How do you label a bar graph of work compared with power?
Answer:
You must label the horizontal axis with the names of the airlines and the vertical axis with the number of flights. The title must clearly state what data the bar chart is showing. With larger numbers, your scale may not go up by one.
Answer:
You must label the horizontal axis with the names of the airlines and the vertical axis with the number of flights. The title must clearly state what data the bar chart is showing. With larger numbers, your scale may not go up by one.
Explanation:
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What happens when a moving object is moving a particular direction experiences a net force opposite the direction?
Answer:
stop
Explanation:
object stop
Answer:
If two forces of equal strength act on an object in opposite directions, the forces will cancel, resulting in a net force of zero and no movement. Two or more opposite forces are balanced forces if their effects cancel each other and they do not cause a change in an object's motion.
When a rocket is 4 kilometers high, it is moving vertically upward at a speed of 400 kilometers per hour. At that instant, how fast is the angle of elevation of the rocket increasing, as seen by an observer on the ground 5 kilometers from the launching pad
Answer:
The angle of elevation of the rocket is increasing at a rate of 48.780º per second.
Explanation:
Geometrically speaking, the distance between the rocket and the observer ([tex]r[/tex]), measured in kilometers, can be represented by a right triangle:
[tex]r = \sqrt{x^{2}+y^{2}}[/tex] (1)
Where:
[tex]x[/tex] - Horizontal distance between the rocket and the observer, measured in kilometers.
[tex]y[/tex] - Vertical distance between the rocket and the observer, measured in kilometers.
The angle of elevation of the rocket ([tex]\theta[/tex]), measured in sexagesimal degrees, is defined by the following trigonometric relation:
[tex]\tan \theta = \frac{y}{x}[/tex] (2)
If we know that [tex]x = 5\,km[/tex], then the expression is:
[tex]\tan \theta = \frac{y}{5}[/tex]
And the rate of change of this angle is determined by derivatives:
[tex]\sec^{2}\theta \cdot \dot \theta = \frac{1}{5}\cdot \dot y[/tex]
[tex]\frac{\dot \theta}{\cos^{2}\theta} = \frac{\dot y}{5}[/tex]
[tex]\frac{\dot \theta\cdot (25+y^{2})}{25} = \frac{\dot y}{5}[/tex]
[tex]\dot \theta = \frac{5\cdot \dot y}{25+y^{2}}[/tex]
Where:
[tex]\dot \theta[/tex] - Rate of change of the angle of elevation, measured in sexagesimal degrees.
[tex]\dot y[/tex] - Vertical speed of the rocket, measured in kilometers per hour.
If we know that [tex]y = 4\,km[/tex] and [tex]\dot y = 400\,\frac{km}{h}[/tex], then the rate of change of the angle of elevation is:
[tex]\dot \theta = 48.780\,\frac{\circ}{s}[/tex]
The angle of elevation of the rocket is increasing at a rate of 48.780º per second.
Object 1 has a momentum of 10 kg m/s and Object 2 has a momentum of 25 kg m/s. Will it be easier to change the direction of movement of Object 1 or of Object 2?
Answer:
I think its object 1
Explanation:
Because the object that has more weight has a greater momentum and the lightest object that has a less momentum will be easier to change because its lighter.
(iii) Gareth cycles 5 laps at this constant spoed. Each lap is 500m.
Calculate the distance he travels.
I
Distance
Answer:
2500 m
Explanation:
Given that,
Each lap is 500 m
Gareth takes 5 laps.
We need to find distance traveled by Gareth. The distance covered by him is given by :
d = 5×500
d = 2500 m
Hence, he will travel 2500 m.
PLS HELP
SHOW WORK
A car starting from rest accelerates at a rate of 1.5 m/s ^ 2 What is its final speed at the end of 18.0 seconds ?
Answer:
27 ms^-1
Explanation:
by using v= u + at
u = 0 ( because the object id starting from rest)
v= 0 + 1.5 x 18
v = 27 ms^-1
ANSWER SOON
3. Let's say we have 3 kg of iron at 100 C, and it touches a 15kg iron at 20 C. Explain what is going to happen in detail in terms of internal energy, temperature, and heat. (you can explain it with just words)
Answer:
one of the mjor effects of heat transfer is temperature change
Explanation:
simple answer
A spring stretches 5 cm when a 300-N mass is suspended from it. Calculate the spring constant in N / m .
Answer:
Spring constant in N / m = 6,000
Explanation:
Given:
Length of spring stretches = 5 cm = 0.05 m
Force = 300 N
Find:
Spring constant in N / m
Computation:
Spring constant in N / m = Force/Distance
Spring constant in N / m = 300 / 0.05
Spring constant in N / m = 6,000
determine the value of a and K when 0.51 is written is scientific nation
Answer:
The value 0.51
Explanation:
What variables affect density weight,conductivity,color,volume, or mass
Answer:
Density is affected by volume and mass.
Explanation:
Density is defined as the quantity of mass per unit of volume, or expressed mathematically, d = m/v.
Question 1 of 10
Which object has the most gravitational potential energy?
A. A 8 kg book at a height of 2 m
B. An 8 kg book at a height of 3 m
C. An 5 kg book at a height of 3 m
D. A5 kg book at a height of 2 m
SUBMIT
Answer:
B = An 8 kg book at a height of 3 m
Physics, calculating net force. Please work it out for me
Answer:
F = 2985.125 N
Explanation:
Given that,
The radius of curvature of the roller coaster, r = 8 m
Speed of Micheal, v = 17 m/s
Mass of body, m = 65 kg We need to find the net force acting on Micheal. Net force act the bottom of the circle is given by :
[tex]F=\dfrac{mv^2}{r}+mg\\\\F=m(\dfrac{v^2}{r}+g)\\\\=65(\dfrac{17^2}{8}+9.8)\\\\=2985.125\ N[/tex]
So, the net force is 2985.125 N.
Two automobiles, each of mass 1000 kg, are moving at the same speed, 20 m/s, when they collide and stick together. In what direction and at what speed does the wreckage move (a) if one car was driving north and one south (b) if one car was driving north and one east?
A. The wreckage after collision is moving at the speed 18 m/s to the south.
B. The wreckage after collision is moving at the speed 9.0 m/s to the north.
C. The wreckage after collision is moving at the speed 9.0 m/s to the south.
D. The wreckage after collision is moving at the speed 18 m/s to the north.
E. The wreckage after collision is motionless.
Answer:
The reckage after collision is motionless (E)
Explanation:
The first law of thermodynamics states that energy is neither created nor destroyed but is converted from one form to another.
The kind of collision described in the question above is known as a perfectly inelastic collision, and in this type of collision, the maximum kinetic energy is lost because the objects moving in opposite directions have a resultant momentum that is equal, but in opposite directions hence they cancel each other out.
The calculation is as follows:
m₁v₁ + m₂v₂
where:
m₁ = m₂ = 1000kg
v₁ = 20 m/s
v₂ = -20 m/s ( in the opposite vector direction)
∴ resultant momentum = (1000 × 20) + (1000 × -20)
= 20000 - 20000 = 0
∴ The reckage after collision is motionless
Answer:
The wreckage after collision is moving at the speed 18 m/s to the south.
Explanation:
A student at a polymer lab conducted a stress-relaxation experiment on a polymer, whose material response can be modeled by the Maxwell model. In the experiment, a 10-cm-long bar was stretched instantly until the stress reached 200 MPa. After 2 min, the measured stress in the bar was 160 MPa. a) Calculate the relaxation time constant of the polymer. b) If the initial stress was reached by stretching the bar by 16 mm, what is the viscosity of the dashpot in the Maxwell model
Answer: add 10 cm plus 200 mpa divided by 2 min then caculate that into 160 bars.
Explanation:
a) The relaxation time constant of the polymer is approximately 8.9 min.
b) The viscosity of the dashpot in the Maxwell model is approximately 4.55 GPa s.
What is the stress-relaxation model?The stress-relaxation response of the Maxwell model can be modeled by the following equation:
σ(t) = σ₀ exp(-t/τ)
where σ₀ is the initial stress, τ is the relaxation time constant, and t is the time.
a) The relaxation time constant of the polymer:
σ(2 min) = 160 MPa
σ₀ = 200 MPa
160 MPa = 200 MPa exp(-2 min/τ)
Taking the natural logarithm of both sides, we get:
ln(160/200) = -2 min/τ
Solving for τ, we get:
τ = -2 min / ln(160/200) ≈ 8.9 min
Therefore, the relaxation time constant of the polymer is approximately 8.9 min.
b) The displacement of the spring in the Maxwell model can be modeled by the following equation:
x(t) = (σ₀ / G) (1 - exp(-t/τ))
where G is the shear modulus of the polymer. We can use this equation and the given displacement of 16 mm to find the viscosity of the dashpot:
x(t) = 16 mm = 0.016 m
σ₀ = 200 MPa
τ = 6.09 min = 365.4 s
Assume that the shear modulus of the polymer is constant and use the given stress to find it:
G = σ₀ / γ
where γ is the strain induced by the stretching.
Since the bar was stretched by 16 mm and its original length was 10 cm (i.e., 100 mm), the strain is:
γ = 16 mm / 100 mm = 0.16
Therefore,
G = 200 MPa / 0.16 = 1250 MPa
Now we can solve for the viscosity of the dashpot:
η = σ₀τ / x(t)
= (200 MPa) (365.4 s) / (0.016 m)
≈ 4.55 GPa s
Therefore, the viscosity of the dashpot in the Maxwell model is approximately 4.55 GPa s.
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A ball is thrown straight up with an initial velocity of 128 ft/sec, so that its height (in feet) after t sec is given by s(t) = 128t-16t2. (a) What is the average velocity of the ball over the following time intervals? [3,4] ft/sec [3,3.5] ft/sec [3,3.1] ft/sec (b) What is the instantaneous velocity at time t = 3? ft/sec (c) What is the instantaneous velocity at time t = 6? ft/sec Is the ball rising or falling at this time? rising falling (d) When will the ball will hit the ground? t = sec
Answer:
one sec let me think
Explanation:
(a)The average velocity of the ball over the following time intervals will be [3,4] ft/sec.
(b)The instantaneous velocity at time t = 3 will be32 ft/sec.
(c)The instantaneous velocity at time t = 6 will be -64 ft/sec.
(d)The ball will hit the ground at 13.4 sec.
What is velocity?The change of displacement with respect to time is defined as the velocity. velocity is a vector quantity. it is a time-based component.
The given data in the question will be ,
u is the initial velocity by which ball thrown=128 ft/sec.
V₃ is the instantaneous velocity at time t=3 sec.
V₆ is the instantaneous velocity at time t=6 sec.
t is the time when ball hits the ground=?
(a) Given equation for the displacement
s(t) =128t-16t² (on differenting got the velocity )
v(t) = 128-32t
Time when velocity is zero will be
[tex]\rm{ t=\frac{128}{32}[/tex]
[tex]\rm{ t=4 sec[/tex]
If the velocity got in the equation is 128 and 32 ft /sec. it can be only when the average velocity is [3,4] ft/sec .
Hence the average velocity obtained from the problem will be [3,4] ft/sec
(b)
s(t) =128t-16t² (on differenting got the velocity )
v(t) = 128-32t
At time( t=3 sec)
v(3) = 128-32×3
v(3) =32 m/sec.
Hence the instantaneous velocity at time t = 3 will be32 ft/sec.
(c)
s(t) =128t-16t² (on differenting got the velocity )
v(t) = 128-32t
At time( t=6 sec)
v(6) = 128-32×6
v(6) = -64 m/sec.
Hence the instantaneous velocity at time t = 6 will be -64 ft/sec.
(d)
According to Newtons third equation of motion we got
v=u+gt
If the body returens from a certain height at max height its velocity must be zero; ( u=0)
[tex]\rm t=\frac{(v-u)}{g} \\\\\ \rm t=\frac{(128-0)}{9.81}\\\\\rm t=13.04 sec.[/tex]
Hence the ball will hit the ground at 13.4 sec.
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How does the current in a series circuit compare
Name the principle which states that energy
cannot be created or destroyed, merely
transferred from one form to another:
Answer:
the Laws of Thermodynamics
Explanation:
these laws states that no form of energy can be created by anyone or anything, without a previous and equal input of energy being put in, that energy can only be transferred from object to object and through different forms
Example: the way a heater runs to warm up an area, that is the process of electrical energy, or energy stored in propane being converted into heat energy
this law is universally implied and has been proven on multiple accounts to be true, in no way can you create energy out of thin air, all you can do is transform and transfer it
hope this is what you was going for, very good point in science
this is one of two correct answers, the other answer to this question is also correct
Select True or False for the following statements about electromagnetic waves. A vertical automobile antenna is sensitive to electric fields polarized horizontally. Ultraviolet radiation causes common sunburn. Radio waves travel in vacuum at a lower speed than the visible light. The sun's radiation is most intense in the visible region. Gamma rays can be produced in transitions of an atomic nucleus from one state to another. Radio waves have wavelengths longer than 1 m. X-rays travel in vacuum at a higher speed than the visible light.
Answer:
a) False, b) True, c) true, d) true, e) True, g) False
Explanation:
Se pide que analicemos cada expresión, f) true
a) False. La antena vertical tiene cargas eléctricas que se pueden mover en la direccion vertical, una onda electromagnética polarizada horizontal el campo eléctrico esta en la dirección horizontal por lo cual no puede mover los electrones que están en direccional vertical
be) True. La radiación ultravioleta es absorvidad por la melanina del la piel y crea las quemaduras comunes de insolación.
C) False. Todas la ondas electromagnetismo viajan en la misma velocidad c
d) True. La Temperatura del sol es 5800K por lo cual la radiación mas intensa esta en el rango visible
e) True. Los rayos gamma son de muy alta energía, por lo cual se producen en ransicio0n de los núcleos atmicos.
f) True. El rango de frecuencia para las onda de radio va desde 500 Kahoy hasta 110 MHz, por lo tanto el rango de longitudes de onda es
c= lam f
lam = c/f
lam = 3 108/500 103
lam = 6 102 m
lam = 3 108 / 110 106
lam = 2,72 m
los lo ttnato en todo el rango de las frecuecias de radio la lambda> 1 m
g) False. Todas las ondas electromagnéticas viajan a la misma velocidad c( 3 108m/s)
A city near the ocean experiences thunderstorms on a frequent basis. Which of these is the BEST explanation for this?
A.
The interactions of the waves with the landmass change the air pressure to cause thunderstorms.
B.
The cold fronts that form only over coastal areas cause thunderstorms.
C.
The amount of sunshine received by coastal areas causes thunderstorms.
D.
The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms.
Answer:
d
Explanation:
The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms. So, option D is correct.
What is meant by heat energy ?Heat energy of a system is defined as the energy transferred between the molecules due to the temperature difference between them. Heat energy is the energy responsible for the temperature of the molecules.
Here,
A city near the ocean experiences thunderstorms on a frequent basis. This is because,
The atmosphere near to the land is highly humid and warm and thus creates a relatively low pressure in the land. In order to balance the pressure variation the air from the oceans make movements towards the land, and as a result, sea breeze are formed. During the evenings when the water in the ocean is more warm and when land begins to cool, the air from land rushes towards the sea, in order to balance the pressure variation occurred here. This makes the air above the ocean highly humid and thus would lead to the formation of thunderstorms.
Hence,
The uneven heating of land and water in coastal areas creates fronts that cause thunderstorms.
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19. In a turtle race, a 20 kg turtle moves with a velocity of 0.1 m/s. What is the kinetic energy of the turtle?
A. 20 J
B. 0.2 J
C. 0.1 J
What factors determine electric potential?
A. Mass and distance
B. Charge and density
C. Charge and distance
O D. Mass and charge
Answer: C. Charge and distance
Suppose that a uniform rope of length L resting on a frictionless horizontal surface, is accelerated along the direction of its length by means of a force F, pulling it at one end. A mass M is accelerated by the rope. Assuming the mass of the rope to be m and the acceleration is a. Stated in terms of the product ma, what is the tension in the rope at the position 0.3 L from the end where the force F is applied if the mass M is 1.5 times the mass of the rope m?
Answer:
2.2 ma
Explanation:
Given :
Length of the rope = L
Mass of the rope = m
Mass of the object pulled by the rope = M
M = 1.5 m
So, L [tex]$\rightarrow$[/tex] m
For unit length [tex]$\rightarrow \frac{m}{L}$[/tex]
∴ 0.3 L = [tex]$0.3 \ L \left(\frac{m}{L}\right)$[/tex]
= 0.3 m
And for remaining 0.7 L = [tex]$0.7 \ L \left(\frac{m}{L}\right)$[/tex]
= 0.7 m
By Newtons law of motion,
F - T = ( 0.3 m) a .........(1)
T = ( M + 0.7 m) a
T = ( 1.5 m + 0.7 m) a
T = ( 2.2 m ) a ..............(2)
So from equation (1) and (2), we have
Tension on the rope
T = 2.2 ma
A spring has a spring constant of 65.5 N/m and it is
stretched with a force of 15.3 N. How far will it stretch?
Two teams of nine members each engage in a tug of war. Each of the first team's members has an average mass of 64 kg and exerts an average force of 1350 N horizontally. Each of the second team's members has an average mass of 69 kg and exerts an average force of 1367 N horizontally. (a) What is the acceleration (in m/s2 in the direction the heavy team is pulling) of the two teams
Answer:
[tex]a=0.13m/s^2[/tex]
Explanation:
From the question we are told that
Mass of first team man [tex]m_1=64kg[/tex]
Force of man first team man [tex]F_1=1350[/tex]
Mass of second team man [tex]m_2=69kg[/tex]
Force of man second team man [tex]F_2=1367N[/tex]
Generally the equation for net force F_n is mathematically given by
[tex]F_n=9(m_1+m_2)a[/tex]
[tex]9(m_1+m_2)a=9(f_2-f_1)[/tex]
[tex]9(64+69)a=9(1367-1350)[/tex]
[tex]a=\frac{9(1367-1350)}{9(64+69)}[/tex]
[tex]a=0.127819m/s^2[/tex]
Therefore the acceleration is given by
[tex]a=0.13m/s^2[/tex]
Help please :)
X-ray waves are transmitted by ....... ?
Answer:
im not sure maybe viberation
Explanation:
Answer:
X-ray waves are transmitted by ....... body tissues with very little absorption
Hope it helps
Please mark me as the brainliest
Thank you
___________is
objects total kinetic and potential energy.
Answer:
Bowling ball
Explanation:
He-Ne Laser device emits photons of wave length 632.8 nm by rate 4.5 x 1020 photon/s, so
the power of the laser beam =
a. 3.14 W
b. 141.3 W
c. 314.1 w
d. 431.4 W
Answer: Option b.
Explanation:
We know:
Wavelength = 632.8 nm
Fluence = 4.5*10^20 photon/s
The energy of a single photon of wavelength λ is:
E = (h*c)/λ
where:
h = 6.6*10^(-34) J*s
c = 3*10^8 m/s
And we should rewrite the wave length in meters, so:
λ = 632.8 nm = 632.8*10^(-9) m
replacing these in the energy equation, we get:
E = (6.6*10^(-34)J*s)*(3*10^8 m/s)/(632.8*10^(-9) m) = 3.13*10^(-19) J
So each one of the 4.5x10^20 photon that flow each second have this energy, then the power is:
P = (3.13*10^(-19) J)*(4.5*10^20 /s) = 140.85 J/s
and 1 W = 140.85 J/S
Then the power is:
P = 140.85 W
Then the correct answer is the option b, where the units are a little bit different than mine because I used really simplified values for c and h.
Can someone plz explain :
Two cars have the same mass, the first car is moving towards the east and the second is
stationary. If the two cars merge together after a collision and head towards the east their speed
after the collision is equal to.......
A)1/4vi b)1/2vi c)vi d) 2vi
Answer: Option b, the final velocity is half of the initial velocity.
Explanation:
Here we will use the conservation of the total momentum of a system.
This means that the total momentum at the beginning must be the same as the final momentum.
Where momentum is:
P = M*v
Initially, we have two cars, both with the same mass M, and only one of them has a velocity v.
Then the initial momentum is:
P = M*v + M*0 = M*v
After the collision, the two cars move together. Then the total mass that is moving is equal to the sum of the masses of the cars, this is 2*M
and we can suppose that the two cars move at a final velocity v'
Then the final momentum is:
P' = (2*M)*v'
Now we use the conservation of momentum, then:
P = P'
M*v = (2*M)*v'
Now we need to solve this for v'
(M*v)/(2*M) = v'
v/2 = v'
This means that the final velocity is half of the initial velocity.
Then the correct option is option b.
a rugby player passes the ball 5.34 m across the field, where it is caught at the same height as it left his hand. at what angle was the ball thrown if its initial speed was 7.7 m/s, assuming that the smaller of the two possible angles was used
Answer:
[tex]31.035^{\circ}[/tex]
Explanation:
x = Displacement in x direction = 5.34 m
t = Time taken to travel the displacement
y = Displacement in y direction = 0
u = Initial velocity of ball = 7.7 m/s
g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
Displacement in x direction is given by
[tex]x=u\cos\theta t\\\Rightarrow t=\dfrac{5.34}{7.7 \cos\theta}[/tex]
Displacement in y direction is given by
[tex]y=u\sin\theta t-\dfrac{1}{2}gt^2\\\Rightarrow 0=7.7\sin\theta \dfrac{5.34}{7.7\cos\theta}-\dfrac{1}{2}\times 9.81 (\dfrac{5.34}{7.7\cos\theta})^2\\\Rightarrow 0=7.7\sin\theta-4.905\times \dfrac{5.34}{7.7\cos\theta}\\\Rightarrow 0=7.7^2\sin\theta \cos\theta-4.905\times 5.34\\\Rightarrow 0=7.7^2\dfrac{\sin2\theta}{2}-4.905\times 5.34\\\Rightarrow 0=7.7^2\sin2\theta-4.905\times5.34\times 2\\\Rightarrow \sin2\theta=\dfrac{4.905\times 5.34\times 2}{7.7^2}\\\Rightarrow 2\theta=\sin^{-1}\dfrac{4.905\times 5.34\times 2}{7.7^2}[/tex]
[tex]\Rightarrow \theta=\dfrac{62.07}{2}\\\Rightarrow \theta=31.035^{\circ}[/tex]
The angle at which the ball was thrown is [tex]31.035^{\circ}[/tex].
g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to mention: What is the underlying model (equation) that you can use to determine the mass from your measurements
Answer:
m = [tex]\frac{k}{g}[/tex] x,
graph of x vs m
Explanation:
For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation
F_e -W = 0
k x = m g
m = [tex]\frac{k}{g}[/tex] x
We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.
In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass