same as the total voltage drop in the circuit because in parallel combination voltage remain same in the circuit buy current get divided in each branch
hence , the voltage drop across the 10.0 Ω resistor = 120 V
correct answer c) 120 V
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A truck accelerates from 25 km/hr to 45 km/hr in 40 seconds. Calculate the average acceleration of the vehicle in m/s?.
Answer:
0.138889 m/s2
Explanation:
The average acceleration of the vehicle would be 0.139 meters/second².
What is acceleration?The rate of change of the velocity with respect to time is known as the acceleration of the object.
As given in the problem a truck accelerates from 25 kilometers/hour to 45 kilometers/hour in 40 seconds.
Let us first convert the velocities from kilometers/hour to meters/seconds
25 kilometers/hour ⇒ 25×1000/3600
= 6.94 meters/seconds
45 kilometers/seconds = 45×1000/3600
= 12.5 meters/seconds
acceleration = change in the velocity/time
=(12.5 -6.94)/40
=0.139 meters/second²
Thus, the acceleration of the truck would be 0.139 meters/second²
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While the boys were playing baseball, one of the boys decides to kick his soccer ball high into the air. As the ball goes upward, which type of energy is increasing?
A.) Kinetic Energy
B.) Thermal Energy
C.) Potential Energy
D.) Mechanical Energy
Definition of uniform speed
Answer:
Uniform Speed: A body is said to be moving with uniform speed, if it covers equal distances in equal intervals of time. Variable Speed: A body is said to be moving with variable speed if it covers unequal distances in equal intervals of time.
Explanation:
I got it from google
Answer:
Speed is a measure of how fast an object is moving at a given instant of time. It is a scalar quantity. Its unit is m/s. For a body covering equal distances in equal time intervals, the speed is called uniform speed.
Explanation:
Question 13 (1 point)
The genetic material of an offspring of sexually reproducing organisms is best described as-
a
Ob
identical to that of the other offspring
a copy of the genetic material of the father.
a copy of The genetic material of the mother
genes from both parents, in unique combinations
ос
Od
The genetic material of an offspring of sexually reproducing organisms is best described as genes from both parents in unique combinations.
SEXUAL REPRODUCTION:
Sexual reproduction is a type of reproduction that involves two organisms (a male and a female). The male organism produces a gamete called SPERM while the female organism produces a gamete called EGG. The gametes are produced via a process called MEIOSIS. Meiosis is a process of cell division whereby genetically different daughter cells are produced. The genetic variation is attributed to a process called crossing over, which is the exchange of genetic material between non-sister chromatids of homologous chromosomes. At the end of the fertilization process between male sperm and female egg, the genetic material of the offspring will contain genes from both parents in unique combinations.Learn more at: https://brainly.com/question/11622266?referrer=searchResults
How did einstines and Newton’s theory’s differ in terms of explaining the cause of gravity
Answer: in the Newton concluded that objects fall because they are pulled by Earth's gravity. Einstein's interpretation was that these objects do not fall.
Explanation: These objects and Earth just freely move in a curved spacetime and this curvature is induced by mass and energy of these objects. - I HOPE THAT HELPED!!
Acceleration measures how much the ___________ of an object changes over time.
a) velocity
b) location
Answer: velocity
Explanation: v/t
1. A ball is thrown straight up.if the launch velocity is 15 m/s, at what velocity will the ball return to the thrower's hand?
2. A boat moves across a river going 18 m/s. At the same time there is a current flowing at a right angle to the boat at 6 m/s. What is the resulting velocity of the boat?
Answer:
1) The velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Explanation:
1) Let suppose that ball experiments a free fall, that is an uniform accelerated motion, in which effects from gravity and Earth's rotation can be neglected. The velocity of the ball is represented by the following equations of motion:
Position
[tex]v_{o}\cdot t -\frac{1}{2}\cdot g\cdot t^{2} = 0[/tex]
[tex]t\cdot \left(v_{o}-\frac{1}{2}\cdot g\cdot t \right) = 0[/tex] (1)
Velocity
[tex]v = v_{o}-g\cdot t[/tex] (2)
Where:
[tex]t[/tex] - Time, measured in seconds.
[tex]g[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]v_{o}[/tex] - Initial velocity of the ball, measured in meters per second.
[tex]v[/tex] - Final velocity of the ball, measured in meters per second.
From (1), we get the time when the ball returns to the thrower's hand:
[tex]v_{o}-\frac{1}{2}\cdot g\cdot t = 0[/tex]
[tex]t = \frac{2\cdot v_{o}}{g}[/tex]
And then we apply this result in (2):
[tex]v = v_{o}-g\cdot \left(\frac{2\cdot v_{o}}{g} \right)[/tex]
[tex]v = -v_{o}[/tex] (3)
Then, the velocity of the ball return to the thrower's hand is -15 meters per second.
2) The resulting velocity of the boat ([tex]\vec v_{B}[/tex]) is represented by the vectorial sum of the velocity of the boat relative to the river ([tex]\vec v_{B/R}[/tex]) and the velocity of the river ([tex]\vec v_{R}[/tex]), both measured in meters per second, that is:
[tex]\vec v_{B} = \vec v_{R}+\vec {v}_{B/R}[/tex] (4)
If we know that [tex]\vec v_{R} = 6\,\hat{i}\,\left[\frac{m}{s} \right][/tex] and [tex]\vec v_{B/R} = 18\,\hat{j}\,\left[\frac{m}{s} \right][/tex], then the resulting velocity of the boat is:
[tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex]
The resulting velocity of the boat is [tex]\vec v_{B} = 6\,\hat{i}+18\,\hat{j}\,\left[\frac{m}{s} \right][/tex].
Please help me out if you want brainliest !!!!! ASAP easy
Answer:
Road A = 8 meters Wet
Road B = 2 meters Muddy
Road C = 12 meters Dry
Explanation:
Two forces of magnitude 40N and 70N acts on an object calculate and write the resultant force acting on the object and the resultant a
direction of force when both the force act in opposite direction
A) 70N in the direction of lesser force
B) 110N,opposite direction
C) 30N,in the direction of the greater force
D) 30N in the direction of lesser force
Explanation:
Required Answer70N-40N=30N
30N in lesser forceA ball weighing 2.0 N falls through a distance of 4 m.
Answer:
This question is incomplete, a possible question would be to calculate the work done by the ball.
Work done = 8J
Explanation:
Work done by an object is calculated my multiplying the force by the distance.
The weight of this ball is 2.0N, which also represents the force exerted by the ball. The ball travels through a distance of 4m
Hence, work done = F × d
Work done = 2N × 4m
Work done = 8Nm or 8J
Two children are spinning on a miracle round. What is 50 cm from the center and the other is 100 cm from the center. Which child has the larger linear speed?
Answer:
The one that is 100 cm from the center.
Explanation:
Given that merry-go-round means moving at uniform circular motion or constant angular speed. Hence the person who is closer to the center is moving at a slower speed, while the one far away from the center has a larger linear speed because he has moved a long distance in the same amount of time, despite being on these objects.
To illustrate
A with the 50 cm
B with the 100 cm
Hence, to get speed, we have
A = 2 * pi * 50 / T
B = 2 * pi * 100 / T
And by the explanation of angular speed
We have w = 2*pi/T where w is the angular speed in radians/s
Hence we have
A = 50w
B = 100w
Therefore, the one that is 100 cm from the center has a larger linear speed.
Which procedure would best demonstrate that moving magnet causes an electric current to flow in a wire coil?
Answer:
D
Explanation:
I took the test
The procedure that would best demonstrate that moving magnet causes an electric current to flow in a wire coil is connect a wire coil to an ammeter. Move a bar magnet into and out of the wire coil as you observe the ammeter. The correct option is D.
What is electric current?The flow of electricity in an electronic circuit, as well as the amount of electricity flowing through a circuit, are referred to as electric current. It is expressed in amperes (A).
The greater the value in amperes, the more electricity flows through the circuit.
When an electron is introduced into a wire, a free electron is attracted to a proton in order to be neutral.
Forcing electrons out of their orbits can result in an electron shortage. Electric current is the continuous movement of electrons in a wire.
Connecting a wire coil to an ammeter is the best way to demonstrate that a moving magnet causes an electric current to flow in a wire coil. As you watch the ammeter, move a bar magnet in and out of the wire coil.
Thus, the correct option is D.
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the velocity of a car changes from 5 m/s to 20 m/s in 30 sec the acceleration?
Answer:
0.5m/s2
..............
1. Discuss how we use trial and error, algorithms, heuristics, and insight to solve problems. For each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept was used to determine a solution to a specific problem. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 64 points)
2., How can confirmation bias and fixation can interfere with effective problem solving. In this portion of your response, for each concept, define the term and then describe an incident (either from your own experience or that of a friend) in which the concept interfered with an appropriate solution being determined. You must use specific details of the incident and terms from our module to show me you understand the concept. (Total 32 pts).
Answer: used concepts to simplify and order the world around us, categories: objects, events, ideas, or people
hierarchies: subdivide categories into smaller more detailed units, prototypes: best example
algorithm: time-consuming but thorough set of rules or procedures
heuristics: simpler way of thinking, solve problems but maybe incorrect solutions
insight: flash of inspiration that solves problem
representativeness heuristic: judge likelihood of things in terms of how they represent our prototype
availability heuristic: judge likelihood of things based on how vivid they are or how readily they come to mind.
Explanation: i hope that helped!
please help me very urgent :((
What is the net force (including direction and magnitude) acting on the object on the above left?
What is the net force (including direction and magnitude) acting on the object on the above right?
Answer:
-150 N
Explanation:
(Newton's second law) F=ma
Sum of forces in Y direction= (+200 N)+(-200 N)= 0...
forces cancel, object does not accelerate up/down
Sum of forces in X direction= (+65 N)+(-65 N)+(-150 N)
= -150 N
notice that the +/- 65 components cancel, leaving a net force of 150 N in the LEFTwards direction (which is typically defined as negative)
Overall, the net force is -150 N
A car of mass 1470 kg is on an icy driveway
inclined at an angle of 40◦. The acceleration of gravity is 9.8 m.
If the incline is frictionless, what is the acceleration of the car Answer in units of m/s
Answer:
a = 7.5 m / s²
Explanation:
For this exercise let's use Newton's second law, let's create a coordinate system with the x axis parallel to the plane and the y axis perpendicular to the plane
Y axis
N - W cos θ = 0
N = mg cos θ
X axis
W sin θ = m a
mg sin θ = m a
a = g sin θ
let's calculate
a = 9.8 cos 40
a = 7.5 m / s²
F = M x G
Find the force of gravity acting upon a 1500Kg Hippopatamus.
Answer:........... .. .....
1. A motorcycle stunt driver rides his motorcycle off a small ledge
that is 8.4 meters high. His initial velocity as he rides off the cliff is
24 m/s in the horizontal direction.
a. How long does it take before he lands on the ground below?
b. How far away from the base of the cliff does he travel while in
the air?
Answer:
Explanation:
Given
Height S = 8.4m
Initial velocity u = 24m/s
Required
Time it will take to reach the ground
Using the equation of motion
S = ut +1/2gt²
8.4 = 24t + 1/2(9.8)t²
8.4 = 24t+4.9t²
4.9t²+24t - 8.4 = 0
Multiply through by 10
49t²+240t-84 = 0
Factorize
t = -240±√240²-4(49(-84)/2(49)
t = -240±√57600+16464/98
t = -240±√74064/98
t = -240±272.15/98
t = 32.15/98
t = 0.328seconds
Hence it takes 0.328seconds before it lands on the ground below.
b) The horizontal distance is the range expressed as;
R = u²/g
R = 27²/9.8
R = 729/9.8.
R = 74.39m
a. The time it took before the motorcycle stunt driver lands on the ground below is 1.31 seconds.
b. The distance from the base of the cliff that the motorcycle stunt driver traveled while in the air is 31.44 meters.
Given the following data:
Maximum height = 8.4 meters.Initial velocity = 24 m/s.We know that the acceleration due to gravity (g) of an object on planet Earth is equal to 9.8 [tex]m/s^2[/tex]
a. To determine how long (time) it took before the motorcycle stunt driver lands on the ground below:
At maximum height, time is given by the formula:
[tex]Time = \sqrt{\frac{2H}{g} }[/tex]
Where:
g is the acceleration due to gravity.H is the maximum height.Substituting the given parameters into the formula, we have;
[tex]Time = \sqrt{\frac{2\times 8.4}{9.8} }\\\\Time = \sqrt{\frac{16.8}{9.8} }\\\\Time =\sqrt{1.7413}[/tex]
Time = 1.31 seconds.
b. To determine how far (distance) away from the base of the cliff the motorcycle stunt driver traveled while in the air:
[tex]Horizontal\;distance = horizontal\;speed \times time\\\\Horizontal\;distance = 24 \times 1.31[/tex]
Horizontal distance = 31.44 meters.
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During a laboratory experiment, the temperature of the gas in a balloon is varied and the
volume of the balloon is measured.
A)
Which quantity is the independent variable?
B)
Which quantity is the dependent variable?
An airplane is flying with velocity of 70km\hr in north east direction .The wind is blowing 30km\hr from north to south.What is the resultant displacement of the aeroplane in 4 h
Answer:
The resultant displacement of the airplane in 4 hours is 212.8 km.
Explanation:
The components of the airplane's velocity and wind's velocity are:
Airplane:
[tex] v_{a_{x}} = v_{a}cos(45) = 70 km/h*cos(45) = 49.50 km/h [/tex]
[tex] v_{a_{y}} = v_{a}sin(45) = 70 km/hsin(45) = 49.50 km/h [/tex]
Wind:
[tex] v_{w_{x}} = 0 [/tex]
[tex] v_{w_{y}} = v_{w} = -30 km/h [/tex]
Now, to know the new velocity of the airplane we to find the result vector:
[tex] v_{x} = v_{a_{x}} + v_{w_{x}} = 49.50 km/h + 0 = 49.50 km/h [/tex]
[tex]v_{y} = v_{a_{y}} + v_{w_{y}} = 49.50 km/h - 30 km/h = 19.50 km/h[/tex]
Now, the magnitude of the new speed of the airplane is:
[tex] v_{a} = \sqrt{v_{x}^{2} + v_{y}^{2}} = \sqrt{(49.50 km/h)^{2} + (19.50 km/h)^{2}} = 53.20 km/h [/tex]
Finally, after 4 hours the resultant displacement of the airplane is:
[tex] x = v*t = 53.20 km/h*4 h = 212.8 km [/tex]
Therefore, the resultant displacement of the airplane in 4 hours is 212.8 km.
I hope it helps you!
what are the Standard System of unit
Answer:
SI
Explanation: