In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​

Answer:

833.9kg that's the answer

Answer:

a. Concave mirror, radius of curvature = 16 cm b. magnification = 2

Explanation:

a. Since the image is upright and larger than the object, we need a concave mirror.

We know image height, h'/object height, h = -image distance, d'/object distance, d

h'/h = -d'/d

Using the real is positive convention,

h'= + 5.4 cm, h = + 2.7 cm and d = + 12 cm.

So, + 5.4 cm/+ 2.7 cm = -d'/+ 12 cm

2 = -d'/12

d' = -2 × 12 cm

= -24 cm

Using the mirror formula 1/d + 1/d' = 2/r where r = radius of curvature of the mirror

1/+12 + 1/- 24 = 2/r

1/12(1 - 1/2) = 2/r

1/12(1/2) = 2/r

1/24 = 2/r

r/2 = 24

r = 2 × 24

r = 48 cm

b.

magnification = image height, h'/object height,h = + 5.4 cm/+ 2.7 cm = 2

Answer:

destructive interference occurs

Answer:

I don't know if its just me, but I don't see the statements so I'm not sure how to help answer your question.

Answer:

i believe that they are or there's something out there

Explanation:

:)

Answer:

T = 10 s

Explanation:

First, we need to find the frequency of the object as follows:

[tex]Frequency = f = \frac{Speed\ in\ rpm}{60}[/tex]

where,

Speed = Angular Speed = 6 rpm

Therefore,

[tex]f = \frac{6\ rpm}{60}\\\\f = 0.1\ Hz[/tex]

Now, for time period (T):

[tex]Time\ Period = T = \frac{1}{f}\\\\T = \frac{1}{0.1\ Hz}\\\\[/tex]

T = 10 s

Answer:

0 j

Explanation:

The work done by the employee on the box at the given zero displacement is 0 J.

The given parameters;

The work done by the employee on the box is calculated as follows;

W = Fd

where;

Since the employee sits on the box without moving it, the distance moved by the box = 0

W = 500 x 0

W = 0 J

Thus, the work done by the employee on the box is 0 J.

Learn more about work done and displacement here: https://brainly.com/question/8635561

Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

Answer:

Image B

Explanation:

although I'm not exactly sure, i've recently gotten this question as well. but model B demonstrates the force- distance trade off because you can see how in that image them distance is increased in the force is decreased with the object being shorter. hopefully this helps in some way

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

Answer:

The total momentum is zero.

Explanation:

This problem can be solved by applying the momentum conservation theorem and the amount of motion. This theorem tells us that the amount of motion is conserved before and after a collision.

In the next equation, we will write to the left of the equal sign the amount of motion before the collision and to the right the amount of motion after the collision.

[tex](P_{1})-(P_{2})=P_{3}[/tex]

where:

P₁ = momentum of the ball moving to the right, before the collision = 85 [kg*m/s]

P₂ = momentum of the ball moving to the left, before the collision = - 85 [kg*m/s]

P₃ = Final momentum after the collision [kg*m/s]

[tex](85) - 85 = P_{3}\\P_{3}= 0[/tex]

There is no movement of any of the balls, they remain at rest after the impact.

Answer:

a) [tex]F_{x} = 58.2 N[/tex]

[tex] F_{y} = 48.9 N [/tex]

b) a = 1.5 m/s²

Explanation:

a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.

Since the handle is inclined at 40.0° below the horizontal we have:

[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]

[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]

b) The acceleration of the car can be calculated as follows:

[tex] F_{x} = ma [/tex]        

We used the horizontal component of the force because the cart is moving in that direction.

[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]

Hence, the acceleration of the car is 1.5 m/s².    

I hope it helps you!

Answer:

As tectonic plates slowly move away from each other, heat from the mantle's convection currents makes the crust more plastic and less dense.

Explanation:

Answer: The main cause of sea floor spreading are the directions and force of the moving tectonic plates.

Explanation:

Answer:

10 Pa

Explanation:

Pressure is defined as force per unit area.

Mathematically, P= F/A where  P is pressure, F is force and A is area.

Force, F = 60 N

Area, A = 2*3 = 6m²

P = 60/6 = 10 Pa

Answer:

35.28m/s

Explanation:

Given

Time t = 3.6secs

Required

Final speed v

Using the equation of motion;

v = u + gt

Substitute;

v = 0 + 9.8(3.6)

v = 0 + 35.28

v = 35.28m/s

Hence the speed of the marble is 35.28m/s

Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.

Given that,

Mass of student 1, m₁ = 90 kg

Mass of student 2, m₂ = 60 kg

Speed of student 1, v₁ = 5 m/s

To find,

The velocity of the other student.

Solution,

Using the conservation of momentum to find the velocity of the other student. Let it is v₂.

[tex]m_1v_1=m_2v_2\\\\v_2=\dfrac{m_1v_1}{m_2}\\\\v_2=\dfrac{90\times 5}{60}\\\\=7.5\ m/s[/tex]

So, the velocity of the other student is 7.5 m/s.

Answer:

Question 4 is actually Acceleration

Answer:

So we can have energy  for electronics. It limits the flow of electric current

Explanation:

It’s in the answer!

Answer:

Basically, the function of a resistor is always to oppose the flow of current through it and the strength of this opposition is termed as its resistance.

Answer: All UV can have harmful effects on biological matter (such as causing cancers) with the highest energies causing the most damage.

Explanation:

Answer:

8

Explanation:

The energy levels is given as

E(n) = n² * h² / ( 8 * m * L²), where

n = 1, 2, 3, 4,... etc

At ground state energy (n = 1), therefore is E(g) = h² / (8 * m * L²).

We can then say that

E(n) = n² * Eg

Therefore, to have E = 64 Eg, we must have n² = 64. And for n² to be equal to 64, we find the square root of n

n = √64

n = 8

Essentially, the needed quantum number is 8

Answer:

The correct answer is 4R1

Explanation:

According to the given scenario ,the radius of the tightest curve on the same road without skidding is as follows:

As we know that

Centeripetal Acceleration is

= v^2 ÷ r

In the case when velocity becomes 2 times so the r would be 4 times

So, the radius of the  tightest curve on the same road without skidding is 4R1

Answer: c. 1.89 x 10^14 J

Explanation:

By Einstein's equation, we know that:

E = m*c^2

Where m is the mass-consumed in this case:

m = 2.10g

And we must rewrite this in Kg, knowing that:

1kg = 1000g

Then:

m = 2.10g = (2.10/1000) kg = 0.0021 kg

And c is the speed of light:

c = 3*10^8 m/s.

Then the energy will be:

E = 0.0021 kg*(3*10^8 m/s)^2 = 1.89*10^14 Joules.

The correct option is:

c. 1.89 x 10^14J

Answer:

Due east - 0.42mps

Due west - 0.29mps

Explanation:

So for the 5 meters 12s

and 2 meters 7s

for the first one we will do 12/5 = 2.4

for the second one 7/2 = 3.5

that is the amount of seconds per meter but we want meters per seconds so

5/12 = 0.42mps

2/7 = 0.29mps

Answer:

The value is [tex]p = - 2.63 \ Diopters[/tex]

Explanation:

From the question we are told that  

      The value of the far point is  [tex]a = 40 \ cm = 0.4 \ m[/tex]

      The distance of the lens to the eye is  [tex]b = 2 \ cm = 0.02[/tex]

Generally

        [tex]1 Diopter = > 1 m^{-1}[/tex]

Generally the power spectacle lens needed is mathematically represented as

           [tex]p = \frac{1}{d_o } + \frac{1}{d_i}[/tex]

Here [tex]d_o[/tex] is the object distance which for a near sighted person is [tex]d_o = \infty[/tex]

And  [tex]d_i[/tex] is the image distance which is evaluated as

        [tex]d_i = b - a[/tex]

=>     [tex]d_i = 0.02 - 0.4[/tex]

=>     [tex]d_i = -0.38 \ m[/tex]

So

         [tex]p = \frac{1}{\infty } + \frac{1}{-0.38}[/tex]

=>      [tex]p = 0 - 2.63[/tex]

=>      [tex]p = - 2.63 \ Diopters[/tex]

Answer:

The number of crate to be lifted is 27

Explanation:

Given;

mass of the crates, m = 25 kg

height in which the crate is lifted, h = 1.0 m

power output, P = 110 W

time to complete the task, t = 1 minutes = 60 s

The input energy is equal to the gravitational energy due to height the crate is lifted is given as;

E(input) = mgh

E(input)  = 25 x 9.8 x 1

E(input)  = 245 J

Output energy is given as;

E(output) = P x t

E(output) = 110 x 60

E(output) = 6600 J

Let the number of crate to be lifted = n

n x E(input)  = E(output)

n x 245 = 6600

n = 6600 / 245

n = 27 crates

Hello!

[tex]\large\boxed{KE = 50J}[/tex]

Use the formula for kinetic energy:

[tex]KE = \frac{1}{2}mv^{2}[/tex]

Plug in the given mass and velocity:

[tex]KE = \frac{1}{2} (4)5^{2}[/tex]

Simplify:

[tex]KE = \frac{1}{2} (100)\\\\KE = 50 J[/tex]

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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