In the reaction Pb + 2Ag+ – Pb2+ + 2Ag, the Ag+ is.
a) reduced, and the oxidation number changes from +1 to 0.
b)reduces and the oxidation number changes from +2 to 0.
c)oxidized and the oxidation number changes from 0 to +1.
d) oxidized, and the oxidation number changes from +1 to 0.
​

Answer:

ummm u ok?

Explanation:

Answer:

By measuring out 3.9 grams of cobalt (II) chloride up to a volume of 1.0 L of solution.

Explanation:

Hello there!

In this case, considering this question about molarity, it turns out possible for us to calculate the required mass of cobalt (II) chloride by firstly compute the moles present in 1.0L of the given 0.03-M solution:

[tex]M=\frac{n}{V} \\n=V*M\\\\n=1.0L*0.03\frac{molCoCl_2}{L}\\\\n=0.03molCoCl_2[/tex]

Next, since the molar mass of cobalt (II) chloride is 129.84 g/mol, we compute the grams we need to measure out in order to prepare this solution:

[tex]m_{CoCl_2}=0.03molCoCl_2*\frac{129.84gCoCl_2}{1molCoCl_2} \\\\m_{CoCl_2}=3.9gCoCl_2[/tex]

Regards!

Answer:

A B D

Explanation:

Answer:  A: Being the power source of stars

                B: Forming heavier elements from light elements

                D: Being used in thermonuclear weapons

Explanation: (Edmentum)

Answer:

36.16 amu

Explanation:

From the question given above, the following data were obtained:

1st Isotope:

Mass of 1st isotope = 35.01 amu

Abundance of 1st isotope = 35%

2nd isotope:

Mass of 2nd isotope = 36.01 amu

Abundance of 2nd isotope = 15%

3rd isotope:

Mass of 3rd isotope = 37.02 amu

Abundance of 3rd isotope = 50%

Atomic mass of element A =?

The atomic mass of element A can be obtained as follow:

Atomic mass = [(mass of 1st × Abundance)/100] + [(mass of 2nd × Abundance)/100] + [(mass of 3rd × Abundance)/100]

= [(35.01 × 35)/100] + [(36.01 × 15)/100] + [(37.02 × 50)/100]

= 12.25 + 5.40 + 18.51

= 36.16 amu

Thus, the atomic mass of element A is 36.16 amu

Answer:

C, energy cannot be created nor destroyed.

Explanation:

Answer:

whats the question?

Explanation:

Explanation:

2nacl+baso4

the orginal equation is

Na2so4+Bacl2

then na react with cl and ba react with so4

Answer:

The answers to your questions are given below.

Explanation:

1. __H₂ + __O₂ —> __H₂O

The above equation can be balance as follow:

H₂ + O₂ —> H₂O

There are 2 atoms of O on the left side and 1 atom on the right side. It can be balance by writing 2 before H₂O as shown below:

H₂ + O₂ —> 2H₂O

There are 2 atoms of H on the left side and a total of 4 atoms on the right side. It can be balance by writing 2 before H₂ as shown below:

2H₂ + O₂ —> 2H₂O

Now the equation is balanced.

Elements >>> Reactants >>> Products

H >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 2 >>>>>>>>>>> 2

2. __ P₄ + __O₂ —> __P₂O₃

The above equation can be balance as follow:

P₄ + O₂ —> P₂O₃

There are 4 atoms of P on the left side and 2 atoms on the right side. It can be balance by writing 2 before P₂O₃ as shown below:

P₄ + O₂ —> 2P₂O₃

There are 2 atoms of O on the left side and a total of 6 atoms on the right side. It can be balance by writing 3 before O₂ as shown below:

P₄ + 3O₂ —> 2P₂O₃

Now, the equation is balanced

Elements >>> Reactants >>> Products

P >>>>>>>>> 4 >>>>>>>>>>> 4

O >>>>>>>>> 6 >>>>>>>>>>> 6

Answer:

C. Base.

Explanation:

Hello there!

In this case, according to the given information, it turns out convenient for us to realize that the concept acid and base we should use here is based off the Bronsted-Lowry one, which says that an acid is a hydrogen donor. In such a way, since water accepts one H ion as it goes to H3O⁺, we infer it is C. Base and the H2S the acid.

Also, we can tell HS⁻ is the conjugate base and H3O⁺ the conjugate acid.

Regards!

Answer:

Percentage of Ba = 52.5%

Explanation:

We'll begin by calculating the molar mass of Ba(NO3)₂. This can be obtained as follow:

Molar mass of Ba(NO3)₂ = 137 + 2[14 +(16×3)]

= 137 + 2[14 + 48]

= 137 + 2[62]

= 137 + 124

= 261 g/mol

Next, we shall determine the mass of Ba in Ba(NO3)₂. This can be obtained as follow:

Mass of Ba in Ba(NO3)₂ = 137 g/mol

Finally, we shall determine the percentage of Ba in Ba(NO3)₂. This can be obtained as follow:

Percentage of Ba = mass of Ba / mass of Ba(NO3)₂ × 100

Percentage of Ba = 137 / 261 × 100

Percentage of Ba = 13700 / 261

Percentage of Ba = 52.5%

Thus, the percentage of Ba in Ba(NO3)₂ is 52.5%

Answer:

Can you translate it on English so we can understand

Answer:

well when you eat some food you will get many tastes mixed with base and acid but salt from NA2CO3 can be a base if it is contained with weak acid.

Explanation:

Basically SALT can be one common base that is NOT harmful to the body when ingested AND a product, or way, in which it is used.

Magnesium hydroxide (Mg(OH)2) is not harmful to our body when ingested AND a product, or way, in which it is used. It is commonly used to get relief from acidity, that is caused when our stomach releases excessive acid. It neutrelises the acid and gives us relief. It is also called Milk of Magnesia commonly.

Answer:

pH = 10.95

Explanation:

To solve this question we must, as first, find pKb of dimethylamine. Then, using H-H equation we can solve the pH of the buffer:

pKb dimethylamine:

Based on the equilibrium:

(CH3)2NH(aq) + H2O(l) ⇄ (CH3)2NH2⁺(aq) + OH-(aq)

Kb is defined as:

Kb = [OH-] [(CH3)2NH2⁺] / [(CH3)2NH]

Both (CH3)2NH2⁺(aq) + OH- comes from the same equilibrium, that means:

[OH-] = [(CH3)2NH2⁺]

And: [(CH3)2NH] = 0.457M

[OH-] can be obtained from pH as follows:

14 -pH = pOH

14-12.2 = 1.8 =pOH

10^-pOH = [OH-] = 0.01585M

Replacing:

Kb = [0.01585M] [(0.01585M] / [0.457M]

Kb = 5.50x10⁻⁴

pKb = -logkb = 3.26

pH of the buffer:

Using H-H equation for bases:

pOH = pKb + log [conjugate acid] / [weak base]

pOH = 3.26 + log [0.280M] / [0.457M]

pOH = 3.05

pH = 14 - pOH

Answer:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this is a question about esterification, process whereby a carboxylic acid and an alcohol react to produce water an an ester, we can set it up as shown below:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH[/tex]

For the reaction between ethanoic acid and butanol; and therefore, the products side is:

[tex]CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

It means that the overall equation is:

[tex]CH_3COOH+CH_3CH_2CH_2CH_2OH\rightarrow CH_3COOCH_2CH_2CH_2CH_3+H_2O[/tex]

And the ester product is butyl ethanoate.

Regards!

Answer:

The gases in a hair spray can are at a temperature of 26.0 °C and a pressure of 25.0 lbs/in2.

If the pressure becomes [tex]90.0lbs/in^{2}[/tex], what is the temperature of the gases?

Explanation:

According to Gay lussac's law:

the pressure of a gas is directly proportional to its absolute temperature.

[tex]P\alpha T[/tex]

[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }[/tex]

Given,

[tex]P1=25.0lbs/in^{2} \\P2=90.0lbs/in^{2} \\T1=26^{o} C=(26+273)K=299K\\T2=?[/tex]

Substitute these values in the above formula:

[tex]\frac{P{1} }{T{1} }=\frac{P{2} }{T{2} }\\\\\frac{25lbs/in^{2} }{299K} }=\frac{90.0lbs/in^{2} }{T{2} }\\\\\\On simplification \\T2=1076.4K\\T2=(1076.4-273)^{o} C=803.4^{o} C[/tex]

Answer:

The gases will be raised to a temperature of 803.4[tex]^{o} C[/tex].

Answer:

IUPAC

Explanation:

International Union of Pure and Applied Chemistry

Answer:

92.1 g

Explanation:

Answer: 92.1 grams

I hope this helped :3

Answer:

a.

Explanation:

electromagnetism

Answer:

[tex]d=9.5g/L[/tex]

Explanation:

Hello there!

In this case, according to the given information, it i possible for us to calculate the density of this gas via the ideal gas equation, according to the following setup:

[tex]PV=nRT\\\\P=\frac{mRT}{V*MM} \\\\\frac{m}{V}=d=\frac{P*MM}{RT}[/tex]

Thus, we plug in the variables (pressure in atm and temperature in K) to obtain:

[tex]d=\frac{113.6368atm*2.02g/mol}{0.08206\frac{atm*L}{mol*K}*(21+273)K} \\\\d=9.5g/L[/tex]

Regards!

Answer:

m = 4.58 g.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to realize this problem is solved via the ideal gas equation:

[tex]PV=nRT[/tex]

As we can calculate the moles of propane given the pressure, temperature and volume as shown below:

[tex]n=\frac{PV}{RT} \\\\n=\frac{1.10atm*2.00L}{0.08206\frac{atm*L}{mol*K}*258K} \\\\n=0.104mol[/tex]

Finally, since the molar mass of propane is 44.1 g/mol, we calculate the mass by following the shown below mole-mass conversion factor:

[tex]m=0.104mol*\frac{44.1g}{1mol}\\\\m= 4.58g[/tex]

Regards!

Explanation:

To show - from E=mc²=hv show that wavelength=h/mv​

Proof -

Given that,

E = mc²

E = hν

By equating both the equations, we get

mc² = hν

Because real particles do not travel at the speed of light, De Broglie submitted velocity ( v ) for the speed of light ( c ).

mv² = hν

Through the equation  λ , de Broglie substituted  v/λ  for  ν  and arrived at the final expression that relates wavelength and particle with speed.

mv² = hv/λ

⇒λ = hv/mv²

⇒λ = h/mv

Hence showed.

Answer:

540,000 (5.4X10^5)

Explanation:

kj means Kilojoules, while we are converting to joules.

- Kilo, or k, represents our base value, Joules, multiplied by 10^3. To convert to joules, we would simply multiply by 10^3 (which is 1000)

answer of this question is [Ar]3d8 4s2

Answer: [Ar] 3d8 4s2

Explanation: Wikipedia

Answer:

Option B: p H equals 2.00 , because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar .

pH = 2 because [H⁺] = 1×10¯² M

Explanation:

To know which option is correct, we shall determine the pH of the 0.010 M HClO₄ solution. This can be obtained as follow:

We'll begin by calculating the concentration of the hydrogen ion [H⁺] in the solution. This is illustrated below:

HClO₄ is a strong acid and will dessociates as follow:

HClO₄ (aq) —> H⁺ (aq) + ClO₄¯ (aq)

From the balanced equation above,

1 mole of HClO₄ produced 1 mole H⁺.

Therefore, 0.010 M HClO₄ will also produce 0.010 M H⁺.

Finally we shall determine the pH of the solution. This can be obtained as follow:

Concentration of the hydrogen ion [H⁺] = 0.010 = 1×10¯² M

pH =?

pH = –Log [H⁺]

pH = –Log 1×10¯²

pH = 2

Thus,

The pH = 2

because,

[H⁺] = 1×10¯² M

Thus, option B gives the correct answer to the question.

Based on the definition of pH, pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.

The pH of a solution is the negative logarithm of the hydrogen ion concentration of a solution.

pH of a solution is a measure of the acidity of the solution.

where

For the 0.010 M solution of HClO4, [H+} = 0.01 M

pH = -log(0.01)

pH = 2.00

Therefore,  pH of 0.010 M solution of HClO4 equals 2.00, because the molar concentration of H with a positive 1 charge equals 1.0 times 10 to the negative 2 power molar.

Learn more about pH at: https://brainly.com/question/172153

Answer:

Isomerism is the phenomenon in which more than one compounds have the same chemical formula but different chemical structures. Chemical compounds that have identical chemical formulae but differ in properties and the arrangement of atoms in the molecule are called isomers. Therefore, the compounds that exhibit isomerism are known as isomers.

The word “isomer” is derived from the Greek words “isos” and “meros”, which mean “equal parts”. This term was coined by the Swedish chemist Jacob Berzelius in the year 1830.

Explanation:

Answer:

The answers are in the explanation.

Explanation:

The energy required to convert 10g of ice at -10°C to water vapor at 120°C is obtained per stages as follows:

Increasing temperature of ice from -10°C - 0°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 2.06J/g°C, ΔT is change in temperature = 0°C - -10°C = 10°C and m is mass of ice = 10g

Q = 2.06J/g°C*10°C*10g

Q = 206J

Change from solid to liquid:

The heat of fusion of water is 333.55J/g. That means 1g of ice requires 333.55J to be converted in liquid. 10g requires:

Q = 333.55J/g*10g

Q = 3335.5J

Increasing temperature of liquid water from 0°C - 100°C:

Q = S*ΔT*m

Q is energy, S specific heat of ice = 4.18J/g°C, ΔT is change in temperature = 100°C - 0°C = 100°C and m is mass of water = 10g

Q = 4.18J/g°C*100°C*10g

Q = 4180J

Change from liquid to gas:

The heat of vaporization of water is 2260J/g. That means 1g of liquid water requires 2260J to be converted in gas. 10g requires:

Q = 2260J/g*10g

Q = 22600J

Increasing temperature of gas water from 100°C - 120°C:

Q = S*ΔT*m

Q is energy, S specific heat of gaseous water = 1.87J/g°C, ΔT is change in temperature = 20°C and m is mass of water = 10g

Q = 1.87J/g°C*20°C*10g

Q = 374J

Total Energy:

206J + 3335.5 J + 4180J + 22600J + 374J =

30695.5J =

30.7kJ

Answer:

D

Explanation:

Answer:

D

Explanation:

Because it is true

Answer:

Metal oxide + acid —> salt + water

Explanation: