In triangle ABC, the size of angle B is 4 times the size of angle A, and the size of
angle C is 1° less than 5 times the size of angle A.
Find the size of the angles.

Answer:

A=18.1, B=72.4, and C=89.5

Step-by-step explanation:

Where A, B and C represent their respective angles:

We are given that:

B=4A

C=5A−1

And since ABC make up a triangle, we know that:

A+B+C=180

Since we have three variables and three equations, we can solve for A, B, and C. To solve for A:

Take the equations B=4A and C=5A−1, and plug B and C into the last equation:

A+B+C=180

A+4A+5A−1=180

10A – 1 + 1 = 180 + 1

10A=181

10 /10 x A = 181/10

             A = 18.1

Then we can plug this value into the first two equations to solve for B and C:

B=4A

B=4(18.1)=72.4

C=5A−1

C=5(18.1)−1= 90.5 - 1=89.5

So A=18.1, B=72.4, and C=89.5

Hope this helps!

The size of ∠A is 18.1°.

The size of ∠B is  72.4°.

The size of ∠C is 89.5°.

It is a two-dimensional figure which has three sides and the sum of the three angles is equal to 180 degrees.

We have,

Triangle ABC

∠A = x

∠B = 4x

∠C = 5x - 1

Now,

The sum of all the angles in a triangle is 180.

This means,

x + 4x + 5x - 1 = 180

10x - 1 = 180

10x = 181

x = 18.1

Now,

∠A = 18.1°

∠B = 4 x 18.1 = 72.4°

∠C = 5 x 18.1 - 1 = 89.5°

Thus,

The sizes of the angles are:

18.1°, 72.4°, and 89.5°

Learn more about triangles here:

https://brainly.com/question/25950519

#SPJ2

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