The convection zone is the area of the sun does gas rise as it heats up, then fall back down as it cools.
What is Convection zone?This part of the Sun is found below the photosphere and helps isn the area where the form of heat transfer known as Convection takes place.
This occurs when heated gases rise up and then falls back when cooled as a result if hot gases being less dense.
Read more about Convection zone here https://brainly.com/question/22542880
(a) Which force is involved in kicking a ball?
i. frictional force
ii.gravity
iii. pushing force
iv. centrifugal force
Question 22 of 32
When a pitcher throws a baseball, it reaches a top speed of 42 m/s. If the
baseball takes 2 seconds to travel from the pitcher to the catcher, what is its
acceleration? (Assume the ball is moving at 0 m/s right before it leaves the
pitcher's hand.)
A 36 m/s
B 48 m/s
C 15 m/s
D 21 m/s
HELP!
Answer:
D 21m/s
Explanation:
because when it leaves the pitcher hand it then possess kinetic energy
The
of a waveform is the number of cycles per second.
O period
O intensity
O frequency
O amplitude
Answer:
frequency is the correct answer for the question if the answer is correct plz mark me as brainliest.
An electromagnetic wave is generated by:
Answer:
Electromagnetic waves are produced whenever electric charges are accelerated. This makes it possible to produce electromagnetic waves by letting an alternating current flow through a wire, an antenna. The frequency of the waves created in this way equals the frequency of the alternating current.
Explanation:
option are
cerebrum, cortex, cerebellum, brain stem, medulla, pons, midbrain , thalamus, hypothalamus, reticular formation
1.________regulates and maintains brain's awareness level.
2. _______controls the activity of the pituitary gland.
3._______relays impulses from one part of the brain to another.
4._______regulates body temperature, hunger, and other internal body conditions.
5______connects nerve impulses from body to cortex.
Answer:
1. Reticular formation.
2. Hypothalamus.
3. Thalamus.
4. Hypothalamus.
5. Thalamus.
Explanation:
The human brain consists of various sections and these includes;
I. Anterior Cingulate Cortex (ACC) which resembles a bow or collar surrounding the frontal part of the corpus callosum. This is the frontal part of the cingulate cortex which helps to make complex cognitive functions such as impulse control, decision-making, emotions and empathy.
II. Ventral prefrontal cortex in humans are interconnected with the brain and are responsible for the processing of risk, empathy, fear and social decision-making
III. The Cerebral Cortex: this part of the brain primarily comprises of grey matter, foldable sheets of neurons and forms its outermost layer. Therefore, cerebral cortex is known as the outermost layer of the brain (cerebrum) and thus, makes up half of its weight. It is about 2.5 millimeters in thickness and as such it's able to fold.
1. Reticular formation: regulates and maintains brain's awareness level.
2. Hypothalamus: controls the activity of the pituitary gland.
3. Thalamus: relays impulses from one part of the brain to another.
4. Hypothalamus: regulates body temperature, hunger, and other internal body conditions.
5. Thalamus: connects nerve impulses from body to cortex.
The frequency of a generated electromagnetic wave matches the
A) field strength of the fields.
B) energy of the fields.
C) frequency of vibrating charges that produced it.
D) frequency of domains in the magnetic part of the wave.
Answer:
C) frequency of vibrating charges that produced it.
A car is traveling at a constant speed of 33 m/s on a highway. At the instant this car passes an entrance ramp, a second car enters the highway from the ramp. The second car starts from rest and has a constant acceleration. What acceleration must it maintain, so that the two cars meet for the first time at the next exit, which is 2.5 km away
Answer:
0.8712 m/s²
Explanation:
We are given;
Velocity of first car; v1 = 33 m/s
Distance; d = 2.5 km = 2500 m
Acceleration of first car; a1 = 0 m/s² (constant acceleration)
Velocity of second car; v2 = 0 m/s (since the second car starts from rest)
From Newton's equation of motion, we know that;
d = ut + ½at²
Thus,for first car, we have;
d = v1•t + ½(a1)t²
Plugging in the relevant values, we have;
d = 33t + 0
d = 33t
For second car, we have;
d = v2•t + ½(a2)•t²
Plugging in the relevant values, we have;
d = 0 + ½(a2)t²
d = ½(a2)t²
Since they meet at the next exit, then;
33t = ½(a2)t²
simplifying to get;
33 = ½(a2)t
Now, we also know that;
t = distance/speed = d/v1 = 2500/33
Thus;
33 = ½ × (a2) × (2500/33)
Rearranging, we have;
a2 = (33 × 33 × 2)/2500
a2 = 0.8712 m/s²
Atoms of elements in the same group have the same
Explanation:
The elements in each group have the same number of electrons in the outer orbital. Those outer electrons are also called valence electrons. They are the electrons involved in chemical bonds with other elements.
State the relation between acceleration and momentum
Answer:
Acceleration is the rate of change of velocity. Momentum is the mass times the velocity. So if you multiply the mass times the acceleration, you get the rate of change of momentum
A penny is dropped from the top of a One World Trade Center (541.3 m tall). Ignoring air resistance, how long would it take for the penny to strike the ground?
Answer:
i would think a couple of seconds
Darcy suffers from farsightedness equally severely in both eyes. The focal length of either of Darcy's eyes is 19.8 mm in its most accommodated state (i.e, when the eye is focusing on the closest object that it can clearly see) What lens strength (a.k.a., lens power) of contact lenses should be prescribed to correct the farsightedness in Darcy's eyes? (Assume the lens-to retina distance of Darcy's eyes is 2.00 cm, and the contact lenses are placed a negligibly small distance from the front of Darcy's eyes)
i. 1.64D
ii. 2.98 D
iii. 2.19 D
iv. 3.49 D
v. 1.37 D
Answer:
Explanation:
Power of defective eye = (1 / near point )+ (1 / lens-retina distance )
1 / .0198 m = (1 / near point )+ (1 / .02 m )
= 50.50 = (1 / near point )+ 50
0.50 = 1 / near point
near point = 1 / .5 = 2m
= 200 cm .
for near point at 25 cm , convex lens will be required.
u = - 25 cm , v = - 200 cm ,
1 / v - 1 / u = 1 /f for lens
- 1 / 200 + 1 / 25 = 1 / f
= .04 - .005 = 1 /f
.035 = 1 / f
f = 28.57 cm = 0.2857 m
power = 1 /f
= 1 / 0.2857
= 3.5 D .
i v ) option is correct .
Work of 2 Joules is done in stretching a spring from its natural length to 14 c m beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (14 c m )
Answer:
F =28.57 N
Explanation:
Assuming that the spring is ideally followed Hooke's law, This means
F=kx
Here F is the force required to stretch or compress the spring through x distance.
the amount of the work done in the displacement of the spring would be:
W = ∫F.dx
=∫kx dx
=1/2kx^2
=1/2k×0.14^2
⇒ 0.0098k =2
⇒ k = 204.081
Therefore, the force (in Newtons) that holds the spring stretched at the same distance.
F = 204.081×0.14
F =28.57 N
A compound consisting of Cr3+ ions and OH ions would be named chromium (III) hydroxide
True or false
The temperature of 10 kg of a substance rises by 55oC when heated. Calculate the
temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Given :
The temperature of 10 kg of a substance rises by 55oC when heated.
To Find :
The temperature rise when 22 kg of the substance is heated with the same quantity of heat.
Solution :
We know, change in temperature when heat is given to object is given by :
[tex]\Delta H = m S\Delta T[/tex]
It is given that same amount of heat is given in both the cases also the substance is same.
So,
[tex]M_1 S \Delta T_1 = M_2 S \Delta T_2\\\\10\times 55 = 22 \times \Delta T_2\\\\\Delta T_2 = 25^o\ C[/tex]
Hence, this is the required solution.
If the torque on an object adds up to zero Group of answer choices the object is at rest. the object cannot be turning. the object could be accelerating linearly but it could not be turning. the forces on it also add up to zero. the object could be both turning and accelerating linearly.
Answer:
the body has linear acceleration, but cannot rotate
Explanation:
Let's analyze the system
If the torque is zero, the two forces are the same magnitude, but applied to each side of the body in such a way that the torque cancels the punch of the other. Therefore the body cannot turn
The two forces go in the same direction so the object can have linear acceleration
The object is at rest because it has a force in the same direction, but in the opposite direction.
therefore the correct answer is:
the body has linear acceleration, but cannot rotate
If U= <4, -6> and V= <-3, 8> Find U+V
Answer:
[tex]\langle 1,\, 2\rangle[/tex].
Explanation:
Both [tex]U[/tex] and [tex]V[/tex] are two-dimensional vectors. In other words, each of them has two components. Each component is a number.
When adding two vectors, add each component separately. The sum should include the same number of components as the vectors that are being added.
Since [tex]U[/tex] and [tex]V[/tex] has two components each, their sum, [tex](U + V)[/tex], would also include two components.
Sum the first components of [tex]U[/tex] and [tex]V[/tex] to find the first component of [tex](U + V)[/tex]: [tex]4 + (-3) = 1[/tex].
Similarly, sum the second components of [tex]U[/tex] and [tex]V[/tex] to find the second component of [tex](U + V)[/tex]: [tex]-6 + 8 = 2[/tex].
Hence, [tex](U + V) = \langle 1,\, 2 \rangle[/tex].
Q11:A police car in hot pursuit goes speeding past you. While the siren is approaching, the frequency of the sound you hear is 5500 Hz. When the siren is receding away from you, the frequency of the sound is 4500 Hz. Use the Doppler formula to determine the velocity of the police car. Use vsound
Answer:
v_s = 34.269 m / s
Explanation:
This is a Doppler effect exercise, in this case the observer is fixed and the sound source is moving.
f ’= f [tex]\frac{v}{v \mp v_s }[/tex]
where the negative sign is used for when the source approaches the observer and the positive sign for when the source moves away from the observer
In this case when f ’= 5500 Hz approaches and when f’ = 4500 Hz moves away, let's write the two expressions together
5500 = f ([tex]\frac{v}{v - v_s }[/tex])
4500 = f ( [tex]\frac{v}{v + vs}[/tex])
let's solve these two equations
[tex]\frac{5500}{4500} = \frac{v+v_s}{v-v_s}[/tex]
1.222 (v-v_s) = v + v_s
v_s (1+ 1.22) = v (1.222 -1)
v_s = v [tex]\frac{0.222}{2.223}[/tex]
the speed of sound in air is v = 343 m / s
v_s = 343 0.09990
v_s = 34.269 m / s
A 2.6 mm -diameter sphere is charged to -4.5 nC . An electron fired directly at the sphere from far away comes to within 0.37 mm of the surface of the target before being reflected. Part A What was the electron's initial speed
Answer: [tex]1.96\times 10^{8}\ m/s[/tex]
Explanation:
Given
Diameter of sphere is [tex]d=2.6\ mm\quad \quad[r=1.3 mm][/tex]
Charge on the sphere is [tex]Q=-4.5\ nC[/tex]
Nearest distance electron can reach to sphere is [tex]d=0.37\ mm[/tex]
Here, kinetic energy of electron is converted into electrostatic energy between the two i.e.
[tex]\Rightarrow \dfrac{1}{2}mv^2=\dfrac{kQq}{d}\\\\\Rightarrow \dfrac{1}{2}\times 9.1\times 10^{-31}\times v^2=\dfrac{9\times 10^9\times 4.5\times 10^{-9}\times 1.6\times 10^{-19}}{(3.7\times 10^{-4})}\\\\\Rightarrow v^2=3.8491\times 10^{16}\\\Rightarrow v=1.96\times 10^{8}\ m/s[/tex]
Thus, the initial speed of electron is [tex]1.96\times 10^{8}\ m/s[/tex].
A tennis ball and a bag filled with sand have the same mass. They are dropped from the same height and they hit the ground. The bag of sand stays on the ground, while the tennis ball rebounds. Which experiences the larger impulse from the ground?
Answer:
The bag of sand
Explanation:
I think it is the bag of sand because according to the definition of impulse, impulse is the average force acting on a particule when an external force is being acted on it.
A trumpet player hears 5 beats per second when she plays a note and simultaneously sounds a 440 Hz tuning fork. After pulling her tuning valve out to slightly increase the length of her trumpet, she hears 3 beats per second against the tuning fork. Was her initial frequency 435 Hz or 445 Hz? Explain.
Answer:
her initial frequency is 445 Hz
Explanation:
Given;
initial beat frequency, [tex]F_B[/tex] = 5
observed frequency, F = 440 Hz
let the initial frequency = F₁
F₁ = F ± 5 Hz
F₁ = 440 Hz ± 5 Hz
F₁ = 435 or 445 Hz
This result obtained shows that her initial frequency can either be 435 Hz or 445 Hz
The last beat frequency will be used to determine the actual initial frequency.
F = v/λ
Frequency (F) is inversely proportional to wavelength. That is an increase in length will cause a proportional decrease in frequency.
This shows that the final frequency is smaller than the initial frequency because of the increase in length.
Initial frequency - frequency of tuning fork = 5 beat frequency
Reduced initial frequency - frequency of tuning fork = 3 beat frequency
Initial frequency = 5Hz + 440 Hz = 445 Hz
Final frequency (Reduced initial frequency) = 440 + 3 = 443 Hz
Check: 445 Hz - 440 Hz = 5 Hz
443 Hz - 440 Hz = 3 Hz
Which three gasses that contribute most to Climate Change?
ans) 1.Green House gasses 2. carbon dioxide 3.nitrious gases
Answer:
Water vapor.
Carbon dioxide.
Methane.
Ozone.
Nitrous oxide.
Chlorofluorocarbons.
Explanation:
thank me later
How many does the stor6 need
Calculate the mass of earth
earth assum
assuming
that it i a
6.67x106m.
Sphere with radius
Answer:
[tex]m=6.85\times 10^{24}\ kg[/tex]
Explanation:
The radius of Earth is [tex]6.67\times 10^6\ m[/tex]
The density of an object is given by :
[tex]d=\dfrac{m}{V}[/tex]
The density of Erth is, d = 5515 kg/m³
Where
m is the mass of the Earth
So,
[tex]m=d\times V\\\\m=\dfrac{4}{3}\pi r^3\times d[/tex]
Put all the values,
[tex]m=\dfrac{4}{3}\pi \times (6.67\times 10^6)^3\times 5515 \\\\m=6.85\times 10^{24}\ kg[/tex]
So, the mass of the Earth is equal to [tex]6.85\times 10^{24}\ kg[/tex].
when a car climbs a hill, it only has potential energy
True or false
t
Explanation:
true , a car climbs a hill, it only has potential energy
Answer:
As the car begins to roll down the hill, it loses potential energy, but gains kinetic energy. The potential energy of the position of the car at the top of the hill is getting converted into kinetic energy. Where "g" is the standard acceleration of gravity which equals 9.8 m/s2.
Explanation:
They realize there is a thin film of oil on the surface of the puddle. If the index of refraction of the oil is 1.81, and they observe the reflected light in the air to be orange (wavelength of 600 nm), what is the thickness of the film of oil in nanometers? Give your answer with one decimal place please.
Answer:
The right solution is "165.8 nm".
Explanation:
Given:
Index of refraction,
n = 1.81
Wavelength,
λ = 600 nm
We know that,
⇒ [tex]t=\frac{\lambda}{2\times n}[/tex]
By putting the values, we get
[tex]=\frac{600}{2\times 1.81}[/tex]
[tex]=165.8 \ nm[/tex]
which wave characteristic is the same for all electromagnetic waves traveling through a vacuum?
Answer:
All waves travel at the same speed c.
a uniform disk is rotating about a stationary acis at its center. the initial angular speed of the disk is 28 rad/s. then a torque is aplied and the disks dlows down. the disks comes to rest 5 seconds after the torque is applied. how many revoluation did the disk turn through before stopping
4. A 268 kg boulder rolls down a hill. If it had 50,000 J of energy to start with, how high was the hill? (Can anyone explain or give the equation for it? Thank you!)
Answer:
h = 18.65 m
Explanation:
Given that,
The mass of a boulder, m = 268 kg
The potential energy at the hill, E = 50,000 J
We need to find the height of the hill.
We know that, the potential energy of an object is given by :
E = mgh
Where
h is the height of the hill
So,
[tex]h=\dfrac{E}{mg}\\\\h=\dfrac{50000}{268\times 10}\\\\h=18.65\ m[/tex]
So, the height of the hill is 18.65 m.
[tex]\\ \sf\longmapsto PE=mgh[/tex]
[tex]\\ \sf\longmapsto 50000=268(10)h[/tex]
[tex]\\ \sf\longmapsto 50000=2680h[/tex]
[tex]\\ \sf\longmapsto h=\dfrac{50000}{2680}[/tex]
[tex]\\ \sf\longmapsto h=18.65m[/tex]
What is one reason why humans cannot live on the planet Jupiter?
A. The gravity is too strong
B. All are reasons why people cannot live on Jupiter
C. The surface is hotter there than the Earth
D. The planet is too rocky
B all are reasons why people cannot live in jupiter
As part of an exercise program, a woman walks south at a speed of 2.8 m/s for 46 minutes. She then turns around and walks north a distance 3,132 m in 54 minutes . What is the woman's average speed in m/s during her entire motion
Answer:
[tex]A_[avg}=1.81m/s[/tex]
Explanation:
From the question we are told that:
North Movement
Velocity[tex]V=2.8[/tex]
Time [tex]t=46 minuites[/tex]
South movement
Distance [tex]d=3,132[/tex]
Time [tex]t'= 54 minutes[/tex]
Generally the equation for Average Velocity is mathematically given by
[tex]A_[avg}\]frac{Total distance}{Total time}[/tex]
Where
Total distance d_t
[tex]d_t=Souther\ distance\ traveled\ +Northern\ distance\ traveled[/tex]
[tex]d_t=(2.8*46*60)+(3132)[/tex]
[tex]d_t=10860[/tex]
An
Total Time
[tex]T=(46+54)60[/tex]
[tex]T=6000[/tex]
Therefore
[tex]A_[avg}=\frac{d_t}{T}[/tex]
[tex]A_[avg}=\frac{10860}{6000}[/tex]
[tex]A_[avg}=1.81m/s[/tex]