In the rectangular prism below, the length of MR is 9 feet, the length of RS is 12 feet, and the length of ST is 5 feet. What is the length of the line segment drawn from point T to point M?
*Note: Figure not drawn to scale.
a
16 feet

b
5√10 feet

c
250 feet

d
5√5 feet

In The Rectangular Prism Below, The Length Of MR Is 9 Feet, The Length Of RS Is 12 Feet, And The Length

Answers

Answer 1

Answer:

[tex]5\sqrt{10}[/tex] feet

Step-by-step explanation:

Find RT:

RS = 12 and ST= 5, RT =?

Use the Pythagorean Theorem

[tex]12^{2} + 5^{2} = RT^{2}[/tex]

[tex]144 + 25 = RT^{2}[/tex]

[tex]\sqrt{169} =RT[/tex]

13 = RT

Find MT:

RT = 13 and MR= 9, MT=?

[tex]13^{2} +9^{2}= MT^{2}[/tex]

[tex]169 + 81 = MT^{2}[/tex]

[tex]\sqrt{250} = MT[/tex]

[tex]5\sqrt{10}[/tex] = MT


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Answers

Answer:

The area of the base of the pyramid is 109.2 mm.

Step-by-step explanation:

The area of the base of a hexagonal pyramid is given by the area of a hexagon:

[tex] A_{b} = \frac{P*a}{2} [/tex]  

Where:

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The perimeter is equal to:  

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[tex] V = \frac{\sqrt{3}}{2}*h*s^{2} [/tex]  

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[tex] s = \sqrt{\frac{2V}{\sqrt{3}*h}} = \sqrt{\frac{2*144}{\sqrt{3}*4}} = 6.5 mm [/tex]

Now, we can find the perimeter and the apothem.

[tex] a = \frac{\sqrt{3}}{2}*s = \frac{\sqrt{3}}{2}*6.5 = 5.6 mm [/tex]

[tex] P = 6*s = 6*6.5 = 39 mm [/tex]

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[tex] A_{b} = \frac{P*a}{2} = \frac{39*5.6}{2} = 109.2 mm^{2} [/tex]

Therefore, the area of the base of the pyramid is around 109 mm.

I hope it helps you!

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Answers

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Answers

i think its C because
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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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