in the sport of curling players slide a large 19 kg base called stones along the surface of the ice towards the target. with the stone traveling 3 m/s strikes a stationary stone directly the first stone will stop moving . using the concept of conservation momentum describe what happened to the second stone, assuming there is no friction

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Answer 1

According to the concept of conservation of momentum, the second stone will start moving at a velocity of 3 m/s in the same direction as the initial motion of the first stone.

In the sport of curling, when a 19 kg stone traveling at 3 m/s strikes a stationary stone and comes to a stop, the concept of conservation of momentum can be used to describe the behavior of the second stone. According to the conservation of momentum, the total momentum before the collision equals the total momentum after the collision. Since there is no friction, the momentum is conserved.

Before the collision, the momentum of the first stone is (19 kg)(3 m/s) = 57 kg m/s, and the momentum of the stationary stone is 0 kg m/s. Therefore, the total momentum before the collision is 57 kg m/s.

After the collision, the first stone stops moving, so its momentum is 0 kg m/s. To conserve momentum, the second stone must now have a momentum of 57 kg m/s. Assuming the second stone also has a mass of 19 kg, its velocity can be calculated as follows:

Velocity = Momentum / Mass = 57 kg m/s / 19 kg = 3 m/s.

So, the second stone will start moving at a velocity of 3 m/s in the same direction as the initial motion of the first stone, due to the conservation of momentum.

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Related Questions

1. down at the ice skating (assume frictionless ice) rink you watch a customer try out the new exercise machine consisting of a large spring allowing the skater to oscillate back and forth. the skater (mass

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At the frictionless ice skating rink, a customer tries out a new exercise machine consisting of a large spring, which allows the skater to oscillate back and forth, the skater's mass is a key factor in determining the oscillation behavior of the spring-skater system.

Down at the ice skating rink, we observe a customer trying out a new exercise machine that consists of a large spring. The spring allows the skater to oscillate back and forth. Assuming frictionless ice, the skater's mass does not have an effect on the motion of the spring. The period of oscillation, which is the time it takes for one complete back-and-forth motion, depends solely on the spring constant and the mass of the skater. Specifically, the period is given by the formula T=2π√(m/k), where T is the period in seconds, m is the mass of the skater in kilograms, and k is the spring constant in newtons per meter.

Thus, a heavier skater will have a longer period than a lighter skater, assuming the spring constant remains the same. Additionally, the amplitude of the oscillation, which is the maximum displacement from the equilibrium position, may also depend on the skater's strength and technique in using the machine.

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the chart below lists the forces applied to each of four toy cars. if all the cars accelerate at the same rate, which car must have the largest mass? a. p b. q c. r d. s

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To determine which car has the largest mass, we need to use the formula F=ma, where F is the force applied, m is the mass of the object, and a is the acceleration. Since all the cars are accelerating at the same rate, we can compare the forces applied to each car to determine which one has the largest mass.

Looking at the chart, we see that car S has the largest force applied to it, which means it must have the largest mass. Therefore, the answer is d. s.If an object is moving at a constant speed in a constant rightward direction, then the acceleration is zero and the net force must be zero.

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in order to determine whether this horizontal position of the pumpkin trajectory represents a minimum or maximum, evaluate d2ydx2 at xm .

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Depending on the direction the pumpkin was thrown, it can be determined if the horizontal position of the pumpkin trajectory reflects a minimum or maximum.

What is trajectory?

A moving object's trajectory is the path it follows through space as a function of time. In mathematics, a trajectory is defined as an object's position over a specific period of time.

To determine whether the horizontal position of the pumpkin trajectory represents a minimum or maximum, we need to evaluate the second derivative of the vertical position with respect to horizontal position at that point. In other words, we need to find d²y/dx² at x = xm.

Assuming that the pumpkin follows a parabolic trajectory given by the equation y = a + bx + cx², where y is the vertical position and x is the horizontal position, we can find the second derivative as follows:

dy/dx = b + 2cx

d²y/dx² = 2c

Since the pumpkin reaches its maximum height at x = xm, the first derivative dy/dx is equal to zero at that point. Therefore, we have:

dy/dx = b + 2cx = 0

2cx = -b

c = -b/(2x)

Substituting this expression for c into the equation for the second derivative, we have:

d²y/dx² = 2c = -b/x

To determine the sign of this expression at x = xm, we need to know whether the coefficient b is positive or negative. If the pumpkin was launched upwards, then b is positive and the second derivative at xm will be negative, indicating that the trajectory has a maximum at that point. On the other hand, if the pumpkin was launched downwards, then b is negative and the second derivative at xm will be positive, indicating that the trajectory has a minimum at that point.

Therefore, the determination of whether the horizontal position of the pumpkin trajectory represents a minimum or maximum depends on the direction in which the pumpkin was launched.

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help please................................................................

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The missing energy at box B is K.E = 590 J.

The missing energy at box C is P.E = 316 J

The missing energy at box D is K.E = 1,350 J

What is the missing values of the kinetic energy and potential energy?

The missing values of the energy is calculated based on the law of conservation of energy as follows;

total energy, E = 1,350 J

For Box B;

K.E = E - P.E

K.E = 1,350 J - 760 J

K.E = 590 J

For box C;

P.E = E - K.E

P.E = 1350 J - 1034 J

P.E = 316 J

For box D

K.E = E - P.E

K.E = 1350 J - 0 J

K.E = 1350 J

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Jupiters orbital period is approximately 12 years. if it were exactly 12 years. Which periods would not produce an effective resonance with jupiter?

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If Jupiter's orbital period were exactly 12 years, then the periods that would not produce an effective resonance with Jupiter would be those that are not simple ratios of Jupiter's period.

A resonance occurs when the orbital period of one planet is a simple ratio of the orbital period of another planet. For example, if the orbital period of one planet is twice that of another planet, they are in a 2:1 resonance.

So, if Jupiter's period were exactly 12 years, the periods that would not produce an effective resonance with Jupiter would be those that are not simple ratios of 12. Here are some examples:

A planet with a period of 3 years (4:1 ratio) would be in resonance with Jupiter.

A planet with a period of 4 years (3:1 ratio) would be in resonance with Jupiter.

A planet with a period of 6 years (2:1 ratio) would be in resonance with Jupiter.

A planet with a period of 8 years (3:2 ratio) would be in resonance with Jupiter.

On the other hand, planets with periods of 5, 7, 9, 10, or 11 years would not be in resonance with Jupiter because their periods are not simple ratios of 12.

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two blocks with the same mass are connected by a string and are pulled across a frictionless surface by a constant force, f, exerted by a string (see diagram).note: this is a multi-part question. once an answer is submitted, you will be unable to return to this part.two objects, joined by a string, are pulled to the right along a horizontal surface by a force f.which of the following statements is correct about what will happen to the boxes?

Answers

The boxes will move together with the same acceleration since they have the same mass and are being pulled by the same force on a frictionless surface.

When two blocks with the same mass are connected by a string and pulled across a frictionless surface by a constant force, F, the following statement is correct about what will happen to the boxes: Both blocks will accelerate at the same rate, since they have the same mass and are experiencing the same net force (F) acting on the entire system. The tension in the string connecting the blocks will also be constant throughout the motion. The acceleration of the two boxes will be proportional to the force applied, divided by the mass of the boxes. Since the boxes have the same mass, they will experience the same acceleration, which means they will move at the same speed.

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If refractive index of small angled prism of 4° is 1.5 then what is the deviation of prism.​

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ans. = 2

we know that,

the formula for small angle deviation is

deviation = ( refractive index - 1)angle of the prism

putting values we get

= ( 1.5 -1 ) 4

= 0.5 x 4

= 2

Hence, the deviation of prism is 2

a 40l contains a fluid at the given initial conditions listed below. the vessel develops a leak and, after its discovery, the temperature and pressure are measured again. for each of the given fluids, determine the kilograms of fluid lost due to the leak

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The kilograms of fluid lost due to the leak in a 40L vessel containing a fluid is 4.2 grams.

To determine the kilograms of fluid lost due to the leak, we need to use the ideal gas law equation, which states:

PV = nRT

Where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.

Assuming the fluid is a gas, we can use this equation to calculate the number of moles of gas in the container at the initial conditions. We can then use the same equation to calculate the number of moles of gas in the container after the leak has occurred, using the new pressure and temperature values.

Once we have the number of moles of gas before and after the leak, we can calculate the difference and convert it to kilograms using the molar mass of the fluid. For example, if the fluid is nitrogen gas (N₂) at an initial temperature of 25°C and pressure of 1 atm, we can calculate the number of moles of gas using:

PV = nRT

(1 atm)(40 L) = n(0.0821 L atm/mol K)(298 K)

n = 1.64 mol

If the leak is discovered and the temperature drops to 20°C and pressure drops to 0.9 atm, we can calculate the number of moles of gas using:

PV = nRT

(0.9 atm)(40 L) = n(0.0821 L atm/mol K)(293 K)

n = 1.49 mol

The difference in moles is 0.15 mol, which we can convert to kilograms using the molar mass of nitrogen gas (28 g/mol):

0.15 mol x 28 g/mol = 4.2 g

Therefore, the amount of nitrogen gas lost due to the leak is 4.2 grams.

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A ball of mass 400g originally at rest gains kinetic energy of 20j. What is its velocity

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The velocity of the ball after gaining 20 J of kinetic energy is approximately 10 m/s.

We can use the conservation of energy principle to find the  haste of the ball after gaining 20 J of kinetic energy.

The conservation of energy principle states that the total energy of a unrestricted system remains constant, meaning that energy can not be created or destroyed, only  converted from one form to another.   originally, the ball is at rest, which means that it has no kinetic energy. thus, the total energy of the system is equal to the implicit energy of the ball, which is zero. After gaining 20 J of kinetic energy, the total energy of the system is 20J. where KE is the kinetic energy, m is the mass, and v is the  haste of the ball.  

Rearranging the formula,

we get   v =  √( 2KE/ m)  

Substituting the values given, we get

  v =  √( 2 × 20 J/0.4 kg) ≈ 10 m/ s

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What length of wire will experience 12N force within a magnetic field of 2.5uT while carrying 7.35 A of current?

Please show all work, thank you.

Answers

The length of the wire that is required is 653 km

What is the force on a current carrying conductor?

The direction of the magnetic force on the conductor is perpendicular both to the direction of the magnetic field and to the direction of the current flow in the conductor.

The formula for the magnetic force on a current carrying conductor is given by:

F = BIL sin(θ)

We know that the force that is acting on a current carrying conductor can be given as;

F = BIL

L = F/BI

L = 12N/2.5 * 10^-6 * 7.35

L = 653 km

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current estimates place the value of hubble's constant ( h0 ) near 22 km/s/mly, giving 14 billion years as the age of the universe. if h0 were in fact 44 km/s/mly, the approximate age of the universe would be current estimates place the value of hubble's constant () near 22 km/s/mly, giving 14 billion years as the age of the universe. if were in fact 44 km/s/mly, the approximate age of the universe would be

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If Hubble's constant (H0) were in fact 44 km/s/mly, the approximate age of the universe would be half of the current estimate, which is 7 billion years.

The solution to this scenario would require a re-evaluation and adjustment of current cosmological models and theories, as the age of the universe plays a significant role in understanding its origins and evolution. However, it is important to note that current observations and measurements support the current estimate of H0 and age of the universe.

Solution:
1. Hubble's constant (H0) is used to calculate the age of the universe.
2. The given value of H0 is 22 km/s/Mly, which results in an age of 14 billion years.
3. To find the age of the universe with H0 at 44 km/s/Mly, we can set up a proportion:
  (22 km/s/Mly) / 14 billion years = (44 km/s/Mly) / X
4. Cross-multiply and solve for X:
  22 * X = 44 * 14
  X = (44 * 14) / 22
  X = 28
5. The age of the universe with H0 at 44 km/s/Mly is approximately 7 billion years.

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If light took 7 seconds to travel from a planet to Earth, how far is the planet?

Answers

Answer:

Distance=speed×time

Speed of light= 299 792 458 m/s

D= 299 792 458m

[tex]d =299 792 458 m/s \times 8s = 2,398,339,664m[/tex]

Which capacitor has the largest potential difference between its plates?A) AB) BC) CD) DE) A and D are the same and larger than B or C.

Answers

The capacitor that has the largest potential difference between its plates is D.

Equation V = Q/C, where V is the potential difference, Q is the charge held on the capacitor, and C is the capacitance, gives the potential difference between the plates of a capacitor.

The four capacitors in the diagram all have the same charge because they are all linked in series. The capacitor with the highest capacitance will therefore have the smallest potential difference, and vice versa.

The capacitor with the smallest capacitance, and consequently the one with the greatest potential difference between its plates, according to the values shown in the diagram, is capacitor D. Therefore, (D) is the correct response.

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does your data show a relationship between the tension in an the linear density of the elastic string? if so, what is that relationship

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Yes, the data shows a relationship between the tension and the linear density of the elastic string. This relationship is described by the equation for the wave speed (v) on a string:


v = √(T/μ)
where v is the wave speed, T is the tension in the string, and μ is the linear density (mass per unit length) of the string. This equation shows that the wave speed in an elastic string is directly proportional to the square root of the tension and inversely proportional to the square root of the linear density. In other words, if the tension in the string is increased while the linear density is kept constant, the wave speed will increase. Conversely, if the linear density of the string is increased while the tension is kept constant, the wave speed will decrease. So, in general, there is a relationship between the tension in an elastic string and its linear density, which affects the wave speed of the string.

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< Chapter 15 Prelecture Assignment Good Vibes: Introduction to Oscillations 3 of 9 Now assume for the remaining Parts G-J, that the x coordinate of point R is 0.12 m and the t coordinate of point K is 0.0050 s.
PartG What is the period T?
Express your answer in seconds View Available Hint(s)
Hint 1. How to approach the problem
In moving from the point t = 0 to the point K what fraction of a full wavelength is covered? Call that fraction a Then you can set aT = 0.005 s Dividing by the fraction a will give the period T
t= Submit Request Answer Part H How much time t does the block take to travel from the point of maximum displacement to the opposite point of maximum displacemen?

Answers

The period T is 0.0100 seconds and the block takes 0.0050 seconds to travel from the point of maximum displacement to the opposite point of maximum displacement.

Part G: To find the period T, we need to first determine the fraction of a full wavelength that is covered when moving from point t = 0 to point K. Since the x-coordinate of point R is 0.12 m and the t-coordinate of point K is 0.0050 s, we can assume that point K is located at half a wavelength.
Step 1: Determine the fraction of a full wavelength (a)
Since point K is at half a wavelength, the fraction a is 1/2.
Step 2: Calculate the period T
We know that aT = 0.0050 s, and a = 1/2.
(1/2) * T = 0.0050 s
Now, divide by the fraction a (1/2) to find the period T.
T = 0.0050 s / (1/2)
T = 0.0100 s
Part H: To find the time t it takes for the block to travel from the point of maximum displacement to the opposite point of maximum displacement, we can use the period T calculated in Part G.
Since the block travels from one point of maximum displacement to the opposite point of maximum displacement in half a period:
Step 1: Calculate the time t
t = (1/2) * T
t = (1/2) * 0.0100 s
t = 0.0050 s

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Fill in the blank. The facet of adolescent egocentrism called the _____ refers to teenagers' belief that everyone is watching everything they do.

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The facet of adolescent egocentrism called the imaginary audience refers to teenagers' belief that everyone is watching everything they do.

Egocentrism refers to the idea that a particular observer's perspective or frame of reference is the only one that matters in determining physical phenomena. This can lead to errors in understanding and describing physical events, as different observers may have different perspectives that affect their observations.

For example, in special relativity, different observers moving at different velocities will measure different values for the same physical quantities, such as time and distance. A person who is egocentric in their thinking may believe that their measurements are the only ones that matter and may not take into account the perspectives of other observers. Egocentrism can also be a hindrance to collaboration and communication among physicists, as individuals may be more focused on their own observations and interpretations rather than working together to develop a shared understanding of a particular phenomenon.

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To which of the following things would newton's laws apply?Galaxiesplanetsrocks on earthtrucksSatellites in spacerocks on marsairplanes

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Newton's laws apply to the following things in your list: galaxies, planets, rocks on Earth, trucks, satellites in space, rocks on Mars, and airplanes.

This is because Newton's laws are universal, governing the motion of objects and the forces that act upon them, regardless of their location or scale.

According to "Newton's first law of motion", if a body is in rest, it will stay in rest until or unless an external or an unbalanced force is applied on the body to make it move. A satellite has a forward thrust, which is offset by the gravity of the earth and keeps the satellite orbiting around its orbit not falling it into the earth. The momentum that the satellite gained from its launch combines with the gravity of the earth cause the satellite go into the orbit above earth.

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star a and star b have same temperatures, but star a is more luminous than star b. based on this information, which of the following must be the case?A. Star A is smaller than Star B
B. Star A is larger than Star B
C. Star A and Star B have same size
D. Star A is more massive than star B

Answers

The correct answer is D. StarA is more massive than starB.

Star A being more luminous than Star B while having the same temperature suggests that Star A must be more

massive than Star B. This is because a star's luminosity is directly proportional to its mass, and therefore, the more

massive the star, the more luminous it will be. The size of the star is not necessarily related to its temperature or

luminosity, so we cannot determine whether Star A is larger, smaller, or of the same size as Star B based on the given information.

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If the Biot number is increased by increasing h while keeping everything else the same, less heat will be exchanged between the block and the fluid bathing the right face.A) TrueB) FalseAn increase in h would imply greater convection at the boundary which would correspond to more heat being exchanged at the boundary. This increase in h could come from an increase in the flow rate of the fluid that is bathing the right face.

Answers

If the Biot number is increased by increasing h while keeping everything else the same, less heat will be exchanged between the block and the fluid bathing the right face.

B) False because, An increase in the Biot number (Bi) is achieved by increasing the convective heat transfer coefficient (h) while keeping other parameters the same.

The Biot number is defined as:
Bi = hL/k
where L is the characteristic length of the object, and k is the thermal conductivity of the material.

As you mentioned, an increase in h would imply greater convection at the boundary, leading to more heat being exchanged at the boundary.

This increase in h could indeed come from an increase in the flow rate of the fluid that is bathing the right face. Therefore, the statement "less heat will be exchanged between the block and the fluid bathing the right face" is false.

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A position vector in the first quadrant has an x component of 3 m and a magnitude of 13 m. What is the value of its y component?

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To find the value of the y-component of a position vector in the first quadrant with an x-component of 3 m and a magnitude of 13 m, we can use the Pythagorean theorem.

The position vector has components (x, y) and a magnitude (||v||) which is the length of the vector. In this case, x = 3 m and ||v|| = 13 m.

The Pythagorean theorem states that for a right-angled triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides. In this case, the hypotenuse is the magnitude of the position vector, and the two sides are the x and y components. Therefore:

||v||² = x² + y²

Substitute the given values:

(13 m)²  = (3 m)²  + y²

169 m²  = 9 m² + y²

Now, solve for y² :

y²  = 169 m²  - 9 m²  = 160 m²

Take the square root of both sides to find y:

y = sqrt(160 m² ) = 4√10 m ≈ 12.65 m

So, the value of the y-component of the position vector is approximately 12.65 m.  

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The drill used by most dentists today is powered by a small air-turbine that can operate at angular speeds of 350000 rpmrpm. These drills, along with ultrasonic dental drills, are the fastest turbines in the world-far exceeding the angular speeds of jet engines. Suppose a drill starts at rest and comes up to operating speed in 2.0 ss . You may want to review (Pages 305 - 307) .a)Find the angular acceleration produced by the drill, assuming it to be constant.Express your answer using two significant figures.b)How many revolutions does the drill bit make as it comes up to speed?Express your answer using two significant figures

Answers

a) The angular acceleration produced by the drill is 1.8x10^5 rad/s^2, assuming it to be constant.

b) The drill bit makes approximately 6.0 revolutions as it comes up to speed.

a) We can use the equation for angular acceleration, α, which is given by α = Δω/Δt, where Δω is the change in angular velocity and Δt is the time taken for the change. Here, Δω = 350000 rpm - 0 rpm = 350000 rpm, and Δt = 2.0 s. Converting rpm to rad/s, we get Δω = 2π(350000/60) rad/s = 3669.4 rad/s. Therefore, α = 3669.4 rad/s / 2 s = 1.8x10^5 rad/s^2.

b) The number of revolutions made by the drill bit can be found using the equation θ = ω_i t + 0.5 α t^2, where θ is the angle turned, ω_i is the initial angular velocity (0 rpm), t is the time taken (2.0 s), and α is the angular acceleration (1.8x10^5 rad/s^2).

Substituting the values, we get θ = 0 + 0.5 x 1.8x10^5 rad/s^2 x (2.0 s)^2 = 360000 rad. Converting to revolutions, we get θ = (360000 rad)/(2π rad/rev) = 57296.9 rev. However, since we are asked for the answer in two significant figures, we round off to 6.0 revolutions.

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constant patterns of particle behavior are called what

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Constant patterns of particle behavior are called "laws of nature" or "physical laws."

These terms refer to the regular, predictable behavior of particles under certain conditions, which can be described mathematically or through scientific principles.

Examples of physical laws include Newton's laws of motion, the laws of thermodynamics, and the laws of conservation of energy and mass.

The constant patterns of particle behavior are often referred to as laws or principles.

In the context of physics, these laws describe the fundamental rules that govern the behavior of particles and systems, such as the laws of motion, the laws of thermodynamics, and the laws of electromagnetism.

These laws have been formulated through observation, experimentation, and theoretical modeling, and they provide a framework for understanding the natural world.

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normally, 100% of the star's light reaches us. estimate how much light reached us during the transit. be sure to report to 4 decimal places. therefore, how much light was blocked by the planet?

Answers

Based on the mentioned informations and provided values, about 99.75% of the star's light reached us during the transit, and the remaining 0.25% was blocked by the planet.

To estimate how much light was blocked by the planet during the transit, we need to know the percentage of the star's surface area that is covered by the planet.

Assuming that the planet is a perfect circle and that it passes directly in front of the star, the percentage of the star's surface area that is covered by the planet can be calculated using the formula:

% coverage = (π x (radius of planet/star)²) / (4 x π x (radius of star)²) x 100%

where π is the mathematical constant pi, and the radius of the planet/star is measured in the same units.

Let's say that the radius of the planet is 0.1 times the radius of the star. In that case, the percentage coverage can be calculated as:

% coverage = (π x (0.1)²) / (4 x π x (1)²) x 100% = 0.25%

This means that during the transit, 0.25% of the star's surface area was covered by the planet, and therefore, the amount of light that reached us was:

100% - 0.25% = 99.75%

So, about 99.75% of the star's light reached us during the transit, and the remaining 0.25% was blocked by the planet.

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what mass of silver will be formed when 15.0 a are passed through molten agcl for 25.0 minutes?

Answers

The mass of silver formed when 15.0 A of current is passed through molten AgCl for 25.0 minutes is approximately 25.08 grams.

To calculate the mass of silver formed when 15.0 A of current is passed through molten AgCl for 25.0 minutes, we need to use Faraday's law of electrolysis.

First, let's convert the time from minutes to seconds:

t = 25.0 minutes

 = 25.0 × 60 seconds

 = 1500 seconds

The formula for Faraday's law is:

Mass of substance = (Current × Time) / (Faraday's constant ×  Number of electrons involved in the reaction)

For the electrolysis of AgCl, the number of electrons involved is 1.

The Faraday's constant is 96,485 C/mol.

Now, let's calculate the mass of silver formed:

1. Calculate the electric charge passed through the electrolyte:

Electric charge = Current × Time

Electric charge = 15.0 A × 1500 s

                         = 22,500 C

2. Calculate the moles of silver formed:

Moles of silver = Electric charge / (Faraday's constant × Number of electrons)

Moles of silver = 22,500 C / (96,485 C/mol × 1)

3. Convert moles of silver to grams:

Mass of silver = Moles of silver × molar mass of silver

Mass of silver = 0.2327 mol × 107.87 g/mol

                       ≈ 25.08 g

Therefore, the mass of silver formed when 15.0 A of current is passed through molten AgCl for 25.0 minutes is approximately 25.08 grams.

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A square uniform raft, 18 m by 18 m , of mass 7100 kg , is used as a ferryboat.
If three cars, each of mass 1350 kg , occupy the NE, SE, and SW corners, determine the coordinates of the CM of the loaded ferryboat relative to the center of the raft. Take the origin to be at the CM of the raft.
Express your answer using two significant figures. Enter your answers numerically separated by a comma.
xCM, yCM = m

Answers

xCM, yCM = 0, -3.27 m are the coordinates of the center of mass of the loaded ferryboat relative to the center of the raft.

To find the coordinates of the center of mass (CM) of the loaded ferryboat, we need to consider the mass and position of the raft and the three cars. We will use the following formulas for finding the x and y coordinates of the center of mass:

xCM = (Σ mi * xi) / Σ mi
yCM = (Σ mi * yi) / Σ mi

where mi is the mass of each object and xi and yi are their respective x and y coordinates.

Determine the coordinates of the raft and the cars
- The raft's center (origin): (0, 0)
- NE corner car: (9, 9)
- SE corner car: (9, -9)
- SW corner car: (-9, -9)

Calculate xCM
xCM = (7100 * 0 + 1350 * 9 + 1350 * 9 + 1350 * (-9)) / (7100 + 1350 + 1350 + 1350)
xCM = (0 + 12150 - 12150) / (11150)
xCM = 0 m

Calculate yCM
yCM = (7100 * 0 + 1350 * 9 + 1350 * (-9) + 1350 * (-9)) / (11150)
yCM = (12150 - 12150 - 12150) / (11150)
yCM = -3.27 m

So, the coordinates of the center of mass of the loaded ferryboat relative to the center of the raft are:
xCM, yCM = 0, -3.27 m

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suppose that a civilization around a nearby star had television like we do. could current seti efforts detect their television transmissions? why or why not?

Answers

It is possible that current SETI efforts could detect the television transmissions of a civilization around a nearby star if they were transmitting strong enough signals in a direction that we are able to receive. However, it is important to note that our current SETI efforts are primarily focused on detecting narrowband signals.

which are typically used for communication purposes, rather than the broad spectrum signals that are typically associated with television transmissions. Additionally, the signals would need to be strong enough to overcome the background noise of the universe and would need to be transmitted at a frequency that we are able to detect. Overall, while it is theoretically possible to detect television transmissions from a nearby civilization, it would be a challenging endeavor and would require the use of advanced technology and techniques.
A civilization around a nearby star with television like ours might not be easily detected by current SETI efforts. SETI mainly focuses on detecting narrowband radio signals, which are different from the broadband signals used for television transmissions. Additionally, the distance and potential interference from other cosmic sources could make it challenging to identify these signals specifically from that civilization.

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Is a ball falling with constant velocity in translational equilibrium?

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Answer: Yes, because the force of air resistance must be equal to the force of gravity, since the ball is not accelerating (constant velocity). Since the net forces acting on the object is zero, the object is in translational equilibrium.

No, a ball falling with constant velocity is not in translational equilibrium.

Translational equilibrium means that the net force acting on an object is zero, and this is not the case for a ball falling with constant velocity. Gravity is still acting on the ball, so there is a force pulling it downwards. However, the ball is moving at a constant velocity because the force of gravity is balanced by the force of air resistance. So, while the ball is not in translational equilibrium, it is in a state of dynamic equilibrium where the forces acting on it are balanced, resulting in a constant velocity.

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Which correctly lists three scientists who supported the heliocentric model of the solar system?
O Aristotle, Ptolemy, Copernicus
O Copernicus, Ptolemy, Kepler
O Galileo, Kepler, Aristotle
O Kepler, Galileo, Copernicus

Answers

Answer:

the answer is

Explanation:

Kepler, Galileo, Copernicus

Final answer:

The heliocentric model of the solar system was supported by three prominent scientists: Kepler, Galileo, and Copernicus. These scientists helped to develop and prove the theory that the Sun, not the Earth, is the center of our solar system.

Explanation:

The three scientists who supported the heliocentric model of the solar system were Kepler, Galileo, and Copernicus. The heliocentric model proposes that the sun is the center of the solar system, which was a revolutionary theory in the time of these scientists. Copernicus was notable for his book 'On the Revolutions of the Celestial Spheres', where he laid the groundwork for the heliocentric model, Galileo supported Copernicus's theory with his observations using an early telescope, and Kepler refined Copernicus's model with his Laws of Planetary Motion that supported the idea of a sun-centered solar system.

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A solenoid is comprised of 1,000 turns of wire and has a net current of 0.5 A running through it. Inside the solenoid is a magnetic field of 250 times mu naught. How long is the solenoid?A. 1.26 m B. 0.33 m C. 2.52 m D. 2.00 m E. 1.05 m

Answers

The length of the solenoid is 2 m, which corresponds to option D.

To find the length of the solenoid, we need to use the formula for the magnetic field inside a solenoid:
B = μ₀ * n * I
where B is the magnetic field, μ₀ is the permeability of free space, n is the number of turns per unit length, and I is the current.
We are given:
B = 250 * μ₀
Total turns (N) = 1,000
Current (I) = 0.5 A
First, we need to find the number of turns per unit length (n). We can do this by dividing the total number of turns (N) by the length (L) of the solenoid:
n = N / L
Now, we can rearrange the formula for the magnetic field to find the length (L) of the solenoid:
L = N / (B / (μ₀ * I))
Substitute the given values:
L = 1,000 / (250 * μ₀ / (μ₀ * 0.5 A))

Notice that μ₀ will cancel out:
L = 1,000 / (250 / 0.5)
Now, solve for L:
L = 1,000 / 500 = 2 m.

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What is the angular acceleration of a ball that starts at rest and increases its angular velocity uniformly to 5 rad/s

Answers

Answer:

no se English plis

Explanatique

que si aumente la rad/s en el angular. de  su velocity

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